Answer:
253.5 ft³
Step-by-step explanation:
Volume of a pyramid = [tex] \frac{1}{3} [/tex]× base area × height
Volume of a prism = base area × height
Volume of the pyramid
= [tex] \frac{1}{3} [/tex]× (6×6.5÷2) × 9
= [tex] \frac{1}{3} [/tex]× 19.5 × 9
= 58.5 ft³
Volume of the prism
= (6×6.5÷2) × 10
= 195 ft³
Volume of the solid
= 58.5 + 195
= 253.5 ft³
Answer:
A
Step-by-step explanation:
the base is 19.5 feet squared
(6 * 6.5 / 2)
multiplied by 10 gives you 195 feet cubed for the lower solid
19.5 * 9 / 3
gives you 58.5 feet cubed for the upper solid
just add both volumes together
the ratio of the following 30 minutes to 2 hours.
Answer:
30 minutes to 120 minutes.
Step-by-step explanation:
Answer:
2 hrs=120 min
30:120=1:4
Step-by-step explanation:
ans is 1:4
marke brainliest plzzzzzzz
hi I need help on this
Answer:
144 cm³ or 144 cubic centimeters
Step-by-step explanation:
Volume = Area triangle * height
Area triangle = 1/2 ( 3 x 8) = 1/2( 24) = 12
12 x 12 = 144 cm³
If my answer is incorrect, pls correct me!
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-Chetan K
the equation of a circle C is (x+2)^2+(y-7)^2=36. What is its crnter (h,k)?
Answer:
The center is ( -2, 7) and the radius is 6
Step-by-step explanation:
A circle is written in the form
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
(x+2)^2+(y-7)^2=36
(x - -2)^2+(y-7)^2=6^2
The center is ( -2, 7) and the radius is 6
The two given figures are similar. Which statements must be true? Select all that apply.
Answer:
angle B=74°
Step-by-step explanation:
the shapes are similar
Please help me with these questions
Answer:
okay the first questions answer is ,c,is true and rest of them are false
If bob gives away 7 blocks, he will have 12 left. How many blocks did he have originally
Answer:
h
Step-by-step explanation:
19 blocks
Answer:
original blocks =19
Step-by-step explanation:
original blocks -7 =12
Add 7 to each side
original blocks -7+7 =12+7
original blocks =19
if f(x) =g(x) + 10 and g(x) = 3(x) - 18
Step-by-step explanation:
This is called a nested function. Remember, math is a language.
We define a function where x is whatever we want it to be, f(x) = g(x) +10
but we have yet another function inside and itvs defined as g(x) = 3x - 18
if we were to write it out, it woukd be
f(x) = (3x - 18) + 10
100 students attended a revision lesson at the weekend.
Each student went to Maths or English or Science.
55 of these students attended on Saturday.
Over the weekend a total of 40 students went to Maths.
12 of the 27 students that went to Science went on Sunday.
10 students went to English on Saturday.
How many students went to the Maths revision lesson on Saturday?
Answer:
I am pretty sure its 30 students
Q1: Suppose that the numbers of persons per car arriving at the entrance to an amusement park has an average 2. What is the probability that a car arriving at the entrance contains a) No person b) Only one person c) More than one person d) Eight persons e) At least 3 person
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.99. How many hours of daylight, to the nearest tenth, does this model predict for February 21, 2013?
Answer:
9.3 hours
Step-by-step explanation:
Given
[tex]y = 2.89\sin(0.0145x-1.40) + 10.99.[/tex]
Required
Hours of sunlight on Feb 21, 2013
First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013
[tex]days = 52[/tex]
So:
[tex]x = 52[/tex]
So, we have:
[tex]y = 2.89\sin(0.0145x-1.40) + 10.99.[/tex]
[tex]y = 2.89\sin(0.0145*52-1.40) + 10.99.[/tex]
[tex]y = 2.89\sin(0.754-1.40) + 10.99.[/tex]
[tex]y = 2.89\sin(-0.646) + 10.99.[/tex]
[tex]y = 2.89*-0.6020 + 10.99.[/tex]
[tex]y = -1.740 + 10.99.[/tex]
[tex]y = 9.25[/tex]
[tex]y = 9.3[/tex] --- approximated
If RT is 10 centimeters long, what is ST?
Answer:
Answer: a
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
First, find x
RT = 2x + 3x
10 = 2x+3x
10 = 5x
10/5 = 2
Now place 2 in place of x in the line ST
ST = 3x
ST = 3 * 2
ST = 6
Two photographers offer different pricing plans for their services. The graph below models the prices Photographer A charges. The table below shows the prices Photographer B charges. Each photographer charges a one-time equipment fee and an hourly rate. a. Which photographer charges the greater hourly rate? By how much? b. Which photographer charges the greater one-time fee? By how much?
Answer:
a. Photographer A by $10
b. Photographer B by $25
Which ordered pairs are solutions to the equation x+6y=4?
Answer:
(10 , -1)
Step-by-step explanation:
(10)+6(-1)=4
10-6=4
PLEASE HELP!
A 95% confidence interval is found to be (28, 32). The sample standard deviation is 7, and the sample size is 49. If you wanted a smaller interval, what could you do? A. Decrease the sample size to 36. B. Increase the standard deviation to 10. C. Increase the confidence level to 99.7%. O D. Increase the sample size to 64. SUBMIT
Using the formula for the margin of error, it is found that a smaller confidence interval would be obtained as follow:
D. Increase the sample size to 64.
What is the margin of error of a confidence interval?It is given by the following formula:
[tex]M = z\frac{s}{\sqrt{n}}[/tex]
In which:
z is the critical value(direct proportional with the confidence level).s is the standard deviation.n is the sample size.For a smaller interval, we need to decrease the margin of error, which is possible increasing the sample size, hence option D is correct.
More can be learned about margin of error at https://brainly.com/question/25779324
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Get brainly if right?
10 points!
Answer:
Tn = -13n +37
ordered list is 24, 11 , -2 , -15, -28 ,-41
Rosa and Micah are playing a game . Which table is the closest to showing Rosa winning approximately plays ? 3/5 of the times she
Answer:
A is the closest
Jun 07, 9:22:26 AM
+
Write a sine function that has an
amplitude of 2, a midline of 3 and a period of 3/2.
Answer:
[tex]\displaystyle y = 2sin\:1\frac{1}{3}\pi{x} + 3[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{3}{8}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]
OR
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although the exercise told you to write the sine equation based on the speculations it gave you, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:1\frac{1}{3}\pi{x} + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{3}{8}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{3}{8}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{3}{8}} = \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have the exercise to wourk with, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]It displays the formula on how to define each wavelength of the graph. You just need to remember that the B-term has [tex]\displaystyle \pi[/tex]in it as well, meaning both of them strike each other out, leaving you with just a fraction. Now, the amplitude is obvious to figure out because it is the A-term, so this is self-explanatory. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter what the vertical shift is, that will ALWAYS be the equation of the midline, and if viewed from a graph, no matter how far it shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
factorise fully 16c^4p^2+20cp^3
Answer:
4cp^2 ( 4c^3+5p
Step-by-step explanation:
See image below:)
The factored form of the expression will be [tex]4cp^2 (4c^3+5p)[/tex]
Factorization:Given the expression 16c^4p^2+20cp^3
Get the factor for each term
[tex]16c^4p^2 = 4 * 4 * c^3 * c * p^2 \\20cp^3= 4 * 5 * c * p^2 * p[/tex]From the factors, you can see that 4cp^2 is common to both terms. Hence the factored form of the expression will be:
[tex]4cp^2 (4c^3+5p)[/tex]
Learn more on factored form here: https://brainly.com/question/25948667
given the points (-4,8)and(6,-12)
1 Determine the midpoint of the line segment connecting the points.
2 Determine the distance separating the two points
Answer:
1.
[tex]midpoint = ( \frac{ - 4 + 6}{2} , \: \frac{ - 12 + 8}{2} ) \\ = (1, \: - 2)[/tex]
2.
[tex]distance = \sqrt{ {( - 4 - 6)}^{2} + {( - 12 - 8)}^{2} } \\ = \sqrt{500} \\ = 22.4 \: units[/tex]
You measure 30 dogs' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 6.1 ounces. Based on this, construct a 95% confidence interval for the true population mean dog weight. Give your answers as decimals, to two places
Answer:
The answer is "[tex](32.8318736, 29.1681264)[/tex]"
Step-by-step explanation:
When the [tex]95\%[/tex] of the confidence interval are true population means of the dog weight then:
[tex]=\bar{x} \pm \frac{\sigma }{\sqrt{n}} \times z_{0.05}\\\\=31 \pm \frac{6.1}{\sqrt{30}}\times 1.64485\\\\=31 \pm 1.83187361\\\\=(32.8318736, 29.1681264)[/tex]
which undefined term can contain parallel lines?
1
5. Monica put $600 in a savings account that pays an interest rate of 3.5%.
She collected $120 in interest
Answer:
pls complete your question. what exactly are we supposed to calculate?
If any of the graphs below have a Hamiltonian circuit, list the vertices of the complete circuit. There may be many possibilities. For full credit, just list one for each graph, if the circuit exists
9514 1404 393
Answer:
ABHGEFDCAdoes not existECBADFEStep-by-step explanation:
A Hamiltonian circuit visits each node once and returns to its start. There is no simple way to determine if such a circuit exists.
__
For graph 2, if there were a circuit, paths ACB, ADB, and AEB would all have to be on it. Inclusion of all of those requires visiting nodes A and B more than once, so the circuit cannot exist.
__
For graph 3, the circuit must include paths BAD and DFE. That only leaves node C, which can be reached from both nodes B and E, so path ECB completes the circuit.
If a distribution for a quantitative variable is thought to be nearly symmetric with very little variation,and a box and whisker plot is created for this distribution,which of the following is true?
A) The box will be quite wide but the whisker will be very short.
B) The left and right-hand edges of the box will be approximately equal distance from the median.
C) The whiskers should be about half as long as the box is wide.
D) The upper whisker will be much longer than the lower whisker.
Answer:
B). The left and right-hand edges of the box will be approximately equal distances from the median.
Step-by-step explanation:
The 'symmetry' si described as a 'satisfying arrangement of a balanced distribution of the elements of the whole' while a 'symmetry group' is characterized as a group whose elements are all the transformations under which a given object remains invariant and whose group operation is function composition.
As per the given conditions, the second statement asserts a true claim regarding the keeping of edges of left, as well as, right-hand side's boxes at equal intervals from the median. This will help in making the arrangement fulfilling while keeping a little scope for the variation. Thus, option B is the correct answer.
HELPPP HOW MANU SURFACE AREAS DOES THIS HAVE DONT SEND A FILE!!
(2x+8)-(x-8) PLS HELP
which numbers in the set (2, 3, 4, 5,) are solutions to the inequality 19- 4x>3
Answer:
2 and 3
Step-by-step explanation:
Given the set (2, 3, 4, 5,) and inequality 19- 4x>3
To obtain which number gives a solution, we test each value in the set ;
19- 4x>3
For x = 2
19- 4(2)>3
19 - 8 > 3
11 > 3 (true)
x = 3
19- 4(3)>3
19 - 12 > 3
7 > 3 (true)
For x = 4
19- 4(4)>3
19 - 16 > 3
3 > 3 (false )
For x = 5
19- 4(5)>3
19 - 20> 3
-1 > 3 (false)
A kitchen floor can somebody plzzzz helpppp
Answer: 876
Step-by-step explanation:so all you need to do is go into
What is the height of a rectangular prism, if the volume is 750 cm, the length 25 cm, and the width is 5 cm?
Answer:
6 cm
Step-by-step explanation:
Volume of a prism= Length X Width x height
750 = 25 x 5 x h
750= 125h
750/125 = 125h/125
h= 6
Answered by Gauthmath
This type of member variable may be accessed before any objects of the class have been created.
a. private
b. public
c. inline
d. static
e. None of these
Answer:
d. static
Step-by-step explanation:
This is a question about Java programming.
A class contains information about it's members(objects). Private, public or inline variables must be related to an object, that is, an object has to be created before the variable is acessed.
Static variables, otherwise, may pertain to the class, and not to the object, that is, and thus, the correct answer is given by option d.