Answer:
1. 766,536cm^3
2. 29,680,948cm^3
3. 41,620.8cm^3
Step-by-step explanation:
1. 123×82 = 10,086 10,086×76 = 766,536
2. 422×278 = 117,316 117,316×253 = 29,680,948
3. 87×2.3 = 200.1 200.1×208 = 41,620.8
Hope this helps! :)
The mean per capita consumption of milk per year is 131 liters with a variance of 841. If a sample of 132 people is randomly selected, what is the probability that the sample mean would be less than 133.5 liters
Answer:
0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean per capita consumption of milk per year is 131 liters with a variance of 841.
This means that [tex]\mu = 131, \sigma = \sqrt{841} = 29[/tex]
Sample of 132 people
This means that [tex]n = 132, s = \frac{29}{\sqrt{132}}[/tex]
What is the probability that the sample mean would be less than 133.5 liters?
This is the p-value of Z when X = 133.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{133.5 - 131}{\frac{29}{\sqrt{132}}}[/tex]
[tex]Z = 0.99[/tex]
[tex]Z = 0.99[/tex] has a p-value of 0.8389
0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!
Answer:
9
[tex]3^{\frac{4}{2} }[/tex] = [tex]3^{2} =9[/tex]
Step-by-step explanation:
One angle of a triangle is twice as large as another. The measure of the third angle is 60° more than that of the smallest angle. Find the measure of each angle.
The measure of the smallest angle is º
Please help :)
Answer:
The measure of the smallest angle is 30º
Step-by-step explanation:
Let the angles be:
[tex]x \to[/tex] the first angle (the smallest)
[tex]y \to[/tex] the second angle
[tex]z \to[/tex] the third angle
So, we have:
[tex]y = 2x[/tex]
[tex]z=x + 60[/tex]
Required
Find x
The angles in a triangle is:
[tex]x + y +z = 180[/tex]
Substitute values for y and z
[tex]x + 2x +x + 60 = 180[/tex]
[tex]4x + 60 = 180[/tex]
Collect like terms
[tex]4x = 180-60[/tex]
[tex]4x = 120[/tex]
Divide by 4
[tex]x = 30[/tex]
Which statement is true about quadrilateral ABCD with vertices A(2, 8), B(3, 11), C(4, 8), and D(3, 5)?
Answer:
The quadrilateral is a rhombus
Step-by-step explanation:
Given
[tex]A = (2, 8)[/tex]
[tex]B = (3, 11)[/tex]
[tex]C = (4, 8)[/tex]
[tex]D=(3, 5)[/tex]
Required
The true statement
Calculate slope (m) using
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Calculate distance using:
[tex]d= \sqrt{(x_2 - x_1)^2 + (y_2 -y_1)^2}[/tex]
Calculate slope and distance AB
[tex]m_{AB} = \frac{11 - 8}{3 - 2}[/tex]
[tex]m_{AB} = \frac{3}{1}[/tex]
[tex]m_{AB} = 3[/tex] -- slope
[tex]d_{AB}= \sqrt{(3 - 2)^2 + (11 -8)^2}[/tex]
[tex]d_{AB}= \sqrt{10}[/tex] -- distance
Calculate slope and distance BC
[tex]m_{BC} = \frac{8 - 11}{4 - 3}[/tex]
[tex]m_{BC} = \frac{- 3}{1}[/tex]
[tex]m_{BC} = -3[/tex] -- slope
[tex]d_{BC} = \sqrt{(4-3)^2+(8-11)^2[/tex]
[tex]d_{BC} = \sqrt{10}[/tex] --- distance
Calculate slope CD
[tex]m_{CD} = \frac{5 - 8}{3 - 4}[/tex]
[tex]m_{CD} = \frac{- 3}{- 1}[/tex]
[tex]m_{CD} = 3[/tex] -- slope
[tex]d_{CD} = \sqrt{(3-4)^2+(5-8)^2}[/tex]
[tex]d_{CD} = \sqrt{10}[/tex] -- distance
Calculate slope DA
[tex]m_{DA} = \frac{8 - 5}{2 - 3}[/tex]
[tex]m_{DA} = \frac{3}{- 1}[/tex]
[tex]m_{DA} = -3[/tex] -- slope
[tex]d_{DA} = \sqrt{(2-3)^2 + (8-5)^2}[/tex]
[tex]d_{DA} = \sqrt{10}[/tex]
From the computations above, we can see that all 4 sides are equal, i.e. [tex]\sqrt{10}[/tex]
And the slope of adjacent sides are negative reciprocal, i.e.
[tex]m_{AB} = 3[/tex] and [tex]m_{CD} = -3[/tex]
[tex]m_{CD} = 3[/tex] and [tex]m_{DA} = -3[/tex]
The quadrilateral is a rhombus
find the h.c.f. if 84 and 72
Answer:
12
Step-by-step explanation:
First lets list all the factors of these numbers
72: 1,2 3,4,6,8,9,12,18,24,36,72
84: 1 , 2 , 3 ,4 , 6 , 7 , 12 , 14 , 21 , 28 , 42 , 84
Now lets find the biggest number that is a factor of both 84 and 72
as we can see the highest number that is the factor of both 84 and 72 is 12
12 is the hcf
What is net cash flow
What is the missing term in the factorization?
12x2 – 75 = 3 (2x+?)(2x – 5)
Answer:
12x2 – 75 = 3 (2x+5)(2x – 5)
Step-by-step explanation:
solve the equation 11n - 17 = 49
Answer:
The correct answer is =6.
Step-by-step explanation:
Solution,
Given;
11−17=49
or,11n-17=49
or,11−17+17=49+17
or,11=66
or,n=66/11
#n=6
HOPE IT HELPED♥︎
Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The function F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___
Answer:
The maximum value of the objective function is 112 when x = 0 and y = 7.
Step-by-step explanation:
Given the constraints:
5x+3y≤37, 3x+5y≤35, x≥0, y≥0
Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:
A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)
The objective function is given as E =2x+16y, therefore:
At point A(0, 7): E = 2(0) + 16(7) = 112
At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8
At point C(5, 4): E = 2(5) + 16(4) = 74
At point D(0, 0): E = 2(0) + 16(0) = 0
Therefore the maximum value of the objective function is at A(0, 7).
The maximum value of the objective function is 112 when x = 0 and y = 7.
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a standard deviation of 118. Determine the 26th percentile for the number of chocolate chips in a bag. (b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags. (c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?
Answer:
a) 1186
b) Between 1031 and 1493.
c) 160
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with mean of 1262 and a standard deviation of 118.
This means that [tex]\mu = 1262, \sigma = 118[/tex]
a) Determine the 26th percentile for the number of chocolate chips in a bag.
This is X when Z has a p-value of 0.26, so X when Z = -0.643.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.643 = \frac{X - 1262}{118}[/tex]
[tex]X - 1262 = -0.643*118[/tex]
[tex]X = 1186[/tex]
(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.
Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.
2.5th percentile:
X when Z has a p-value of 0.025, so X when Z = -1.96.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.96 = \frac{X - 1262}{118}[/tex]
[tex]X - 1262 = -1.96*118[/tex]
[tex]X = 1031[/tex]
97.5th percentile:
X when Z has a p-value of 0.975, so X when Z = 1.96.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.96 = \frac{X - 1262}{118}[/tex]
[tex]X - 1262 = 1.96*118[/tex]
[tex]X = 1493[/tex]
Between 1031 and 1493.
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?
Difference between the 75th percentile and the 25th percentile.
25th percentile:
X when Z has a p-value of 0.25, so X when Z = -0.675.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.675 = \frac{X - 1262}{118}[/tex]
[tex]X - 1262 = -0.675*118[/tex]
[tex]X = 1182[/tex]
75th percentile:
X when Z has a p-value of 0.75, so X when Z = 0.675.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.675 = \frac{X - 1262}{118}[/tex]
[tex]X - 1262 = 0.675*118[/tex]
[tex]X = 1342[/tex]
IQR:
1342 - 1182 = 160
Cole biked at 5 mph for 1 1/2 hours. Which of the following choices show how far he biked?
Answer:
Should be 5 1/2 if thats on there
Step-by-step explanation:
u take 11/2 and take out the 1 u get 10/2 so u cut 10 in half get 5 then add the one and make it 5 1/2
√(9+ √32)
Please simplify
Answer:
3.82
Step-by-step explanation:
[tex]\sqrt{(9+\sqrt{32}) }[/tex] Do not confirm the answer unless your equation looks like that?
[tex]\sqrt{(9+\sqrt{32}) }[/tex] Start by the [tex]\sqrt{32}[/tex]
[tex]\sqrt{(9+5.65) }[/tex] Now add (9 + 5.65)
[tex]\sqrt{14.65}[/tex] Finally Simplify
[tex]3.82[/tex] Final answer
For the problem I tried dividing but my answers were not correct. How can I solve this problem then? Can someone help me out here please?
Answer:
8
Step-by-step explanation:
5 = 40
1 = x
Then we multiply by the rule of crisscrossing
5 x X = 40 x 1
5x = 40 then divide both by 5
X = 8
Compute ????×????, where ????=????−2????+5????, ????=2????+????+3????. (Write your solution using the standard basis vectors ????, ????, and ????. Use symbolic notation and fractions where needed.)
Given: ????=????−2????+5????
and ????=2????+????+3????
To find: We need to find the value of ????×????
Solution: Here given,
????=????−2????+5????
and ????=2????+????+3????
Therefore, solving these two we have, ????=0
So,????×????=0
what graph shows the solution to the equation below log3(x+2)=1
Answer:
The solution to the equation log3(x+2)=1 is given by x=1
Step-by-step explanation:
We are given that
[tex]log_3(x+2)=1[/tex]
We have to find the graph which shows the solution to the equation log3(x+2)=1.
[tex]log_3(x+2)=1[/tex]
[tex]x+2=3^1[/tex]
Using the formula
[tex]lnx=y\implies x=e^y[/tex]
[tex]x+2=3[/tex]
[tex]x=3-2[/tex]
[tex]x=1[/tex]
Rajah 1 menunjukkan lukisan pelan berskala bagi sebuah rumah
lantainya berbentuk dua segi empat sama.
Skala yang digunakan adalah 1:200. Jika
kos memasang jubin jalah Rm 30 per m3
berapakah jumlah kos memasang jubin bagi
rumah tersebut?
Answer:
RM 1200 kalau ada gambar cuba insert
Which of the following are rational numbers?
Hi there!
»»————- ★ ————-««
I believe your answer is:
{7, -5, (2/3), 5.79}
»»————- ★ ————-««
Here’s why:
Rational numbers are numbers that could be written as a fraction with two integers.⸻⸻⸻⸻
[tex]\boxed{\text{\underline{\textbf{Some Examples of Rational Numbers Are...}}}}\\\\\rightarrow \text{Integers}\\\\\rightarrow \text{Perfect Squares}\\\\\rightarrow \text{Terminating Decimals}\\\\\rightarrow \text{Recurring Decimals}[/tex]
⸻⸻⸻⸻
7 and -5 are integers, so they are rational. [tex]\frac{2}{3}[/tex] is already a fraction with integers. It is rational.5.79 is a terminating decimal. It is rational.The number π is a famous irrational number. It does not terminate nor repeat. [tex]\sqrt{13}[/tex] is not a perfect square. It is irrational.[tex]\sqrt{-4}[/tex] is a perfect square, but it is simplified to a complex number. Complex numbers are not rational.⸻⸻⸻⸻
The rational numbers are {7, -5, (2/3), 5.79}.
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Order the following decimals. State your method of choice and your reasons for choosing it. Explain how you know this order is accurate.
Answer:
.40 is the greatest .350 is the second greatest and last but not least .3456 is the lowest
Step-by-step explanation:
Determine which diagram could be used to prove triangle ABC is congruent to triangle EDC using similarity transformations
Answer:
A
Step-by-step explanation:
edge 2021
NO LINKS OR ANSWERING WHAT YOU DON'T KNOW?
1. Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5?
a. 15
b. 5
c. 25
d. 1
2. Suppose y varies inversely with x, and y = a when x = a^2. What inverse variation equation related x and y?
a. y = a^2/x
b. y = a^3/x
c. y= a^3x
d. y = ax
3. Suppose y varies inversely with x, and y = 3 when x = 1/3. What is the inverse variation equation that relates x and y?
a. y = 1/x
b. y =x
c. y = 3x
d. y = 3/x
Answer:
1. D. 1
2. B. y=a³/x
3. A. y=1/x
Step-by-step explanation:
too long to give te explanations but they're there in the attachments
Question 1 of 10
One advantage of a long-term loan compared to a short-term loan is that a
long-term loan:
A. does not require the borrower to have a good credit score.
O
B. can be paid off in full without the borrower paying any interest.
C. does not force the borrower to make payments every month.
D. allows a person to borrow more money at a lower interest rate.
Answer:
D. allows a person to borrow more money at a lower interest rate
1. 650 - 700 - 800 = ?
2. 25 - 45 + 23 ＝?
carry on learning
Answer:
- 850
3
Step-by-step explanation:
650 - 700 - 800
650 - 1500
- 850
25 - 45 + 23
- 20 + 23
3
Simplify this math problem plz show your work
9514 1404 393
Answer:
(8a -a²)/(a +2)
Step-by-step explanation:
Cancel common factors from numerator and denominator.
[tex]\dfrac{-56+15a-a^2}{a^2+2a}\div\dfrac{a-7}{a^2}=-\dfrac{(a-7)(a-8)(a^2)}{a(a+2)(a-7)}\\\\=-\dfrac{a(a-8)}{a+2}=\boxed{\dfrac{8a-a^2}{a+2}}[/tex]
Solve by using matrices. 2x – y +2 + w = -3 x + 2y – 3z + w = 12 3x - y - + 2w = 3 -2x + 3y + 2 – 3w = -3
Some symbols and numbers are missing. I assume the system is supposed to read
2x - y + 2z + w = -3
x + 2y - 3z + w = 12
3x - y - z + 2w = 3
-2x + 3y + 2z - 3w = -3
In matrix form, this is
[tex]\begin{bmatrix}2&-1&2&1\\1&2&-3&1\\3&-1&-1&2\\-2&3&2&-3\end{bmatrix}\begin{bmatrix}x\\y\\z\\w\end{bmatrix}=\begin{bmatrix}-3\\12\\3\-3\end{bmatrix}[/tex]
which we can strip down to the augmented matrix,
[tex]\left[\begin{array}{cccc|c}2&-1&2&1&-3\\1&2&-3&1&12\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]
Now for the row operations:
• swap rows 1 and 2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\2&-1&2&1&-3\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]
• add -2 (row 1) to row 2, -3 (row 1) to row 3, and 2 (row 1) to row 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&-7&8&-1&-33\\0&7&-4&-1&21\end{array}\right][/tex]
• add 7 (row 2) to -5 (row 3), and row 3 to row 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&16&-2&-24\\0&0&4&-2&-12\end{array}\right][/tex]
• multiply through rows 3 and 4 by 1/2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&8&-1&-12\\0&0&2&-1&-6\end{array}\right][/tex]
• add -4 (row 4) to row 3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&0&3&12\\0&0&2&-1&-6\end{array}\right][/tex]
• swap rows 3 and 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&3&12\end{array}\right][/tex]
• multiply through row 4 by 1/3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&1&4\end{array}\right][/tex]
• add row 4 to row 3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&0&-2\\0&0&0&1&4\end{array}\right][/tex]
• multiply through row 3 by 1/2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• add -8 (row 3) and row 4 to row 2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&0&0&-15\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• multiply through row 2 by -1/5
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• add -2 (row 2) and 3 (row 3) and -1 (row 4) to row 1
[tex]\left[\begin{array}{cccc|c}1&0&0&0&-1\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
Then the solution to the system is (x, y, z, w) = (-1, 3, -1, 4).
Find the mean or average of these savings accounts $215, $156,$318, $75, and $25
Answer:
157.8
Step-by-step explanation:
Add them all up to get 789 and divide them by 5 as there are five numbers to get the answer:)
Change 9/3 to percentage
Answer:
300%
Step-by-step explanation:
because 9/3×100=900/3=300 so it is 300%
Answer:
300%
Step-by-step explanation:
9/3 * 100%
900%/3 = 300%
I can’t remember how to solve this?
Answer:
Step-by-step explanation:
[tex]\frac{(5.27+x)}{2} =-4.51[/tex],[tex]\frac{8.21+y}{2} = 1.37[/tex]
(3.75,-5.47)
Given the data points below, compute the sum of squared errors for the regression equation
Y
=
2
+
3
X
.
X
0
3
7
10
Y
5
5
27
31
Answer:
The sum of squared errors for the regression equation is 62.
Step-by-step explanation:
The sum of squared errors can be computed as follows:
X Y Y* = 2 + 3X Y - Y* (Y - Y*)^2
0 5 2 3 9
3 5 11 -6 36
7 27 23 4 16
10 31 32 -1 1
20 68 68 0 62
From the above, we have:
Error = Y - Y*
Error^2 = (Y - Y*)^2
Sum of squared errors = Sum of Error^2 = Total of (Y - Y*)^2 = 62
Therefore, the sum of squared errors for the regression equation is 62.
SOMEONE HELP PLEASE! So for this problem the answer I got is $4000. Is that the correct or incorrect answer? Can someone please help me if it is the incorrect answer. Thank you for your time.
Answer:
You're correct
Step-by-step explanation:
Each of the 8 cats in a pet store was weighed. Here are their weights (in pounds): 6,6, 10, 6, 8, 7, 14, 12 Find the median and mean weights of these cats. If necessary, round your answers to the nearest tenth. Median: pounds Х X ? Mean: pounds
Answer:
Median: 7.5
Mean: 8.6
Step-by-step explanation:
Median = the average of the 2 middle numbers of the set in ascending order, 6, 6, 6, 7, 8, 10, 12, 14
(7+8)/2 = 2
Mean = the sum of the numbers divided by the number of values
6 + 6+ 6+ 7 +8 +10 +12 +14/8
69/8
8.625
