Find the equation of the line perpendicular to y = 3x - 6 that runs through the point (-1, -3).


y
=
1
3
x
+
8
3
y=
3
1
​
x+
3
8
​


y
=
−
1
3
x
−
10
3
y=
3
−1
​
x−
3
10
​


y = -3x + 8

y
=
3
x
+
10
y=3x+10

Answer:

The area is 8

Step-by-step explanation:

If the perimeter is 12, we can just start guessing and checking. in this case, if 4 is the length, that means 2 is its width, since 4-2=2. then you find the area(basexhight) 4x2=8!

Answer:

-2x-10=-2(x+5)

Step-by-step explanation:

Just multiply and find the pair that matches which happens to be the 3rd pair. you're welcome

Answer:

C is the answer 3rd one...

Answer:

C

Step-by-step explanation:

y=-x^2+1. y is a decreasing function as x^2 is an increasing function

Answer:

---------------------------

Hope it helps...

Have a great day!!

Answer:

B

Step-by-step explanation:

From -1 to 1 on the x-axis, the graph has to be below the x-axis because then the y-values will be negative.

Answer choice C & D have the graph above the x-axis in that interval, so it's positive instead of being negative. We can cross out those two answer choices.

The reason why answer choice A isn't correct is because at 1, the graph line is above the x-axis, since the brackets [-1, 1] means it includes -1 and 1.

So the only answer left is B.

Hope that helps (●'◡'●)

Answer:

Step-by-step explanation:

Answer,

C

Step-by-step explanation:

I had the same question 2 days ago

Answer:

462 is the exact answer

Step-by-step explanation:

Answer:

Even Numbers from 2 to 48:

2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48.

Add

2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+

46+48= 600

OAmalOHopeO

[tex]\sf \: {x}^{2} - 5[/tex]

[tex]\sf \: Use \: the \: algebraic \: identity \\ \sf \: a {}^{2} - {b}^{2} = (a - b)(a + b)[/tex]

[tex]\sf \: Substitute \: the \: value \: of \: a \: and \: b \: in \: the \: identity.[/tex]

[tex]\sf \: a = \sqrt{x ^{2} } = x \\ \sf \: b = \sqrt{5} [/tex]

[tex]\sf \: the \: identity \: becomes \: [/tex]

[tex]\sf {x}^{2} - 5 \\ \sf = (x - \sqrt{5} )(x + \sqrt{5} ) \\ [/tex]

Answer ⟶ [tex]\boxed{\bf{(x - \sqrt{5} )(x + \sqrt{5} )}}[/tex]

Answer:

B

Step-by-step explanation:

[tex]d \: = \frac{h}{24} [/tex]

make h the subject of the formula

h = 24 d

Answer:

\left(-32ux+19u^2x^3-12u^6x^7\right)\:divided\:by\:\left(-4u^2x^3\right)

Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

\frac{8}{ux^2}\:-\frac{19}{4}+3u^4x^4

Answer:

BE.

Step-by-step explanation:

If AD is to DG, then BE must be to EH, and CF must be to FI.

3x ² - 2x + 1 = 2x ² - 3x + 7

x ² + x - 6 = 0

(x + 3) (x - 2) = 0

x + 3 = 0   or   x - 2 = 0

x = -3   or   x = 2

Step-by-step explanation:

Given that,

The area of a rectangle, A = 35 cm²

Let x is the length.

Width, Y = 12-x

We know that,

The area of a rectangle is given by :

[tex]A=lb[/tex]

[tex]x(12-x)=35\\\\12x-x^2=35\\\\-x^2+12x-35=0\\\\or\\\\x^2-12x+35=0[/tex]

Hence, [tex]x^2-12x+35=0[/tex].

Answer:

Step-by-step explanation:

Answer:

-10/3 < x < 2

so the answer is  x<-10/3 or x>2

Step-by-step explanation:

:)

[tex] \huge \mathtt \blue{answer}[/tex]

Here, “p” is a numerator and “q” is a denominator. The examples of rational numbers are 6/5, 10/7, and so on. The rational number is represented using the letter “Q”. Like real numbers, the arithmetic operations, such as addition, subtraction, multiplication, and division are applicable to the rational numbers.

Answer:

Step-by-step explanation:

That was some horse.

20*t + 30*t = 800           Each day he rode the same amount of time (t). On the first day, he rode a distance of 20*t. On the second day, he rode a distance of 30*t

50t = 800

t = 800/50

t = 16

Each day he rode 16 hours

Total time = 32 hours.

Answer:

32 hours

Step-by-step explanation:

Answer:

£ 157.5

Step-by-step explanation:

12.5  × 180 = 22.5

100

180 - 22.5 = 157.5

I hope this helps.

Answer:

Kristi will pay $22.77 for the shirt.

Step-by-step explanation:

First, determine the sales price of the shirt. If the full price is $27.99, a 25% reduction is $7. Subtract the discount from the full price to get a sales price of $20.99 for the shirt.

Next, determine the amount of tax Kristi will pay for the shirt. In her state, the sales tax is 8.5% (0.085). Multiply $20.99 by 0.085 and you will see that the sales tax is $1.78. Add the amount of the tax, $1.78, to the sales price of the shirt, $20.99, and you will get $22.77 as the cost of the shirt after the sales tax is added.

Answer:

learn what is binary system

add one by changing the last 0 into 1

Write another digit if all the numbers are one.

Use these rules to count to five.

Count to six.

Count to ten

Notice when new digits get added.

Practice with higher numbers.

hope this will help you and pls answer my questions also

Answer:

[tex]32\:\mathrm{m^2}[/tex]

Step-by-step explanation:

When cut by a diagonal, the parallelogram will be divided into two congruent triangles. By definition, congruent polygons have equal areas. Therefore, let the area of each of the triangle be [tex]x[/tex]:

[tex]x+x=64,\\2x=64,\\x=\frac{64}{2}=\boxed{32\:\mathrm{m^2}}[/tex]

Answer:

next 3 terms are -15, -28, -41. The formula would be n= (n-1)-13 to get the nth term

Step-by-step explanation:

Answer:

point 1 = (3, 6)

point 2 = (24, -15)

Step-by-step explanation:

8/x - 10/y = 1

x + y = 9

x = 9 - y

=>

8/(9-y) - 10/y = 1

8 - 10×(9-y)/y = 9 - y

-90/y + 10y/y = 1 - y

-90/y + 10 = 1 - y

-90 + 10y = y - y²

y² + 9y -90 = 0

the solution to a squared equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case we use y instead of x.

a = 1

b = 9

c = -90

y = (-9 ± sqrt(81 - -360))/2 = (-9 ± sqrt(441))/2 =

= (-9 ± 21)/2

y1 = 12/2 = 6

y2 = -30/2 = -15

8/x - 10/6 = 1

8 - 10x/6 = x

8 - 5x/3 = x

24 - 5x = 3x

24 = 8x

x = 3

8/x - 10/-15 = 1

8/x + 2/3 = 1

8 + 2x/3 = x

24 +2x = 3x

24 = x

Answer:

y = (x-15)/-8

Step-by-step explanation:

When solving for an inverse function, swap x and y without bringing the x coefficient with it, just simply swap the variables. Then, solve for y, and that's it.

y = -8x + 15

x = -8y + 15

x-15 = -8y

(x-15)/-8 = y

Step-by-step explanation:

Hey there!

Given function is: y = -8x + 15

~ Interchange"X" and "y".

x = -8y + 15

~ Solve it

8y = 15-x

y = (15-x)/8

Therefore, the inverse of function is y = (15-x)/8.

Hope it helps!

Answer:

Yes

Step-by-step explanation:

From the origin means from the centre or middle but about a vertex is from a named point.

======================================================

Explanation:

The rule we use is

a^b * a^c = a^(b + c)

This says that if we multiply exponential expressions with the same base, then we add the exponents. We keep the base the same the entire time.

For example, 2^3*2^4 = 2^(3+4) = 2^7

--------------

For this problem, we'll say,

5^(56)*5^(22)*5^(-96)

5^( 56+22+(-96) )

5^(-18)

Be sure that you use parenthesis so that you tell your teacher that all of the -18 is in the exponent. Saying 5^-18 could lead to ambiguity.

Answer:

sorry it he question isn't clear

Answer:

x > 7

Step-by-step explanation:

Let x be the unknown number

x+3 > 10

Subtract 3 from each side

x+3-3 > 10-3

x > 7

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{\underline{The sum of a number and 3 is greater than 10.}}[/tex]

[tex]\large\textsf{Well, the word sum simply means add. The word number}\\\large\textsf{ is unknown so we will label it as x.}[/tex]

[tex]\large\textsf{We will make this your equation: x + 3 } \mathsf{ > } \large\textsf{ 10}[/tex]

[tex]\large\textsf{Now lets solve for your answer.}\downarrow[/tex]

[tex]\large\textsf{x + 3 }\mathsf{>}\large\textsf{ 10}[/tex]

[tex]\large\textsf{SUBTRACT 3 to BOTH SIDES}[/tex]

[tex]\large\textsf{x + 3 - 3 } \mathsf{>} \large\textsf{ 10 - 3}[/tex]

[tex]\large\textsf{CANCEL out: 3 - 3 because that gives you 0}[/tex]

[tex]\large\textsf{KEEP: 10 - 3 because that helps what is being compared to the x-value}[/tex]

[tex]\large\textsf{x } \mathsf{>} \large\textsf{ 10 - 3}[/tex]

[tex]\large\textsf{10 - 3 = \bf 7}[/tex]

[tex]\large\textsf{\bf x } \mathsf{\bf >\ } \large\textsf{ \bf 7}[/tex]

[tex]\boxed{\boxed{\large\textsf{Therefore, your answer is: \bf x}>\textsf{\bf 7}\huge\textsf{ (Option B.)}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]