find the length of the arc. round your answer to nearest tenth

Answer:

4

Step-by-step explanation:

We want the cubed root of 64  

(64)^(1/3)  

(4*4*4) ^ (1/3)  

4  

Unless this is 3 * sqrt(64)  

then it would be  

3 sqrt(8*8)  

3 (8)  

24

Answer:

431.2

Step-by-step explanation:

Area of a regular polygon = # of sides * side length of 1 side * apothem

We want to find the area of a regular polygon with 7 sides, an apothem of 8 meters, and a side length with 7.7 meters

So # of sides = 7

apothem = 8

side length = 7.7

so the area would equal 7 * 8 * 7.7 = 431.2

It says to round to the nearest tenth however 431.2 is already rounded to the nearest tenth

Answer:

That answer ^ is incorrect. The correct answer ( in acellus that is ) is 2

15.6

Step-by-step explanation:

Answer:

1/4 ÷ 3/8 = 2/3

Step-by-step explanation:

When dividing fractions, you have to take the reciprocal of the second fraction, then multiply from there. The reciprocal of a fraction is basically flipped. So then, 1/4 ÷ 3/8 becomes 1/4 x 3/8. Multiplying fractions should be pretty straight forward as you just need to multiply numerator (top number of a fraction) with numerator and vice versa for the denominators (bottom number of a fraction).

So then you get: (1 x 8)/(3 x 4) = 8/12. Then you just simplify it by dividing the numerator and denominator by their greatest possible factor, which in this case is 4. So then, (8 ÷ 4)/(12 ÷ 4) = 2/3.

Answer:

540 miles per hour and 50 miles per hour respectively.

Step-by-step explanation:

Let the speed of plane in still air be x and the speed of wind be y.

ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50

Answer:

Step-by-step explanation:

Answer:

Sample space = 36

P(sum of 6) = 5/36

Step-by-step explanation:

Number of faces on a dice = 6

The sample space, for a toss of 2 dice ; (Number of faces)^number of dice

Sample space = 6^2 = 6*6 = 36

Sum of numbers appearing on the dice = 6

The sum of 6 from the roll of two dice has 5 different outcomes ; Hence, required outcome = 5

Total possible outcomes = sample space = 36

Probability, P = required outcome / Total possible outcomes

P = 5 / 36

Probabilities are used to determine the chances of events

The given parameters are:

[tex]n=6[/tex] --- the faces of a six-sided die

[tex]r = 2[/tex] -- the number of dice

(a) The number of sample points

This is calculated as:

[tex]Sample = n^r[/tex]

So, we have:

[tex]Sample = 6^2[/tex]

Evaluate the exponent

[tex]Sample = 36[/tex]

Hence, the number of sample points is 36

(b) The probability that the sum of 6

See attachment for the sample space of the sum of two dice.

From the sample space, there are 5 outcomes where the sum is 6.

So, the probability is:

[tex]Pr = \frac{5}{36}[/tex] --- where 36 represents the number of sample points

Divide 5 by 36

[tex]Pr = 0.1389[/tex]

Hence, the probability that the sum of the numbers appearing on the dice is equal to 6 is 0.1389

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...

Calculate Energy Cost by Appliance

The scatterplot is below.

I used GeoGebra to make the scatterplot. Though you could use other tools such as Excel or Desmos, or lots of other choices.

Side note: I'm not sure why, but you repeated the point (0.7,1.11) three times.

Answer:

The right answer is:

(a) -10.67

(b) 0.7986

Step-by-step explanation:

(a)

According to the question,

X                          P(X)                  X.P(X)                 X2.P(X)

12130                  0.002               24.26                 294274

-35                      0.998               -34.93                1222.55      

Now,

[tex]\Sigma x.P(x) = -10.67[/tex]

or,

[tex]\Sigma x^2.P(x) = 295496.35[/tex]

hence,

The mean will be:

[tex]\Sigma x.P(x) = -10.67[/tex]

(b)

According to the question,

n = 12

p = 0.125

q = 1 - p

  = 0.875

Now,

⇒ [tex]P(X=x) = \binom{n}{x} p^x q^{n-x}[/tex]

By substituting the values, we get

⇒ [tex]P(X \geq 1)=1-(\binom{12}{0} 0.125^0. 0.875^{12-0})[/tex]

⇒                  [tex]=1-(1 (0.125^0) (0.875^{12}))[/tex]

⇒                  [tex]=1-(1(1.0)(0.2014))[/tex]

⇒                  [tex]=1-(0.2014)[/tex]

⇒                  [tex]=0.7986[/tex]    

Answer:

Step-by-step explanation:

You have three data points. Equation of the line passing through (30,2), (45,2.75), and (60,3.50):

y = 0.5x + 0.5

It takes 0.5 hour to clean up.

Answer:

AC = 377.19

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 5 = 33/AC

AC tan 5 = 33

AC = 33/ tan 5

AC = 377.19

Answer:

B

Step-by-step explanation:

they have the same intercepts

Answer:

A

Step-by-step explanation:

i think so..sorry if im wrong

Answer:

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 3.0123

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 3.0123\frac{279.29}{\sqrt{14}} = 224.85[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 224.85 = $439.29

The upper end of the interval is the sample mean added to M. So it is 664.14 + 224.85 = $888.99.

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

Answer:

According to the proposed interrogate, as well as the graph provided, the correct answers to such are identified as B. Y = -2x + 5 and C. 2x + y = 4.

Step-by-step explanation:

To evaluate such, a comprehension of linear Cartesian data is required:

Slope = rise/run. If there is a negative rise, the direction of the line is proportional to the left-hand side as it exponentially grows or augments in units.

Y-intercept: The peculiar point in which the linear data observed intersects the y-axis.

X-intercept: The peculiar point in which the linear data observed intersects the x-axis.

Since this is a negative linear, all negative slopes apply.

The interrogate states, “Check all that apply.” Thus, there may be more than one correct answer, shall such be disseminated.

A. Cannot be the answer as the line should have been a horizontal line contained within quadrants I and II on the Cartesian Plane.

B. Contains a negative slope, thus is disclosed as a correct answer.

C. This configuration is denoted in “Standard Form” or “General Form”. To convert this to “Slope-Intercept Form” the following must be executed mathematically:

2x + y = 4

Y = -2x + 4 <== Slope-Intercept Form (Contains a negative slope, thus considered a correct answer.

D. Likewise, this configuration is denoted in “Standard Form” or “General Form”. To convert this to “Slope-Intercept Form” the following must be executed mathematically:

X - y = 9

-y = -x + 9

Y = x - 9 <== Slope-Intercept Form (Cannot be considered as the correct answer, given the positive slope configuration, thus is marked out).

Thus far, as evaluated, the correct answers to the proposed interrogate, as according to the linear data provided in the Cartesian Plane is acknowledged, and henceforth disseminated, as B. Y = -2x + 5 and C. 2x + y = 4.

*I hope this helps.

Answer:

His least score for him in the fourth paper has to be 76.

Step-by-step explanation:

Given that Michael has an average of 68% in his 3 papers but that is below the pass mark of 70%, to determine what must be his least score in the fouth paper to enable him pass the following calculation must be performed:

(70 x 4) - (68 x 3) = X

280 - 204 = X

76 = X

Therefore, his least score for him in the fourth paper has to be 76.

Answer:

The sample observations are not a random​sample, so a test about a population proportion using the normal approximating method cannot be used.

Step-by-step explanation:

The necessary conditions are

The sample must be random and independently selected from the normally distributed population.

n*p and n*q both must be greater than 5

There must be two outcomes "success" and "failure"

The number of trials must be fixed.

From the given information 2), 3)and 4) conditions are satisfied, but not 1) because we are not given that people are selected randomly.

Answer: The sample observations are not a random​sample, so a test about a population proportion using the normal approximating method cannot be used.

Answer:

-1/20

Step-by-step explanation:

As x approaches c,

g(x)         1/5

------ = ------------ = -1/20            (matches last of the four given possible answers)

f(x)          -4

Answer:

[tex]\displaystyle \frac{-1}{20}[/tex]

General Formulas and Concepts:

Calculus

Limit Property [Division]:                                                                                              [tex]\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \frac{ \lim_{x \to c} f(x)}{ \lim_{x \to c} g(x)}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \lim_{x \to c} f(x) = -4[/tex]

[tex]\displaystyle \lim_{x \to c} g(x) = \frac{1}{5}[/tex]

Step 2: Solve

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

Answer:

The proportion of products that exhibit edge roughness is 0.029 = 2.9%.

Step-by-step explanation:

Proportion of products that exhibit edge roughness:

2% of 25%(new blades).

3% of 60%(average sharpness).

4% of 15%(worn). So

[tex]p = 0.02*0.25 + 0.03*0.6 + 0.04*0.15 = 0.029[/tex]

The proportion of products that exhibit edge roughness is 0.029 = 2.9%.

Answer:

a

Step-by-step explanation:

The correct answer is option C which is the graph of the equation ( x-1 )² + ( y+ 2 )² = 4 will be the circle in the third and the fourth quadrant.

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

Given equation is ( x-1 )² + ( y + 2 )² = 4

The graph of the equation is attached with the answer below when we plot the graph we will get the circle that is lying in the third and the fourth quadrant.

Therefore the correct answer is option C which is the graph of the equation ( x-1 )² + ( y+ 2 )² = 4 will be the circle in the third and the fourth quadrant.

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Answer:

x=8

Step-by-step explanation:

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

  250

Step-by-step explanation:

Let 'a' represent the number of adult tickets.

  a +(a -73) = 427

  2a = 500 . . . . . add 73

  a = 250 . . . . . . divide by 2

250 adult tickets were sold.

_____

Additional comment

I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.

9514 1404 393

Answer:

  23°

Step-by-step explanation:

The angle a vector makes relative to the +x axis is found as ...

  α = arctan(y/x) = arctan(4.30/10.3) ≈ 22.66°

The angle is about 23°.

__

Additional comment

This vector resides in the first quadrant, so no adjustment of the angle is needed. In other quadrants, 180° may need to be added or subtracted from the angle given by the arctan function to arrive at the correct value. (Some calculators and spreadsheets have an ATAN2(x, y) function that takes signs into account.)

Answer:

Lift

Step-by-step explanation:

Finding patterned and relationship between large sets of data can be obtained using the association rule as it finds insights, relationships and trends within sets of data variables. Lift is a parmater of interest whichbus used when performing analysis on association between variables in datasets. The Lift is literally the ratio of confidence to expected confidence. Where, the confidence of association is divided by the expected confidence (benchmark confidence).

Answer:

6 11/12

Step-by-step explanation:

4 1/6 + 2 3/4

Get a common denominator of 12

4 1/6 *2/2  + 2 3/4 *3/3

4 2/12 + 2 9/12

6 11/12

Line geometry are caused from the intersection of two line. The measure of angle x from the diagram is 110degrees

Line geometry are caused from the intersection of two lines. From the given figures, you can see that <KOH and <IOK forms a linear pair, hence;

<KOH + <IOK = 180

110 + <IOK = 180
<IOK = 180 - 110
<IOK = 70 degrees

Similarly <x and MIOK are linear pair pair such that <x + 1<IOK = 180
<x + 70 =180
<x = 180 - 70
<x = 110degrees

Hence the measure of angle x from the diagram is 110degrees

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Answer:

<IOK = 70 degrees

<x and <IOK form a linear pair, so m<x is = 110

Step-by-step explanation:

i did it on khan and got it right, i hope your day goes well and you get all your other questions right :)

Answer:

0.0287 = 2.87% probability the total of the 100 claims exceeds 1,530,000.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is [tex]n\mu[/tex] and the standard deviation is [tex]s = \sigma\sqrt{n}[/tex]

Sum of normal variables:

When two normal variables are added, the mean is the sum of the means, while the standard deviation is the square root of the sum of the variances.

Group A follow a normal distribution with mean 10,000 and standard deviation 1,000. 50 claims of group A.

This means that:

[tex]\mu_A = 10000*50 = 500000[/tex]

[tex]s_A = 1000\sqrt{50} = 7071[/tex]

Group B follow a normal distribution with mean 20,000 and standard deviation 2,000. 50 claims of group B.

This means that:

[tex]\mu_B = 20000*50 = 1000000[/tex]

[tex]s_B = 2000\sqrt{50} = 14142[/tex]

Distribution of the total of the 100 claims:

[tex]\mu = \mu_A + \mu_B = 500000 + 1000000 = 1500000[/tex]

[tex]s = \sqrt{s_A^2+s_B^2} = \sqrt{7071^2+14142^2} = 15811[/tex]

Find the probability the total of the 100 claims exceeds 1,530,000.

This is 1 subtracted by the p-value of Z when X = 1530000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{1530000 - 1500000}{15811}[/tex]

[tex]Z = 1.9[/tex]

[tex]Z = 1.9[/tex] has a p-value of 0.9713

1 - 0.9713 = 0.0287

0.0287 = 2.87% probability the total of the 100 claims exceeds 1,530,000.