find the radius of a circle that has a circumference of 16

Answer:

Area = 14.8

Step-by-step explanation:

Area = 5/2 + a^2*sqrt(5 + 2 sqrt(5) )

This formula given the side length, calculates the area.

a = 2

Area = 2.5 + 2^2 * sqrt(5 + 2*sqrt(5) )

Area = 2.5 + 4 * sqrt(5 + 2*2.236)

Area = 2.5 + 4* sqrt(5+ 4.4721)

Area = 2.5 + 4*sqrt(9.4721)

Area = 2.5 + 4*3.0776

Area = 2.5 + 12.3107

Area = 14.8107

Answer:

A ≈ 30.8 m2

Step-by-step explanation:

Answer:

<5 and <6 are supplementary angles

<1 and <6 are vertical angles

Answer:

W

Step-by-step explanation:

I done it before

Answer:

given values are:

1200 = 20×30 + 1/2 × 30²a

1200= 600 + 1/2 × 900a

600 = 450a

a = 600 / 450

a = 1.33 m/s²

v² = 20² +2 × 1.33 × 1200

v²= 400 + 3192

v = √3592

v = 59.9 ≈ 60 m/s

Answer:

35

Step-by-step explanation:

48-15÷(3×5)+12

48-15÷15+12

48-1+12

59

Answer:

Solution given:

f(x)=2x²-5

g(x)=3x+3

now

(f-g) (x)=?

we have

(f-g)(x)=f(x)-g(x)

Answer:

[tex]2x^{2} - 3x - 8[/tex]

Step-by-step explanation:

Step 1:  Define what (f-g)(x) means

(f-g)(x) means that we have two different functions, f(x) and g(x).  (f-g)(x) is a shorter way of writing f(x) - g(x).  Therefore you just plug in the equations and combine like terms.

Step 2:  Find (f-g)(x)

[tex]f(x) = 2x^{2} - 5[/tex]

[tex]g(x) = 3x + 3[/tex]

[tex](f-g)(x) = 2x^{2} - 5 - (3x + 3)[/tex]

[tex](f-g)(x) = 2x^{2} - 5 - 3x - 3[/tex]

[tex](f-g)(x) = 2x^{2} - 3x - 8[/tex]

Answer:  [tex]2x^{2} - 3x - 8[/tex]

Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2) , Given volume and lateral area: r = 2 * V / A_l , Given base area: r = √(A_b / (2 * π)) , Given lateral area and total area: r = √((A - A_l) / (2 * π)) .

Answer:

See below.

Step-by-step explanation:

Call the sum of the first n terms S.

S = a + ar + ar^2 + ar^3 + ... + ar^(n -1)

Multiply both sides by r.

Sr = ar + ar^2 + ar^3 + ar^4 + ... + ar^n

No subtract S - Sr.

      S =  a + ar + ar^2 + ar^3 + ar^4 + ... + ar^(n -1)

(-)    Sr =       ar + ar^2 + ar^3 + ar^4 + ... + ar^(n - 1) + ar^n

-------------------------------------------------------------------

  S - Sr = a - ar^n

S(1 - r) = a(1 - r^n)

S = a(1 - r^n)/(1 - r)

S = a(r^n - 1)/(r - 1)

a + ar + ar^2 + ar^3 + ... + ar^(n -1) = a(r^n - 1)/(r - 1)

Answer:

it's the 3rd option

Step-by-step explanation:

f(x) 0 over the intervals (–∞ –3)

Hope it's right

============================================================

Explanation:

We'll use the distance formula here. Rather than compute the distance d based on two points given, we'll go in reverse to use the given distance d to find what the coordinate must be to satisfy the conditions.

We're given that d = 5

The first point is [tex](x_1,y_1) = (5,2)[/tex] and the second point has coordinates of [tex](x_2,y_2) = (x,5)[/tex] where x is some real number.

We'll plug all this into the distance formula and solve for x.

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\5 = \sqrt{(5-x)^2+(2-5)^2}\\\\5 = \sqrt{(5-x)^2+(-3)^2}\\\\5 = \sqrt{(5-x)^2+9}\\\\\sqrt{(5-x)^2+9} = 5\\\\(5-x)^2+9 = 5^2\\\\(5-x)^2+9 = 25\\\\(5-x)^2 = 25-9\\\\(5-x)^2 = 16\\\\5-x = \pm\sqrt{16}\\\\5-x = 4 \ \text{ or } \ 5-x = -4\\\\-x = 4-5 \ \text{ or } \ -x = -4-5\\\\-x = -1 \ \text{ or } \ -x = -9\\\\x = 1 \ \text{ or } \ x = 9\\\\[/tex]

This means that if we had these three points

Then segments AB and AC are each 5 units long.

Option B is 1/3 + 1/4.

1/3 + 1/4 is equal to 7/12.

Here, we have,

To find the sum of 1/3 and 1/4, you need to have a common denominator.

The common denominator of 3 and 4 is 12.

To make the fractions have the same denominator, you can convert them as follows:

1/3 = (1/3) * (4/4) = 4/12

1/4 = (1/4) * (3/3) = 3/12

Now that both fractions have a denominator of 12, you can add them together:

1/3 + 1/4 = 4/12 + 3/12 = (4+3)/12 = 7/12

Therefore, 1/3 + 1/4 is equal to 7/12.

now, from the given options, we have,

in option B. it is indicating that,

2/6 + 1/4

=> 1/3 + 1/4.

Hence, Option B is 1/3 + 1/4.

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Answer:

300 raisins

Step-by-step explanation:

sum the parts of the ratio, 3 + 27 = 30 parts

Divide the total by 30 for the value of one part of the ratio.

3000 ÷ 30 = 100 ← value of 1 part of the ratio , then

3 parts = 3 × 100 = 300 ← number of raisins in a box

Answer:

7a²b²(a - 2b)

Step-by-step explanation:

Given

7a³b² - 14a²b³ ← factor out 7a²b² from each term

= 7a²b²(a - 2b)

Answer:

13/9

Step-by-step explanation:

Given

5/9 + 8/9

Both fractions have the same denominator.

Therefore, pick one of the denominator and add the numerators

5/9 + 8/9

= (5+8) / 9

= 13/9

5/9 + 8/9 = 13/9

Answer:

Step-by-step explanation:

r = d/2

r = 2.4 m/2 = 1.2

h = 1.8

pi = 3.14

Volume = pi * r^2 * h

Volume = 3.14 * 1.2^2 * 1.8

Volume = 8.139

Volume = 8 to the nearest m^3

Mark Brainliest if correct:

x = -2, 9

Step-by-step explanation:

x2: x + 2 = 0

x = -2

x1: x - 9 = 0

x = 9

x = -2, 9

Step-by-step explanation:

a is the answer if is wrong I'm sorry

Answer:

The answer is -51146

Step-by-step explanation:

Just substract simple

[tex] \large\color{lime}\boxed{\colorbox{black}{Answer : - }}[/tex]

We know that, in ∆ABC,

∠A+∠B+∠C = 180°

But the triangle is right angled at C

ie., ∠C = 90°

Therefore, ∠A+∠B+ 90° = 180°

⇒ ∠A + ∠B = 90°

Therefore, cos(A + B) = cos 90º = 0

Answer:

Step-by-step explanation:

[tex]\displaystyle \Large \boldsymbol{} \tt a) \ 3-2x=3(x+4)-x-1\\\\3-2x=3x+12-x-1 \\\\3-12+1=3x+2x-x \\\\4x=-8 \\\\\boxed{ \tt x=-2} \\\\\\b) \ 5x\underline{(x-1)}-4\underline{(x-1)}=0 \\\\\\(5x-4)(x-1)=0 \Longrightarrow \boxed{ \tt x_1=0.8 \ \ ; \ \ x_2=1}[/tex]

Step-by-step explanation:

(-1,0),m=2

(1-7),m=12

m=-4,(-1,-4)

Answer:

A = 216.24 km²

Step-by-step explanation:

Answer:

domain : {3,4,6}

range: {1,5,9}

Answer:

5•362165924

Step-by-step explanation:

first make root of 32-6=5•099019514

then make root of 2+root2=1•84--

then divide upper by lower part answer comes

or

root32-6=root26

root 2+root 2=2root2

root26/root2root2

ans=3•0318---

Answer:

[tex] \frac{ \sqrt{32} - 6 }{ \sqrt{2} + \sqrt{2} } \\ \frac{ \sqrt{16 \times 2} - 6}{2 \sqrt{2} } \\ \frac{4 \sqrt{2} - 6}{2 \sqrt{2} } \\ \frac{2(2 \sqrt{2} - 3) }{2 \sqrt{2} } \\ \frac{2 \sqrt{2} - 3}{ \sqrt{2} } \\ thnk \: you[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

Let r, c, h represent the numbers of meals eaten in a restaurant, car, and at home, respectively. The problem statement tells us of the relations ...

  r + c + h = 193

  -r + c + h = 15

  r + 0c -h = 30

Add the last two equations:

  (-r +c +h) +(r -h) = (15) +(30)

  c = 45

Add the first two equations:

  (r + c + h) +(-r + c + h) = (193) +(15)

  2c +2h = 208

  h = 104 -c = 59 . . . . solve for h, substitute for c

The last equation can be used to find r.

  r = 30 +h = 30 +59 = 89

89 meals are eaten in a restaurant; 45 meals in a car; and 59 at home.

Step-by-step explanation:

we see, for x=-1 we get 3³

x=0 we get 3²

x=1 we get 3¹

so the function is definitely a 3 to the power of x version.

but we need to adapt the exponent a bit and correct x, so that at least for these 3 values of x the result is "running backwards".

the easiest way : 2-x as exponent.

it fits.

for x=-1 we get 2 - -1 = 3 as exponent.

for x=0 we get 2-0 = 2 as exponent.

for x=1 we get 2-1 = 1 as exponent.

so, the exponential function passing through these 3 points is

[tex]f(x) = {3}^{2 - x} [/tex]

Answer:

x=1°.

see the IMAGE FOR SOLUTION