Answer:
8Step-by-step explanation:
As,
1/4 = (1×2)/(4×2) = 4/8
4/8 = (4×1)/(8×1) = 4/8
In both case,
The denominator 8 is least common multiple
Factor the polynomial x^2+9x+8 using the pattern x^2+(a+b)x+ab=(x+a)(x+b)
Answer: final answer is (x+1) (x+8)
We need two numbers that...
Add together to get 9
Multiply together to get 8
Try 1 and 8:
1+8 = 9
1*8 = 8
therefor the answer is (x+1) (x+8)
Write equivalent expressions.
1. 5(a+a+a)= ________________________________________________________________________
2.6(3x-4)=____________________________________________________________ _______
Answer:
15a
18x -24
Step-by-step explanation:
5(a+a+a)
Combine terms in the parentheses
5(3a)
Multiply
15a
6(3x-4)
Distribute
18x -24
The volume of a prism with side lengths measured in millimeters is 20. How could this measurement be written? Check all that apply.
20 millimeters
20 mm3
20 mm2
20 square millimeters
20 cubic millimeters
Answer:
20 mm^3, 20 cubic millimeters
Step-by-step explanation:
The volume of a prism is length times width times height.
Length, width, and height can have units of mm.
mm * mm * mm = mm^3
The units of a volume must be cubic units.
Answer: 20 mm^3, 20 cubic millimeters
Will give us many points as possible thank you very much
Answer:
27 1/2 cm^2
Step-by-step explanation:
The area of a parallelogram is
A = bh
A = 5 * 5 1/2
Change to an improper fraction
A = 5 * (2*5+1)/2
A = 5*11/2
A = 55/2
Change back to a mixed number
A = 27 1/2
hat is the measure of x?
X = [?]
D
126
Answer:
since those are angles on a straight line.
we work out as follows
x+126°=180°x+126°-126°=180°-126°x=54°∠DBA and ∠DBC are making linear pair.
Linear pair of angles are formed when two lines intersect each other at a single point.
The sum of angles of a linear pair is always equal to 180°[tex]\rm \large\longrightarrow \: \: x \: + \: 126 \degree \: = \: 180 \degree[/tex]
[tex]\rm \large\longrightarrow \: \: x \: = \: 180 \degree \: - \: 126 \degree [/tex]
[tex]\rm \large\longrightarrow \: \: x \: = \: 54 \degree[/tex]
CAN SOMBOBY HELP ME find the surface area of each figure. Round it to the nearest tenth if necessary.
Answer:
365.65
Step-by-step explanation:
you can find the formula online
please help with me
Answer:
217
Step-by-step explanation:
53 + 44 + 46 = 143
360 - 143 = 217
In a city of 26000 populations, 5000 read English newspaper, 12000 read Nepali newspaper and 1000 read both. What percentage read neither English and Nepali newspaper? ( from set theory )
Answer:
38.46%
Step-by-step explanation:
total readers=16000
population=26000
no of non-readers=total population-total readers
=26000-16000
=10000
percentage of non-readers=non-readers×100%
population
=10000×100%
26000
percentage of non-readers is 38.46%
Question 8 If f (2) = (1 + 3) and g (2) VO+ 7, find g (f (x)). 9(f()) = 1 + 10 O g(f ()) = VI + 3 +7 Og(f (x)) = v= + 10 Og(f (2)) = 2? + 10
Answer:
x+10
Step-by-step explanation:
f(x) = (x+3)^2 and g(x) = sqrt(x)+7
g(f(x)) =
Replace f(x) in for x in the function g(x)
= sqrt((x+3)^2)+7
= x+3 +7
= x+10
x(x - 2) = 4 please help
Answer:
[tex]x = 1 + \sqrt{5} x = 1 - \sqrt{5} [/tex]
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
A(1, 1), B(-3, 0), C(-4, -1), D(3, -2)
Answer:
is this geomtey
Step-by-step explanation:
Make sure to put what kind of maths (geometry algebra ect.) this is so others can meet your needs better. Also might want to put what unit or type of problem this is as well.
Please help me get the answers
Answer:
1. (4)
2. (2)
Step-by-step explanation:
what is y=2x*2-6x-8 as a graph
Answer:
[tex] \bf \: y = 2 {x}^{2} - 6x - 8[/tex]
It is equation of a parabolla.
It is to be noted that the graph of y = 2x * 2-6x-8 which when simplified is y = -12x² - 12x. is attached accordingly.
What are the qualities of the graph of y = -12x² - 12x?The graph of y = -12x² - 12x is a downward-opening parabola.
It has a concave shape and its vertex is the highest point on the graph. The axis of symmetry is a vertical line passing through the vertex.
The graph may intersect or be tangent to the x-axis at two points, one point, or no points, depending on the discriminant.
Learn more about Graph at:
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plss help me with this :(
Answer:
(k) cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)
From trigonometric identities, we have;
1 + cot²θ = cosec²θ
On the Left Hand Side of the equation, we get;
cos(θ)·√(1 + cot²θ) = cos(θ) × cosec(θ) = cot(θ)
On the Right Hand Side of the equation, we have;
√(cosec²(θ) - 1) = √(1 + cot²(θ) - 1) = √(cot²(θ)) = cot(θ)
∴ √(cosec²θ - 1) = cot(θ)
By transitive property of equality, therefore;
cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)
(l) sin⁶A + cos⁶A = 1 - 3·sin²A·cos²A
sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³
(sin²A)³ + (cos²A)³ = ((sin²A) + (cos²A))³ - 3·((sin²A)·(cos²A))·((sin²A) + (cos²A))
∴ (sin²A)³ + (cos²A)³ = (1)³ - 3·((sin²A)·(cos²A))·(1) = 1 - 3·((sin²A)·(cos²A))
sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³ = 1 - 3·((sin²A)·(cos²A))
sin⁶A + cos⁶A = 1 - 3·((sin²A)·(cos²A))
(m) (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1
(sinA - cosecA)² = sin²A - 2×sinA×cosecA + cosec²A = sin²A - 2 + cosec²A
(cosA - secA)² = cos²A - 2×cosA×secA + sec²A = cos²A - 2 + sec²A
∴ (sinA - cosecA)² + (cosA - secA)² = sin²A - 2 + cosec²A + cos²A - 2 + sec²A
Where;
sin²A - 2 + cosec²A + cos²A - 2 + sec²A = sin²A + cos²A - 2 - 2 + cosec²A + sec²A
sin²A + cos²A - 2 - 2 + cosec²A + sec²A = 1 - 4 + cosec²A + sec²A
1 - 4 + cosec²A + sec²A = cosec²A + sec²A - 3
Where;
cosec²A = cot²A + 1
sec²A = tan²A + 1
∴ cosec²A + sec²A - 3 = cot²A + 1 + tan²A + 1 - 3 = cot²A + tan²A - 1 = The Right Hand Side of the equation
∴ (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1
(n) [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA
Squaring the Right Hand Side of the equation, we get;
(sinA - cosA)² = sin²A -2·sinA·cosA + cos²A = sin²A + cos²A -2·sinA·cosA
sin²A + cos²A -2·sinA·cosA = 1 - 2·sinA·cosA
∴ (sinA - cosA)² = 1 - 2·sinA·cosA
Taking the square root of both sides gives;
√((sinA - cosA)²) = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]
∴ sinA - cosA = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]
By symmetric property of equality, we have;
[tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA
Step-by-step explanation:
Kenya solved the equation below. Negative 6 (x minus 2) + 3 x = negative 3 (x + 3) + 21 What is the solution to Kenya's equation? –4 12 no solution infinitely many solutions
Answer: No solution
Step-by-step explanation:
-6(x - 2) + 3x = -3(x + 3) + 21
-6x + 12 + 3x = -3x - 9 + 21
Collect like terms
-6x + 3x + 3x = -9 + 21 - 12
-6x + 6x = - 9 + 9
0 = 0
In this scenario, it can be deduced that there is no solution to Kenya's equation.
Answer:
infinitely many solutions
Step-by-step explanation:
i got it right
Si confused as to how to solve this
Answer:
x^2, 10-x , 1.5x -5
Step-by-step explanation:
Liang bought a basket of apples to make pies for her friends. The basket of apples weighed ppp pounds. Before she had time to make the pies, she ate 3 pounds of apples. There are 17 pounds of apples left to make pies.
Answer: The equation to describe the situation is p-3= 17
And, the total weight of the basket of apples was 20 pounds.
Step by step: Now, to write an equation to describe the situation. And to find the total weight of the basket of apples.
So, the basket of apples total weighed = p pounds
Liang ate apples weighed = 3 pounds.
And the apples left for the pies weighed = 17 pounds.
Now, to write an equation describing the situation:
p-3=17 .
Thus, the equation is p-3=17
Now, to get the total weight of the basket of apples:
p-3=17
adding both sides by 3 we get : p=20
Hence, the basket of apples total weighed = 20 pounds.
Therefore, the equation to describe the situation is p-3=17
And, the total weight of the basket of apples was 20 pounds.
THIS SHOULD HELP U
HAVE A GOOD DAY !
How many solutions does this equation have x^4 - 6x^2 -7 = 0
Answer:
2 solutions
Step-by-step explanation:
x^4-6x^2-7=0
Replace x^2 by y
(x^2)^2-6x^2-7=0
y^2-6y-7=0
D=b^2-4ac= (-6)^2-4*1*(-7)= 36+28=64
sqrtD=8
y1=(-b-sqrtD)/2a=-2/2=-1
y2= (-b+sqrtD)/2a=14/2=7
x^2=-1(n0 roots) x^2=7 x=sqrt7 or x=-sqrt7
2 roots
Instructions: Given the following coordinates complete the glide reflection
transformation.
A(-9,-2)
B(-9,-5)
C(-5,-4)
Transformation: Reflection over the y-axis and a translation of shifting up 5 units
Answer:
A(9,3)
B(9,0)
C(5,1)
Step-by-step explanation:
Please help me with this I need it
9514 1404 393
Answer:
2/3
Step-by-step explanation:
Let x represent the fraction of Cheryl's income she spent in September. Then 1-x is the fraction she saved.
In October, her spending increased by 0.2x, and her savings decreased by 0.4(1 -x). Since Cheryl spends or saves all of her income, these two change amounts must be equal:
0.2x = 0.4(1 -x)
x = 2(1 -x) . . . . . . multiply by 5 to clear fractions
x = 2 -2x . . . . . . eliminate parentheses
3x = 2 . . . . . . . . add 2x
x = 2/3 . . . . . . divide by 3
Cheryl spent 2/3 of her income in September.
If a and b are parallel and c and d are parallel, which pair of angles are congruent?
A. 1 and 16
B. 5 and 8
C. 9 and 11
D. 12 and 13
Professor Goodheart has two exams, exam 1 and exam 2. The exam 1 weights 40% and the exam 2 weights 60% of the final grades. Put the grades on the exam 1 on the horizontal axis and the grade on the exam w on the vertical axis. What kind of preference a student should have for these two grades
Answer:
Imperfect substitutes
explanation:
The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.
A company's stock price flucated over a period of four days. The table shows the change in stock price per day. The net change in the company's stock price over the four days
Answer:
The net change is -.30
Step-by-step explanation:
increase means add
decrease means subtract
+3.50
-3.70
+3.30
-3.40
-------------
-.30
The net change is -.30
1-tanx/1+tanx=1+sin2x
are you sure about the ques?
what should I do?
in the picture
The expression has y and x variables in denumerator and numerator, these variables will form the results as y^1/2 / x^3/2.
This expression is given in choice A.
The correct expression will place the y in denomerator with change in power sign in the numerator and x value will become in denomerator form the expression under root power 3 over 2.
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Helppp plssss help meeee
Answer:
C. $1,260
Step-by-step explanation:
80 × 14.5 = 1,160
2,500 × 0.04 = 100
Answer:
C. $1260
Step-by-step explanation:
What is the area of this triangle?
I can't type it I have to solve on a paper for you
the circumference of a circle is 11pi ft. find its diameter, in feet
Answer:
The diameter would be 11 feet
Step-by-step explanation:
C = pi * d
we don't know D so we rearrange the equation to solve for D by dividing both sides by pi:
C/pi = d
Now we plug in everything
11pi/pi = d
The pi cancel each other out leaving with 11 feet
Therefore D = 11 feet
Solve simultaneous equations 3x-2y=17 +2x-2y=10
Answer:
(7;2)
Step-by-step explanation:
[tex]3x - 2y = 17 \\ - 2y = 17 - 3x \\ 2x + 17 - 3x = 10 \\ 2x - 3x = 10 - 17 \\ - x = - 7 \\ x = 7 \\ - 2y = 17 - 21 \\ - 2y = - 4 \\ y = 2[/tex]
Will Mark Brainlest helpppp
Answer:
R = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]
Step-by-step explanation:
P - Q + R = I ( I is the identity matrix )
[tex]\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( subtract corresponding elements )
[tex]\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]
R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]
