Answer:
(250+250+130+130)*30=22,800
Explain what the vertical line test is and how it is used.
What is the range of the given function?
{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}
{x | x = –5, –4, –2, 0, 2}
{y | y = –9, –3, 0, 5, 7}
{x | x = –9, –5, –4, –3, –2, 0, 2, 5, 7}
{y | y = –9, –5, –4, –3, –2, 0, 2, 5, 7}
✧ [tex] \underline{ \underline{ \pink{\large{ \tt{E \: X \: P \: L\: A \: N \: A \: T \: I \: O \: N}}}}}: [/tex]
Part 1 :
☃ [tex] \underline{ \large{ \sf{Vertical \: Line \: Test}}} : [/tex] ⇾ All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called the vertical line test.
If the vertical line intersects the graph of a relation at one point , the relation is a function.If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.( See the attached picture )
In the picture ' 1 ' , The vertical line ( dotted line ) cuts the graph at one point ( P ). Thus the graph represents a function.In the picture ' 2 ' , The vertical line ( dotted line ) cuts the graph at two points P & Q. So, the graph does not represent a function.Part 2 :
☂ The set of all the images of the elements of domain under the function ' f ' is called the range of a function. In other words , the set of second components of a function is called range. We are given the function :
{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}The above numbers [ in bold ] are the range of given function. Now, If we arrange these numbers in ascending order, we get ( -9 , -3 , 0 , 5 , 7 ).
Hence , Choice B [ {y | y = –9, –3, 0, 5, 7} ] is correct.
♕ Hope I helped! ♡
☄ Have a wonderful day / night ! ☼
✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ☥
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Sample Response:
The vertical line test is a way to determine if a relation is a function. This test determines if one input has exactly one output on the graph. If any vertical line passes through more than one point on the graph, then the relation is not a function because two different outputs have the same input.
PLEASE HELP ME!!!!!!!!!ASAP!!!!!
Write down three integers, all less than 25, whose range is 8 and mean is 11.
Answer:
11,15,7
Step-by-step explanation:
11+15+7=33 33/3=11 the mean
then 15-7=8 the range
What is the area of this polygon? Im really bad a geometry so can I have help please.
add 2 please add
[tex]2 \frac{3}{4} + 5 \frac{4}{5} = [/tex]
Answer:
Step-by-step explanation:
19/4 + 29/5
2.75 + 5.8
= 8.55
write an expression that represents the quotient of a number and 3 multiplied by 4
Answer:
N (3×4) or (N×3) 4
Step-by-step explanation:
5(2 + 2m). Simplify the expression
Answer:
10m+10
Step-by-step explanation:
5x2=10
5x2m=10m
10m+10
Ann races her bicycle for 58m. A wheel of her bicycle turns 29 times as the bicycle travels the distance. What is the diameter of the wheel
Answer:
0.637 m or 63.7 cm
Step-by-step explanation:
Formula
d = n * pi di
Givens
di = diameter and is unknown
n = 29 times
d = 58 meters
Solution
58 = 29 * 3.14 * di
2 = 3.14 * di
2/3.14 = di
d = 0.637 meters
or
d = 63.7 cm
please help me I've been asking for this question for a while and I keep getting those spam messages please help me 15pts
How would you go about finding the confidence interval of say 90% or 95% for any given distribution scenario?
Answer:
You'd want to divide.
Step-by-step explanation:
Let's say you got a 9/10 on a test.
You'd do 9 divided by 100 and multiply it by 10 to get 90%
That is how you solve a percentage problem
FORMAT IN LESS DETAILED EXPLANATION:
9/100x10=90%
Nine divided by one-hundred times ten equals ninety percent
An investor wants to invest up to $100,000 as follows:
X amount into a Certificate of Deposit (CD) that yields an expected annual return of 1% with a risk index of 1,
Y amount into a Bond with an expected annual return of 3% and a risk index of 4,
Z amount into a Stock with an expected annual return of 7% and a risk index of 8.
The investor’s objective is to maximize the total expected annual return of the investment.
However, to be prudent, the investor requires that:
The fraction of the total investment in X must be at least 20%.
The fraction of the total investment in Z must not exceed 50%.
The combined portfolio risk index must not exceed 5.
Required:
a. Set up this investment problem as a linear program, which has 3 variables, 3 basic constraints, and 4 special constraints.
b. Use an LP software to find the maximum expected annual return in dollars and the dollar values of X, Y, and Z for this best investment.
c. From the software solution, show the values of the dual variables for the four special constraints.
Answer:
a-The Linear Model is as follows:
[tex]X+Y+Z\leq 100,000\\{0.001X}\geq 20\\{0.001Z}\leq 50\\0.00001X+0.00004Y+0.00008Z\leq5\\X\geq0\\Y\geq0\\Z\geq0[/tex]
b-The values are
X=$33,333.33
Y=$16,666.67
Z=$50,000.00
Leading to a total expected return of $4333.33.
c-The values of constraints are as follows
X+Y+Z=33333.33+16666.67+50000=100,000
X=33%, Y is 16.67% and Z is 50%
Risk component of X is 0.33
Risk component of Y is 0.66
Risk component of Z is 4.00
Step-by-step explanation:
a
From the conditions, the first special constraint is the total amount which is that the sum of investments must not be more than the total available amount of $100,000 so
[tex]X+Y+Z\leq 100,000[/tex]
The second special constraint is that the percentage of X must be at least 20% So
[tex]\dfrac{X}{100,000}\times100 \geq20\\\dfrac{X}{1000} \geq20\\{0.001X}\geq 20[/tex]
The third special constraint is that the fraction of total investment of Z must not exceed 50% So
[tex]\dfrac{Z}{100,000}\times100 \leq50\\\dfrac{Z}{1000}\leq 50\\0.001Z\leq50[/tex]
The fourth special constraint is that the combined portfolio risk index must not exceed 5 so
[tex]\dfrac{X}{100,000}\times1+\dfrac{Y}{100,000}\times4+\dfrac{Z}{100,000}\times8\leq5\\0.00001X+0.00004X+0.00008Z\leq5[/tex]
As the investments cannot be negative so three basic constraints are
[tex]X\geq0\\Y\geq0\\Z\geq0[/tex]
The maximization function is given as
[tex]f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times1\%+\dfrac{Y}{X+Y+Z}\times3\%+\dfrac{Z}{X+Y+Z}\times7\%\\f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times0.01+\dfrac{Y}{X+Y+Z}\times0.03+\dfrac{Z}{X+Y+Z}\times0.07[/tex]
b
By using an LP solver with BigM method the solution is as follows:
X=$33,333.33
Y=$16,666.67
Z=$50,000.00
Leading to a total expected return of $4333.33.
c
The values of constraints are as follows
X+Y+Z=33333.33+16666.67+50000=100,000
X=33%, Y is 16.67% and Z is 50%
Risk component of X is 0.33
Risk component of Y is 0.66
Risk component of Z is 4.00
What is the mode of this
data?
5, 3, 3, 6, 7, 9, 10
uh help
Answer:
3
Step-by-step explanation:
3 appears the most (twice)
The rest of the numbers only appear once
If l || m, determine what type of angles they are and find the value of x.
Please help I’m stuck
Answer:
96
Step-by-step explanation:
Its a pattern :) BTW can you help with mine please
brainiest exchange give me and I will give you 2+2
Answer:
4
Step-by-step explanation:
and sure
Answer:
4
Step-by-step explanation:
y = x2 – 3x + 2
use the discriminant to determine the number of solutions
Answer:
2 real solutions
Step-by-step explanation:
The formula for determining the discriminant is b² - 4ac.
So, let's identify our variables.
a = 1
b = 3
c = 2
Now, we can plug in our values.
3² - 4(1)(2)
9 - 8
1
1 is the discriminant of this function, and since 1 is positive, this indicates that there are two distinct real number solutions.
Historically, about 53% of the population of a certain country believed that the planet's temperature was rising ("global warming"). A March 2010 poll wanted to determine whether this proportion had changed. The poll interviewed adults in the population, and said they believed that global warming was real. (Assume these adults represented a simple random sample.)
Required:
a. What percentage in the sample believed global warming was real in 2010?
b. Is this more or less than the historical 57%?
Answer:
(a) The proportion is 61.23%
(b) It is more than the historical 57%
Step-by-step explanation:
This question has missing details, and they are:
[tex]n = 926[/tex] ---- The Sample Adults
[tex]x = 567[/tex] -- Those that believe global warming was real
Solving (a): The proportion of those that believe.
This is calculated as:
[tex]p = \frac{x}{n}[/tex]
Substitute values for x and n
[tex]p = \frac{567}{926}[/tex]
[tex]p = 0.6123[/tex]
Express as percentage
[tex]p = 0.6123 * 100\%[/tex]
[tex]p = 61.23\%[/tex]
Solving (b) More or less than 57%
By comparison:
[tex]61.2\% > 57\%[/tex]
Hence, it is more than the historical 57%
Find the area of this trapezoid:
Answer:
Pls add the image
Step-by-step explanation:
Find the point on a circle that has a radius of 8 with an angle of rotation of 130 degrees centered at (-3,5)?
Access the hourly wage data on the below Excel Data File (Hourly Wage). An economist wants to test if the average hourly wage is less than $29.
Hourly EDUC EXPER AGE Gender
Wage
37.85 11 2 40 1
21.72 4 1 39 0
34.34 4 2 38 0
21.26 5 9 53 1
24.65 6 15 59 1
25.65 6 12 36 1
25.45 9 5 45 0
20.39 4 12 37 0
29.13 5 14 37 1
27.33 11 3 43 1
28.02 8 5 32 0
20.39 9 18 40 1
24.18 7 1 49 1
17.29 4 10 43 0
15.61 1 9 31 0
35.07 9 22 45 0
40.33 11 3 31 1
20.39 4 14 55 0
16.61 6 5 30 1
16.33 9 3 28 0
23.15 6 15 60 1
20.39 4 13 32 0
24.88 4 9 58 1
23.88 5 4 28 0
37.65 6 5 40 1
15.45 6 2 37 0
26.35 4 18 52 1
19.15 6 4 44 0
16.61 6 4 57 0
18.39 9 3 30 1
25.45 5 8 43 0
28.02 7 6 31 1
23.44 4 3 33 0
17.66 6 23 51 1
26.33 4 15 37 0
34.34 4 9 45 0
35.45 6 3 55 0
37.43 5 14 57 0
35.89 9 16 36 1
20.39 4 20 60 1
31.81 4 5 35 0
35.45 9 10 34 0
37.66 5 4 28 1
23.87 6 1 25 0
36.35 7 10 43 1
25.45 9 2 42 1
23.67 4 17 47 0
26.02 11 2 46 1
23.15 4 15 52 0
24.18 8 11 64 0
a) Choose the null and the alternative hypotheses for the test.
A. H0:μ≥29;HA:μ<29
B. H0:μ=29;HA:μ≠29
C. H0:μ≤29;HA:μ>29
b) Use the Excel function Z. TEST to calculate the p-value. Assume that the population standard deviation is $6.
c) At α = 0.01 what is the conclusion?
A. Do not reject H0; the hourly wage is not less than $29.
B. Do not reject H0; the hourly wage is less than $29.
C. Reject H0; the hourly wage is not less than $29.
D. Reject H0; the hourly wage is less than $29.
Answer:
A. H0:μ≥29;HA:μ<29
Pvalue < 0.01
D. Reject H0; the hourly wage is less than $29
Step-by-step explanation:
The null hypothesis will negate the claim which will be the hypothesis to be tested. Therefore, since the claim is to test if hourly wage is less Than 29 ; then the null will be that hourly wage is equal to or greater than 29
H0:μ≥29;HA:μ<29
The Pvalue measure the probability that the extremity of our finding against a certain α level. The Pvalue obtained using the Excel function should be 0.00058
When Pvalue is < α ; We reject the null hypothesis
Hence, Reject H0; the hourly wage is less than $29 and conclude that hourly wage is less Than $29
work out the value of (6-2.5)( 8+4)
Answer:
42
Step-by-step explanation:
Uh, I'm guessing what is being asked here is to solve, so, time to distribute.
(6 - 2.5)(8 + 4)
48 + 24 - 20 - 10
42
the ratio of the corresponding sides of two similar triangles is 2:5 the sides of the smaller triangle is 6mm 8mm and 12mm what is the perimeter of the larger triangle?
Answer:
65
Step-by-step explanation:
using the ratio we can find the side lengths of the other triangle.
since it is 2:5
6:x=2:5
so x = 15(first side)
8:x=2:5
so x = 20(second side)
12:x=2:5
x=30(third side)
so then we add them up
15+20+30
65
hope this was helpful
A quarter has a diameter of 24 mm.
Which measurement is closest to the
circumference of the quarter in
millimeters?
A. 452.39 mm
B. 37.7 mm
C. 75.4 mm
D. 150.8 mm
Answer:
C or D
Step-by-step explanation:
Which one is correct?
At 3:30 p.m., you have 15 megabytes of a movie. At 3:45 p.m., you have 75 megabytes. What is the download rate in megabytes per minute?
A and B are similar solid cylinders base area of A : base area of B = 9 : 25
complete these ratios
curved surface area of A : curved surface area of B : = ? : ?
height of A : height of B = ? : ?
Answer:
Two figures are similar if the figures have the same shape but different sizes.
Then if we have two figures X and X'
Such that one dimension of X is D, the correspondent dimension on X' will be:
D' = k*D
Such that k is the scale factor that relates the figures.
1:k
Because all the dimensions will be rescaled by the same scale factor k, we can conclude that any surface on X will be related to the same surface in X' by:
S' = k^2*S
then the ratio of the surfaces is:
1:k^2
While the relation between the volumes will be:
V' = k^3*V
Here the ratio is:
1:k^3
Ok, in this case we have two cylinders
We know that the ratio between the base area ( a surface) is:
9:25
a) We want to find the ratio: curved surface area of A : curved surface area of B
Because again we have a surface area, the ratio should be exactly the same as before, 9:25
b) height of A : height of B
In this case, we have a single dimension.
Because in the rescaling of a surface we need to use k^2, then we can conclude that the ratios:
9:25
is related to k^2
Then the ratio, in this case, is given by applying the square root to both sides of the previous ratio, so we get:
√9:√25
3:5
This is the ratio of the heights.
Also from this we could get the value of k, that is the right value when we leave the left value equal to 1, we can get that if we divide both sides by 3.
(3/3):(5/3)
1:(5/3)
Then:
k = 5/3
Pls help
If a varies jointly as b and c, find a when b = 4 and c = -3.
a = -96 when b = 3 and c = -8
a=
Answer:
a=4bc
a=4(4)(-3)=-48
a= - 48 when b equals to 3 is equals to - 8
The required answer by direct variation a is equal to 96. In other words, when b = 4 and c = -3, the value of a is 96.
When a variable varies jointly as two other variables, it means that the relationship between the variables can be expressed using direct variation. In this case, we have that "a varies jointly as b and c."
To find the value of a when b = 4 and c = -3, we can set up the proportion based on the direct variation relationship:
a/bc = k
where k is the constant of variation.
Substituting the given values:
a/(4)(-3) = k
Simplifying, we have:
a/-12 = k
Now, we can find the value of a when b = 4 and c = -3 by substituting these values into the equation and solving for a:
a/(-12) = k
a/(-12) = -96/-12 (since k = -96 when b = 3 and c = -8)
a = 96
Therefore, the required answer by direct variation a is equal to 96. In other words, when b = 4 and c = -3, the value of a is 96.
Learn more about direct variation here:
https://brainly.com/question/29150507
#SPJ2
plssssss helppp last diagnostic
Answer:
9/20 square miles
Step-by-step explanation:
9/10× 1/2= 9/20 square miles
please help (no links) or i will report you i just need answers
Answer:
15.) 104 ... I hope angles are not drawn to scale
16.) 144
17.) 37
Step-by-step explanation:
15.)
3x + 10 = 4x -12
22 = x
so 3x +10 = 76
180 - 76 = t = 104
16.)
2(21) + 36 + 90 + bcd + a = 360
a = 90 - 21 = 69
360 - (2(21) + 36 + 90 + 69) = bcd
bcd = 360 - 237 = 123
angle acd = 21 + bcd = 21 + 123 = 144
17.)
(5x - 7) + 90 + (3x + 1) = 180
8x -6 = 90
8x = 96
x = 12
so 5x - 7 = 53
90 - 53 = angle lmn = 37
what is:
k/3 + 17 = 12?
Answer:
-15
Step-by-step explanation:
yan po ang answer thank you na lang po
Find the coefficient of the x^3 in the expansion of (2x-9)^5
Use the binomial theorem:
[tex]\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}[/tex]
The x ³ terms occurs for 5 - k = 3, or k = 2, and its coefficient would be
[tex]\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}[/tex]
A pair of weak earthquakes is modeled by a system of inequalities. One earthquake occurred roughly 20 km east and 14 km north of the center of Columbia, NC. The quake could be felt from 25 km away. A couple days later, another earthquake occurred 8 km west and 3 km north of the center of Columbia and could be felt from 14 km away. If Columbia is located at (0, 0) on a coordinate grid, the system of inequalities represents this scenario.
StartLayout Enlarged left-brace first row (x minus 20) squared + (y minus 14) squared less-than-or-equal-to 625 second row (x + 8) squared + (y minus 3) squared less-than-or-equal-to 196 EndLayout
Which location relative to Columbia felt both earthquakes?
4 km west and 12 km south
6 km west and 4 km north
2 km east and 10 km north
6 km east and 8 km north
Answer:
2 km east and 10 km north
Step-by-step explanation:
I did the activity and got the right answer.
By evaluating the inequalities, we will see that the correct option is: 2 km east and 10 km north
Which location will feel both earthquakes?
Here we have the inequalities:
(x - 20)^2 + (y - 14)^2 ≤ 625
(x + 8)^2 + (y - 3)^2 ≤ 196
Where, x is the distance due east, and y is the distance due north.
So we just need to find which of the given options makes both inequalities true, for example, for the first one we have:
x = -4
y = -12
Replacing that on the first inequality we get:
(-4 - 20)^2 + (-12 - 14)^2 ≤ 625
1,252 ≤ 625
This is false, so this option is not correct.
Now we just need to check the other options. Particularly for the third we have:
x = 2
y = 10
Replacing that in both inequalities we get:
(2 - 20)^2 + (10 - 14)^2 ≤ 625
340 ≤ 625 (true).
(2 + 8)^2 + (10 - 3)^2 ≤ 196
149 ≤ 196 (true)
So at 2km east and 10km north of Columbia, the two earthquakes can be felt.
If you want to learn more about inequalities, you can read:
https://brainly.com/question/18881247
