find the value of x pls show work

Answer:

First option

... -0.9 ...

Answer:

[tex]\frac{1}{x^{5} }[/tex]

Step-by-step explanation:

x^-12/ x^-7

= x^(-12-(-7))

= x^-5

= 1/x^5

Answer:

-3.662rad × 180/π = -209.8°

Step-by-step explanation:

Answer:

1 degree = .01745329 radians

1 radian = 57.2957877856 degrees

-209.8 degrees = .01745329 * -209.8 =

-3.66170024200 radians

Step-by-step explanation:

Answer:

486cm^2

Step-by-step explanation:

Surface area of cube = (6a^2)

6×9×9=486.

Answer:

Step-by-step explanation:

If the function is f(x), then shift 8 units left and 3 units down will result in:

Apply to the given function to get:

Correct choice is A

Answer:

D. X + 9​

Step-by-step explanation:

x² + 2x - 63

What 2 numbers multiply to -63 and add to 2

9 * -7 = -63

9+-7 = 2

(x+9)(x-7)

Answer:

The answer is B (4, 8) and (0, -8)

Answer:

60

Step-by-step explanation:

Is means equals and of means multiply

21 = 35% * n

21 = .35*n

Divide each side by .35

21/.35 = .35n/.35

60 = n

Answer:

60

Step-by-step explanation:

35% of 60 is 21 its that simple

Answer:

Given:

i) Since DN and BC are transversals, we have:

As two angles and one side is congruent, the triangles are also congruent:

So their areas are same.

ii)

The quadrilateral has area of:

And the triangle has area of:

Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.

Answer:

I think I have proved it before you asked this question before also.

Step-by-step explanation:

SEE the image for solution.

HOPE it helps

Have a great day

Given:

The probability of drawing a red candy at random from a bag of 25 candies is [tex]\dfrac{2}{5}[/tex].

To find:

The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

Solution:

Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:

[tex]P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}[/tex]

[tex]\dfrac{2}{5}=\dfrac{n}{25}[/tex]

[tex]\dfrac{2}{5}\times 25=n[/tex]

[tex]10=n[/tex]

After removing the 5 candies from the bag, the number of remaining candies is [tex]25-5=20[/tex] and the number of remaining red candies is [tex]10-5=5[/tex].

Now, the probability of randomly drawing a red candy from the bag is:

[tex]P(Red)=\dfrac{5}{20}[/tex]

[tex]P(Red)=\dfrac{1}{4}[/tex]

Therefore, the required probability is [tex]\dfrac{1}{4}[/tex].

Answer:

5 trees per day

Step-by-step explanation:

Answer:

5 trees per day

Step-by-step explanation:

(1, 5)

(2,10)

the day increases by 1 and the trees increase by 5

Answer:

Step-by-step explanation:

[tex]\frac{9}{11}=0 .818181....[/tex]

     __  

= 0.81

Answer:

C

Step-by-step explanation:

f(x) = x-8 when x>3, f(7)=7-8=-1

Answer:

or, -4a - 2a -7 = 11

or, -4a -2a =11 +7

or, - 6a = 18

or, a= 18÷ -6

a= -3

Answer:

tan Z = 4/3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta= opp / adj

tan Z = 32/24

Divide top and bottom by 8

tan Z = 4/3

Answer:

4500

Step-by-step explanation:

The first digit can't be 0. so it will be a number from 1000 to 9999. That's a total of 9000 numbers (9999-1000+1=9000). Since the last digit must be an even number that is one half of the 9000 numbers which is 4500.

Answer:

i think you have to count till you get to 4 or 3 then the remaining you plus with the 3

Answer:

[tex]d=5[/tex]

Step-by-step explanation:

you have to use the distance formula, making the origin (0,0) the 1st point and (4,0) the second point.

[tex]d=\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2} }[/tex]

[tex]d=\sqrt{(4-0)^{2}+(3-0)^2 }[/tex]

[tex]d=\sqrt{(4)^2+(3)^2}[/tex]

[tex]d=\sqrt{16+9}[/tex]

[tex]d=\sqrt{25}[/tex]

[tex]d=5[/tex]

Given:

The equation is:

[tex]y=\sqrt[3]{x}[/tex]

To find:

The graph of the given equation.

Solution:

We have,

[tex]y=\sqrt[3]{x}[/tex]

The table of values is:

x                 y

-8              -2

-1                -1

0               0

1                 1

8                8

Plot these points on a coordinate plane and connect them by a free hand curve as shown in the below graph.

Answer:

D

Step-by-step explanation:

edge 2020

Initial velocity (u) = 0m/s

Final velocity (v) = 20m/s

Time (t) = 10 s

Acceleration (a)

= (v - u)/t

= [(20m/s) - (0m/s)]/10s

= (20m/s)/10s

= (20m/s²)/10

=> 2m/s²

Answer:

Step-by-step explanation:

Answer:

a. 5 hours

b. 40 kph

Step-by-step explanation:

300 km ÷ 60 km = 5 hours

200 km ÷ 5 hours = 40 kilometers per hour

Answer:

C is the answer

Step-by-step explanation:

Quadratic equations have at most 2 solution, and linear equations only have 1 solution, and since y is equal to both of them, it can only have 1 or 2 solutions.

The correct answer is option D.  The system may have no, 1, or 2 solutions

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .

f(x) is a quadratic function and g(x) is linear function

y=f(x)

y=g(x)

Quadratic equations have at most 2 solution

linear equations only have 1 solution,

f(x)=g(x)=y

y is equal to both of them, it can only have 1 or 2 solutions.

A line and a parabola can intersect zero, one, or two times

Therefore, a linear and quadratic system can have zero, one, or two solutions

Hence, the correct answer is option D.  The system may have no, 1, or 2 solutions

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Answer:

Step-by-step explanation:

Equation for a circle of radius r, centered at (h,k):

(x-h)² + (y-k)² = r²

Answer:

-$87

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Answer:

The answer us Option C

Step-by-step explanation:

Hope this helps!!

Answer:

C

Step-by-step explanation:

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

Answer:

b=8

Step-by-step explanation:

7b-7-8b=-15

Combine like terms

-b-7=-15

Add 7 on both sides

-b=-15+7

-b=-8

Divide by -1

b = 8

Answer: b = 8

Step-by-step explanation:

Given

7b - 7 - 8b = -15

Combine like terms

-b - 7 = -15

Add 7 on both sides

-b - 7 + 7 = -15 + 7

-b = -8

Divide -1 on both sides

-b / -1 = -8 / -1

b = 8

Hope this helps!! :)

Please let me know if you have any questions

Answer:

B. 0.024

The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

1999:

Of 100, 20 were in the bottom thid. So

[tex]p_B = \frac{20}{100} = 0.2[/tex]

[tex]s_B = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]

2001:

Of 100, 10 were in the bottom third, so:

[tex]p_A = \frac{10}{100} = 0.1[/tex]

[tex]s_A = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]

To determine this, you test the hypotheses H0 : p1 = p2 , Ha : p1 > p2.

Can also be rewritten as:

[tex]H_0: p_B - p_A = 0[/tex]

[tex]H_1: p_B - p_A > 0[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

From the sample:

[tex]X = p_B - p_A = 0.2 - 0.1 = 0.1[/tex]

[tex]s_A = \sqrt{s_A^2+s_B^2} = \sqrt{0.03^2+0.04^2} = 0.05[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{0.1 - 0}{0.05}[/tex]

[tex]z = 2[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a difference of proportions of at least 0.1, which is 1 subtracted by the p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.976.

1 - 0.976 = 0.024, so the p-value is given by option B.

The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.

Answer:

Step-by-step explanation:

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. The distance between A and B is 85.6 yds.

The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,

[tex]c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}[/tex]

where

c is the third side of the triangle

a and b are the other two sides of the triangle,

and θ is the angle opposite to the third side, therefore, opposite to side c.

The three points A, B, and C will form a triangle. Therefore, using the law of cosine the measure of the third side AB can be written as,

[tex]AB =\sqrt{(AC)^2 + (BC)^2 -2(AC)(BC)\cdot \cos(51.2^o)}\\\\AB =\sqrt{(80)^2 + (104)^2 -2(80)(104)\cdot \cos(51.2^o)}\\\\AB = \sqrt{6400+10816-16640\cos51.2^o}\\\\AB = \sqrt{7328.4}\\\\AB=85.6\rm\ yd[/tex]

Hence, the distance between A and B is 85.6 yds.

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