Find the value of x. Your answer must be exact.
X
12.
600
X=

Answer:

60 miles per hour

Step-by-step explanation:

Total distance= 180 miles

Total time =3 hours

Average rate of change= ?

Distance= Rate × time

Make Time the subject of the formula

Time= Distance / Rate

Make average rate of change the subject of the formula

Average rate of change = Distance / time

= 180 miles / 3 hours

= 60 miles per hour

Answer:

(a) Triangles are similar if corresponding angles are congruent and the ratios of the lengths of corresponding sides are equal.

(b) x = 24

(c) y = 17; z = 51

Step-by-step explanation:

(a) Triangles are similar if corresponding angles are congruent and the ratios of the lengths of corresponding sides are equal.

(b)

15/45 = 8/x

1/3 = 8/x

x = 3 * 8

x = 24

(c)

a^2 + b^2 = c^2

x^2 + 45^2 = z^2

24^2 + 45^2 = z^2

576 + 2025 = z^2

z^2 = 2601

z = 51

15/45 = y/z

1/3 = y/51

3y = 51

y = 17

Answer:

A) The number halfway between -2 and 6 is 2.

B) -10 is halfway between -18 and 8

Answer:

y=6x-23

Step-by-step explanation:

-5=6(3)+b

-5=18+b

b=-23

If this helps, plz give brainly, I rlly need it!

Answer:

6x-23

Step-by-step explanation:

Answer:

50%

Step-by-step explanation:

its 50% it will land on head and 50% it will land on tails since there is only two sides on a coin

Answer:

1/2 or .5

p(1/2)

Step-by-step explanation:

its simple, there are 2 sides to a coin, so there are 2 possible outcomes. and the question asks what is the probability of the coin landing on one or in other wrds, its asking what is te probilitity of one of the two heads to be up. SO the probility is 1/2

Answer:

Step-by-step explanation:

The question above means that how many numbers can divide 2003 with a remainder of 23

That means all the numbers are less than 2003

The number of numbers that have this property are only

Hope this helps you

Answer:

Step-by-step explanation:

Step1: find the interval of roots. Consider -3 and -2

[tex]f(-3) = -7 <0[/tex]

[tex]f(-2) = 18 >0[/tex]

Hence, the root must be on [-3,-2]

Step2:  consider the middle point -2.5

[tex]f(-2.5) = 3.875 >0[/tex]

Then, the root must be on [-3, -2.5]

Step 3: Repeat step 2 by finding the value of f at the middle point -2.75

[tex]f(-2.75) = -1.0468 <0[/tex]

Step 3: Repeat step 2 by finding the value of f at the middle point of the interval [-2.75,-2.5] which is -2.625

[tex]f(-2.625) = 1.537 >0[/tex]

Step4: Repeat step 2 on [-2.75, -2.625]

Repeat step 2 until you got the root which is -2.701

Answer:

a) The total weight of fruits is [tex]8\,\frac{1}{4}[/tex] kilograms, b) The weight of the fruits left is [tex]4\,\frac{1}{2}[/tex] kilograms.

Step-by-step explanation:

a) The total weight of fruits ([tex]m_{T}[/tex]) is calculated by the following formula:

[tex]m_{T} = m_{a} + m_{m}+m_{o}[/tex]

Where:

[tex]m_{a}[/tex] - Total weight of apples, measured in kilograms.

[tex]m_{m}[/tex] - Total weight of mangoes, measured in kilograms.

[tex]m_{o}[/tex] - Total weight of oranges, measured in kilograms.

If [tex]m_{a} = 1\,\frac{1}{2} \,kg[/tex], [tex]m_{m} = 5\,\frac{1}{4}\,kg[/tex] and [tex]m_{o} = 1\,\frac{1}{2}\,kg[/tex], then:

[tex]m_{T} = 1\,\frac{1}{2}\,kg + 5\,\frac{1}{4}\,kg + 1\,\frac{1}{2}\,kg[/tex]

[tex]m_{T} = \frac{6}{4}\,kg + \frac{21}{4}\,kg + \frac{6}{4}\,kg[/tex]

[tex]m_{T} = \frac{33}{4}\,kg[/tex]

[tex]m_{T} = 8\,\frac{1}{4}\,kg[/tex]

The total weight of fruits is [tex]8\,\frac{1}{4}[/tex] kilograms.

b) The weight eaten by her family is determined by the following expression:

[tex]m_{E} = m_{a,e} + m_{m,e} + m_{o,e}[/tex]

Where:

[tex]m_{a,e}[/tex] - Eaten weight of apples, measured in kilograms.

[tex]m_{m,e}[/tex] - Eaten weight of mangoes, measured in kilograms.

[tex]m_{o,e}[/tex] - Eaten weight of oranges, measured in kilograms.

Given that [tex]m_{a,e} = \frac{3}{4}\,kg[/tex], [tex]m_{m,e} = 2\,\frac{1}{2}\,kg[/tex] and [tex]m_{o,e} = \frac{1}{2}\,kg[/tex], the weight eaten by her family is:

[tex]m_{E} = \frac{3}{4}\,kg + 2\,\frac{1}{2}\,kg + \frac{1}{2}\,kg[/tex]

[tex]m_{E} = \frac{3}{4}\,kg + \frac{10}{4}\,kg + \frac{2}{4}\,kg[/tex]

[tex]m_{E} = \frac{15}{4}\,kg[/tex]

[tex]m_{E} = 3\,\frac{3}{4}\,kg[/tex]

The weight of the fruits left is found by subtraction:

[tex]m_{R} = m_{T}-m_{E}[/tex]

[tex]m_{R} = 8\,\frac{1}{4} \,kg -3\,\frac{3}{4}\,kg[/tex]

[tex]m_{R} = \frac{33}{4}\,kg-\frac{15}{4}\,kg[/tex]

[tex]m_{R} = \frac{18}{4}\,kg[/tex]

[tex]m_{R} = 4 \,\frac{1}{2}\,kg[/tex]

The weight of the fruits left is [tex]4\,\frac{1}{2}[/tex] kilograms.

1) 3 is the Coefficient.

2) 10 is the constant.

3) 10.8 is the ans.

verifying, by putting [tex] \theta=60^{\circ}[/tex]

LHS≠RHS

hence the question is FALSE

Answer:

r = 1

Step-by-step explanation:

2πr = x

πr² = y

x = 2y

2πr = 2πr²

r = 1

Answer:

Every choice is not equivalent to 4✖️38.

Step-by-step explanation:

4✖️38=152

A. 54✖️4=216

B. 12✖️18=216

C. 72✖️3=216

D. 12✖️72=864

Every choice is not equivalent to 4✖️38.

Answer:

X = 14,700

Step-by-step explanation:

you can use a calculator to get the x.

X=3816371/(27×63)

Answer:

10:5 OR 2:1

Step-by-step explanation:

Let x be the parts of 25% dextrose and

y be the parts of 10% dextrose are mixed so that

20% dextrose mixture is obtained.

amount of dextrose in the mixture will be 20% of (x+y).

We have to find the value of [tex]\frac{x}y \ OR\ x:y[/tex]

Now, we can apply the concept that sum of amount of dextrose in the two liquids will be equal to the amount of dextrose in the mixture.

[tex]\Rightarrow x \times 25\% + y \times 10\%=(x+y)\times 20\%\\\Rightarrow x \times\dfrac{25}{100} + y \times \dfrac{10}{100}=(x+y)\times \dfrac{20}{100}\\\Rightarrow x \times25 + y \times 10=(x+y)\times 20\\\Rightarrow 25x + 10y=20x+20y\\\Rightarrow 25x -20x =20y-10y\\\Rightarrow 5x=10y\\\Rightarrow \dfrac{x}{y} = \dfrac{10}{5}\\\Rightarrow \bold{x:y=10:5\ OR\ 2:1}[/tex]

So, the answer is 10:5 or 2:1.

Answer:

4.90% is approximately the new Dextrose concentration.

Explanation:

Volume by Volume percent is given by ;

Volume percentage of dextrose solution = 5%

In 100 mL of solution 5 ml of dextrose is present.

Now, volume sterile water added was equal to the 40% of volume of dextrose volume.

So, volume of the sterile water added =  

Total volume of the solution after addition of water = 100 mL + 1 mL = 102 mL

New concentration of dextrose will be;

4.90% is approximately the new Dextrose concentration.

Step-by-step explanation:

Question 1:

Price per milliliter

Small $4.50 / 250ml

Medium $9.95 / 500 ml

Large $16.95 / 1000 ml

Question 2:

$9.95 / 500 ml > $4.50 / 250ml > $16.95 / 1000 ml

Question 3 - 4:

$4.50 / 250ml = ($4.50 * 6) / (250ml * 6 ) = $27 / 1500ml = 0.018

$9.95 / 500 ml = ($9.95 * 3) / (500 ml * 3) = $29.85 / 1500ml = 0.019

$16.95 / 1000 ml = ($16.95 * 3) / (1000 ml * 3) = $50.85 / 1500ml = 0.0339

( Use the first one for question 3 and the second for question 4)

$4.50 / 250ml would be the cheapest way to get 1500ml.

$9.95 / 500ml would be the most expensive way to get 1500ml.

I hope this helps you! Tell me if I'm wrong!

Answer:

The correct option is;

B. Range

Step-by-step explanation:

In descriptive statistics which analyses the quantitative summary of the statistical data, the range is the region or area or the statistical interval where the data is obtained from and as such the range (in descriptive statistics) gives a guide to the dispersion of the statistical information.

The range is best suited for the representation of the dispersion when the size of the data set is small.

Answer:

B The graft of h is the graft of g vertically shifted up 3 units

Answer: Vertically shifting it by 3

The transformation of a function is horizontally shrink by a factor of 3 .

Let’s go ahead and look at how f(x) = x2 will be affected by a scale factor of 1/2 and 1/3.

How do you horizontally shrink  by a factor of 3 ?

Learn more about Transformation on :

brainly.com/question/10644134

#SPJ2

Answer:

Step-by-step explanation:

Hello, please consider the following.

The "vertex form" is as below.

[tex]y=a(x-h)^2+k\\\\\text{Where (h, k) is the vertex of the parabola.}\\[/tex]

Let's do it!

[tex]f(x)=\dfrac{1}{2}x^2+3x-2\\\\f(x)=\dfrac{1}{2}\left(x^2+3*2*x\right) -2\\\\f(x)=\dfrac{1}{2}\left( (x+3)^2-3^2\right)-2\\\\f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{9}{2}-\dfrac{4}{2}\\\\f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{9+4}{2}\\\\\large \boxed{\sf \bf \ \ f(x)=\dfrac{1}{2}(x+3)^2-\dfrac{13}{2} \ \ }[/tex]

Thank you.

Answer:

68 square cm

Step-by-step explanation:

Interior square WXYZ is making four right triangles of equal bases (8 cm) and heights (2 cm) inside the square ABCD. Therefore,

Area of shaded Square = Area of square ABCD - 4 times area of one right triangle.

[tex] = {10}^{2} - 4 \times \frac{1}{2} \times 8 \times 2 \\ = 100 - 32 \\ = 68 \: {cm}^{2} [/tex]

Hello, please consider the following.

[tex]x^2 + 10x + 25 = 8\\\\\text{\bf We can notice that } x^2+10x+25=(x+5)^2 \text{ so}\\\\x^2 + 10x + 25 = (x+5)^2=8\\\\\text{\bf We take the root.}\\\\x+5=\pm\sqrt{8}\\\\\text{\bf We subtract 5}\\\\\boxed{x=-5-\sqrt{8}} \ \ or \ \ x=-5+\sqrt{8}[/tex]

In the box, you can find the smallest solution.

Thank you.

Answer:

z=-3

Step-by-step explanation:

1:open the brackets.

2:take 21 to the other side to be subtracted by 42

3:you get a -z but you can take it to the other side to get a +z but -21 divide to get the answer

42=-7(z-3)

-7(z-3)=42

-7z+21=42

-7z=42-21

-7z=21

therefore,

z=21\-7

that is, -21\7=-3

Answer:

(a) (f o g)(x) =  x^2 - 15x + 54

(b) (g o f)(x) = x^2 + 3x - 9

(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d) (g o g)(x) = x - 18

Step-by-step explanation:

f(x) = x^2 + 3x

g(x) = x - 9

(a)

(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)

(f o g)(x) = x^2 - 18x + 81 + 3x - 27

(f o g)(x) = x^2 - 15x + 54

(b)

(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9

(c)

(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)

(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x

(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d)

(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18

Answer:

D) 84cm

Step-by-step explanation:

Square area = √(441cm²) = 21 cm

perimeter = 4*21 = 84 cm

Answer:

(3.5,4)

x coordinate =

[tex] \frac{5 + 2}{2} [/tex]

= 3.5

y coordinate =

[tex] \frac{ - 1 + 9}{2} [/tex]

= 4

midpoint = (3.5,4)

Answer:

(  3.5,4)

Step-by-step explanation:

To find the midpoint

Add the x coordinates together and divide by 2

(5+2)/2 = 7/2 = 3.5

Add the y coordinates together and divide by 2

(9+-1)/2 = 8/2 = 4

( 3.5,4)

Answer:

[tex]\Large \boxed{\mathrm{100\pi \ cm^2 }}[/tex]

Step-by-step explanation:

[tex]\displaystyle area \ of \ circle \ = \ \pi (\frac{diameter}{2} )^2[/tex]

[tex]\displaystyle A \ = \ \pi ( \frac{20}{2} )^2[/tex]

[tex]\displaystyle A \ = \ \pi ( 10 )^2[/tex]

[tex]\displaystyle A \ = \ 100\pi[/tex]

Answer:

m∠C = 102°

Step-by-step explanation:

This is is a cyclic quadrilateral

• The sum of opposite angles in a cyclic quadrilateral is equal to 180°

m∠D + m∠B = 180°

m∠B = 180° - m∠D

m∠B = 180° - 80°

m∠B = 100°

If you look at the above diagram properly, you will notice there are are angles outside the circle. We refer to this an exterior or external angles in a cyclic quadrilateral

• Note that m∠B is Opposite the exterior angle m∠CDA

Hence,

m∠CDA = 2 × m∠B

m∠CDA = 2 × 100°

m∠CDA = 200°

• m∠CDA = m∠CD + m∠DA

m∠DA = m∠CDA - m∠CD

m∠DA = 200° - 116°

m∠DA = 84°

• Another external angle we need to find is m∠DAB

m∠DAB = m∠DA + m∠AB

We know that m∠DA = 84°, therefore,

m∠DAB = 84° + 120°

m∠DAB = 204°

• The final step is to solve for m∠C

m∠DAB is Opposite m∠C

Hence

m∠C = 1/2 × m∠DAB

m∠C = 1/2 × 204

m∠C = 102°

Answer:

Step-by-step explanation:

i) The union of the two sets is the list of elements that are in either. Duplicates are listed only once.

  U = {1, 2, 3, 4, 5, 10, 11, 12}

  A' = U - A = {10, 11, 12}

  A'∪B' = {10, 11, 12}∪{1, 2, 4} = {1, 2, 4, 10, 11, 12}

__

ii) A has 5 elements, so has 2^5 = 32 subsets, including the empty set and the whole set.

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be [tex]900-880=20[/tex] meters from the starting point.