Find the first four terms in the sequence
an 15 + 6n

A. 21, 27, 33, 39
B. 18, 12, 6,0
C. 20, 26, 32, 38
D. 20, 14, 8, 2

Answer:

See graph

[tex](x +3)^{2}[/tex] + [tex](y + 1)^{2}[/tex] = 9

(-3 , -1) is the center.

[tex]\sqrt{9}[/tex] = 3 = radius

Step-by-step explanation:

[tex](x - h)^{2} + (y - k)^{2} = r^{2}[/tex]

center (h,k)

radius = r

Answer:

The events are independent and are not mutually exclusive.

Step-by-step explanation:

Two events A and B are independent if the outcome of each of them does not affect the outcome of the other.

And two events are mutually exclusive if these can't occur at the same time.

Here the events are:

a = rolling a 4 on the first die

b = rolling a 3 on the second die.

Becuase, these are number cubes, we know that the outcome of one die has no impact in the outcome of the other die.

And because each outcome is on a different die, we can conclude that these events are independent.

(rolling a 4 in the first die does not change the probability of getting a 3 when we roll the second die).

Now, the events are mutually exclusive?

No, we can roll both dices and get a 3 in the first one and a 4 in the second one, so these events can happen in the same time.

Answer:

YES.

Step-by-step explanation:

The event rolling a number '4' and the event rolling a number '3' are mutually exclusive events because both of them cannot occur at the same time.

Just took quick check

Answer:

next 3 terms are -15, -28, -41. The formula would be n= (n-1)-13 to get the nth term

Step-by-step explanation:

Answer:

1) The length of [tex]DC[/tex] is 20.

2) The length of [tex]PS[/tex] is 17.

Step-by-step explanation:

1) If [tex]DR = RE[/tex] and [tex]CS = SB[/tex], then we can use the following proportionality ratio:

[tex]\frac{DE}{DR} = \frac{32 - x}{26 - x}[/tex] (1)

Where [tex]x[/tex] is the length of segment [tex]\overline{CD}[/tex].

If [tex]DE = 2\cdot DR[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{32-x}{26-x}[/tex]

[tex]52 - 2\cdot x = 32 - x[/tex]

[tex]20 = x[/tex]

The length of [tex]DC[/tex] is 20.

2) If [tex]QV = VP[/tex] and [tex]RW = WS[/tex], then we can use the following proportionality ratio:

[tex]\frac{QP}{QV} = \frac{x-7}{12-7}[/tex] (2)

Where [tex]x[/tex] is the length of segment [tex]\overline{PS}[/tex].

If [tex]QP = 2\cdot QV[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{x-7}{5}[/tex]

[tex]10 = x-7[/tex]

[tex]x = 17[/tex]

The length of [tex]PS[/tex] is 17.

Answer:

The length of the segment is 10.

Step-by-step explanation:

Think of the segment as the hypotenuse of a right triangle.

Draw the legs and label the lengths.

See the picture below.

The length of the hypotenuse is c.

c^2 = a^2 + b^2

c^2 = 6^2 + 8^2

c^2 = 36 + 64

c^2 = 100

c = 10

Answer: 10

Answer:

67.3

Step-by-step explanation:

Let x = unknown angle

Supplementary angles add up to equal 180

Hence 112.7 + x = 180

Solve for x

112.7 + x = 180

Subtract 112.7 from both sides

x = 67.3

An angle supplementary to an angle with a measure of 112.7 degrees has a measure of 67.3

Step-by-step explanation:

First sentence

Let the number be X

second sentence

X-5

Third sentence

X-5=14

X=19

The number is 19

Hi there!  

»»————-　★　————-««

I believe your answer is:

19

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\text{"I am thinking of a number. l take away 5. The result is 14."}\\\\\text{5 taken away from 'said number' would be 14.}\\\\\boxed{n-5=14}\\\\\\\boxed{\text{Solving for 'n'...}} \\\\\rightarrow n - 5 + 5 = 14 + 5\\\\\rightarrow \boxed{n = 19}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

hope this helps! feel free to clarify if unsure

Answer:

Kristi will pay $22.77 for the shirt.

Step-by-step explanation:

First, determine the sales price of the shirt. If the full price is $27.99, a 25% reduction is $7. Subtract the discount from the full price to get a sales price of $20.99 for the shirt.

Next, determine the amount of tax Kristi will pay for the shirt. In her state, the sales tax is 8.5% (0.085). Multiply $20.99 by 0.085 and you will see that the sales tax is $1.78. Add the amount of the tax, $1.78, to the sales price of the shirt, $20.99, and you will get $22.77 as the cost of the shirt after the sales tax is added.

Answer:

[tex]\boxed {\boxed {\sf y= 6x+5}}[/tex]

Step-by-step explanation:

We are asked to find the slope-intercept equation of a line. Slope-intercept form is one way to write the equation of a line. It is:

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

We are given a point (-1, -1) and the line is parallel to the line y= 6x-2. Since the line is parallel to the other line, they have the same slope, which is 6. We have a point and a slope, so we should use the point-slope formula to find the equation of the line.

[tex]y-y_1= m (x-x_1)[/tex]

Here, m is the slope and (x₁, y₁) is the point. We know the slope is 6 and the point is (-1, -1). Therefore:

Substitute the values into the formula.

[tex]y- -1 = 6(x- -1) \\y+1= 6(x+1)[/tex]

Distribute the 6. Multiply each value inside the parentheses by 6.

[tex]y+1 = (6*x)+ (6*1) \\y+1= 6x+6[/tex]

Slope-intercept form requires y to be isolated. 1 is being added to y. The inverse of addition is subtraction. Subtract 1 from both sides.

[tex]y+1-1=6x+6-1 \\y= 6x+5[/tex]

The equation of the line in slope-intercept form is y=6x+5

Answer:

(x-12)^2+(y-2)^2=4

Step-by-step explanation:

Answer:

Step-by-step explanation:

The answer is 4.

Once you add 4, you get:

x^2 -2x + 4 = 7.

The left side is factorable:

(x-2)^2 = 7.

There is your perfect square.

Answer:

720

Step-by-step explanation:

Using the equation given

[tex]\frac{6!}{(6-6)!}=\frac{6!}{0!}=\frac{6!}{1}=720[/tex]

Answer:

-0.301

Step-by-step explanation:

Correct Question :-

If log 2 = 0.301 , find log 0.5

Solution :-

We are here given that the value of log 5 is 0.699 . Here the base of log is 10 .

[tex]\rm\implies log_{10}2= 0.301 [/tex]

And we are supposed to find out the value of log 0.5 . We can write it as ,

[tex]\rm\implies log_{10}(0.5) = log _{10}\bigg( \dfrac{5}{10}\bigg)[/tex]

Simplify ,

[tex]\rm\implies log _{10}\bigg( \dfrac{1}{2}\bigg)[/tex]

This can be written as ,

[tex]\rm\implies log_{10} ( 2^{-1})[/tex]

Use property of log ,

[tex]\rm\implies -1 \times log_{10}2 [/tex]

Put the value of log 2 ,

[tex]\rm\implies -1 \times 0.301 =\boxed{\blue{-0.301}} [/tex]

Hence the value of log (0.5) is -0.301 .

*Note -

Here here there was no use of log 5 in the calculation .

Answer:

Step-by-step explanation:

Answer:

C is the answer 3rd one...

Answer:

QXV=WXV

Step-by-step explanation:

Answer:

£ 157.5

Step-by-step explanation:

12.5  × 180 = 22.5

100

180 - 22.5 = 157.5

I hope this helps.

Answer: 29152332 ≡ 0 (mod 3)

Step-by-step explanation:

In modular arithmetic, there is the form a ≡ b (mod m) where b is the remainder.

To solve this problem, we want to divide 29152332 by 3 and find the remainder.

29152332 ÷ 3 = 9717444

Since we get an integer with no remainder, we know the answer is 29152332 ≡ 0 (mod 3).

Answer:

25.

Step-by-step explanation:

Let the number of pupils be x, then:

there are 0.6x girls and 0.4x boys.

From the given information:

0.6x - 0.4x = 5

0.2x = 5

x = 5/0.2

= 50/2

= 25.

Answer:

Triangle ISK

Step-by-step explanation:

Answer:

Triangle ISK

Step-by-step explanation:

if the angles and sides of one triangle are equal to the corresponding sides and angles of the other triangle, they are congruent.

∠Q = ∠I

∠R = ∠S

∠S = ∠K

Answer:

ii

Step-by-step explanation:

from what you've written in the comments I think this question requires you to find the equation that can be expressed in two variables,so the best way to do this is to solve the pairs as simultaneous equations and see the ones that will give you two answers x and y

if you solve the first pair you will have

x + y = 5

2x+2y=10

2(x + y =5)

1(2x+2y=10)

2x+2y=10

2x+2y=10--

now from this you will see that it cannot be expressed as two variables because the answer is just zero..

for the second equation it can be expressed as two variables

x - y = 8

3x-3y =16

3(x-y =8)

1(x-3y=16)

3x-3y=24

x - 3y=16

2x/2=8/2

x=4

x-y=8

4-y=8

-y=8-4

-y/-1=4/-1

y=-4...

so you see it can be expressed as two variables..

if you solve the third one it will also give you an answer which is zero so it can't be expressed as two variables.

and the fourth one also cannot.

I hope this helps and if you don't understand feel free to ask..and sorry if it's wrong

Answer:

16 × X + 3=

Step-by-step explanation:

u will get your answer

Answer:

- 3 + 2y

Step-by-step explanation:

[tex]\frac{-\frac{15}{2} +5y}{\frac{5}{2} }[/tex]

[tex]\frac{2}{5}( -\frac{15}{2} +5y} )[/tex]

[tex]-3+2y[/tex]

Step-by-step explanation:

Division by a fraction such as 5/2 is equivalent to multiplication by the reciprocal of the fraction (2/5).

Multiplying (-15/2 + 5y) by 2/5 yields:

-3 + 2y (answer)

Answer:

1) -7929

2) -2401

3)-5414

4) -7592

5) 12888

6)-237726

7) 7287

8)-4588

9)-394495

10) 891856

Answer:

126,000

Step-by-step explanation:

150,000 * .15 = 22,500

150,000 - 22,500= 127,000

127,000 - 1500 = 126,000

Answer:

a) 272 used at least one prescription​ medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription​ medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 3149, \pi = 0.866[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876[/tex]

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

The number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is:  [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%

Suppose that we have:

Then, we get:

[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

where [tex]Z_{\alpha/2}[/tex] is the critical value of Z at specified level of significance and is obtainable from its critical value table(available online or in some books)

For this case, we have:

Part (a):

The number of subjects used at least one prescription​ medication is:

[tex]\dfrac{3149}{100} \times 86.6 \approx 2727[/tex]

Thus, the sample proportion we get is:

[tex]\hat{p} = \dfrac{2727}{3149} \approx 0.8659[/tex]

For level of significance 0.10, we get: [tex]Z_{\alpha/2} = 1.645[/tex]

Thus, the confidence interval needed is:

[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\CI \approx 0.8659\pm 1.645 \times \sqrt{\dfrac{0.8659(1-0.8659)}{3149}}\\\\\\CI \approx 0.8659 \pm 0.0099[/tex]

Thus, CI is [0.8659 - 0.0099, 0.8659 + 0.0099] = [0.8560, 0.8758]

Thus, the number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is:  [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%

Learn more about population proportion here:

https://brainly.com/question/7204089

Answer:

D. [tex] \frac{15}{8} [/tex]

Step-by-step explanation:

Recall: SOH CAH TOA

Thus,

Tan A = Opposite/Adjacent

Reference angle (θ) = A

Length of side Opposite to <A = 15

Length of Adjacent side = 8

Plug in the known values

[tex] Tan(A) = \frac{15}{8} [/tex]