Find all possible values of α+
β+γ when tanα+tanβ+tanγ = tanαtanβtanγ (-π/2<α<π/2 , -π/2<β<π/2 , -π/2<γ<π/2)
Show your work too. Thank you!​

Answers

Answer 1

Answer:

[tex]\rm\displaystyle 0,\pm\pi [/tex]

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

[tex] \rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma ) [/tex]

factor out tanγ:

[tex]\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)[/tex]

divide both sides by tanαtanβ-1 and that yields:

[tex]\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}[/tex]

multiply both numerator and denominator by-1 which yields:

[tex]\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)[/tex]

recall angle sum indentity of tan:

[tex]\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta ) [/tex]

let α+β be t and transform:

[tex]\rm\displaystyle \tan( \gamma ) = - \tan( t) [/tex]

remember that tan(t)=tan(t±kπ) so

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi ) [/tex]

therefore when k is 1 we obtain:

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi ) [/tex]

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi ) [/tex]

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm \pi [/tex]

isolate -α-β to left hand side and change its sign:

[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }[/tex]

when is 0:

[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 ) [/tex]

likewise by Opposite Angle Identity we obtain:

[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 ) [/tex]

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm 0 [/tex]

isolate -α-β to left hand side and change its sign:

[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }[/tex]

and we're done!

Answer 2

Answer:

-π, 0, and π

Step-by-step explanation:

You can solve for tan y :

tan y (tan a + tan B - 1) = tan a + tan y

Assuming tan a + tan B ≠ 1, we obtain

[tex]tan/y/=-\frac{tan/a/+tan/B/}{1-tan/a/tan/B/} =-tan(a+B)[/tex]

which implies that

y = -a - B + kπ

for some integer k. Thus

a + B + y = kπ

With the stated limitations, we can only have k = 0, k = 1 or k = -1. All cases are possible: we get k = 0 for a = B = y = 0; we get k = 1 when a, B, y are the angles of an acute triangle; and k = - 1 by taking the negatives of the previous cases.

It remains to analyze the case when "tan "a" tan B = 1, which is the same as saying that tan B = cot a = tan(π/2 - a), so

[tex]B=\frac{\pi }{2} - a + k\pi[/tex]

but with the given limitation we must have k = 0, because 0 < π/2 - a < π.

On the other hand we also need "tan "a" + tan B = 0, so B = - a + kπ, but again

k = 0, so we obtain

[tex]\frac{\pi }{2} - a=-a[/tex]

a contradiction.


Related Questions

please help, i don't understand the subject so i need an answer to help me out:) i will give brainliest to a good answer.

Answers

To be honest, I don't think it has anything to do with the exponent part at all. Instead, I think it has to do with the fact that integers are inherently easier to grasp compared to fractions (which is exactly what rational numbers are).

For instance, it's much easier to say 2+3 = 5 than it is to say 1/2 + 1/4 = 3/4

So going back to the exponent example, it's easier to say

x^2*x^3 = x^(2+3) = x^5

than it is to say

x^(1/2)*x^(1/4) = x^(1/2+1/4) = x^(3/4)

So that's my opinion as to why rational exponents are more tricky to grasp compared to integer exponents. Of course, everyone learns math differently so maybe some find fractions easier than others.

come help me!! rack up those points!! needing lots of help with geometry today :)

Answers

Answer:

312 in^2

Step-by-step explanation:

Yet again, not the best way but let's add up all the sides...

2(24+96+36) = 2(156) = 312 in^2

Hope this helped!

312in squared ________

ASAP!! can i get some help on this question please, and can i get a step by step explanation, thank you.

Answers

Answer:

2xy^2

Step-by-step explanation:

8/4=2

x^3/x^2=x

y^5/y^3=y^2

Answer:

2xy^2

Step-by-step explanation:

First, 8/4 is 2.

2x^3y^5 / 4x^2y^3

Then, we can bring the x^2 up. It becomes the -x^2. Combined with the x^3, we have x. Finally, we can bring the y^3 up, where it becomes -y^3. Combined with the y^5, we get y^2.

Our final answer is 2xy^2.

How to you write 1/25 using exponents

Answers

Answer:

[tex]5^{-2}[/tex]

Step-by-step explanation:

Using the rule of exponents

[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex] , then

[tex]\frac{1}{25}[/tex] = [tex]\frac{1}{5^{2} }[/tex] = [tex]5^{-2}[/tex]

In exponent form, it should be written as [tex]5^{-2}[/tex].

Given that,

The fraction is [tex]\frac{1}{25}[/tex]We need to write in the exponent form

Based on the above information, the calculation is as follows:

[tex]a^{-m} = \frac{1}{a^{m}} \\\\\frac{1}{25} = \frac{1}{5^{2}}[/tex]

[tex]5^{-2}[/tex]

Learn more: brainly.com/question/17429689

find the missing side of the triangle​

Answers

Answer:

197 is the missing side of the triangle

x= 197 ! i did it on a sheet of paper

I could really use a hand

Answers

Answer : -5a² + 10a

It was way easy ikr ~w~

Answer:

-5a2+10a

Step-by-step explanation:

distribute

-5a(a-2)

-5a2+ 10

Can someone help me on this please

Answers

The choices :

Three

B , E , D

Find an explicit formula for the geometric sequence \dfrac12\,,-4\,,\,32\,,-256,.. 2 1 ​ ,−4,32,−256,..start fraction, 1, divided by, 2, end fraction, comma, minus, 4, comma, 32, comma, minus, 256, comma, point, point. Note: the first term should be \textit{a(1)}a(1)start text, a, left parenthesis, 1, right parenthesis, end text. a(n)=a(n)=a, left parenthesis, n, right parenthesis, equals

Answers

Answer:

a(n)= 1/2 * (-8) n-1

Step-by-step explanation:

In a geometric sequence, the ratio between successive terms is constant. This means that we can move from any term to the next one by multiplying by a constant value. Let's calculate this ratio over the first few terms:

\dfrac{-256}{32}=\dfrac{32}{-4}=\dfrac{-4}{\frac12}=\blue{-8}  

32

−256

=  

−4

32

=  

2

1

 

−4

=−8start fraction, minus, 256, divided by, 32, end fraction, equals, start fraction, 32, divided by, minus, 4, end fraction, equals, start fraction, minus, 4, divided by, start fraction, 1, divided by, 2, end fraction, end fraction, equals, start color #6495ed, minus, 8, end color #6495ed

We see that the constant ratio between successive terms is \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. In other words, we can find any term by starting with the first term and multiplying by \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed repeatedly until we get to the desired term.

Let's look at the first few terms expressed as products:

nn 111 222 333 444

h(n)\!\!\!\!\!h(n)h, left parenthesis, n, right parenthesis \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large0}\!\!\!\!\!\!  

2

1

⋅(−8)  

0

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 0, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large1}\!\!\!\!\!\!  

2

1

⋅(−8)  

1

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 1, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large2}\!\!\!\!\!\!  

2

1

⋅(−8)  

2

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, squared \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large3}  

2

1

⋅(−8)  

3

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, cubed

We can see that every term is the product of the first term, \red{\dfrac12}  

2

1

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, and a power of the constant ratio, \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. Note that this power is always one less than the term number nnn. This is because the first term is the product of itself and plainly 111, which is like taking the constant ratio to the zeroth power.

Thus, we arrive at the following explicit formula (Note that \red{\dfrac12}  

2

1

start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030 is the first term and \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed is the constant ratio):

a(n)=\red{\dfrac12}\cdot\left(\blue{-8}\right)^{\large{\,n-1}}a(n)=  

2

1

⋅(−8)  

n−1

a, left parenthesis, n, right parenthesis, equals, start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, n, minus, 1, end superscript

Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.

Subtract – 7x2 + 4x + 2 from x2 – 3.

Answers

Answer:

8x^2 - 4x - 5

See the steps below for better explanation:

8 x (5 - 2) = ( _ x 5) - ( _ x 2)

Answers

Answer:

8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)

Step-by-step explanation:

8 x (5 - 2) = ( _ x 5) - ( _ x 2)

Distribute

8 x (5 - 2) = ( 8 x 5) - ( 8 x 2)

Please help will give brainliest, pls don’t just guess

Answers

Answer:

B = multiply both sides by 2y+1

Step-by-step explanation:

Answer:

B. multiply both sides by the equation 2y + 1

Please Help Asap Its Pre-Calculus

The point (−2, 2) is a solution to which of the following systems?

y > −2x + 2 and y > x + 5
y < x + 2 and y > x − 1
y < 2x + 8 and y ≥ −x − 3
y < 2x + 3 and y ≥ −2x − 5

Answers

The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]

Given point: [tex](-2,2)[/tex]

Given systems:

[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]

To find: The system to which the given point is a solution

If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.

(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]

Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.

Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,

[tex]2>-2(-2)+2[/tex]

[tex]2>4+2[/tex]

[tex]2>6[/tex]

The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.

This implies that the given point is not a solution of this system.

(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]

Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.

Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,

[tex]2<-2+2[/tex]

[tex]2<0[/tex]

The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.

This implies that the given point is not a solution of this system.

(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]

Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.

Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,

[tex]2<2(-2)+8[/tex]

[tex]2<-4+8[/tex]

[tex]2<4[/tex]

This is a true inequality. Then, the given point satisfies the first inequality of the system.

We will now check if the point satisfies the second inequality of the system.

Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,

[tex]2 \geq -(-2)-3[/tex]

[tex]2 \geq 2-3[/tex]

[tex]2 \geq -1[/tex]

This is also a true inequality. Then, the given point also satisfies the second inequality of the system.

Thus, the given point is a solution of this system.

(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]

Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.

Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,

[tex]2<2(-2)+3[/tex]

[tex]2<-4+3[/tex]

[tex]2<-1[/tex]

The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.

This implies that the given point is not a solution of this system.

Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.

Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].

Learn more about geometric solutions of system of linear inequalities here:

https://brainly.com/question/17174433

PLEASE simplfy 8^15÷8^−3

Answers

Answer:

8^18

Step-by-step explanation:

We know that a^b ÷ a^c = a^(b-c)

8^15÷8^−3

8^(15 - -3)

8^(15+3)

8^18

make g the subject 4m+2g=p​

Answers

Step-by-step explanation:

4m+2g=p

2g=p-4m

g=(p-4m)/2

Answer:

g = p/2 - 2m

Step-by-step explanation:

4m +2g = p

Subtract 4m from each side

4m -4m +2g = p-4m

2g = p -4m

Divide each side by 2

2g/2 = p/2 - 4m/2

g = p/2 - 2m

A motorbike is for sale at $13000. Finance is available at $3000 deposit and monthly
repayments of $520 for 4 years. What is the interest paid?

Answers

520 x 12 months x 4 years = 24960

24960 + 3000 deposit = 27,960 total paid.

27,960 - 13,000 = 14,960 total interest paid

Factor the polynomial

Answers

Answer:

(x+8)(x+7)

Step-by-step explanation:

Find two numbers that add to

b

and mulitply to

a*c

so find two numbers that add to

15

and mulitply to

56

Those two numbers are 8 and 7

therefore the answer is

(x+8)(x+7)

(X + 7) (x + 8). You just take the multiples of 56 that equal 15

Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)

Answers

Answer: 7m⁵ -3m³ - 3

Working:

= (6m⁵ + 3 - m³ - 4m) -(-m⁵ + 2m³- 4m +6)

= 6m⁵ + 3 - m³ - 4m +m⁵-2m³+4m - 6

= 6m⁵ + m⁵-m³ -2m³ -4m + 4m - 6 +3

= 7m⁵ -3m³ - 3

Answered by Gauthmath must click thanks and mark brainliest

Given that cos 75 = X, show that cos 105 = −X

Answers

Step-by-step explanation:

cos(90) = 0

around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.

but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90

75 = 90 - 15

105 = 90 + 15

so, a = 15

and because of

|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90

cos (90-15) = cos(75) = -cos(90+15) = -cos(105)

A giant pie is created in an attempt to break a world record for baking. The pie is shown below:

A circle is shown with a central angle marked 45 degrees and the diameter marked 15 feet.

What is the area of the slice of pie that was cut, rounded to the nearest hundredth?

22.08 ft2
24.45 ft2
26.32 ft2
28.97 ft2

Answers

Answer:

22.08 ft^2

Step-by-step explanation:

First find the area of the full circle

A = pi r^2

The diameter is 15 so the radius is 1/2 (15) = 7.5

A = (3.14) (7.5)^2

   =176.625

45 degrees is  a fraction of a circle which is 360 degrees

45/360 = 1/8

Multiply the area of the circle by this fraction

1/8 (176.625) =22.078125

Rounding to the nearest hundredth

22.08

Answer:

22.08 ft2

Step-by-step explanation:

Two kids, Albert and Bhara, are 20.0 m apart. Albert sees a soccer ball 25.0 m away. If the angle between the line formed by Albert and Bhara and the line from Albert to the soccer ball is 25 degrees, how far is Bhara from the soccer ball? Correctly round your answer to the nearest tenth of a meter.

Answers

Answer:

11m

I did it by Geometry and used the scale : 1cm represents 5m

b)
Four students represented the same pattern with the following equations:

Simon C = 4n + 1
Shania C = 3n + 4 + n-3
Tate C = (6n + 1) + (-2n)
Navdeep C = 2(2n + 3) -5
Use algebra skills to determine which of these four equations are equivalent. Show your work.

Answers

Simon

C = 4n + 1

Shania

C = 3n + 4 + n -3

C = 4n + 1

Tate

C = (6n + 1) + (-2n)

C = 6n + 1 - 2n

C = 4n + 1

Navdeep

C = 2(2n + 3) -5

C = 4n + 6 - 5

C = 4n + 1

Therefore all of them are equivalent.

Answered by Gauthmath must click thanks and mark brainliest

CAN SOMEONE HELP ME PLEASE

Answers

It’s 0.39 Hope this helps!

ignore drawings of triangles and the answer is not D !! Thank you!!​

Answers

Answer:

it's A

Step-by-step explanation:

the two triangles make up a parallelogram

how prove the following
cos²(120°-A) + cos²A + cos²(120°+A)= 3/2

Answers

Answer:

Sorry if it is not clear enough

PLEASE HELP I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

correct option is A

Step-by-step explanation:

mark me

A. is your correct answer!!!!
Hope this helps!!!!!!

1.
Write a function rule for the table.

Answers

Answer:

Step-by-step explanation:

If you plot these points on a graph, you would see that this is definitely a line. Let's find the slope of the line first:

[tex]m=\frac{2-1}{6-5}=1[/tex] (I used the last 2 coordinates on the table because I don't like negatives; and since the slope is the same for the whole entire line, it doesn't matter which points you pick to go into your slope formula)

And then use that slope and any other point in the table to write the equation. I am going to use (4, 0), since I like the 0 (less work!)

In point-slope form:

y - 0 = 1(x - 4) and

y = x - 4

That's the function rule (aka equation) for the table.

(PLEASE ANSWER ASAP I JUST NEED TO SEE IF I GOT THE RIGHT ANSWER PLEASE EXPLAIN ALSO)

Answers

Answer:

37.15 pounds left

Step-by-step explanation:

Add the two pound values

1.3+1.75= 3.05

Subtract it from the total number of pounds in the bag

40.2-3.05

=37.15

So you would start by adding up the total amount he ate. So that would be

1.3 + 1.75 = 3.05

Then you have to subtract the amount he ate from the total amount.

40.2 - 3.05 = 37.15

So your answer would be 37.15 let me know if you don’t understand something, more than happy to help.

A brick is in the shape of a rectangular prism with a length of 6 inches, a width of 3 inches, and a height of 5.5 inches. The brick has a density of 2.7 grams per cubic centimeter. Find the mass of the brick to the nearest gram.

pls pls pls help

Answers

y............. xnxnxnxnxnccncncncnnncncjcjnf

I am really bad at algebra please help!!
I need it now please with explanation ☺️​

Answers

Answer:

E. 7x

Step-by-step explanation:

3x plus 4x is equal to 7x because they both have the same terms and when added cannot the X of 3x and 4x cannot be joined together .

So they remain the same.

(e) 12x

(f) 12x²

(g) 12x²

(h) 1x

(I) 2x²

(J) 2x²

(K) -10x

(L) -20x

(M) 6x²

(N) 20x²

(O) -15x²

(P) -12x³

Your answers were wrong so i did all of them

Quick tip the power comes only when you multiply and not when you add

For example x + x = 2x

x × x = x²

All the answers

Must click thanks and mark brainliest

18. DEFG is a rectangle. Find the
length of each side.

Answers

hdxhjxjxjsndhxycyyxhdj

Answer:

DE=27

EF=13

DG=13

GF=27

Step-by-step explanation:

12x+3=5x+17

12x-5x=17-3

u'll get 14 then simply it by the numbe of X u'll get 2 then replace the X with the number

Other Questions
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