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13) A student walks 20 m north, 10 m south, and 3 m north. To have a displacement of 0 m,
the student should walk _____m toward the _____.

The deceleration of the motorcycle is -3.0 m/s^2 and it travels 75.0 m during deceleration.

To find the deceleration of the motorcycle, we can use the formula:

deceleration = (final velocity - initial velocity) / time

Plugging in the given values, we get:

deceleration = (0 m/s - 15.0 m/s) / 5.0 s = -3.0 m/s^2

To find the distance the motorcycle travels during deceleration, we can use the formula:

distance = (initial velocity * time) + (1/2 * deceleration * time^2)

Plugging in the given values, we get:

distance = (15.0 m/s * 5.0 s) + (1/2 * -3.0 m/s^2 * 5.0 s^2) = 75.0 m

So the deceleration of the motorcycle is -3.0 m/s^2 and it travels 75.0 m during deceleration.

The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m

We'll begin by obtaining the acceleration of the box. Details below:

Net force = mass × acceleration

40 = 10 × acceleration

Divide both sides by 10

Acceleration = 40 / 10

Acceleration = 4 m/s²

Finally, we shall determine the distance. Details below

v² = u² + 2as

5² = 0² + (2 × 4 × s)

25 = 0 + 8s

25 = 8s

Divide both side by 8

s = 25 / 8

s = 3.125 m

Thus, we can conclude that the distance covered is 3.125 m

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It is a well-known fact that often applying force does not cause a change in the condition of motion. For instance, even if you use all of your force, a hefty box could not budge at all. Again, attempting to push a wall has no noticeable effect.

Because you pushed against the wall, but the wall pushed back against you with an equal and opposite force, you slide in the opposite direction (away from the wall).

Therefore, There are just two forces at work: friction and gravitation. Yes, the frictional force's magnitude must match the weight. Given that it is parallel to the wall, the friction is in the vertical direction (which is vertical)

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The car’s average acceleration is 6 meter/second^2.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given that: the car can accelerate from rest to 30 m/s in 5 seconds.

Hence, average acceleration of the car = change in speed/time interval

= ( final speed - initial speed)/time interval

= ( 30 m/s - 0 m/s) / 5 second

= (30/5) meter/second^2

= 6 meter/second^2.

Hence, the  average acceleration of the car  is  6 meter/second^2.

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Answer:

Below

Explanation:

ESE = 1/2 k d^2

        = 1/2 *  10 N/m * .1 m = .5 J

The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is  147.2 N .

The Pascal's Law states that the relation between the pressure , force and area is given as :

Pressure = Force/Area ;

given that the diameter of the master cylinder is = 1.93 cm ;

so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;

the diameter of slave cylinder is = 24.9 cm ;

the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;

Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²

Area of the master cylinder (A₂) =  π(0.00965)² = 0.000292 m² ;

given mass of the car = 2500 Kg ,

the force exerted will be : F = m*a

F₁ = 2500*9.8 = 24500 N ;

F₁/A₁ = F₂/A₂

So , 24500/0.0486 = F₂/0.000292

F₂ = (24500/0.0486)×0.000292

F₂ = 147.2 N

Therefore , the force exerted on the master cylinder is 147.2 N  .

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Answer: Acceleration

Explanation:

When two objects interact through the gravitational force between them, the more massive one has a lower acceleration than the less massive object.

Answer:

.30 kg mass moving at 1.0 m/s

Explanation:

Well if the 30 mass isn't moving, then that isn't momentum. But if the .30 kg of mass if moving, then that would be momentum. So the correct answer is .30 kg of mass

Answer:

a 0.30 kg mass moving at 1.0 m/s

Explanation:

p = mv

Momentum is the product of mass and velocity. Since a stationary object has velocity=0, it has momentum=0*mass=0

An object with positive mass and nonzero velocity will always have positive momentum, so we could stop here.

An object with m=0.3kg and v=1m/s has

p = mv = 0.3kg * 1m/s = 0.3kg*m/s

which is more than 0.

The rate at which sun transfers its mass to other forms of energy is 4.3* 10⁹ kg/s.

The fraction of its original mass has the sun lost in this way since it began to burn hydrogen, about 4.5 x 109 y ago is 3.1 * 10⁻⁴.

Given that,

Mass of the sun = 2* 10³⁰ kg

Radiation power P = 3.9* 10²⁶ W

The rate of changing mass is P = E/t = (m*c²)/t

Re-arranging the terms, we have,

m/t = P/c² = (3.9* 10²⁶)/(3* 10⁸)² = 4.3* 10⁹ kg/s

Fraction of original mass lost is Δm = m/t * t = (4.3* 10⁹)* (4.5* 10⁹)

⇒ 6.15 * 10²⁶ kg

Fraction of mass lost = Δm/(m + Δm) = (6.15 * 10²⁶)/(2* 10³⁰ + 6.15 * 10²⁶)

⇒ 3.1 * 10⁻⁴

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The magnitude of the tangential acceleration is 0.329m/s².

At=r a t = r is the formula for tangential acceleration, where r is the circle's radius and is the angular acceleration. The definition is derived from the fact that the arc length is equal to the circle's radius times the angle in radians.

d = Diameter of rim = 11.0 in = 11 × 0.0254 = 0.2794m

r = Radius = d/2 = 0.2794/2 = 0.1397m

[tex]\omega_{f}[/tex] = Final angular velocity = 79 × 2π/60 = 8.26rad/s

[tex]\omega_{i}[/tex] = Initial angular velocity = 0

∝ =  Angular acceleration

t = Time taken = 3.5s

Rotational motion equation,

[tex]\omega_{f}[/tex] = [tex]\omega_{i}[/tex] + ∝t

∝ = [tex]\omega_{f}[/tex] - [tex]\omega_{i}[/tex]/t

∝ = 8.26 - 0/3.5

∝ = 2.36 rad/s²

Magnitude of the tangential acceleration given by

[tex]a_{t}[/tex] = r∝

[tex]a_{t}[/tex] = 2.36 × 0.1397

[tex]a_{t}[/tex] = 0.329m/s².

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The angle between the resultant and the larger force is 60 degree  if resultant force value is value 9.1Newtons.

We know that resultant force is given by the superposition principle which uses a formula

Resultant force =√((F₁)² + (F₂)² + 2 ˣ F₁ ˣ F₂ ˣ cosθ)

Superposition principle of electric force to find the resultant power, all accuses are thought about independently of that specific charge as though any remaining charges are missing. Along these lines, for each charge, the power on that specific charge is to be found out. Then the vector amount of the multitude of forces gives the resultant forces on that charge.

We have resultant force as 9.1Newton,F₁=6.2newton,F₂=4.4 newton

So,on putting the values,we get

=>(9.1) = √[(6.2)² + (4.4)² + 2 × 6.2×4.4×cosθ]

Squaring on both sides,we get

=>9.1 × 9.1 =(6.2)² + (4.4)² + 2× 6.2×4.4×cosθ

=>82.81=38.44 + 19.36 + 54.56×cosθ

=>82.81=57.8+ 54.56×cosθ

=>82.81-57.8= 54.56×cosθ

=>25.01=54.56×cosθ

=>cosθ=25.01/54.56

=>cosθ = 0.458

=>cosθ=cos(62.5)°

=>θ=62.5°

=>θ=60°(nearest 10th)

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  (+ , -)

- sin(55)=y/18.5 -> 18.5sin(55)=y

- cos(55)=x/18.5 -> 18.5cos(55)=x

The magnitude will be given by |v|=a2+b2 if v=a,b is indeed the coordinates.In accordance with the application the direction usually equal to the angle made with the x-axis or the y-axis.The formula tan=(ba)=tan1(ba) can be used to determine the direction of a position vector, as shown in Figure 8.8.

Any number of dimensions can be included in the generalization of the vector magnitude formula.For instance, the formula for the magnitude of a four-dimensional vector a=(a1,a2,a3,a4) is a=a21+a22+a23+a24.

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Answer:

heat energy

Explanation:

heat energy

The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m

To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:

s = ut

20 = 5 × t

Divide both sides by 5

t = 20 / 5

t = 4 s

Finally, we shall determine the height of the cliff. Details below:

h = ½gt²

h = ½ × 9.8 × 4²

h = 4.9 × 16

h = 78.4 m

Thus, the height of the cliff is 78.4 m

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Assuming a piece of stone is projected vertically upwards with a speed of 25ms^-1, its speed at its highest point reached is equal to zero (0) m/s.

In Science, projectile motion can be defined as a form of motion which is experienced by a physical object (body) that is projected near the surface of planet Earth, while moving along a parabolic path, and under the influence of a gravitational force (gravity) only.

Generally speaking, when this stone is thrown straight up or projected vertically upwards at a certain speed, it begins to slow down as a result of the effect of downward gravitational acceleration.

Consequently, the stone reaches a maximum height (highest point) where it cannot go higher anymore and then starts to fall down (descend) due to gravity.

In this context, we can reasonably infer and logically deduce that the speed of any physical object would be equal to zero (0) meter per seconds when it reaches a maximum height (highest point).

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Complete Question:

A piece of stone is projected vertically upwards with a speed of 25 ms^-1. Determine its speed at its highest point reached. (g = 10 ms-2).

After thrown from his horse, Collin might have trouble with his occipital lobe.

The occipital lobe is one of the four significant lobe of the cerebral cortex in the mind of warm blooded creatures. The name gets from its situation at the rear of the head, from the Latin ob, "behind", and caput, "head".

The occipital lobe is the visual handling focus of the mammalian mind containing a large portion of the physical locale of the visual cortex. The essential visual cortex is Brodmann region 17, ordinarily called V₁(visual one). Human V₁ is situated on the average side of the occipital curve inside the calcarine sulcus; the full degree of V₁ frequently go on onto the occipital shaft.

V₁ is much of the time likewise called striate cortex since it tends to be distinguished by a huge stripe of myelin, the Stria of Gennari. Outwardly determined locales outside V₁ are called extrastriate cortex. There are numerous extrastriate districts, and these are specific for various visual errands, for example, visuospatial handling, variety separation, and movement insight. Two-sided injuries of the occipital curve can prompt cortical visual deficiency.

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Using the water that is both held in dams and flowing in rivers, hydropower, also known as hydroenergy, is a renewable energy source.

In order to generate electricity, hydroelectric power uses the force of moving water, making it a renewable energy source. Long before you switch on a light at home or at work, the hydroelectric process has already begun.

Water must flow in order to generate power. Kinetic energy is energy that moves. The energy transforms into mechanical (machine) energy as flowing water turns blades in a turbine.

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On an ECG machine that meets the international standard, the paper moves at 25 mm/second.

When a soap bubble 100 nm thick and illuminated by white light incident perpendicular to its surface, then wavelength, λ is calculated =  5.32 *10^-7 m.

The ratio of the speed of light in a vacuum, c, to the speed of light in a medium, c' is called as index of refraction. One of the consequence of this difference in speed is that when light goes from one medium to another at an angle, then the propagation vector in the new medium has a different angle with respect to normal.

Given, t= 100nm= 100 * 10 ^-9  n= 1.33

ΔФ1 = λ/4

ΔФ2 = 2√2 t λ n/2 λ

=2 t n

=2 * 100 * 10 ^-9 * 1.33

= 2.66 *10^-7

2.66 *10^-7= λ/2

λ=  5.32 *10^-7 m.

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Newton's third law states that any action will have a(n) equal and opposite reaction.

According to the given statement 11303.5 kg  is the weight of the truck.

The buoyant force, which applies to a person at rest in a fluid, is proportional to the weight of the displaced water and pushes higher. The amount of fluid displaced when the body is fully immersed is equal to the body's volume.

The Archimedean principle, which asserts that the hydrostatic push is equal to the weight of the desalinated liquid, is used to solve this task.

B = ρ g V

It is in balance with the push when the truck is at full weight, according to Newton's law of equilibrium.

          Σ F = 0

          B-W = 0

          B = W

body weight

          W = M g

the volume is

          V = l to h

          (l to h) = M g

          M = l a h

we calculate

          M = F = 1000 . 10. (4.70 x 6.50 x 0.037)  = 11303.5 N

          M = 11303.5 kg

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The change in internal energy of a system is - 5290×10⁴J.

Innate strength A system's or a body's (with clearly defined boundaries) U is made up of the sum of the kinetic and potential energies resulting from molecular motion as well as the electric and vibrational motion of the atoms within molecules.

Heat transfer into the system Q₁ = 4.23×10⁶J

Heat transfer out of the system Q₂ = 9.07× 10⁶J

Work done W =  4.50×10⁵J

The heat transfer into the system less the heat transfer out of the system is now known as the net heat transfer.

Q = Q₁ - Q₂

Q = 4.23×10⁶ -  9.07× 10⁶

Q = -4.84× 10⁶J

The first law of thermodynamics provides the following formula for the change in internal energy:

ΔU = Q - W

ΔU = -4.84× 10⁶ -  4.50×10⁵

ΔU = - 5290×10⁴J.

A negative sign indicates a decrease in internal energy.

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Answer:

TRUE - A test booklet is sitting at rest on a desk. Compared to the force of the booklet on the desk, the force of the desk on the booklet is the same.

TRUE - The acceleration of an object is always in the direction of the net force acting on it.

Answer: D. Annular Solar Eclipse

Explanation:

An annular solar eclipse happens when the Moon passes between the Sun and Earth, but when it is at or near its farthest point from Earth. Because the Moon is farther away from Earth, it appears smaller than the Sun and does not completely cover the Sun.

True. The Big Bang Theory is the current scientific explanation for the origin and evolution of the universe. According to this theory, the universe was initially in a state of extremely high density and temperature, and it has been expanding and cooling since its inception.

One reason we cannot directly observe the Big Bang is that the universe's density was so low at that time that there were no solid particles, such as atoms or molecules, that could have formed into stars or galaxies. Instead, the universe was filled with a hot, ionized plasma that was too diffuse to be observed by telescopes. Another reason is that the expansion of the universe has caused the light and other electromagnetic radiation that was emitted during the Big Bang to become redshifted, or stretched out in wavelength, over time. This means that the light from the earliest moments of the universe has shifted into the microwave and radio frequency ranges, which are not visible to the human eye. Therefore, while we can infer some details about the conditions of the early universe based on observations of the cosmic microwave background radiation and the large-scale structure of the universe, we cannot directly observe the Big Bang itself.

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The downward force here on top of the cylinder is greater than this pressure's equivalent upward force here on bottom of the cylinder.

By pressing a knife on some fruit, one can get a straightforward illustration of pressure. The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area (low pressure).

Other pressure measurements include pounds per square inch, bar, millimeters of mercury (used to measure blood pressure), centimeters of water, torr, MSW, and FSW. Atmospheric pressure is measured in atm.

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The magnitude of the velocity of the aircraft P relative to aircraft Q is zero

The velocity of the two aircraft given is

P & Q, v = 300 m/s

The angle of the direction between P&Q is

Ф = 90°

The magnitude of the velocity of aircraft P relative to aircraft Q is given by the formula which is as follows:

 V = v cos Ф

Substituting the values in the above equation

                                  v = 300 x cos 90°

                                     = 300 x 0

                                     = 0

Since the aircraft are at right angles, the velocity of one aircraft relative to the other would be equal to zero.

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Answer:

The answer seems to be,

A) The ball is accelerated while it is pushed by the student's hand due to an

A) The ball is accelerated while it is pushed by the student's hand due to anunbalanced force.

(The answer might be wrong. )