find the missing side plzzz helpppp

The current price of the mask is $1 per mask and there is expected demand of 6000 masks per week.

If the company plans to increase the price the demand for the masks will decrease.

Revenue  = 6000 * x

Total revenue will be  $6,000 if the price of mask is $1. If price of mask increase by 10% then quantity will be declined to 5850 masks [6000 - 150].

New price = $ 1 * 110% = $1.10

Revenue = 5850 masks * $ 1.10 = $6,435.

Then correct answer is Revenue will increase if price of mask is increased.

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Answer:

$5,102.05

Step-by-step explanation:

Present value of the car = $21,500

Present percentage value = 100% = 1

Percentage of Depreciation per year = 25% = 0.25

Years of depreciation = 5 years

The value of the car after 5 years = Present value of the car (Present percentage value - Percentage of Depreciation per year)^Years of depreciation

= 21,500(1 - 0.25)^5

= 21,500(0.75)^5

= 21,500(0.2373046875)

= 5,102.05078125

Approximately,

The value of the car after 5 years = $5,102.05

Answer:

19. 11

21. 119

Step-by-step explanation:

19.

(-5)² - [4(-3 ∙ 2 + 4)² + 3] + 5 =

= (-5)² - [4(-6 + 4)² + 3] + 5

= (-5)² - [4(-2)² + 3] + 5

= (-5)² - [4(4) + 3] + 5

= (-5)² - [16 + 3] + 5

= 25 - 19 + 5

= 6 + 5

= 11

21.

5 - 8[6 - (3 ∙ 2 - 8 + 2|4 ÷ -2 + (-3)| - 4) - 7 · 2] - 3² · (-2) =

= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-2 + (-3)| - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-5| - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - (3 ∙ 2 - 8 + 2(5) - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - (6 - 8 + 10 - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - (-2 + 10 - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - (8 - 4) - 7 · 2] - 3² · (-2)

= 5 - 8[6 - 4 - 7 · 2] - 3² · (-2)

= 5 - 8[6 - 4 - 14] - 3² · (-2)

= 5 - 8[2 - 14] - 3² · (-2)

= 5 - 8[-12] - 3² · (-2)

= 5 - (-96) - 9 · (-2)

= 5 + 96 + 18

= 101 + 18

= 119

Answer:

Figures A,D are polygons.

Reason:

Polygon is a closed figure with atleast three strange lines and angles.

Answer:

13/50

Step-by-step explanation:

#of original states/# of states now

The fraction of the states are original states is [tex]\frac{13}{50}[/tex].

A  numerical value that expresses a part of a whole is called a fraction.

According to the given question.

Number of original states before = 13

Number of original states now = 50

Therefore, the fraction of original states

= number of original states before/ number of original states now

=[tex]\frac{13}{50}[/tex]

Hence, the fraction of the states are original states is [tex]\frac{13}{50}[/tex].

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Answer:

The length is 12metres, the width is 6metres

Step-by-step explanation:

Suppose the width is x, the length is x+6

The square is 72. The square of rectangular field is equal to product of length and width.

so x(x+6)=72

x^2+6x-72=0

a=1 b=6 c=-72

D= b^2-4ac= 6*6+288= 36+288= 324

sqrtD= 18

x1= (-b-sqrtD)/2a=(-6-18)/2= -12 (it is negative, but width is only positive. So this root doesn't match)

x2=(-b+sqrtD)/2a= (-6+18)/2= 12/2=6 - the width

The length is 6+6=12

Answer:

Step-by-step explanation:

Given,

Radius of a circle = 17m

Therefore,

Area in terms of pi

[tex] = \pi {r}^{2} [/tex]

[tex] = \pi \times 17m \times 17m[/tex]

[tex] = 289\pi {m}^{2} (ans)[/tex]

Answer:

A = 289π m²

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius ) , then

A = π × 17² = 289π m²

Answer:

Equation A is true; Equation B is not

Step-by-step explanation:

There is a standard formula for the "difference of cubes" that is:

x^3 - y^3 = (x - y)(x^2 + xy + y^2)

and this perfectly matches equation A.

Equation B has the square of n (n^2) on the left side but not on the right side.  Thus this is not an identity.

Answer:

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get

[tex]x-12=\sqrt{x}[/tex] and then square both sides to get

[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:

[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex]  If 16 is a solution, then this statement will be mathematically true.

[tex]\frac{7}{4+3}=1[/tex]  and   [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:

[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex]  We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

Answer:

x =  16

Step-by-step explanation:

[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16            {(-9)+(-16) = -25  & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0     ; x - 9 = 0

x = 16          ; x = 9

x = 9 is  an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]

       [tex]= \frac{0}{3+3}[/tex]

        = 0 ≠ RHS

So, x = 16 is the only  solution

Answer:

D

Step-by-step explanation:

Slope is (1/8) and y intercept can be found by setting x=0.

Answer:

Multiply 800 by 1.022^7 because 1.022^(n-1)

Step-by-step explanation:

Series and sequences.

Have a good day and I'll hope you get to good score for this homework

Answer:

false

Step-by-step explanation:

i'm not sure if this is a true or false question, but if so, it is false

the x-axis has a positive side and a negative side, so the coordinate isn't necessarily negative. it could also be zero if the point is at the origin

hope this helps!

Answer:

[tex]\displaystyle lne^4 = 4[/tex]

General Formulas and Concepts:

Algebra II

Natural Logarithms ln and Euler's number e

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle lne^4[/tex]

Step 2: Evaluate

Answer:

Area: 24 sq units

Step-by-step explanation:

Area of a rectangle formula:

A = 0.5bh

Given:

b = 6

h = 8

Work:

A = 0.5bh

A = 0.5(6)(8)

A = 3(8)

A = 24

Answer: A = 24 unit²

Concept:

The area is the quantity that expresses the extent of a two-dimensional region, shape, or planar lamina, in the plane.

Area (triangle) = bh/2

b = base

h = height

Solve:

Given information

1 unit = 1 grid

b = 6 grids = 6 × 1 = 6 units

h = 8 grids = 8 × 1 = 8 units

Given expression

A = bh / 2

Substitute values into the expression

A = (6) (8) / 2

A = 48 / 2

A = 24 units²

Hope this helps!! :)

Please let me know if you have any questions

Answer:

-11f +15

Step-by-step explanation:

-f-5(2f-3)

Distribute

-f -10f +15

Combine like terms

-11f +15

Answer:

B

Step-by-step explanation:

We apply distributive property first on the 2f thingie.

The negative 5 is applied on both the 2f and the negative 3 to get

-10f + 15 since two negatives equals a positive in math.

Then we subtract an "f" from the current data to get your answer since the original question was

-f -5 ( 2f - 3 )

So we get

-11f + 15 or B.

Answer:

hello,

answer C

Step-by-step explanation:

As |a| ≥0,

f(|a|)=|a|+5

Answer:

8.44 m

Step-by-step explanation:

SohCahToa is a good way to remember that Sin = opposite/hypotenuse, Cosine = adjacent/hypotenuse and Tangent = opposite/adjacent. In this case, we have to use tangent. So tan 37° = x/11.2. Multiply both sides by 11.2 and you get tan 37° × 11.2 = x; The height of the school is x so the height of the school is 8.44 m

Answer:

0.4

Step-by-step explanation:

Fraction =2/5

In decimal =0.4

Answer:

x = 0

y = -2

Step-by-step explanation:

2304.06 is written in expanded form

4 is unit place. So, 4 *10⁰ = 4 * 1 = 1    {Any integer to the power of 0 is 1}

x = 0

6 is hundredth place = 6 * 1/100 = 6*10⁻²

y= -2

Answer:

so you multiply the 13 by 12. Then divid 12 by 2 to get 6 as the radius then use a calculator and type in 2(PIE SYMBOL) R. R=radius then whatever number you get cut it in half then subtract it from 13x12.

Answer:

Yes ,because of SAS similarity theorem

Step-by-step explanation:

In ΔYOM , ΔTON

∠YOM = ∠TON        

[tex]\frac{OY}{OT}=\frac{96}{84}=\frac{8}{7}\\\\\frac{OM}{ON}=\frac{104}{91}=\frac{8}{7}[/tex]

SAS similarity theorem

Answer:

Hello,

Answer C

Step-by-step explanation:

[tex]\dfrac{96}{104}=? \dfrac{84}{91} \\\\Calculating\ crossed\ products\\96*91=8736\\104*84=8736\\they\ are\ equals\\\\\\\dfrac{YO}{MO} =\dfrac{OT}{ON} \\\\\\Triangles\ are\ similar\ because \ SAS \theorem\\\\[/tex]

Answer:2 and 6

Step-by-step explanation:

Given

In 4 years Craston's age will be the same as Terrins age is now

Suppose the present of Craston's and Terrins are [tex]x[/tex] and [tex]y[/tex] respectively

According to the question

[tex]\Rightarrow x+4=y\\\Rightarrow y-x=4\quad \ldots(i)[/tex]

In 2 years Terrin will be twice as old  as craston

[tex]\Rightarrow (y+2)=2(x+2)\\\Rightarrow y-2x=4-2\\\Rightarrow y-2x=2\quad \ldots(ii)\\[/tex]

Solving (i) and (ii) we get

[tex]x=2,y=6[/tex]

Thus, the present age of Craston and Terrins are [tex]2[/tex] and [tex]6[/tex]

The equation in point slope form is y - 6 = 2(x + 3)

This is from the general point slope template of [tex]y - y_1 = m(x - x_1)[/tex]

The m is the slope, which in this case is m = 2. The [tex](x_1,y_1)[/tex] is the point the line goes through. In this case, [tex]x_1 = -3 \text{ and } y_1 = 6[/tex]

If you were to solve that equation in bold for y, then you should get y = 2x+12 which is now in y = mx+b form, aka slope intercept form.

8m+4m-6m-12

12m-6m-12

12m-6m

-6m

Answer:

its 80 meters longs

Step-by-step explanation:

if it is wrong just go look it up

Answer: 48 dimes, 15 quarter

Step-by-step explanation:

Given

The money is of the net worth of [tex]\$8.55[/tex]

If there is total of 63 coins

Suppose there are [tex]x[/tex] dimes and [tex]y[/tex] quarter

[tex]\therefore x+y=63\quad \ldots(i)\\\Rightarrow 0.1x+0.25y=8.55\quad \ldots(ii)[/tex]

Solve (i) and (ii)

[tex]x=48,y=15[/tex]

Thus, there are 48 dimes and 15 quarters

Answer: 1/32

Step-by-step explanation:

Answer:

answer of this question is A