Find the solution set of the inequality and what is the number? 16x − 7 ≤ − 71 A. C. ≤ D. ≥ E. =

Answer:

Question 18: B. 104

Question 19: [tex] x = \frac{3}{2} [/tex]

Step-by-step Explanation:

Question 18:

Step 1: express the inverse relationship with an equation

[tex] y = \frac{k}{x^2} [/tex] ,

where k is constant

y = 26 when x = 4,

Constant, k, = [tex] y*x^2 = k [/tex]

[tex] k = 26*4^2 = 416 [/tex]

The equation would be [tex] y*x^2 = 416 [/tex]

Step 2: use the equation to find y when X = 2.

[tex] y*x^2 = 416 [/tex]

[tex] y*2^2 = 416 [/tex]

[tex] y*4 = 416 [/tex]

Divide both sides by 4

[tex] \frac{y*4}{4} = \frac{416}{4} [/tex]

[tex] y = 104 [/tex]

Question 19:

[tex] \frac{x}{3} = \frac{x + 2}{7} [/tex]

Cross multiply

[tex] x(7) = 3(x + 2) [/tex]

[tex] 7x = 3x + 6 [/tex]

Subtract 3x from both sides

[tex] 7x - 3x = 3x + 6 - 3x [/tex]

[tex] 4x = 6 [/tex]

Divide both sides by 4

[tex] \frac{4x}{4} = \frac{6}{4} [/tex]

[tex] x = \frac{3}{2} [/tex]

Answer: D.) 52

Explanation: I guessed and got it right lol

Answer:

12 units

Step-by-step explanation:

Since all of the sides of a rhombus are congruent, JK = JM which means:

2x + 4 = 3x

-x = -4

x = 4 so 3x = 3 * 4 = 12

Answer:

34 grams

Step-by-step explanation:

If the remaining sample has 30.26 grams of radioactive substance, and 11% of it decayed, that means that 30.26 grams is 89% of the original. Let the original be x.

30.26=0.89x

Multiply both by one hundred

3026=89x

Divide both by 89

34=x

x=original, so the original was 34 grams.

Answer:

14 mi

Step-by-step explanation:

Cedarburg is 22 13/16 miles from Allenville and 8 13/16 miles from Lakeside.  You have to solve for the distance from Lakeside to Allenville.

8 13/16  +  x  =  22 13/16

(8 13/16  +  x)  -  8 13/16  =  22 13/16  -  8 13/16

x  =  14

The distance from Lakeside to Allenville is 14 miles.

Answer:

Brainleist!

Step-by-step explanation:

0

there is no y=mX+b

there is no x no XXXX

that means the slope must be 0 (bc theres a y)

Sorry if my explanation is bad... let me know in comments if u need more help

Answer:

Step-by-step explanation:

Given that:

[tex]\mathsf{f(x) = x^2 -5 } \\ \\ \mathsf{x_1 = 2}[/tex]

The derivative of the first function of (x) is:

[tex]\mathsf{f'(x) =2x }[/tex]

According to Newton's Raphson method for function formula:

[tex]{\mathrm{x_{n+1} = x_n - \dfrac{f(x_n)}{f'(x_n)}}[/tex]

where;

[tex]\mathbf{x_1 =2}[/tex]

The first iteration is as follows:

[tex]\mathtt{f(x_1) = (2)^2 - 5} \\ \\ \mathbf{f(x_1) = -1}[/tex]

[tex]\mathtt{f'(x_1) = 2(2)} \\ \\ \mathbf{ = 4}[/tex]

[tex]\mathtt{\dfrac{f(x_1)}{f'(x_1)}} = \dfrac{-1}{4}}[/tex]

[tex]\mathbf{\dfrac{f(x_1)}{f'(x_1)} =-0.25}[/tex]

[tex]\mathtt{x_1 - \dfrac{f(x_1)}{f'(x_1)}} = \mathtt{2 - (-0.25)}}[/tex]

[tex]\mathbf{x_1 - \dfrac{f(x_1)}{f'(x_1)} = 2.25}[/tex]

Therefore;

[tex]\mathbf{x_2 = 2.25}[/tex]

For the second iteration;

[tex]\mathtt f(x_2) = (2.25)^2 -5}[/tex]

[tex]\mathtt f(x_2) = 5.0625-5}[/tex]

[tex]\mathbf{ f(x_2) =0.0625}[/tex]

[tex]\mathtt{f'(x_2)= 2(2.25)}[/tex]

[tex]\mathbf{f'(x_2)= 4.5}[/tex]

[tex]\mathtt{ \dfrac{f(x_2)}{f'(x_2)}} = \dfrac{0.0625}{4.5}}[/tex]

[tex]\mathbf{ \dfrac{f(x_2)}{f'(x_2)} = 0.01389}[/tex]

[tex]\mathtt{x_2 - \dfrac{f(x_2)}{f'(x_2)}} = \mathtt{2.25 -0.01389}}[/tex]

[tex]\mathbf{x_2 - \dfrac{f(x_2)}{f'(x_2)} = 2.2361}}[/tex]

Therefore, [tex]\mathbf{x_3 = 2.2361}[/tex]

Answer:

x = 12

Step-by-step explanation:

3(x–6)=18

x-6 = 18:3

x-6 = 6

x = 6+6

x = 12

Answer:

x=12

Step-by-step explanation:

Answer:

The minimum sample size is [tex]n = 2123[/tex]

Step-by-step explanation:

From the question we are told that

    The margin of error is  [tex]E = 0.028[/tex]

Given that the confidence level is  99% then the level of significance is evaluated as

        [tex]\alpha = 100 - 99[/tex]

        [tex]\alpha = 1 \%[/tex]

        [tex]\alpha =0.01[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table

   The  value is  [tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]

Now let  assume that the sample proportion is  [tex]\r p = 0.5[/tex]

  hence  [tex]\r q = 1 - \r p[/tex]

=>            [tex]\r q = 0.50[/tex]

   Generally the sample size is mathematically represented as

                [tex]n =[ \frac{Z_{\frac{ \alpha }{2} }}{ E} ]^2 * \r p * \r q[/tex]

                [tex]n =[ \frac{2.58}{ 0.028} ]^2 * 0.5 * 0.5[/tex]

              [tex]n = 2123[/tex]

Answer:

D) 3/2(X-4)

Step-by-step explanation:

Invert and multiply to get:

3(x+4)/2(x²-16)

factor the bottom

3(x+4)/2(x+4)(x-4)

The (x+4)’s cancel out, and you’re left with

3/2(X-4)

[tex]\dfrac{{x+4\over2}}{{x^2-16\over3}}[/tex]

[tex]=\dfrac{3(x+4)}{2(x+4)(x-4)}=\frac{3}{2(x-4)} [/tex]

but in original fraction, denominator can't be zero so we have to exclude x=±4

do that answer is D

Answer:

[tex]\frac{x^2}{4^2}+\frac{y^2}{\sqrt{7} ^2}=1[/tex]

Step-by-step explanation:

Since the vertex of the parabola is at (4,0), it has the vertex on the x axis (horizontal axis). The standard equation of an ellipse with horizontal major axis is given by:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

Where (h,k) is the center of the ellipse, a is the vertex and ±√(a²- b²) is the focus (c).

Since the ellipse center is at (0, 0), h = 0 and k = 0. Also the vertex is at (4, 0) therefore a = 0

To find b we use the equation of the focus which is:

[tex]c=\sqrt{a^2-b^2}\\ \\Substituing:\\\\3=\sqrt{4^2-b^2} \\4^2-b^2=3^2\\b^2=4^2-3^2\\b^2=16-9\\b^2=7\\b=\sqrt{7}[/tex]

Substituting the values of a, b, h and k:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\\\\\frac{(x-0)^2}{4^2}+\frac{(y-0)^2}{\sqrt{7} ^2}=1\\\\\frac{x^2}{4^2}+\frac{y^2}{\sqrt{7} ^2}=1[/tex]

Answer:

d. 60000000000

Step-by-step explanation:

Answer:

The answer is D. 60,000,000,000

Step-by-step explanation:

Answer:

[tex]\boxed{\frac{984}{1000}}[/tex]

Step-by-step explanation:

Hey there!

Well .984 is 984 over 1000 so .984 as a fraction is 984/1000.

We can check this by doing 984 / 1000 which is .984.

Hope this helps :)

Answer:

$935.76

Step-by-step explanation:

BOND VALUATION Asiana Fashion's bonds have 10 years remaining to maturity. Interest is paid annually; they have a $1,000 par value; the coupon interest rate is 8% and thebyield to maturity is 9%.What is the bond's current market price?​

Step 1

We find the Present value factor of sum

The formula =

(1 + i)^n

Where

i = maturity rate = 9% = 0.09

n = number of years = 10 years

Present Value = ( 1 + 0.09)^-10

= 0.4224

Step 2

We find the present value factor of annuity

The formula is given as:

1 - (1+i)^-n / i

i = maturity rate = 9% = 0.09

n = number of years = 10 years

= 1 - (1 + 0.09)^-10 /0.09

= 1 - 0.4224 /0.09

= 0.5775 /0.09

= 6.417

Step 3

The bond's current market price is calculated as:

= PV factor of Sum × Par Value + PV factor of annuity × coupon payment

Coupon payment is calculated as:

= Coupon interest × par value

= 8% × 1000

= 80

Hence,

= 0.4224 × 1,000 + 6.417 × 80

= 422.4 + 513.36

= 935.76

In this exercise we have to use the knowledge of finance to calculate the corrective value of the market place, in this way we find that:

[tex]\$935.76[/tex]

We find the Present value factor of sum, by the formula of:

[tex](1 + i)^n[/tex]

Where:

Substituting the values ​​in the formula as;

[tex]Present \ Value = ( 1 + 0.09)^{-10} = 0.4224[/tex]

We find the present value factor of annuity, by the formula as:

[tex]1 - (1+i)^{-n} / i[/tex]

Where:

Substituting the values ​​in the formula as;

[tex]= 1 - (1 + 0.09)^{-10} /0.09\\= 1 - 0.4224 /0.09\\= 0.5775 /0.09\\= 6.417[/tex]

The bond's current market price is calculated as:

[tex]= PV \ factor\ of\ Sum * Par\ Value + PV\ factor\ of\ annuity * coupon\ payment[/tex]

Coupon payment is calculated as:

[tex]= Coupon\ interest * par\ value\\= 8\% * 1000= 80[/tex]

So continue the calcule;

[tex]= 0.4224 *1,000 + 6.417 * 80\\= 422.4 + 513.36\\= 935.76[/tex]

See more about market place at brainly.com/question/24518027

Answer:

Sample size n [tex]\simeq[/tex] 1269.15

Step-by-step explanation:

From the information given ,

At 99% of confidence interval,

the level of significance ∝ = 1 - 0.99

the level of significance ∝ =  0.01

the critical value for 99% of confidence interval is:

[tex]\mathtt{\dfrac{\alpha }{2} = \dfrac{0.01}{2}}[/tex]

= 0.005

[tex]\mathtt {z_{\alpha/2} = z_{0.005/2} }[/tex]

The value for z from the standard normal tables

= 2.58

The Margin of error E= 3% = 0.03

The formula to  determine the sample size n used can be expressed as follows:

[tex]\mathtt { n = (\dfrac{z_{\alpha/2}}{E})^2 \ \hat p (1 - \hat p) }[/tex]

where;

[tex]\mathtt{\hat p }[/tex] = 22% = 0.22

Then:

[tex]\mathtt { n = (\dfrac{2.58}{0.03})^2 \ \times 0.22 \times (1 - 0.22) }[/tex]

[tex]\mathtt { n = (86)^2 \ \times 0.22 \times (0.78) }[/tex]

[tex]\mathtt { n = 7396 \ \times 0.22 \times (0.78) }[/tex]

n = 1269.1536

Sample size n [tex]\simeq[/tex] 1269.15

Answer:

[tex]42-j=16[/tex]

Step-by-step explanation:

"Decreased by" means subtraction.

The information says 42 decreased "by Jose's savings", which is represented by j.

"Is" means equal to.

Put it all together:

[tex]42-j=16[/tex]

:Done

Answer:

j - 42 = 16

Step-by-step explanation:

J = Jose Savings

42 = the amount decreased

16 = the left amount

J-42 = 16

j = 16+42

J = 58

Jose's savings was $58.

Answer:

D. the bottom one is the answer, because hyperbola is two curves that curve infinitely

Answer:

A

Step-by-step explanation:

A 1.75 * 10^6 = 1750000

B  1.25 * 10^6 = 1250000

C 2.75*10^5  = 275000

D 3.82*10^5 = 82000

option A (1.75 * 10⁶) represents the largest number among the given options.

To determine which of the given numbers represents the largest number, we can compare the exponents of 10 in each option.

A. 1.75 * 10⁶

B. 1.25 * 10⁶

C. 2.75 * 10⁵

D. 3.82 * 10⁵

Comparing the exponents:

A: 10⁶

B: 10⁶

C: 10⁵

D: 10⁵

Since both options A and B have an exponent of 10⁶, we need to compare the coefficients.

1.75 is greater than 1.25, so option A (1.75 * 10⁶) represents the largest number among the given options.

Therefore, the answer is A. 1.75 * 10⁶.

Learn more about exponents here

https://brainly.com/question/5497425

#SPJ2

Answer:

the unknown number is 1500

Step-by-step explanation:

let "a" be the unknown number we finding so from the above question we can deduce that

(80/100)*a=1200

80a=1200*100

80a=120000

a=120000/80

a=1500

Answer:

Hey there!

Simple interest formula: I=PRT

I=700(8.25)(0.25)

I=1443.75

Hope this helps :)

Answer:

Step-by-step explanation:

I = PRT

I = 700(0.0825)(1/4) = 14.44

Because the interest is usually in percentage and it's impossible to have 825% as your interest rate. So the actual interest rate has to be 0.0825.

The formula above calculated the interest, if you want the total, you will need to add 700 to that number.  

Here's a small quick example of the formula that should help.

Answer:

ans right down there

Step-by-step explanation:

Here,Part 1

if the circle has a radius r so,

15 = r theta

here, theta is in radian.

Part 2

[tex]theta = \frac{15}{6} = 2.5[/tex]

part 3

[tex]theta = \frac{2.5 \times 180}{\pi} [/tex]

or theta =

143.2394487827058021919953870352629258310136811664108038729006

Answer:

x = 34° and y = 62°

Step-by-step explanation:

Complementary angles sum to 90°, therefore 90 = 56 + x which means that x = 34°. The angles formed by an angle bisector are congruent and so are vertical angles; this means that ∠SOR = ∠POU = 56° and ∠POQ = ∠QOR = y. Since POS is a straight line, straight lines have a measure of 180° and because ∠POS = ∠POQ + ∠QOR + ∠SOR, we know that 180 = y + y + 56 → 180 = 2y + 56 → 180 → 2y = 124 → y = 62°.

Answer: $43,823.37

Step-by-step explanation:

Formula to calculate the accumulated amount earned on principal (P) at rate of interest (r) compounded daily after t years :

[tex]A=P(1+\dfrac{r}{365})^{365t}[/tex]

As per given , we have

P= $ 30,700

r= 8.9 % = 0.089

t= 4 years

[tex]A=30700(1+\dfrac{0.089}{365})^{365(4)}\\\\=30700(1+0.0002438)^{365(4)}\\\\=30700(1.0002438)^{1460}\\\\=30700(1.42747138525)\\\\=43823.3715272\approx43823.37[/tex]

Hence, the amount at the end of 4 years would be $43,823.37 .

Answer:

Section I test scores are more dispersed that that of section II.

Step-by-step explanation:

Consider the data collected from the arithmetic test given to two sections of a school.

Section I: Mean = 45, Standard  Deviation = 6.5

Section II: Mean = 45,  Standard deviation = 3.1

The mean of both the sections are same, i.e. 45.

So there is no comparison that can be made from the center of the distribution.

The standard  deviation for section I is 6.5 and the standard  deviation for section II is 3.1.

The standard deviation is a measure of dispersion, i.e. it tells us how dispersed the data is from the mean or how much variability is present in the data.

The standard  deviation for section I is higher than that of section II.

So, this implies that section I test scores are more dispersed that that of section II.

Answer:

d=55(t+0.5)

Step-by-step explanation:

d=55(t+0.5)

Answer:

27.5

Step-by-step explanation:

Answer:

[tex]163 -y =-5\\Collect\:Like\:terms\\163+5 = y\\Simplify\\168 =y\\\\y = 168[/tex]

Hello There!

[tex]163-y=-5[/tex]

To solve your equation, you can just change the -5 to 5 and move it to where y is. After that, change the minus sign to addition.

[tex]163+5=y[/tex]

Now all you have to do is sum it up.

[tex]163+5=168[/tex]

So y = to 168

So your answer is

[tex]163-168=-5[/tex]

Hope this Helps!

Answer:

Answer is attached below :)

Answer:

1 square foot is the answer

Answer:

1 ft^2

Step-by-step explanation:

We know 12 inches = 1 ft

12 inches by 12 inches

1 ft by 1 ft

The area is 1 * 1 = 1 ft^2

Answer: n = 52

Step-by-step explanation:

when we have two vectors (x,y) and (a,b) the distance between the vectors is:

D = √( (x - a)^2 + (y - b)^2)

now, we know that:

1) the distance between (x, y ) and the x-axis is 6 units.

The nearest point to (x, y) in the x-axis is the point (x, 0) so we have:

D = 6 = √( (x - x)^2 + (y - 0)^2) = √y^2

so y can be 6 or -6.

So we know that y = 6, and now we can write our point as (x, +-6)

2) The distance between our point and (8, 3) is 5 units:

D = √( (x - 8)^2 + (y - 3)^2) = 5.

And we know that the distance from the origin, (n, n) is:

D = √n = √(x^2 + y^2}

n = x^2 + y^2

Now, we should start with:

√( (x - 8)^2 + (y - 3)^2) = 5

first suppose that y = -6, then:

√( (x - 8)^2 + (-6 - 3)^2) = √( (x - 8)^2 + (-9)^2) = 5.

√( (x - 8)^2 + 81) = 5.

Then we must have that:

and we know that √25 = 5

so (x-8)^2 + 81 = 25

this can never happen, so we can discard y = -6

Now the second case, if y = 6,

√( (x - 8)^2 + (6 - 3)^2) = 5.

√( (x - 8)^2 + (3)^2) = 5.

√( (x - 8)^2 + 9) = 5.

here:

(x - 8)^2 + 9 = 25

(x - 8)^2 = 16

(x - 8) = √16 = +-4

So again we have two cases:

if x - 8 = 4, then:

x = 4 + 8 = 12

but we must have x < 8, so this can be discarded.

now, if x - 8 = -4 then:

x = -4 + 8 = 4, this is an acceptable answer, then our point is (4, 6)

And we have:

n = 4^2 + 6^2 = 16 + 36 = 52

Answer:

The answer is sector. B.

Answer:

149 degrees

Step-by-step explanation:

This shape is a cyclic, so opposite angles add up to 180 degrees.

180-31 = 149