Answer:
160=130+x
x=160-130
x=30
Any help is appreciated!!!!
Answer:
D
Step-by-step explanation:
because 3x - 12y = 15 has only numbers that are divisible by 3 leaving just one single x term, and the other terms simply reduce their used numbers to still integer numbers (4 and 5).
this makes it easier to be used in the other equation.
The diagram shows a cylinder of diameter 6 cm and height 20 cm what is the volume in cm3
Answer:
565.2cm³
Step-by-step explanation:
the radius= 6/2= 3 cm
the height= 20cm
the volume= 3.14× 3²×20
= 3.14×180= 565.2 cm³
Check the picture below.
If two boxes of cereal and a jug of milk cost $8.50, and three boxes of cereal and two jugs of milk cost $14.00, how much does a box of cereal cost?
Answer:
$3
Step-by-step explanation:
Let c represent the cost of a box of cereal and let m represent the cost of a jug of milk.
Create a system of equations:
2c + m = 8.5
3c + 2m = 14
Solve by elimination by multiplying the top equation by -2:
-4c - 2m = -17
3c + 2m = 14
Add them together and solve for c:
-c = -3
c = 3
So, a box of cereal costs $3
A box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, two boxes of cereal and a jug of milk cost $8.50, and three boxes of cereal and two jugs of milk cost $14.00
Let c stand for the price of a box of cereal and m for the price of a milk jug.
The obtained system of equations is as follows,
2c + m = 8.5
3c + 2m = 14
Multiply the top equation by -2 to reach the solution by elimination:
-4c - 2m = -17
3c + 2m = 14
Put them all together to find c:
-c = -3
c = 3
Thus, a box of cereal cost $3 if two boxes and a jug of milk cost $8.50, and three boxes and two jugs of milk cost $14.00.
Learn more about the equation here,
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A boy spent 20% of his money on books and 20% of the remainder on food.If he had $2000 left, how much money did he have at first?
Answer:
[tex]\$3,125[/tex]
Step-by-step explanation:
Let [tex]s[/tex] represent the amount of money he initially started with.
After he spent 20% on books, he will have [tex]100\%-20\%=80\%[/tex] of his initial money left. We can represent this as [tex]0.8s[/tex].
Following that, the boy spends 20% of the remainder of his money on food. Similarly, he will have [tex]100\%-20\%=80\%[/tex] of the remainder of money he had left after he purchased the books. Therefore, he ends up with [tex]0.8(0.8s)=0.64s[/tex] of his money left.
Since we're given that he had $2,000 after all these transactions, we have the following equation:
[tex]0.64s=\$2,000[/tex]
Divide both sides by 0.64 to isolate and solve for [tex]s[/tex]:
[tex]s=\frac{2,000}{0.64}=\boxed{\$3,125}[/tex]
Therefore, the boy had $3,125 to begin with.
Answer:
2800
Step-by-step explanation:
20%+20%=40%
40/100x2000=2800
Find the product
14/4 • 33/10 =
Answer:
Step-by-step explanation:
[tex]\frac{14}{4}*\frac{33}{10}=\frac{7}{2}*\frac{33}{10}\\\\ =\frac{7*33}{2*10}\\\\=\frac{231}{20}\\\\=11\frac{11}{20}[/tex]
A side of the triangle below has been extended to form an exterior angle of 158º. Find
the value of x.
Answer:
22°
Step-by-step explanation:
180° - 158° = 22°
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
solve the equatiuon =
Find the standard form for the equation of the line which passes through the point (10, 53) and which has a y-intercept of — 3.
Answer:
Step-by-step explanation:
eq. of line with slope m and intercept 3 is
y=mx+3
∵ it passes through (10,53)
53=10m+3
10m=53-3=50
m=50/10=5
y=5x+3
so standard form of eq. is
5x-y+3=0
or
5x-y=-3
Someone please help me out
Answer:
[tex] {x}^{3} + 5 {x}^{2} - x - 5 \\ {x}^{2} (x + 5) - 1(x + 5) \\ (x + 5)( {x}^{2} - 1)[/tex]
The 584 students at Sunset Elementary School participated in a canned food drive. Each student brought an average of 7 cans. If the school had a goal to donate 3,500 cans, by how much did they exceed their goal?
Answer:
they exceeded their goal by 668 cans.
Step-by-step explanation:
multiplying 524 by 7 you get 3668, then subtracting 3,000 from that you get 668.
In triangle XYZ. the measurements of angle X and angle Y are 45° Which is the longest side of the triangle
Answer:
the side XY
Step-by-step explanation:
we know 2 angles in a triangle. but are 45 degrees.
that means the third angle Z is 180-45-45 = 90 degrees.
the side opposite of the largest angle is the longest side.
opposite of Z is the side XY.
What is -2y + -4y. Simplify the answer.
Step-by-step explanation:
Explanation is in the attachment
hope it is helpful to you
Answer:
[tex]-2y+\left(-4\right)y[/tex][tex]=-2y-4y[/tex][tex]=-6y[/tex][tex]-----------[/tex]
hope it helps...
have a great day!!
Help,anyone can help me do quetion,I will mark brainlest.
Answer:
c) 25 cm^2
d) 52.5 cm^2
Step-by-step explanation:
5*2 = 1
10/2 = 5
40/2 = 20
20+5 = 25
This is just scratch work^
Solve for x. Round to the nearest tenth, if necessary.
Answer:
X would be 63.9
Hope it helps
Step-by-step explanation:
The value of the variable 'x' using the cosine formula will be 63.9 units.
What is a right-angle triangle?It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.
Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.
The value of 'x' is given by the cosine of the angle ∠QSR. And the cosine of an angle is the ratio of the base and hypotenuse of the right-angle triangle. Then we have
cos 35° = x / 78
x = 63.9
The value of the variable 'x' using the cosine formula will be 63.9 units.
More about the right-angle triangle link is given below.
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nth term of an AP is given by an expression 7n-2,find the common difference of this sequence if fisrt term of sequence is 1? a.2 b.-2 c-7 d7
Step-by-step explanation:
there is something wrong with what your write here as problem description.
either there is something missing in the main expression, or in the answer options.
given your nth-term expression 7n-2, none of the 4 answer options can fit.
so, I thought, maybe there was a typo.
the possible interpretations of the expression could be
7n - 2
7(n-2)
[tex] {7}^{n} - 2[/tex]
[tex] {7}^{n - 2} [/tex]
we know that
a1 = 1
a2 = either
a1 + 2 = 3
a1 - 2 = -1
a1 + 7 = 8
a1 - 7 = -6
so, we can eliminate both negative answer options, because they would cause only negative sequence elements, but the main expression (neither of the 4 possibilities) does not allow that.
but also none of the 4 possibilities of the expression delivers any of the 4 values for a2 as described above.
7×2 - 2 = 14 - 2 = 12
7(2-2) = 7×0 = 0
7² - 2 = 49 - 2 = 47
[tex] {7}^{2 - 2} = {7}^{0} = 1[/tex]
similar not for a3.
so, if I consider your answer options right, we have 4 possible arithmetic sequences:
1. 1, 3, 5, 7, 9, 11, 13, 15, ...
2. 1, -1, -3, -5, -7, -9, -11, -13, ...
3. 1, 8, 15, 22, 29, 36, 43, 50, ...
4. 1, -6, -13, -20, -27, -34, -41, ...
the nth term expression is for
a. an = 2n - 1
b. an = 2×(-n) + 3 = 2×(-n + 1) + 1
c. an = 7n - 6
d. an = 7×(-n) + 8 = 7×(-n + 1) + 1
so, please pick the right expression from this list, and then use the answer option with the same letter.
helpppppppppppppppp//////////////////////////////////////////
Answer:
m(x)
Step-by-step explanation:
Leonardo is solving the equation 4 (x minus one-fifth) = 2 and two-thirds. His work is shown. Where is his error?
Answer:
Step 3
Step-by-step explanation:
Leonardo is solving the equation 4 (x minus one-fifth) = 2 and two-thirds. His work is shown. Where is his error?
Given :
4(x - 1/5) = 2 2/3
Open the bracket
4x - 4/5 = 2 2/3
Add 4/5 to both sides
4x - 4/5 + 4/5 = 8/3 + 4/5
Lcm of 3 and 5 = 15
4x = (40 + 12) / 15
4x = 40/15 + 12/15
4x = 52/15
Multiply by 1/4
4x * 1/4 = 52/15 * 1/4
x = 52 / 60
x = 13 / 15
Hence, the error is in step 3
15/5 * 3 = 12
Rather ; Leonardo wrote 16
How can an expression written in either radical form or rational exponent form be rewritten to fit the other form? Explain thoroughly and thank you for your time.
Answer:
Step-by-step explanation:
We'll start with going form exponential to radical, since it may be easier to follow. For example,
[tex]x^{\frac{4}{3}[/tex] can be written, in radical form, as
[tex]\sqrt[3]{x^4}[/tex]. What happens is that the denominator of the fraction serves as the index (the number that sits in the bend of the radical) and the numerator serves as the power on the variable (or number, if that's the case). Let's look at another one:
[tex]4^{\frac{2}{3}[/tex] becomes
[tex]\sqrt[3]{4^2}=\sqrt[3]{16}=\sqrt[3]{8*2}=2\sqrt[3]2}[/tex]
And you can go the other way with it. For example,
[tex]\sqrt[5]{x^4}[/tex] becomes
[tex]x^{\frac{4}{5}[/tex], etc. Get it?
Answer:
When you're given a problem in radical form, you may have an easier time if you You can rewrite every radical as an exponent by using the following property — the top ... For example, 643/2 is easier if you write it as (641/2)3 = 83 = 512 rather than (643)1/2, Rewrite the entire expression using rational exponents.
log_(5)(x-4)=1-log_(5)(x-8)
Answer:
x = 3, x = 9
Step-by-step explanation:
When solving this problem, keep the general format of a logarithm in mind:
[tex]b^x=y\\log_b(y)=x[/tex]
Where, (b) represents the base, (x) is the exponent, and (y) is the evalutaor. Please note that others might use slightly different terminotoly than what is used in this answer.
One is given the following expression, and is asked to solve for the parameter (x);
[tex]log_5(x-4)=1-log_5(x-8)[/tex]
First, manipulate the exquestion such that all of the logarithmic expressions are on one side. Use inverse operations to do this.
[tex](log_5(x-4))+(log_5(x-8))=1[/tex]
Now use the Logarithmic Base Change rule to simplify. The Logarithmic Base Change rule states the following;
[tex]log_b(x)=\frac{log(x)}{log(b)}[/tex]
Remember, if no base is indicated in a logarithm, then the logarithm's base is (10). Apply the Logarithmic Base Change rule to this problem;
[tex]\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1[/tex]
Now remove the denominator. Multiply all terms in the equation by the least common denominator; ([tex]log(5)[/tex]) to remove it from the denominator on the left side.
[tex](\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1)*(log(5))[/tex]
[tex]log(x-4)+log(x-8)=log(5)[/tex]
All logarithms have the same base, the left side of the equation has the addition of logarithms. This means that one can apply the Logarithm product rule. The logarithm product rules the following;
[tex]log_b(x*y)=(log_b(x))+(log_b(y))[/tex]
This rule can be applied in reverse to simplify the left side of the equation. Rather than rewriting the product of logarithms as two separate logarithms being added, one can rewrite it as one logarithm getting multiplied.
[tex]log(x-4)+log(x-8)=log(5)[/tex]
[tex]log((x-4)(x-8))=log(5)[/tex]
Now used inverse operations to bring all of the terms onto one side of the equation:
[tex]log((x-4)(x-8))=log(5)[/tex]
[tex]log((x-4)(x-8))-log(5)=0[/tex]
Similar to the Logarithm product rule, the Logarithm quotient rule states the following;
[tex]log_b(x/y)=(log_b(x))-(log_b(y))[/tex]
One can apply this rule in reverse here to simplify the logarithms on the left side:
[tex]log((x-4)(x-8))-log(5)=0[/tex]
[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]
The final step in solving this equation is to use the Logarithm of (1) property. This property states the following:
[tex]log_b(1)=0[/tex]
When applying this property here, one can conclude that the evaluator must be equal to (1), therefore, the following statements can be made.
[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]
[tex]\frac{(x-4)(x-8)}{5}=1[/tex]
Inverse operations,
[tex]\frac{(x-4)(x-8)}{5}=1[/tex]
[tex](x-4)(x-8)=5[/tex]
[tex](x-4)(x-8)-5=0[/tex]
Simplify,
[tex](x-4)(x-8)-5=0[/tex]
[tex]x^2-12x+32-5=0[/tex]
[tex]x^2-12x+27=0[/tex]
Factor, rewrite the quadratic expression as the product of two linear expressions, such that when the linear expressions are multiplied, the result is the quadratic expression:
[tex]x^2-12x+27=0[/tex]
[tex](x-3)(x-9)=0[/tex]
Now use the zero product property to solve. The zero product property states that any number times (0) equals (0).
[tex]x=3,x=9[/tex]
Hello,
I suppose the question is solve for x.
[tex]\displaystyle log_5\ (a)=\dfrac{ln (a)}{ln (5)} \\\\log_5(x-4)=1-log_5(x-8)\\\\\dfrac{ln(x-4)}{ln(5)} =1- \dfrac{ln(x-8)}{ln(5)}\\\\ln(x-4)=ln(5)-ln(x-8)\\\\ln(x-4)+ln(x+8)=ln(5)\\\\ln((x-4)*(x-8))=ln(5)\\\\(x-4)*(x-8)=5\\\\x^2-12x+27=0\\\\\Delta=12^2-4*27=36=6^2\\\\x=9\ or\ x=3\\\\Sol=\{3,9\}\\[/tex]
For Moderators,
this is a mathematical resolution without any bla-bla sentences that you will easily find. (I can not do it sorry)
Shelly believes the honor roll students at her school have an unfair advantage in being assigned to the math class they request. She asked 500 students at her school the following questions: "Are you on the honor roll?" and "Did you get the math class you requested?" The results are shown in the table below:
Honor Roll - Not on Honor Role - Total
Received Math Class Requested 125 215 340
Didn't Get Math Class Requested 80 80 160
Total 205 295 500
Help Shelly determine if all students at her school have an equal opportunity to get into the math class they requested. Show your work, and explain your process for determining the fairness of the class assignment process.
Answer:
I believe this would be the answer?
Step-by-step explanation:
{2, 3, 4, 6, 8, 9, 10, 12}
WILL GIVE BRAINLIEST AND 30 POINTS!
PLEASE SHOW WORK!
f(x)=x2+10 and g(x)=|x|
Find (f+g)(2).
Answer:
14
Step-by-step explanation:
[tex]f(x) = {x}^{2} + 10 \\ \therefore \: f(2) = {2}^{2} + 10 \\ \therefore \: f(2) = 4 + 10 \\ \therefore \: f(2) = 14 \\ \\ g(x) = |x| \\ \therefore \:g(2) = |2| \\ \therefore \:g(2) = 2 \\ \\ f(2) + g(2) = 14 + 2 \\ \red{ \bold{(f + g)(2) = 14}}[/tex]
Step by step Explanation:
[tex]f(x) = x2 + 10g(x) = 1[/tex]
[tex](f + g)(2).[/tex]
Step 1
The equation is in standard form.
[tex]xf = 10gx + x2[/tex]Step 2
Divide both sides by x.
[tex] \frac{xf}{x} = \frac{10gx + x2}{x} [/tex]Step 3
Dividing by x undoes the multiplication by x.
[tex]f = \frac{10gx + x2}{x} [/tex]Step 4
Divide x 2 + 10 g x by x.
[tex]f = 10g + \frac{x2}{x} [/tex]My Answer is.
[tex]\color{green}f \ = \frac{10g + \frac{x2}{x} }{f€g} x2 = {14}^{x} [/tex]Solve the following pair of linear equations using substitution method
[tex] x-3y = 13[/tex]
[tex]x+2y=8[/tex]
Answer:
(10, - 1 )
Step-by-step explanation:
Given the 2 equations
x - 3y = 13 → (1)
x + 2y = 8 → (2)
Rearrange (1) making x the subject by adding 3y to both sides
x = 3y + 13 → (3)
Substitute x = 3y + 13 into (2)
3y + 13 + 2y = 8
5y + 13 = 8 ( subtract 13 from both sides )
5y = - 5 ( divide both sides by 5 )
y = - 1
Substitute y = - 1 into (3) for corresponding value of x
x = 3(- 1) + 13 = - 3 + 13 = 10
solution is (10, - 1 )
Can someone help me with this question
What is the other solution to the equation (Algebra ll) *URGENT*
Given:
The equation is:
[tex]3-2|0.5x+1.5|=2[/tex]
One solution of this equation is -2.
To find:
The another solution of the given equation.
Solution:
We have,
[tex]3-2|0.5x+1.5|=2[/tex]
It can be written as:
[tex]-2|0.5x+1.5|=2-3[/tex]
[tex]-2|0.5x+1.5|=-1[/tex]
Divide both sides by -2.
[tex]|0.5x+1.5|=0.5[/tex]
After removing the modulus, we get
[tex]0.5x+1.5=\pm 0.5[/tex]
Case I:
[tex]0.5x+1.5=0.5[/tex]
[tex]0.5x=0.5-1.5[/tex]
[tex]0.5x=-1[/tex]
Divide both sides by 0.5.
[tex]x=-2[/tex]
Case II:
[tex]0.5x+1.5=-0.5[/tex]
[tex]0.5x=-0.5-1.5[/tex]
[tex]0.5x=-2[/tex]
Divide both sides by 0.5.
[tex]x=-4[/tex]
One solution of the given equation is [tex]x=-2[/tex] and the another one is [tex]x=-4[/tex].
Therefore, the correct option is B.
11. Write a compound inequality that represents each situation. Graph your solution.
all real numbers that are greater than 8 but less than 8
85x<8
8 SXS 8
-8 < x <8
8
its the third choice
Find the measure of the indicated angle
Answer:
yes
Step-by-step explanation:
A parabola opens upward. The parabola goes through the point (3,-1),
and the vertex is at (2,-2).
Find the value of A for the parabola. Show your work. Use Part 1 and 2 to write the equation of the parabola.
Answer:
a=1
Step-by-step explanation:
Hopefully this helps :)
The equation of the parabola is: y = (x - 2)² - 2. Finding the value of A
The vertex of the parabola is at (2,-2). Since the parabola opens upward, the equation of the parabola will be of the form:
y = A(x - 2)² - 2
We can plug the point (3,-1) into this equation to find the value of A.
-1 = A(3 - 2)² - 2
Simplifying the right side of the equation, we get:
-1 = A - 2
Adding 2 to both sides of the equation, we get:
1 = A
Therefore, the value of A is 1.
Writing the equation of the parabola
The equation of the parabola is:
y = (x - 2)² - 2
To know more about parabola:
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Which of these is the equation of the new function?
Answer:
B: g(x) = -4(x + 3)^2
Step-by-step explanation:
When we shift to the left by a units
we have the new equation become
( x + 3)^2
Stretching by a factor of 4, we have it that;
4(x + 3)^2
reflecting over the x-axis means the y-axis value becomes negative
So we have
g(x) = -4(x + 3)^2
Which equation is NOT true?
Answer:
[tex]{ \bf{15x + 30 = 180}}[/tex]
Pls answer it with explanation
Answer:
x=24 y=131
Step-by-step explanation:
it is right answer
Answer:
x = 24, y = 131
Step-by-step explanation:
The sum of the 3 angles in Δ ABC = 180°
Sum the 3 angles and equate to 180
72 + 35 + 25 + 2x = 180 , that is
2x + 132 = 180 ( subtract 132 from both sides )
2x = 48 ( divide both sides by 2 )
x = 48
--------------------------------------------
Similarly in the lower triangle
25 + x + y = 180
25 + 24 + y = 180
49 + y = 180 ( subtract 49 from both sides )
y = 131