Find the product of 0.3×0.23.

Answers

Answer 1

Answer:

0.069

Step-by-step explanation:

0.3*0.23=0.069


Related Questions

Bias can _____ be completely eliminated. a) always b)sometimes c) never

Answers

Answer:

the answer is c.

Step-by-step explanation:

c is the only reasonable option.

Evaluate the function below at x=7. Then enter your solution rounded up to 2 decimal places. 1500•1.09^x

Answers

Answer:

Value of the function will be 2742.06

Step-by-step explanation:

Given function is,

f(x) = 1500(1.09)ˣ

By substituting the value of x we can find the value of the given function.

For x = 7,

f(7) = 1500(1.09)⁷

     = 1500(1.828)

     = 2742.0587

     ≈ 2742.06

Value of the function will be 2742.06

Which one of these relations are functions ?


Please helpppp fast

Answers

Answer:

the 4th and 6th one

Step-by-step explanation:

A function is when there are x- and y-values but each x value has only 1      y-value

Simple: If the x-value is repeated its not a function

Answer:

Step-by-step explanation:

1,2,3

Convert the following: 2 liters is equivalent to ounces (rounded to the nearest hundredth)

Answers

Answer:

67.63 oz

Step-by-step explanation:

1 liter = 33.814 oz

2 litres = 2 x 33.814 oz = 67.628 oz

A car can cover a distance of 522 km on 36 liters of petrol. How far can it travel on 14 liters of petrol?

Answers

522km / 36= 14.5km PER litre

14.5 x 14= 203

John used 1 3/4 kg os salt to melt the ice on the sidewalk. He then used another 3 4/5 kg on the driveway. How much salt did he use in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINIEST AND PLEASE EXPLAIN HOW YOU GOT YOUR WORK.

Answers

Answer:

111/20 = 5.55

Step-by-step explanation:

He used a total of 1  3/4 and  3  4/5 salt.

Convert both these mixed numbers into fractions.

=> 7/4 + 19/5

Take the LCM of the denominators

=> 35/20 + 76/20

Add the numerators

=> 111/20 = 5.55

He used a total of 111/20 or 5.55 kgs of salt.

Suppose y varies jointly as x & z. If y = -180 when z = 15and x = -3,then find y when x = 7 and z = -5.

Answers

Answer:

y = - 140

Step-by-step explanation:

Given that y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = - 180 when z = 15 and x = - 3, thus

- 180 = k × - 3 × 15 = - 45k ( divide both sides by - 45 )

4 = k

y = 4xz ← equation of variation

When x = 7 and z = - 5, then

y = 4 × 7 × - 5 = - 140

-7p+2(5p-8)=6(p+6)-7

Answers

Answer:

-15

Step-by-step explanation:

-7p+10p-16=6p+36-7

3p-16=6p+29

3p-6p=29+16

-3p=45

p=45/-3

p=-15

P=5

-7p+2(5p-8)=6(p+6)-7
Distribute
-7p+10p-16=6p+36-7
Add -7p and 10p together
3p-16=6p+36-7
Subtract 7 from 36
3p-16=6p+29
+6p (on both sides)
9p-16=29
+16 (on both sides)
9p=45
Divide both sides by 9
P=5

Greyson completes a dive from a
cliff 75-feet above a river. It takes
him only 1.5 seconds to hit the
water and then another 0.5
second to descend 10 feet into the river

what’s the x axis and y axis?

Answers

Answer: y: height, x: time.

Step-by-step explanation:

The data we have is:

The initial position of Greyson is 75ft above the river.

He needs 1.5 seconds to hit the water, and other 0.5s tho reach the bottom of the river.

Then we have a relationship of height vs time.

The y axis will represent the heigth of Greyson, and the x-axis will represent the time, such that at the time x = 0 seconds, we have y = 75ft

La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el peso del auto y el cuadrado de la velocidad del mismo. Supongamos que 400 libras de fuerza evitan que un auto que pesa 1600 libras derrape en una curva cuyo radio mide 800 si viaja a 50mph. ¿Cuánta fuerza evitaría que el mismo auto derrapara en una curva cuyo radio mide 600 si viaja a 60mph ?

Answers

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

Helppp thanksss!!!!!!

Answers

Answer:

1 mile

Step-by-step explanation:

in 20 minutes Stuart has gone 1 mile

in 20 minutes Brandy has gone 4 miles

therefore they meet 1 mile from Stuart's house

Answer:

1 mile

Step-by-step explanation:

Pick out the set of numbers that is not Pythagorean triple
9 40 46
16 30 34
10 24 26
50 120 130

Answers

Answer:

[tex]\huge\boxed{9,40,46}[/tex]

Step-by-step explanation:

Let's check it using Pythagorean Theorem:

[tex]c^2 = a^2 + b^2[/tex]

Where c is the longest sides, a and b are rest of the 2 sides

1) 9 , 40 , 46

=> [tex]c^2 = a^2 + b^2[/tex]

=> [tex]46^2 = 9^2 + 40^2[/tex]

=> 2116 = 81 + 1600

=> 2116 ≠ 1681

So, this is not a Pythagorean Triplet

2) 16, 30 and 34

=> [tex]c^2 = a^2 + b^2[/tex]

=> [tex]34^2 = 16^2 + 30^2[/tex]

=> 1156 = 256 + 900

=> 1156 = 1156

No need to check more as we've found the one which is not a Pythagorean Triplet.

Answer:

[tex] \boxed{ \huge{ \boxed{ \sf{ \blue{9 , \: 40 \:, 46 \: }}}}}[/tex]

Option A is the correct option.

Step-by-step explanation:

1. Let h , p and b are the hypotenuse , perpendicular and base of a right - angled triangle respectively.

From Pythagoras theorem,

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

Here, we know that the hypotenuse is always greater than perpendicular and base,

h = 46 , p = 40 , b = 9

⇒[tex] \sf{ {46}^{2} = {40}^{2} + {9}^{2} }[/tex]

⇒[tex]2116 = 1600 + 81[/tex]

⇒[tex] \sf{2116  ≠ 1681}[/tex]

Thus , the relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is not satisfied by h = 46 , p = 40 , b = 9

So, The set of numbers 9 , 40 , 46 is not Pythagorean triple.

------------------------------------------------------

2. 16 , 30 , 34

h = 34 , p = 30 , b = 16

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {34}^{2} = {30}^{2} + {16}^{2} }[/tex]

⇒[tex] \sf{1156 = 900 + 256}[/tex]

⇒[tex] \sf{1156 = 1156}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 34 , p = 30 , b = 16

So, the set of numbers 16 , 30 , 34 is a Pythagorean triple.

------------------------------------------------------

3. 10, 24 , 26

h = 26 , p = 24 , b = 10

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {26}^{2} = {24}^{2} + {10}^{2} }[/tex]

⇒[tex] \sf{676 = 576 + 100}[/tex]

⇒[tex] \sf{676 = 676}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and h i.e h = 26 , p = 24 , b = 10

So, the set of numbers 10, 24 , 26 is the Pythagorean triple.

-----------------------------------------------------

4. 50 , 120 , 130

h = 130 , p = 120 , b = 50

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {130}^{2} = {120}^{2} + {50}^{2} }[/tex]

⇒[tex] \sf{16900 = 14400 + 2500}[/tex]

⇒[tex] \sf{16900 = 16900}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 130 , p = 120 , b = 50

So, the set of numbers 50, 120 , 130 is the Pythagorean triple.

-----------------------------------------------------

In this way, to satisfy the Pythagoras Theorem , the hypotenuse ( h ) , perpendicular ( p ) and the base ( b ) of a right - angles triangle should have the particular values in order. These values of h , p and b are called Pythagorean triple.

Hope I helped!

Best regards!!

Prove: The square of the sum of
two consecutive integers is odd.

Answers

[tex](2n+1)^2=4n^2+4n+1[/tex] therefore, the first blank is 1.

[tex]4n^2+4n+1=2(2n^2+2n)+1[/tex] therefore, the two other blanks are both 2.

The number in the proof ''The square of the sum of two consecutive integers is odd'' is 2 and 2.

To prove that, The square of the sum of two consecutive integers is odd.

The expression to prove is,

Let us assume that two consecutive integers are n and (n + 1).

Hence, the expression is written as,

[n + (n + 1)]² = (2n + 1)²

= (2n)² + 2 × 2n × 1 + 1²

= 4n² + 4n + 1

= 2 (2n² + 2n) + 1

= odd

Therefore, the number in the blanks are 2 and 2.

To learn more about the Number system visit:

https://brainly.com/question/17200227

#SPJ4

another find the equation of this line, please help meeee!

Answers

Answer:

y = 3/4x + 2

Step-by-step explanation:

to find the slope its rise over run and you go up 3 and run 4 to get 3/4. then you just look on the y axis and see that the line passes 2. so that is the answer

help with geometry pls

Answers

Answer:

option 2 must be the correct answer because the two figure are congruent figure.

Answer:

B

Step-by-step explanation:

Since Δ ABC ~ Δ DEF then the ratios of corresponding sides are equal, that is

[tex]\frac{AB}{DE}[/tex] = [tex]\frac{BC}{EF}[/tex] = [tex]\frac{CA}{FD}[/tex] → B

(x-1)(x+2)(x-3)(x+7)(x-5)/2x-2

=0

What can x be?

Answers

Answer:

see below

Step-by-step explanation:

Multiplying the equation by 2x - 2 on both sides to cancel out the denominator gives us (x - 1)(x + 2)(x - 3)(x + 7)(x - 5) = 0. Using Zero Product Property and setting each factor to 0, we get:

x - 1 = 0 or x + 2 = 0 or x - 3 = 0 or x + 7 = 0 or x -  5 = 0

x = 1, x = -2, x = 3, x = -7, x = 5

Unfortunately, x cannot be 1 as the numerator would become 0 and then the expression on the left side would become undefined so the final answer is x = -2, x = 3, x = 7, x = 5.

please help me you will recieve 5 stars IF RIGHT ANSWER !

Answers

Answer:

[tex]\huge\boxed{\frac{7}{8}}[/tex]

Step-by-step explanation:

[tex](\frac{49 }{64})^{1/2}[/tex]

=> [tex](\frac{7^2}{8^2} )^{1/2}[/tex]

=> [tex]\frac{7^{2*1/2}}{8^{2*1/2}}[/tex]

=> [tex]\frac{7}{8}[/tex]

Answer:

Below

Step-by-step explanation:

You should now that:

● (m/n)^(1/2) = √(m/n)

So:

● (49/64)^(1/2) = √(m/n)

You shoukd now also that:

● √(m/n) = √m / √n

So:

● √(49/64) = √49/√64

Notice that 64 = 8^2 and 49 = 7^2

● √49 / √64 = √(7^2)/√(8^2) = 7/8

So the answer is 7/8

If you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows, the total number of marshmallows is given by the expression 5(x+12). Identify an equivaler expression

Answers

The answer of the question is 60.

Answer:

The expression that is equivalent to the given expression is:

              5x+60

Step-by-step explanation:

It is given that:

if you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows.

so, let x be the initial number of marshmallows in each bag and now 12 are added to each bag this means that the number of marshmallows in each bag is:  

x+12

Hence, total number of marshmallows in 5 bags is:

5(x+12)=5×x+5×12

5(x+12)=5x+60

Hence, the answer is:

5x+60

Feel free to brainliest :)

Martha estimated there were 86 marbles in a jar for a contest. The actual number of marbles in the jar was 108. What was the percent error of Martha's estimation?

Answers

Answer:

Roughly 20.4%

Step-by-step explanation:

Use the formula of percent of error:

| Actual number - Guess / Actual number | (100)

The actual number is 108 and the guessed number is 86:

| 108 - 86 / 108 | (100)

= | 22/108 | (100)

= | 0.2037037037 | (100)

The vertical lines indicate absolute value.  This means that anything inside of it must be turned into its positive form.  Since it is already positive, just take the signs away:

0.2037037037(100)

≈ 0.204(100)

= 20.4

Turn this into a percent:

20.4%

Martha's percent of error is 20.4%

Please tell me if I was right or not.  I really hope this helps!

What is the median of the following set of measurements?
"22 kg, 24 kg, 28 kg, 19 kg, 27 kg",
The median of the measurements is kg.

Answers

Answer:

24 kg

Step-by-step explanation:

The median can be found by putting the numbers in order and then finding the middle value.

In order from least to greatest:

19, 22, 24, 27, 28

24 is the middle value

So, 24 kg is the median.

Answer:

24 kg

Step-by-step explanation:

The median is the number in the middle of the data set. To find the median, arrange the numbers from least to greatest, then locate the middle number.

1. Arrange the numbers from least to greatest

Numbers: 22 kg, 24 kg, 28 kg, 19 kg, 27 kg

Least to greatest: 19 kg, 22 kg, 24 kg, 27 kg, 28 kg

2. Locate the middle number

Cross one number off each end of the set until the middle is reached.

19 kg, 22 kg, 24 kg, 27 kg, 28 kg

Cross off 19 and 28

22 kg, 24 kg, 27 kg

Cross off 22 and 28

24 kg

The middle number has been reached.

median= 24 kg

The median of the measurements is 24 kilograms.

Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to know how many
cars she installed axles on. You can write an equation that relates the total number of cars, the total number of axles, and the number of axles
installed per car. This equation will have two known quantities and one unknown quantity.
Part A
Write an equation forj, the number of cars Jessie installed axles in.
BIŲ X, Font Sizes
EEE 를 를
!!!
Characters used: 0 / 15000

Answers

Answer:

             Jessie instaled axels on 23 cars              The equation:   2·j = 46  

Step-by-step explanation:

j    -  total number of cars she installed axles on

2    - number of axles she installed on one car

2·j   - total number of axles she installed on

46   - total number of axles she installed on

2·j = 46              {divide both sides by 2}

j = 23

what is y ? x=1 y=? y=3x-7

Answers

Answer:

-4.

Step-by-step explanation:

y = 3x - 7; x = 1.

y = 3(1) - 7

= 3 - 7

= -4

Hope this helps!

Answer:

y = - 4

Step-by-step explanation:

y=3x-7

Let x =1

y = 3*1 -7

y = 3-7

y = - 4

Hellllllllllppppppppppp please

Answers

Answer:

As x decreases in value.f(x) decreases in value.......

Can you help Jorge organize the results into a two-way frequency table? Please answer this ASAP

Answers

Answer:

The table is attached!

Step-by-step explanation:

6 students play both musical instrument and a sport3 students play neither a musical instrument nor a sport14 students in total play a sport

Given: There are 24 students in the class

The number of students that does not play a sport is 24 - 14 = 10

The number of students that does not play a musical instrument but play a sport = 14 - 6 = 8

The frequency table thus is attached below:

Find the distance between points K(−1, −3) and L(0, 0). Round to the nearest tenth.

Answers

Answer:

d = √10

Step-by-step explanation:

[tex]K(-1, -3) , L(0, 0).\\\\d=\sqrt{((x_2-x_1)^2+ (y_2-y_1)^2) } \\\\x_1 =-1\\\\y_1 =-3\\\\x_2 =0\\\\y_2 =0 \\\\d = \sqrt{(0-(-1))^2+(0-(-3))^2}\\\\ d = \sqrt{(0+1)^2+(0+3)^2}\\\\ d = \sqrt{(1)^2 + (3)^2}\\\\ d = \sqrt{1 + 9}\\\\ d = \sqrt{10} \\[/tex]

Answer:

[tex]\huge\boxed{|KL|=\sqrt{10}\approx3.2}[/tex]

Step-by-step explanation:

METHOD 1:

The formula of a distance between two points (x₁; y₁) and (x₂; y₂):

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We have K(-1; -3) and L(0; 0). Substitute:

[tex]|KL|=\sqrt{(0-(-3))^2+(0-(-1))^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}}[/tex]

METHOD 2:

Look at the picture.

We have the right triangle with the legs 3 and 1.

Use the Pythagorean theorem:

[tex]leg^2+leg^2=hypotenuse^2[/tex]

substitute:

[tex]3^2+1^2=|KL|^2\\\\|KL|^2=9+1\\\\|KL|^2=10\to|KL|=\sqrt{10}[/tex]

Three whole numbers have an HCF of 3 and an LCM of 180. Two of the numbers are 45 and 60. Find the third number.

Answers

Answer:

Step-by-step explanation:

45=3×3×5

60=2×2×3×5

L.C.M=180

2| 180

2|90

3|45

3|15

3|5

180=2×2×3×3×5

third number=2×3=6

or 2×2×3=12

or2×3×3=18

or 2×2×3×3=36

so third number can be one of  6,12,18,36

Use the distributive property to write an expression that is equivalent to 1/2 (8y - x - 12).​

Answers

Answer:

4y - 0.5x - 6

Step-by-step explanation:

1/2 (8y - x - 12)

= (8y * [1/2]) - (x * [1/2]) - (12 * [1/2])

= (8y/2) - (x/2) - (12/2)

=  4y - 0.5x - 6

Tell me if I got it wrong! Hope this helps!

Answer:

4y+1/2x+6

Step-by-step explanation:

uh nvm someone already answered my bad

Solve the equation for X (If possible please show work)

Answers

Answer:

the correct answer is x=5

B) What is the value of f(n-1)?

Answers

Answer:

Add information

Step-by-step explanation:

According to mu understanding, this is the part (B) of the question. If you could provide the first part, I can complete it because some useful information is left out.

An owner of Honda City car sells his car at a price of RM 7.50,000 with a loss present of 12.5%. Then find the price at which he purchased the car and also find the loss suffered by the owner.


Answers

Answer:

Cost = RM 857143

Loss = RM 107143

Step-by-step explanation:

Given:

Selling price SP = RM 750000Loss% = 12.5Cost price CP = x

Cost price is found as:

SP = CP - 12.5%750000 = x - 12.5%750000= x*(100-12.5)/100750000= 0.875xx= 750000/0.875x≈ RM 857143

Loss is:

RM 857143 - 750000 = RM 107143

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