Find the measure of each missing angle. Subject: Geometry
Unit 5: Relationships in Triangles
Homework 1: Triangle Midsegments
Answers
Answer:
Q10
∠1 = ∠5 = 180° - 144° = 36°∠2 = 56°∠3 = 180° - 56° = 124°∠4 = 144° - 56° = 88°∠5 = ∠1 = 36°Q11
∠1 = 35°∠2 = 180° - 35° = 145°∠3 = 90° - 35° = 55°∠4 = 180° - ∠5 = 180° - ∠3 = 180° - 55° = 125°∠5 = ∠3 = 55°Measure of angles for figure 1:
∠1=36∠2=56∠3=124∠4=88∠5=36Measure of angles for figure 2:
∠1=35∠2=145∠3=55∠4=125∠5=55The angle is formed by two rays at a common point of the two rays.
For given figure 1:
∠1+144=180 (Sum of angles on same side of transversal is 180°)
∠1=180-144
∠1=36
∠5+144=180(Sum of angles on a line is 180°)
∠5=180-144
∠5=36
Similarly, ∠3=180-56
∠3=124
∠4+36+56=180(Sum of all angles of a triangle is 180°)
∠4=180-36-56
∠4=88
∠2+36+88=180
∠2=56
Thus, measure of angles for figure 1 are ∠1=36, ∠2=56, ∠3=124, ∠4=88, ∠5=36.
For given, figure 2:
∠1=35(Alternate angle on same side of transversal are equal)
∠2=180-35
∠5=180-35-90(Sum of all angles of a triangle is 180°)
∠5=55
∠4+55=180(Sum of angles on a line is 180°)
∠4=180-55
∠4=125
Similarly, ∠2=180-35(Sum of angles on a line is 180°)
∠2=145
∠3=180-35-90(Sum of all angles of a triangle is 180°)
∠3=55
Thus, measure of angles for figure 2 are ∠1=35, ∠2=145, ∠3=55, ∠4=125, ∠5=55
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Answers
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
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