Fig. A shows a paper cup in the shape of an inverted right circular cone. Its base radius is 4 cm and its slant height is 8.5 cm.
(a) Find the capacity of the paper cup.
(b) The paper cup is cut along PQ to form the sector in Fig. B. Find
(i) the area of the sector,
(ii) the angle of the sector.
(a)
Height of the cup
= [tex]\sqrt{ {8.5}^{2} - {4}^{2} }[/tex]
= 7.5 cm
The capacity of the cup
= [tex] \frac{1}{3} \times \pi \times {4}^{2} \times 7.5[/tex]
= 126 cm³ (cor. to 3 sig. fig.)
(b)(i)
The area of the sector
= [tex]\pi \times 4 \times 8.5[/tex]
= 107 cm² (cor. to 3 sig. fig.)
Can you help me for (b)(ii)?
Answers
9514 1404 393
Answer:
16π/17 radians ≈ 169.41°
Step-by-step explanation:
The arc length of the sector is the circumference of the cone:
C = 2πr = 2π(4 cm) = 8π cm
The angle and arc length are related by ...
s = rθ . . . . . θ in radians
8π cm = (8.5 cm)θ
θ = 8π/8.5 = 16π/17 . . . . radians
bii) The angle of the sector is 16π/17 radians ≈ 169.41°.
Answer:
169° (3sf)
Step-by-step explanation:
the area of a circle multiplied by the angle over 360 gives you ans.
x/360 × π × r²=34π -> ur ans frm part i
x × π(8.5²)=12240π
x × 72.25=12240
x=169.41°
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What is Ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Prasad worked 15 hours this week and earned $195
We have to find the amount earned by prasad for work 12 hours
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