Find the height of the triangle by applying formulas for the area of a triangle and your knowledge about triangles.
A. 10.5 cm
B. 3.4 cm
C. 8.5 cm
D. 12 cm

Answer:

If there are 1500 students in your school then 960 students would enjoy watching TV

Step-by-step explanation:

Step 1: We know that 64% of kids aged from 11 to 15 enjoy watching TV and there is 1500 students in your school

Step 2: We now want to find 64% of 1500, we can rewrite 64% as 0.64. We multiple 1500 by 0.64 to find out how many students enjoy watching TV

0.64 x 1500 = # of students who like watching TV

960 = # of students who like watching TV

Therefore out of 1500 students, 960 would enjoy watching TV

Answer:

.75cm³

Step-by-step explanation:

To find the volume of a shape like this it is,

base×height×width.

In this case it is .5×.5×3=.75cm³

Answer:

3/4 or 0.75

Step-by-step explanation:

Length times width times height:

1/2 * 1/2 * 3

= 3/4

Answer:

Step-by-step explanation:

a:b = 2:3

a = 2x    - first number

b = 3x   - second number

a³ + b³  =  945

[tex](2x)^3 + (3x)^3=945\\\\8x^3 +27x^3=945\\\\35x^3 = 945\\\\x^3=945:35\\\\x^3=27\\\\ x^3=3^3\\\\x=3\\\\\\a=2\cdot3 = 6\\\\b=3\cdot3=9[/tex]

Answer:

a. 8.5 in.

b. 34 in

c. x = 1/39 x^2.

Step-by-step explanation:

Part a.

x = 1/34 y^2

y^2 = 34x

Comparing with y^2 = 4px where p is the focus:

4p = 34

p = 8.5 in.

Part b.

The diameter = 4p = 34 in.

Part c.

Diameter = 4p = 34 + 5 = 39 in

The new equation is x = 1/39 x^2.

Answer:  see proof below

Step-by-step explanation:

Use the following when solving the proof...

Double Angle Identity: cos2A = 1 - 2sin²B

Pythagorean Identity: cos²A + sin²A = 1

note that A can be replaced with B

Proof from LHS → RHS

Given:                            cos²A + sin²A · cos2B

Double Angle Identity: cos²A + sin²A(1 - 2sin²B)

Distribute:                      cos²A + sin²A - 2sin²A·sin²B

Pythagorean Identity:                        1 - 2sin²A·sin²B

Pythagorean Identity:   cos²B + sin²B - 2sin²A·sin²B

Factor:                           cos²A + sin²B(1 - 2sin²A)

Double Angle Identity: cos²B + sin²B · cos2A

cos²B + sin²B · cos2A = cos²B + sin²B · cos2A  [tex]\checkmark[/tex]

Answer:

D: {x∈R | -2 ≤ x ≤ 2 }

R: {y∈R | 0 ≤ y ≤ 4 }

Step-by-step explanation:

The domain ranges between -2 and 2

The range ranges between 0 and 4

Answer:

[tex] { x^2+3x-4} [/tex]

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

[tex] \frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} } [/tex]

= [tex]\frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}[/tex]

= [tex] \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)} [/tex]

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= [tex] { (x-1)(x+4)} [/tex]

= [tex] { x^2+3x-4} [/tex]

Answer:

The answer is

Step-by-step explanation:

[tex] \frac{9 {x}^{2} - ( { {x}^{2} - 4})^{2} }{4 + 3x - {x}^{2} } [/tex]

To solve the expression first factorize both the numerator and the denominator

For the numerator

9x² - ( x² - 4)²

Expand the terms in the bracket using the formula

( a - b)² = a² - 2ab + b²

(x² - 4) = x⁴ - 8x² + 16

So we have

9x² - (x⁴ - 8x² + 16)

9x² - x⁴ + 8x² - 16

- x⁴ + 17x² - 16

Factorize

that's

(x² - 16)(-x² + 1)

Using the formula

a² - b² = ( a + b)(a - b)

We have

(x² - 16)(-x² + 1) = (x + 4)(x - 4)( 1 - x)(1 + x)

For the denominator

- x² + 3x + 4

Write 3x as a difference

- x² + 4x - x + 4

Factorize

That's

- ( x - 4)(x + 1)

So we now have

[tex] \frac{(x + 4)(x - 4)( 1 - x)(1 + x)}{ - (x - 4)(x + 1)} [/tex]

Simplify

[tex] \frac{ - (x + 4)(1 - x)(1 + x)}{x + 1} [/tex]

Reduce the expression by x + 1

That's

-( x + 4)( 1 - x)

Multiply the terms

We have the final answer as

Hope this helps you

Answer:

Graphing Calculator

Step-by-step explanation:

Full question :

The Tasty Sub Shop Case:

A business entrepreneur uses simple linear regression analysis to predict the yearly revenue for a potential restaurant site on the basis of the number of residents living near the site. The entrepreneur then uses the prediction to assess the profitability of the potential restaurant site.

And

The QHIC Case:

The marketing department at Quality Home Improvement Center (QHIC) uses simple linear regression analysis to predict home upkeep expenditure on the basis of home value. Predictions of home upkeep expenditures are used to help determine which homes should be sent advertising brochures promoting QHIC’s products and services.

Discuss the difference in the type of prediction in both cases and provide rational of the reasons that these predictions were used.

Answer and explanation:

In the first case, The Tasty Sub Shop Case, the entrepreneur aims to utlilize the predicted values from his regression analysis in ascertaining profit of his potential business. He does this using the values from number of residents in the area(independent variables) to predict the revenue for his business(dependent variables). His predictions using the number of residents in the area are largely because the residents in the area are his target consumers and are the ones to buy food from his restaurant and increase his revenue.

In the other case, the marketing department in QHIC utilizes the predicted values in determining their customers who need to be aware of their products. They get the predicted values(home upkeep expenditure and dependent variable) by plotting their relationship with home value(independent variable) and then use predicted values of home upkeep expenditures in determining their customers who they will market their products to. They do this because predicting home upkeep expenditures will enable them determine what homes can afford or will need their products and services.

one utilizes his predictions at ascertaining profit while the other uses his predictions in determining potential customer base to market products to. The first case is making a revenue/ profitability prediction while the other is making a market prediction

Answer:

11.6%

I hope this helps!

Answer:

Step-by-step explanation:

Since the triangle is a right angled triangle we can use the Pythagoras theorem to find the missing side

Using the Pythagoras theorem

That's

[tex] {a}^{2} = {b}^{2} + {c}^{2} [/tex]

From the question

x is the hypotenuse or the longest side of the triangle

Substituting the values into the above formula we have

[tex] {x}^{2} = {9}^{2} + {7}^{2} [/tex]

[tex] {x}^{2} = 81 + 49[/tex]

[tex] {x}^{2} = 130[/tex]

Find the square root of both sides

We have the final answer as

Hope this helps you

Answer:

Step-by-step explanation:

[tex]6^2 =6\times 6\\\\= 36[/tex]

Answer:

313/7

Step-by-step explanation:

Here, we are interested in turning the wordings of the statement to numeric values.

We take it one at a time.

Sum of 35 and 1/5(35) = 35 + 7 = 42

This is added to 1/7(11 + 8)

= 1/7(19) = 19/7

So we have;

42 + 19/7 = (294 + 19)/7 = 313/7

Answer:

a-2b= -1.6x-2.0

Step-by-step explanation:

[tex]a=1.4-2x\\b=-0.2x+1.7\\a-2b= (1.4-2x)-2(-0.2x+1.7)\\a-2b= 1.4-2x+0.4x-3.4\\a-2b=-1.6x-2.0\\[/tex]

{By, substituting the values of a and b in a-2b , we can find the value of a-2b}

the answer for this is A

Answer:

Correct option is A

Step-by-step explanation:

3x - 7

Three times a number x minus 7

Or

The difference of there times a number and 7

If everybody on the team scores 6 points, and the team has a total of 42 points, the people that are on the team are 7 people.

The addition is one of the four basic mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

The addition is a method of merging items and counting them as a single, large group. In mathematics, addition is the process of joining two or more integers.

The process of adding two or more numbers together to get their sum is known as an addition. The addition is a fundamental arithmetic operation that is used to compute the sum of two or more numbers. For instance, 7

+ 7 = 14.

6p = 42

P = 42/6

P = 7

Therefore, the people that are on the team are 7 people.

To learn more about addition, refer to the link:

https://brainly.com/question/29560851

#SPJ2

Answer:

the answer that i find is 17-3x

Answer:

  f(x) = x +3

Step-by-step explanation:

The first differences for adjacent x-values are all 1, so this is a linear function. Because those differences are all 1, it is a linear function with a slope of 1. We observe that f(0) = 3, so that is the y-intercept.

__

The slope-intercept form of a linear function is ...

  y = mx + b . . . . . where m is the slope (1) and b is the y-intercept (3).

A suitable function rule is ...

  f(x) = x +3

Answer:

A) No because the theater did not survey everyone in the theater.

Answer:

Yes, because the theater surveyed a random sample.

Step-by-step explanation:

The survey is valid because there was a random sample. They surveyed every fifth person, so there was a variety of age groups, genders, and preferences included in the sample. Therefore, the correct answer is yes, because the theater surveyed a random sample.

Answer:

[tex]\frac{1}{9^4}[/tex].

Step-by-step explanation:

[tex]9^{-4}[/tex]

= [tex]\frac{1}{9^4}[/tex]

= [tex]\frac{1}{9 * 9 * 9 * 9}[/tex]

= [tex]\frac{1}{81 * 81}[/tex]

= [tex]\frac{1}{6561}[/tex]

= 0.0001524157903.

Hope this helps!

[tex] \LARGE{ \underline{ \boxed{ \orange{ \rm{Solution:)}}}}}[/tex]

☃️ Refer to the trigonometric table....

Then, proceeding

⇛ tan 60 ° = √3

⇛ tan 60° = tan (a + b)

⇛ 60° = a + b

Flipping it,

⇛ a + b = 60° --------(1)

And,

⇛ tan 30° = 1 / √3

⇛ tan 30° = tan (a - b)

⇛ 30° = a - b

Flipping it,

⇛ a - b = 30° ---------(2)

Now adding eq.(1) and eq.(2),

⇛ a + b + a - b = 60° + 30°

⇛ 2a = 90°

⇛ a = 90° / 2

⇛ a = 45°

Putting value of a in eq.(1),

⇛ 45° + b = 60°

⇛ b = 15°

☄ So, Our Required answers:

━━━━━━━━━━━━━━━━━━━━

Answer:

Step-by-step explanation:

c - 10  ≥  15 =

c  ≥ = 15 + 10

c  ≥ = 25

c  = 26 ( or numbers above 26)

Answer:

There is not sufficient evidence to support a claim of linear correlation between the two variables.

Step-by-step explanation:

The data provided is as follows:

X        Y

78       5.5

79       8.8

56.2      3.3

68.3       1.7

77.9      10.8

38.2       0.1

(a)

The scatter plot is attached below.

(b)

Use the Excel function: =CORREL(array1, array2) to compute the correlation coefficient, r.

The correlation coefficient between the number of internet users and the award winners is,

r = 0.797.

(c)

The test statistic value is:

[tex]t=r\sqrt{\frac{n-2}{1-r^{2}}}[/tex]

  [tex]=0.797\times\sqrt{\frac{6-2}{1-(0.797)^{2}}}\\\\=0.797\times 3.311372\\\\=2.639163484\\\\\approx 2.64[/tex]

The degrees of freedom is,

df = n - 2

   = 6 - 2

   = 4

Compute the p-value as follows:

[tex]p-value=P(t_{n-2}<2.64)=0.057[/tex]

*Use a t-table.

p-value = 0.057 > α = 0.05

The null hypothesis will not be rejected.

Thus, it can be concluded that there is not sufficient evidence to support a claim of linear correlation between the two variables.

Answer:

see explanation

Step-by-step explanation:

Since (k, 3) lies on each of the lines, the point satisfies the equations.

Substitute x = k, y = 3 into each and solve for k

y = 3x + 1

3 = 3k + 1 ( subtract 1 from both sides )

2 = 3k ( divide both sides by 3 )

k = [tex]\frac{2}{3}[/tex]

-------------------------------------------------------

y = 4x - 2

3 = 4k - 2 ( add 2 to both sides )

5 = 4k ( divide both sides by 4 )

k = [tex]\frac{5}{4}[/tex]

--------------------------------------------------------

y = [tex]\frac{1}{2}[/tex] x

3 = [tex]\frac{1}{2}[/tex] k ( multiply both sides by 2 to clear the fraction )

k = 6

---------------------------------------------------------

2x + 3y = 4

2k + 3(3) = 4

2k + 9 = 4 ( subtract 9 from both sides )

2k = - 5 ( divide both sides by 2 )

k = - [tex]\frac{5}{2}[/tex]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

          Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

A) Let's solve for x.  [tex]2x + 3y = 40[/tex]

Step 1: Add -3y to both sides.

[tex]2x + 3y + -3y = 40 + -3y[/tex]

[tex]2x = -3y + 40[/tex]

Step 2: Divide both sides by 2.

[tex]\frac{2x}{2} = \frac{-3y + 40}{2}[/tex]

[tex]x = \frac{-3}{2} y + 20[/tex]

Answer : [tex]\frac{-3}{2} y + 20[/tex]

~~~~~~~~~~~~~~~~~

B) Let's solve for x. [tex]5x + 2y = 30[/tex]

Step 1: Add -2y to both sides.

[tex]5x + 2y + -2y = 30 + -2y[/tex]

[tex]5x = -2y + 30[/tex]

Step 2: Divide both sides by 5.

[tex]\frac{5x}{5} = \frac{-2y + 30}{5}[/tex]

[tex]x = \frac{-2}{5} y + 6[/tex]

Answer : [tex]\frac{-2}{5} y + 6[/tex]

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

Answer:

41 inches

Step-by-step explanation:

Let the point at the top of the door on the left be x

Wx + xH = 45

Let the point at the top of the door  on the right be c

Yc + cZ = 37

We know the door is

xH +  plus the width of the tile

The width of the tile is Yc

xH + Yc

On the right door

cZ +  the height of the tile

cZ + Wx

Add the two doors together

xH + Yc + cZ + Wx = 2 times the height of the door

Rewriting

xH +  Wx +  Yc + cZ = 2 times the height of the door

45+ 37 = 2 times the door height

82 = 2 times the door height

Divide by 2

41 = door height

Answer:

x = y/( ku-1)

Step-by-step explanation:

Here in this question, we are asked to solve for x.

we have;

Ux = x+ u/ k

cross multiply;

k * Ux = x + y

kUx = x + y

kUx- x = y

x(KU-1) = y

x = y/( ku-1)

Answer:

x-3 is cancelled and just one remains in numerator.

Answer:

The answer to this question can be defined as follows:

In option A, the answer is "- 357.14 miles per hour".  

In option B, the answer is "-0.98".

Step-by-step explanation:

Given:

[tex]\frac{dx}{dt} =- 300 \text{ miles per hour}[/tex]

[tex]\frac{dy}{dt} =- 400 \text{ miles per hour}[/tex]

find:

[tex]\frac{ds}{dt} =?[/tex] when

[tex]x= 150 \\y= 200\\s=x+y\\\\[/tex]

  [tex]= 150+200 \\\\=350[/tex]

[tex]\to s^2=x^2+y^2\\[/tex]

differentiate the above value:

[tex]\to 2s\frac{ds}{dt}= 2x \frac{dx}{dt}+2y \frac{dy}{dt}[/tex]

[tex]\to 2s\frac{ds}{dt}= 2(x \frac{dx}{dt}+y \frac{dy}{dt})\\\\\to \frac{ds}{dt}= \frac{(x \frac{dx}{dt}+y \frac{dy}{dt})}{s}\\\\[/tex]

        [tex]= \frac{(150 \times -300 +200 \times -400 )}{350}\\\\= \frac{-45000+ (-80000) }{350}\\\\= \frac{- 125000 }{350}\\\\= - 357.14 \ \text{miles per hour}[/tex]

In option B:

[tex]\to d=rt\\\\ \to t= \frac{d}{r}[/tex]

[tex]\to \ \ d= 350 \ \ \ \ \ \ r= -357.14\\[/tex]

[tex]\to t= - \frac{350}{357.14}\\\\\to t= - 0.98[/tex]

Answer:

x = 5

Step-by-step explanation:

Notice that there is also a base 5 on the right hand side of the equation, therefore, let's move [tex]5^{x-4}[/tex] to the right by dividing both sides by it. and then re-writing the right hand side as 5 to a power:

[tex]2^{x-5}\,*\,5^{x-4}=5\\2^{x-5}=5/5^{x-4}\\2^{x-5}=5\,*\,5^{4-x}\\2^{x-5}=5^{5-x}[/tex]

Now apply log to both sides in order to lower the exponents (where the unknown resides):

[tex](x-5)\,log(2)=(5-x)\,log(5)[/tex]

Notice that when x = 5, this equation is true because it makes it the identity: 0 = 0

So, let's now examine what would be the solution of x is different from 5, and we can divide by (x - 5) both sides of the equation:

[tex]log(2)=\frac{5-x}{x-5} \,log(5)\\log(2)=-1\,\,log(5)\\log(2)=-log(5)[/tex]

which is an absurd because log(2) is [tex]\neq[/tex] from log(5)

Therefore our only solution is x=5

Answer:

if decimal  no solution

if multiply x =5

Step-by-step explanation:

If this is a decimal point

2^(x-5) . 5^(x-4) = 5

Rewriting .5 as 2 ^-1

2^(x-5)  2 ^ -1 ^(x-4) = 5

We know that a^ b^c = a^( b*c)

2^(x-5)  2 ^(-1*(x-4)) = 5

2^(x-5)  2 ^(-x+4) = 5

We know a^ b * a^ c = a^ ( b+c)

2^(x-5 +-x+4) = 5

2^(-1) = 5

This is not true so there is no solution

If it is multiply

2^(x-5)  * 5 ^(x-4) = 5

Divide each side by 5

2^(x-5)  * 5 ^(x-4) * 5^-1 = 5/5

We know that a^ b * a^c = a^ ( b+c)

2^(x-5)  * 5 ^(x-4 -1)  = 1

2^(x-5)  * 5 ^(x-5)  = 1

The exponents are the same, so we can multiply the bases

a^b * c*b = (ac) ^b

(2*5) ^ (x-5) = 1

10^ (x-5) = 1

We know that 1 = 10^0

10^ (x-5) = 10 ^0

The bases are the same so the exponents are the same

x-5 = 0

x=5