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Explanation:

The table says that

That's 5+10+15 = 30 students out of 35 total.

The probability is therefore 30/35 = 0.8571 approximately which rounds to 0.86

There's roughly an 86% chance of picking someone who got an A, B or C.

Answer:

Step-by-step explanation:

Answer:

Amount of his salary spent on food = Php 7400

Step-by-step explanation:

Mr. Bartolome's salary = Php 18500

Percentage of salary spent on food = 40%

Amount of his salary spent on food = 40% of Php 18,500

= 40/100 × Php 18,500

= 0.4 × Php 18,500

= Php 7400

Amount of his salary spent on food = Php 7400

Answer:

70. 8x⁴

71. 3n - 10

72. a/5 + 12

Step-by-step explanation:

70. a number "x" raised to the fourth = x⁴

Product of 8 and x⁴ = 8 × x⁴

= 8x⁴

71. 3 times a number "n" = 3 × n = 3n

3n decreased by 10 = 3n - 10

72. Quotient of a number "a" and 5 = a/5

12 more than a/5 = a/5 + 12

Answer:

|||

Step-by-step explanation:

the answer is c (|||)

Answer:

the answer is c

Step-by-step explanation:

the answer is C(111)

[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]

[tex]y=\dfrac{qx}{p}\\\\qx=py\\\\x=\dfrac{py}{q}[/tex]

Answer:

[tex]x = \frac{yp}{q}[/tex]

Step-by-step explanation:

Answer:

51

Step-by-step explanation:

See the other answer

Answer:

(B). 51°

Step-by-step explanation:

i think 51 is answer......

Answer:

Option B

<F = 26°

<D = 64.01°

FD = 89

Answered by GAUTHMATH

For right triangle EFD,  m ∠F ≈ 26°, m ∠D ≈ 64.01° and FD = 89

The correct answer is an option (B)

It is the longest side of the right triangle.

For a right triangle,

[tex]a^{2}+ b^{2} = c^{2}[/tex], where c is hypotenuse and a, b area other two sides of the right triangle

For given example,

We have been given a right triangle EFD with hypotenuse FD.

Also, EF = 80, ED = 39

Using the Pythagoras theorem,

[tex]\Rightarrow FD^{2}= EF^{2} + ED^{2}\\\\ \Rightarrow FD^{2}= 80^{2} + 39^{2}\\\\ \Rightarrow FD^2 = 6400 + 1521\\\\ \Rightarrow FD^2 = 7921\\\\\Rightarrow FD = 89[/tex]

Consider, sin(F)

[tex]\Rightarrow sin(F)=\frac{ED}{FD} \\\\\Rightarrow sin(F)=\frac{39}{89}\\\\ \Rightarrow sin(F)=0.4382\\\\\Rightarrow \angle F=sin^{-1}(0.4382)\\\\\Rightarrow \angle F=25.98^{\circ}\\\\\Rightarrow \angle F\approx 26^{\circ}[/tex]

Now, consider sin(D)

[tex]\Rightarrow sin(D)=\frac{FE}{FD}\\\\ \Rightarrow sin(D)=\frac{80}{89}\\\\ \Rightarrow \angle D = sin^{-1}(0.8988)\\\\\Rightarrow \angle D = 64.009^{\circ}\\\\\Rightarrow \angle D \approx 64.01^{\circ}[/tex]

Therefore, for right triangle EFD,  m ∠F ≈ 26°, m ∠D ≈ 64.01° and FD = 89

The correct answer is an option (B)

Learn more about Pythagoras theorem here:

https://brainly.com/question/343682

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Answer:

D. e - 35

Step-by-step explanation:

We have that:

George earned e extra points.

Kate earned k extra points.

Kate earned 35 fewer extra credit points than George.

This means that k is e subtracted by 35, that is:

k = e - 35

So the correct answer is:

D. e - 35

Step-by-step explanation:

Answer:

Answer is derived according to the procedure of calculating LCM of any two numbers

Step-by-step explanation:

If you have any other questions

ask in comments

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]x^2-y^2-1-2y \\\\x^2-(y^2+2y+1)\\\\x^2-(y+1)^2\\\\(x)^2-(y+1)^2\\\\(x+y+1)(x-y-1)[/tex]

[tex]\\\\[/tex]

[tex] y^2-1-x^2-2x\\\\y^2-(x^2+2x+1)\\\\y^2-(x+1)^2\\\\(y)^2-(x+1)^2\\\\(y+x+1)(y-x-1) [/tex]

According to the question,

we have to find the LCM

Answer:

same y intercept

Step-by-step explanation:

The y intercept is when r = 0

Function 1

p = -3/2 r - 5

Let r = 0

p = 0-5

p = -5

Function 2

When r = 0  p = -5

They both equal -5, so they both have the same y intercept

We found that the height of the short wall "x" is 162.6 ft, the height of the tall wall "y" is 221.8 ft, and the distance between the canyon walls "z" is 162.6 ft.

To find the x, y, and z values we need to denote the right triangles from top to bottom as triangles 1, 2, and 3.

1. Finding the height of the short wall "x"

We can find the height of the short wall "x" (in triangle 3) with the following trigonometric function:

[tex] cos(\theta) = \frac{x}{H} [/tex]

Where:

H: is the hypotenuse = 230 ft

θ: is the angle between x and H.

Knowing that the sum of θ and the angle 45° must be equal to 90°, θ is:

[tex] \theta = 90 - 45 = 45 [/tex]

Hence, the height of the short wall "x" is:

[tex]x = cos(\theta)*H = 230cos(45) = 162.6 ft[/tex]                

2. Finding the height of the tall wall "y"  

The height of the tall wall "y" is given by the sum of the bases of the two first right triangles (the right triangles 1 and 2):

[tex] y = y_{1} + y_{2} [/tex]        

Where y₁ and y₂ can be calculated with the tangent and sine trigonometric functions.  

[tex]y_{1} = A*tan(20)[/tex]        

[tex] y_{2} = 230sin(45) [/tex]

Where A is the adjacent side to the angle 20°.

[tex] y = A*tan(20) + 230sin(45) [/tex]      

Since the right triangles 2 and 3 form a square, with all the sides equals to x, we have:        

[tex] A = z = y_{2} = x = 230cos(45) [/tex]        

We can use 230cos(45) or 230sin(45) to calculate y₂, so the height of the tall wall "y" is:      

[tex] y = y_{1} + y_{2} = A*tan(20) + 230cos(45) = 230cos(45)tan(20) + 230cos(45) = 221.8 ft [/tex]                        

3. Finding the distance between the canyon walls "z"

As we said above, the "z" value is the same as "x", then:

[tex]z = x = 230cos(45) = 162.6 ft[/tex]

Learn more about trigonometric functions here: https://brainly.com/question/14272510?referrer=searchResults

I hope it helps you!                                        

Answer:

D. Closed circle on 8, shading to the right.