Find the mean,median, and mode(s) of the distance in feet from home plate to the left-field fence at various ball park: 303,279,297,321,310,310,301.

The graph of the inequality is plotted using the below points.

Graph:

In math, graph show you information as a visual image or picture.

Given,

Here we need to find the graph of the given inequality.

To graph an inequality:

To graph the related boundary line. We have to replace the <, >, ≤ or ≥ sign in the inequality with = to find the equation of the boundary line.

Now, we have to identify at least one ordered pair on either side of the boundary line and substitute those (x, y) values into the inequality.

Then shade the region that contains the ordered pairs that make the inequality a true statement.

Here if points on the boundary line are solutions, then use a solid line for drawing the boundary line. This will happen for ≤ or ≥ inequalities.

Where as if points on the boundary line are not solutions, then use a dotted line for the boundary line. This will happen for < or > inequalities.

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The linear equations that represent the relationships in the question order are;

A linear equation is an equation of the form; y = m·x + c

The slope of the line is found as follows;

(-5 - (-21))/(-1 - (-5)) = 4

The equation is y - (-5) = 4·(x - (-1)) = 4·x + 4

y = 4·x + 4 - 5 = 4·x - 1

The y-intercept is (0, 4), the x-intercept is (4, 0)

The slope is therefore; (0 - 4)/(4 - 0) = -1

The equation is therefore; y - 0 = -1 × (x - 4) = -x + 4

The y-intercept is (0, -1), the x-intercept is (4, 0)

The slope is therefore; (0 - (-1))/(4 - 0) = 1/4

The equation is therefore; y - 0 = (1/4) × (x - 4) = x/4 - 4/4 =

The slope of the line is; [tex]\dfrac{-3\frac{3}{4} - \left(-\frac{3}{4}\right) }{4-1} = -1[/tex]

y - (-3/4) = -1 × (x - 1) = -x + 1

y = -x + 1 - (3/4) = -x + 1/4

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The factor theorem states that x+2 is a factor of x³+3x²+5x+6.

A factor is a number that completely divides another number.

To put it another way, if adding two whole numbers results in a product, then the numbers we are adding are factors of the product because the product is divisible by them.

The numbers that can divide a number exactly are called factors.

There is therefore no residual after division.

The numbers you multiply together to obtain another number are called factors.

A factor is therefore another number's divisor.

So, the expression is: x³+3x²+5x+6

Check whether x+2 is the factor:

Then,(x = -2)

p(-2) = (-2)³+3(-2)²+5(-2)+6

p(-2) = - 8 + 12 - 10 + 6

p(-2) = 0

Therefore, the factor theorem states that x+2 is a factor of x³+3x²+5x+6.

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Correct question:
Examine whether x+2 is a factor of x³+3x²+5x+6

The test that Joan can use to determine if husbands earn more is the t test.

A t test is a statistical test used to compare two groups' means. It is frequently used in hypothesis testing to determine whether a process or treatment has an effect on the population of interest, or whether two groups differ. A t-test is an inferential statistic that is used to determine whether or not there is a significant difference in the means of two groups and how they are related.

The Independent Samples t Test compares the means of two independent groups to see if there is statistical evidence that the associated population means differ significantly. This can be utilized by Joan.

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Using the rate, the number of book Mason reads per month is 2 books.

Mason read 4 books in 2 months. Mason reads at a constant rate. The number of books he reads each month can be calculated as follows;

The number of books he reads is at a constant rate. The rate formula can be used to find the number of book Mason read each month.

rate = number of books read / number of month

Therefore,

number of books read = 4 books

number of month = 2 month

Hence,

rate  = 4 / 2

rate = 2 books per month

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The total number of pounds of avocados Jenna bought is B. 2

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Assuming Jenna bought x pounds of apples and y pounds of avocados.

Altogether she bought 7 pounds of apples and avocados.

∴ x + y = 7...(i)

Altogether, she spent $14. 25.

∴ 1.25x + 4y = 14.25...(ii)

Now multiplying eqn(i) by 1.25 and subtracting from eqn(ii) to cancel out the variable x, we get

2.75y = 5.5.

y = 2 pounds of avocados and hence 5 pounds of apples.

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Answer: false

Step-by-step explanation:

if the expected grade was 100 but passing was 80 then she couldn't have passes with a 48

Step-by-step explanation:

x = the integer number

8×(x + 2) - x = 86

8x + 16 - x = 86

7x = 70

x = 10

x + 2 = 12

the larger integer is 12.

Answer:

4

Step-by-step explanation:

3(-5x-5) + 19x = _x - 15

-15x-15+19x = _x - 15

4x - 15 = _x - 15

It has to be the same on both sides so 4 would go in that blank.

Answer: 4

Step-by-step explanation:

Answer:

Step-by-step explanation:

x = 32

x - 10 = 22

add 10 to both sides of the equation

-10 + 10 = 0

22+ 10 = 32

x = 32

Using the par value method, the journal entry to record the treasury stock transaction is as follows:

Debit Treasury Stock $2,350

Debit Paid-in Capital in Excess of Par Value $1,880

Credit Cash $4,230

Treasury stock transactions can be recorded using the cost or the par value methods.

When the cost method is used, the Treasury Stock account is debited or credited with the cost (cash price paid or received).

When the par value method is used, the difference between the cash price or cost and the par value is recorded in the Paid-in Capital in Excess of the Par Value account.

The Treasury Stock account is then credited or debited with the par value.

Treasury Stock $2,350 (470 x $5) Paid-in Capital in Excess of Par Value $1,880 (470 x $9 - $5) Cash $4,230 (470 x $9)

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Journalize the treasury stock transaction using the par value method.

The Distributive property on the expression gives a result of 4.9 and the distributed expression is (2 + 4) * 0.82

From the question, we have the following parameters that can be used in our computation:

The expression is given as:

The product of 6 and 0.82

Mathematically, this expression can be represented as

6 * 0.82

To apply the distributive property,

We need to express 6 as the sum of two numbers

So, we have the following representation

6 * 0.82 = (2 + 4) * 0.82

Remove the brackets

6 * 0.82 = 2 * 0.82 + 4 * 0.82

Expand the terms of the expression

6 * 0.82 = 1.64 + 3.28

Evaluate the sum

6 * 0.82 = 4.92

Hence, the solution is 4.9

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Answer:

Answer:

[tex]8\sqrt{11}[/tex]

Step-by-step explanation:

Given:

[tex]x+\dfrac{1}{x}=\sqrt{11}[/tex]

Sum of two squares

[tex]\boxed{a^2+b^2=(a+b)^2-2ab}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^2+\dfrac{1}{x^2}&=\left(x+\dfrac{1}{x}\right)^2-2x\left(\dfrac{1}{x}\right)\\\\&=\left(\sqrt{11}\right)^2-2\\\\&=11-2\\\\&=9\end{aligned}[/tex]

Sum of two cubes

[tex]\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^3+\dfrac{1}{x^3}&=\left(x+\dfrac{1}{x}\right)\left(x^2-x\left(\dfrac{1}{x}\right)+\left(\dfrac{1}{x}\right)^2\right)\\\\ &=\left(x+\dfrac{1}{x}\right)\left(x^2-1+\dfrac{1}{x^2}\right)\\\\&=\left(x+\dfrac{1}{x}\right)\left(x^2+\dfrac{1}{x^2}-1\right)\\\\&=\sqrt{11}\left(9-1\right)\\\\&=8\sqrt{11}\end{aligned}[/tex]

Answer: One Real Solution

We can Identify the coefficients a, b, and c from your equation because as it says, it is in the format of the quadratic equation ( ax^2 + bx + c = 0 )

a=2,b=-4,c=2

Now we can use the discriminant to determine how many solutions this has using the equation b^2 - 4ac

Once we plug in our coefficients:

(-4)^2 - 4 x 2 x 2

Once we simplify, we get 0.

One real solution.

I hope this helps.

In this case, we first need to simplify the given quadratic equation 2x² - 4x = -2, and to do so, we perform the following simplification steps:

For a quadratic equation of the form ax² + bx + c = 0, the discriminant is calculated using the following formula:

   Δ = b² - 4ac

In this case, we have that the equation that we must solve is 2x²-4=-2, which implies that the corresponding coefficients are:

By introducing these values into the formula we get:

         Δ = b² - 4ac = (-4)² - 4·(2)·(2) = 0

Therefore, the discriminant for the given quadratic equation is Δ=0=0, which is zero, and indicates that the equation 2x²-4=-2 has only one real root.

The comparison of the terms are:

From the question, we have the following equation:

-4x + 11 = -10x + 17

The variable terms are terms that have the variable x represented

In this case, the variable terms are

Left-hand side = -4x

Right-hand side = -10x

When -4x and -10 are compared, we can conclude that

-4x is greater than -10x

From the question, we have the following equation:

-4x + 11 = -10x + 17

The constant terms are terms that do not have the variable x represented

In this case, the constant terms are

Left-hand side = 11

Right-hand side = 17

When 11 and 17 are compared, we can conclude that

11 is less than 17

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Answer:

5, 4, 7

Step-by-step explanation:

Answer:

undefined

Step-by-step explanation:

The square root of any negative number is undefined because there is no possible solution. - × - = + and + × + = +

Answer:

find p (A or ),given that A and B are independent

Assuming [tex]\overline{BC}[/tex] is a diameter, minor arc [tex]AB[/tex] has a measure of [tex]180^{\circ}-108^{\circ}=72^{\circ}[/tex].

Using the inscribed angle theorem, [tex]36=x+3 \implies x=\boxed{33}[/tex].

The angle with 180° is a straight line, and the ray can be drawn in any way.

The definition of ray in maths, that it is a part of a line that has a fixed starting point but no endpoint.

Given that, angle PKW is 180 degrees and two additional rays were added,

The figure has been attached in answer.

We know when an angle measures 180° it makes a straight line and on it, we can draw as many ray as we want and in any way.

Hence, The angle with 180° is a straight line, and the ray can be drawn in any way.

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In the concept of geometry, the pair of triangles that are congruent by the ASA Congruent Theorem are the pairs that have two corresponding angles and an included side that are congruent to each other.

Congruent:

Congruent refers the identical in shape and size.

Given,

Here we need to find in which pair of triangles is congruent by the ASA postulate.

As per the Angle-Side-Angle Congruent Theorem (ASA) states that when two triangles are considered congruent if they have two corresponding angles that are congruent and an included side that are congruent to each other.

So, this one included side is the side that is lie between the two congruent angles in each of the triangles.

Therefore, the triangle which form the pairs of angles given has two corresponding angles and an included side that are congruent to each other in each triangle.

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Answer:

100 times square times Y 49 gives= 14000

The measure of the largest side of the triangle is 102cm.

Ratio, is a term that is used to compare two or more numbers. It is used to indicate how big or small a quantity is when compared to another. In a ratio, two quantities are compared using division.

For example, 2:3:6 shows the ratio of the sides of a triangle. The perimeter which is the addition of the triangle is 187cm.

Therefore the measure of each side will be given as:

2/11×187= 34cm

3/11×187= 51cm

6/11×187= 102cm

This means that the measure of the three sides are 34cm, 52cm, and 102cm.

Therefore the measure of the largest side is 102cm

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Answer:

5/12

Step-by-step explanation:

we need to subtract these 2 fractions

3/4-1/3

to start we change so they can have common denominators and both of them can be 12

3x3/4x3-1x4/3x4

9/12-4/12

5/12

hopes this helps please mark brainliest

Answer: 4/3

Step-by-step explanation:

The reciprocal of a/b is b/a.

The linear equation with a slope of 1/2 and that passes through the point (1, -2) is written in point-slope form as:

y = (1/2)*(x - 1) - 2

For a linear equation with a slope m and a known point (h, k), the slope-point form is written as:

y = m*(x - h) + k

Where y and x are the two variables.

Here we know that the slope is 1/2, and the known point is (1, -2), then the values on the equation above are:

m = 1/2

h = 1

k = -2

Replacing that in the general formula for the linear equation in the slope-point form that is written above, we will get:

y = (1/2)*(x - 1) - 2

That is what we wanted to find.

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Answer:

2 1/4 kg

Step-by-step explanation:

The value of the expression 1+1+q+q++1+1+1 is 5 + 2q.

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.

As an illustration, the expression x + y has the terms x and y with an addition operator between them.

The expression will be:

= 1+1+q+q++1+1+1

= 5 + 2q

The value is 5 + 2q.

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Answer:

5+2q

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Fill in X and Y for each of the equations until you find one that fits

The equation of the line y=2x+3 passes through the (1,4) point only.
The line gave y=2x+3.

In order to check whether the line passes through the points the following steps are:

A) (1,4)

Here x=1 , y=4.

We will put these values in the line y=2x+3.

4= 2(1)+3

4=4
As L.H.S=R.H.S, therefore this point (1,4) passes through the line.

B) (-1,4)

Here x=-1 , y=4.

We will put these values in the line y=2x+3.

4= 2(-1)+3

4= -2+3
4 [tex]\neq[/tex] 1
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (1,4) does not pass through the line.

C) (2,3)

Here x=2 , y=3.

We will put these values in the line y=2x+3.

3= 2(2)+3

3= 4+3
3 [tex]\neq[/tex] 7
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (2,3) does not pass through the line.

D) (3,2)

Here x=3 , y=2.

We will put these values in the line y=2x+3.

2= 2(3)+3

2= 6+3
2 [tex]\neq[/tex] 9
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (3,2) does not pass through the line.

Only (1,4) point passes through the line.

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The area of this rectangular walk is 390[tex]ft^{2}[/tex]

A rectangle is a closed two-dimensional figure with four sides. The opposite sides of a rectangle are equal and parallel to each other and all the angles of a rectangle are equal to 90°.

The width of the walk is constant and is 2ft, length of the walk is determined by the part of the rectangular yard.

Area of walk = 3 x 27 +3x27 + 3 x 38 + 3 x 38 which is 390[tex]ft^{2}[/tex]

In conclusion the area of the walk is 390[tex]ft^{2}[/tex]

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