Find the volume of a pyramid with a square base, where the side length of the base is 17 in 17 in and the height of the pyramid is 9 in 9 in. Round your answer to the nearest tenth of a cubic inch.

Answer:

60°

Step-by-step explanation:

A full rotation is 360°. The figure has six sides.

1. Divide

360 ÷ 6 = 60

Each angle of the polygon is 60°. Therefore, the polygon must be rotated at least 60° for the figure to match all sides and vertices.

Answer:

[tex]\displaystyle (s-r)(x) = x^2 - x + 1[/tex]

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle r(x) = -x^2 + 3x \text{ and } s(x) = 2x + 1[/tex]

And we want to find:

[tex]\displaystyle (s-r)(x)[/tex]

This is equivalent to:

[tex]\displaystyle (s-r)(x) = s(x) - r(x)[/tex]

Substitute and simplify:

[tex]\displaystyle \begin{aligned}(s-r)(x) & = s(x) - r(x) \\ \\ & = (2x+1)-(-x^2+3x) \\ \\ & = (2x+1)+(x^2-3x) \\ \\ & = x^2 +(2x-3x) + 1 \\ \\ & = x^2 - x + 1 \end{aligned}[/tex]

In conclusion:

[tex]\displaystyle (s-r)(x) = x^2 - x + 1[/tex]

Answer:

16 yards of barbed wire

Step-by-step explanation:

Length=5 yards

Width=3 yards

Perimeter of the pasture=2(length + width)

=2(5 yards +3 yards)

=2(8 yards)

=16 yards

You should order 16 yards of barbed wire for fencing the pasture

Answer:

The original number could be 85.

Step-by-step explanation:

Let the 2 digits be x and y.

Let the number be xy then, assuming that x is the larger digit:

x - y = 3.

x = y + 3

Also

10y + x + 10x + y = 143

Substituting for x:

10y + y + 3 + 10(y + 3) + y = 143

22y + 33 = 143

22y = 110

y = 5.

So x = y + 3 = 8.

Answer:

➥ 10(x + 3) + x + 10x + x + 3 = 143

➥ 10x + 30 + 12x + 3 = 143

➥ 22x + 33 = 143

➥ 22x = 143 - 33

➥ 22x = 110

➥ x = 110/22

➥ x = 5

The unit digit number = x = 5

The tens digit number = x + 3 = 5 + 3 = 8

The original number = 10(x + 3) + x

The original number = 10(5 + 3) + 5

The original number = 50 + 30 + 5

The original number = 85

Hence,the original number is 85.

Answer:

see explanation

Step-by-step explanation:

4a + 8               4

2a² + 8a            2a

12a² - 8a           4a

4 - 6a                2

Match each expression with its greatest common factor as follows;

4a + 8               4

2a² + 8a            2a

12a² - 8a           4a

4 - 6a                2

The largest number that is found in the common factors is called the greatest common factor.

The given expression are;

4a + 8              

2a² + 8a            

12a² - 8a      

4 - 6a              

The greatest common factor of the expression are as follows;

4a + 8  = 4(a+2) = common factor = 4    

2a² + 8a = 2a(a+4a) = common factor = 2a

12a² - 8a = 4a(3a-2) = common factor = 4a

4 - 6a = 2(2-3a) = common factor = 2

Learn more about the greatest common factor here;

https://brainly.com/question/15333869

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Answer:

65dg.

Step-by-step explanation:

Triangles are 180dg.

So 68dg + 47dg = 115dg.

-180dg - 115dg = 65dg.

So the missing length is 65 degrees.

Answer: 65

Step-by-step explanation:

Add both of the numbers on there. Then do 180- that number.

68+47=115

180+115=65

This is because in a triangle all the angles together equal 180.

Answer:

Step-by-step explanation:

2(75)=150 that's the amount due in total for two months so

400-150= 250 they will owe $250 after two months payment

Answer:

68 ft³

Step-by-step explanation:

Take the above figure to be 2 rectangular prism. A smaller prism on top, and a bigger one under.

Volume of the smaller rectangular prism on top:

[tex] Volume = whl [/tex]

Where,

w = 2 ft

h = 4 ft

l = 4 ft

[tex] Volume = 2*4*4 = 32 ft^3 [/tex]

Volume of bigger Rectangle prism under:

w = 2 ft

h = 3 ft

l = 6 ft

[tex] Volume = 2*3*6 = 36 ft^3 [/tex]

Volume of composite figure = 32 + 36 = 68 ft³

Answer:

Step-by-step explanation:

The correct answer is 76

Big prism: 4x8x2=64

What's Left: (6-4)x2x3=12

64+12=76

Answer:

V = 60 m³

Step-by-step explanation:

Volume of Triangular Pyramid: V = 1/3bh

Area of Triangle: A = 1/2bh

b = area of bottom triangle (base)

h = height of triangular pyramid

Step 1: Find area of base triangle

A = 1/2(8)(5)

A = 4(5)

A = 20

Step 2: Plug in known variables into volume formula

V = 1/3(20)(9)

V = 1/3(180)

V = 60

Answer:

  (a)  (x -3)^2 = -6(y +5.5)

Step-by-step explanation:

The equation of a parabola can be written as ...

  (x -h)^2 = 4p(y -k)

where (h, k) is the vertex, and p is the distance from the focus to the vertex.

The vertex is half-way between the focus and directrix, so is ...

  (h, k) = (1/2)((3, -7) +(3, -4)) = (3, -5.5)

The focus is at y=-7, and the vertex is at y=-5.5, so the distance between them is ...

  -7 -(-5.5) = -1.5

Then the equation for the parabola is ...

  (x -3)^2 = 4(-1.5)(y -(-5.5))

  (x -3)^2 = -6(y +5.5) . . . . matches the first choice

Answer:

Volume injected  = 1.65 ml

Step-by-step explanation:

mass of Demerol =45 mg.

density of pre-filled in syringe = 50 mg/ml

Volume = 45/50 = 0.9 ml

For atropine mass = 0.3 mg

density= 400 mcg/ml     [ Note : 1 mcg = 0.001 mg]

volume filled  = 0.3/400(0.001) = 0.75 ml

So, the total volume filled = 0.75+0.9 = 1.65 ml

Answer:

232 cars

Step-by-step explanation:

Let's say the number of cars that entered is c.

At 9:00 am, there are a total of 24 + c cars and 64 trucks. We know that this value of 64 represents 1/5 of the total number of vehicles. The total number of vehicles is (24 + c) + 64 = 88 + c. So, we have:

64/(88 + c) = 1/5

Cross-multiply:

88 + c = 64 * 5 = 320

c = 320 - 88 = 232

Thus, the answer is 232 cars.

Note: as 232 doesn't show up in the answer choices, it's possible that the problem was copied correctly.

~ an aesthetics lover

Answer:

232 cars entered between 8 and 9

Step-by-step explanation:

at 9 am there are 64 x 5 vehicles total = 320

320 - 64 - 24 = 232

Answer:

(x-4)^4=x⁴+4x³(-4)¹+6x²(-4)²+4x¹(-4)³+(-4)⁴

=x⁴-16x³+96x²-256x+256

Answer: please find the attached files

Step-by-step explanation:

A unit circle formula and special triangle of 45, 30 and 60 degrees can be used to solve the problem.

Please find the attached files for the solution

Look at where we don't have repeating x values. This happens with function C and function D. All the x values are unique for each choice mentioned.

In choices A, B, and E, the value x = -3 repeats itself. So we don't have a function for either of these. A function is only possible if any input (x) leads to exactly one output (y).

Answer:

7/8

Step-by-step explanation:

1. Make 1 9/8 into an improper fraction

1 = 8/8

8/8 + 9/8 = 17/8

2. Subtract

17/8 - 11/8 = 7/8

Answer:

  $2587.87 per month

Step-by-step explanation:

The listed deductions are ...

The percentages have a total of ...

  25 +9.3 +6.2 +1.45 +0.9 +5 = 47.85 . . . percent

So, Christine's take-home pay is ...

  $5250(1 -0.4785) -150 = $2587.87 . . . per month

Answer:

37-2=35 or 3^7-2=2185

Answer:

x= -42

Step-by-step explanation:

put the liketerms together

x+35= -7

x=-35-7

note*the operation sign changes after crossing the equal sign

x= -42

Answer:

Unpainted  surface area = 514.28 cm²

Step-by-step explanation:

Given:

Side of cube = 20 Cm

Radius of circle = 20 / 2 = 10 Cm

Find:

Unpainted  surface area

Computation:

Unpainted  surface area = Surface area of cube - 6(Area of circle)

Unpainted  surface area = 6a² - 6[πr²]

Unpainted  surface area = 6[a² - πr²]

Unpainted  surface area = 6[20² - π10²]

Unpainted  surface area = 6[400 - 314.285714]

Unpainted  surface area = 514.28 cm²

Answer:

12t+7w=D

t+w=110

Step-by-step explanation:

12t= $12 made every tutor hour

7w= $7 made every waiter hour

D= total dollars made

t+w=110 is the tutor hour and the waiter hour adding together

Answer:

12t + 7y = x

      or

5t + 770 = x

Step-by-step explanation:

12t + 7y = x

t = number of hours he worked as a tutor

y = number of hours he worked as a waiter

x = the total amount of money he earned

t + y = 110

=> y = 110 - t

=> 12t + 7(110 - t) = x

=> 12t + 770 - 7t = x

=> 5t + 770 = x

Answer:

C

Step-by-step explanation:

13/4 simplified---->3and 1/4

Answer:

1: x = -1

2: x = 3

3: x = -3

Step-by-step explanation:

f(x)=x^3+x^2−9x−9

f(x)=x^2(x+1) −9x−9

f(x) = x^2(x+1) - 9(x+1)

f(x)= (x+1)(x^2-9)

f(x) =(x+1)(x-3)(x+3)

Answer:

[tex]\boxed{x=-1, \ x=-3, \ x=3}[/tex]

Step-by-step explanation:

The zeros of a function are the values of x when f(x) = 0.

[tex]x^3 +x^2-9x-9=0[/tex]

Factor left side of the equation.

[tex]x^2(x +1)-9(x+1)=0[/tex]

Take (x+1) common.

[tex](x^2-9)(x+1)=0[/tex]

Set factors equal to 0.

First possibility:

[tex]x^2 -9=0[/tex]

[tex]x^2 =9[/tex]

[tex]x=\± \sqrt{9}[/tex]

[tex]x=\± 3[/tex]

[tex]x=-3 \ \mathrm{or} \ x=3[/tex]

Second possibility:

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

Answer:

The value of e is -1 and f is -2.

Step-by-step explanation:

The steps are :

[tex]2e - 3f = 4 - - - (1)[/tex]

[tex]2e - 5f = 8 - - - (2)[/tex]

[tex]2e - 3f - 2e - ( - 5f) = 4 - 8[/tex]

[tex]2f = - 4[/tex]

[tex]f = - 4 \div 2[/tex]

[tex]f = - 2[/tex]

[tex]substitute \: f = - 2 \: into \: (1)[/tex]

[tex]2e - 3( - 2) = 4[/tex]

[tex]2e + 6 = 4[/tex]

[tex]2e = 4 - 6[/tex]

[tex]2e = - 2[/tex]

[tex]e = - 2 \div 2[/tex]

[tex]e = - 1[/tex]

To solve this system of equations by addition, our first goal is to cancel

out one of the variables by adding the two equations together.

However, before we add, we need to cancel out a variable.

I would choose to cancel out the e's.

To do this, we need a 2e and a -2e and

here we have a 2e in both equations.

If we multiply the second equation by -1 however,

that will give us the -2e we are looking for.

So we have (-1)(2e - 3f) = (4)(-1).

So rewriting both equations, our first equation stays the same

but our second equation becomes -2e + 3f = -4.

Notice that every term in the second

equation has been multiplied by -1.

2e - 3f = 4

-2e + 5f = -8

Now when we add the equations together,

the e's cancel and we have 2f = -4 so f = -2.

To find e, plug -2 back in for f in the

first equation to get 2e - 3(-2) = 4.

Solving from here, e = -1.

Note that e comes before f in our final answer, (-1, -2).

To determine which variable should go first

in your answer, use alphabetical order.

===================================================

Work Shown:

x = starting length of the shadow

y = height of the pole

tan(angle) = opposite/adjacent

tan(58) = y/x

1.6003345 = y/x

1.6003345x = y

x = y/1.6003345

x = (1/1.6003345)y

x = 0.62486936y

-------------------------

When the angle changes, the adjacent side gets 90 meters longer

tan(angle) = opposite/adjacent

tan(36) = y/(x+90)

0.72654253 = y/(0.62486936y+90)

0.72654253(0.62486936y+90) = y

0.453994166y + 65.3888277 = y

65.3888277 = y-0.453994166y

65.3888277 = 0.546005834y

0.546005834y = 65.3888277

y = 65.3888277/0.546005834

y = 119.758478075162

y = 119.76

The height of the pole is about 119.76 meters.

Answer:

(-2, 4, 2)

Where x = -2, y = 4, and z = 2.

Step-by-step explanation:

We are given the system of three equations:

[tex]\displaystyle \left\{ \begin{array}{l} 4x -y -2z = -8 \\ -2x + 4z = -4 \\ x + 2y = 6 \end{array}[/tex]

And we want to find the value of each variable.

Note that both the second and third equations have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all one variable.

Solve the second equation for z:

[tex]\displaystyle \begin{aligned} -2x+4z&=-4 \\ x - 2 &= 2z \\ z&= \frac{x-2}{2}\end{aligned}[/tex]

Likewise, solve the third equation for y:

[tex]\displaystyle \begin{aligned} x+2y &= 6\\ 2y &= 6-x \\ y &= \frac{6-x}{2} \end{aligned}[/tex]

Substitute the above equations into the first:

[tex]\displaystyle 4x - \left(\frac{6-x}{2}\right) - 2\left(\frac{x-2}{2}\right)=-8[/tex]

And solve for x:

[tex]\displaystyle \begin{aligned} 4x+\left(\frac{x-6}{2}\right)+(2-x) &= -8 \\ \\ 8x +(x-6) +(4-2x) &= -16 \\ \\ 7x-2 &= -16 \\ \\ 7x &= -14 \\ \\ x &= -2\end{aligned}[/tex]

Hence, x = -2.

Find z and y using their respective equations:

Second equation:

[tex]\displaystyle \begin{aligned} z&=\frac{x-2}{2} \\ &= \frac{(-2)-2}{2} \\ &= \frac{-4}{2} \\ &= -2\end{aligned}[/tex]

Third equation:

[tex]\displaystyle \begin{aligned} y &= \frac{6-x}{2}\\ &= \frac{6-(-2)}{2}\\ &= \frac{8}{2}\\ &=4\end{aligned}[/tex]

In conclusion, the solution is (-2, 4, -2)

Answer:

x = -2

y =4

z=-2

Step-by-step explanation:

4x−y−2z=−8

−2x+4z=−4

x+2y=6

Solve the second equation for x

x = 6 -2y

Substitute into the first two equations

4x−y−2z=−8

4(6-2y) -y -2 = 8  

24 -8y-y -2z = 8

-9y -2z = -32

−2(6-2y)+4z=−4

-12 +4y +4z = -4

4y+4z = 8

Divide by 4

y+z = 2

z =2-y

Substitute this into -9y -2z = -32

-9y -2(2-y) = -32

-9y -4 +2y = -32

-7y -4 = -32

-7y =-28

y =4

Now find z

z = 2-y

z = 2-4

z = -2

Now find x

x = 6 -2y

x = 6 -2(4)

x =6-8

x = -2

Answer:

[tex] d = 55h [/tex]

Step-by-step explanation:

We are given that Chantal drives at a constant speed of 55 miles per hour.

If, d represents the total distance in miles, and

h represents number of hours, the following equation can be used to express the given situation:

[tex] d = 55h [/tex]

For every hour, a distance of 55 miles is covered.

Thus, if h = 1, [tex] d = 55(1) = 55 miles [/tex]

If h = 2, [tex] d = 55(2) = 110 miles [/tex].

Therefore, [tex] d = 55h [/tex] , is an ideal equation that represents the situation given in the question above.

Answer:

Here's what I get  

Step-by-step explanation:

a. Net of a cube

Fig. 1 is the net of a cube  

b. Does the formula work?

Tony's formula works if you ignore dimensions.

There are six squares in the net of a cube.

If each side has a unit length s, the total area of the cube is 6s.

c. Will the formula work for any rectangular prism?

No, because a rectangular prism has sides of three different lengths — l, w, and h — as in Fig. 2.

d. Area of a rectangular prism

A rectangular prism has six faces.

A top (T) and a bottom (b) — A = 2×l×w

A left (L) and a right (R)    —   A = 2×l×h

A front (F) and a back (B) —   A = 2×w×h

                                  Total area = 2lw + 2lh + 2wh

If l = 5 m, w = 6 m and h = 8 m,

[tex]\begin{array}{rl}A &=& \text{2$\times$ 5 m $\times$ 6 m + 2$\times$ 5 m $\times$ 8 m + 2 $\times$ 6 m $\times$ 8 m}\\&=& \text{60 m}^{2} + \text{80 m}^{2} + \text{96 m}^{2}\\&=& \textbf{236 m}^{2}\\\end{array}[/tex]

Answer:

Step-by-step explanation:

Given the set T{X: 2<x ≤ 9} where x is an integer, the element of the set T will be {3, 4, 5, 6, 7, 8, 9}.  note that from the inequality set 2<x ≤ 9, x is not equal to 2 but greater than 2. The inequality can be divided into two as shown;

If 2<x ≤ 9 then 2<x and x≤9

If 2<x, this means x>2 but not equal to 2. This is the reason why 2 is not contained in the set T.

Similarly if x≤9, this shows that x can not be greater than 9 but less than or equal to 9.

Since the set T =  {3, 4, 5, 6, 7, 8, 9}, we are to find n(T). n(T) means cardinality of the set T and cardinality of a set is defined as the total number of element in a set.

Hence n()n(T) = 7 (since there are 7 elements in the set T)

Answer:

11 meters.

Step-by-step explanation:

The important thing to note here is that the backyard is a square. Since it's a square, all of its sides all equivalent in length. Thus, let's find the length of the sides. To do this, we use the area formula.

The formula for the area of a square is:

[tex]A=n^2[/tex]

Where n is a side. Since we know the area already, we can find n. Find n:

[tex]121=n^2\\n=11[/tex]

Since every side in a square are equivalent, all sides are 11 meters in length.

Therefore, each section of the fence should be 11 meters long.