Find y. A. √22 B. 8 C. √42 D. 4

Answer:

Yes, it is invertible

Step-by-step explanation:

We need to find in the matrix determinant is different from zero, since iif it is, that the matrix is invertible.

Let's use co-factor expansion to find the determinant of this 4x4 matrix, using the column that has more zeroes in it as the co-factor, so we reduce the number of determinant calculations for the obtained sub-matrices.We pick the first column for that since it has three zeros!

Then the determinant of this matrix becomes:

[tex]4\,*Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] +0+0+0[/tex]

And the determinant of these 3x3 matrix is very simple because most of the cross multiplications render zero:

[tex]Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] =1 \,(3\,*\,1-0)+4\,(0-0)+6\,(0-0)=3[/tex]

Therefore, the Det of the initial matrix is : 4 * 3 = 12

and then the matrix is invertible

Answer:

26.75 units²

Step-by-step explanation:

Cube Area: A = l²

Triangle Area: A = 1/2bh

Step 1: Find area of biggest triangle

A = 1/2(3.5)(2 + 2 + 5)

A = 1.75(9)

A = 15.75

Step 2: Find area of 2nd biggest triangle

A = 1/2(5)(2)

A = 1/2(10)

A = 5

Step 3: Find area of smallest triangle

A = 1/2(2)(2)

A = 1/2(4)

A = 2

Step 4: Find area of cube

A = 2²

A = 4

Step 5: Add all the values together

A = 15.75 + 5 + 2 + 4

A = 20.75 + 2 + 4

A = 22.75 + 4

A = 26.75

Complete Question

Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150

Answer:

Normal sampling distribution can not be used

Step-by-step explanation:

From the question we are told that

    The  null hypothesis is  [tex]H_o : p = 0.015[/tex]

     The  alternative hypothesis is    [tex]H_a : p < 0.015[/tex]

The  sample size is  n= 150

Generally in order to use  normal sampling distribution  

     The value  [tex]np \ge 5[/tex]

So  

         [tex]np = 0.015 * 150[/tex]

         [tex]np = 2.25[/tex]

Given that  [tex]np < 5[/tex]   normal sampling distribution  can not be used

Based on the normal sampling assumption, the product of the sample size and the proportion must be greater than or equal to 5. Hence, since, the condition isn't met, then the normal sampling cannot be used.

Given the Parameters :

Test if np ≥ 5 :

2.25 < 5

Hence, np < 5 ;

Hence, the normal sampling distribution cannot be used.

Learn more : https://brainly.com/question/19338417

Answer:

8-2x

Step-by-step explanation:

2 distributed over the entire expression equals 8-2x

Answer:

the answer is b

Step-by-step explanation:

Answer:

Using Anova for a tri linear probability at ∝= 0.005

Step-by-step explanation:

Here simple probability cannot be used because  we want to enter your answer as a tri-linear inequality using decimals (not percents).

So we can use ANOVA

Null hypothesis

H0: µA = µB=µC

all the means are equal

Alternative hypothesis

H1: Not all means are equal.

The significance level is set at α-0.005

The test statistic to use is

F = sb²/ sw²

Which if H0 is true has an F distribution with v₁=k-1 and v₂= n-k degrees of freedom .

The computations are as follows

                     XA (XA)²            XB (XB)²         XC (XC)²       Total   ∑X²

Male                   19(361)          4(16)                 12(144)           35     521    

Female               3(9)                13 (169)           5  (25)            21      203  

TotalTj                  22                   17                      17              56     724

T²j                       (22)(22)

                             484                 289                  289        1062  

∑X²                     370               285                     169

Correction Factor = CF = Tj²/n = (56)²/6= 522.67

Total SS ∑∑X²- C. F = 724- 522.67= 201.33

Between SS ∑T²j/r - C.F = 1062/ 2 - 522.877 =8.33

Within SS = Total SS - Between SS

=201.33- 8.33= 193

The Analysis of Variance Table is

Source Of                Sum of          Mean         Computed

Variation        d.f    Squares      Squares                    F

Between

Samples           1        8.33               8.33           8.33/ 48.25= 0.1726

Within

Samples          4       193              48.25                                  

The critical region is F >F ₀.₀₀₅ (1,4) = 31.3328

Calculated value of F = 0.1726

Since it is smaller than 5 %  reject H0.

However the decimal probability will be

Male 19 4 12 35

Female 3 13 5 21

Total 22 17 17 56

There are total 22 people who get an A but only 19 males who get an A

So the probability that a male gets an A is = 19/22= 0.8636

Answer: Rational, integer, whole, natural, real

So basically everything but irrational

====================================================

Explanation:

109 is a rational number because 109 = 109/1. Any rational number is a fraction of two integers. Because of this, it cannot be irrational as "irrational" means "not rational".

An integer is anything that does not have a fractional or decimal part. So it involves the set of positive and negative whole numbers, and zero as well. So we can see that 109 is an integer.

A whole number is very similar to an integer, but we're referring to the set {0, 1, 2, 3, ..} meaning we ignore the negative integers. This makes 109 a whole number as well.

A natural number is from the set {1, 2, 3, ...}. We've kicked 0 out from the set of whole numbers. This is the set of counting numbers. So 109 is also a natural number.

A real number is any number you have encountered so far assuming your teacher has not introduced complex and imaginary numbers yet. Effectively a real number is any number that can be written as decimal. This makes 109 to be a real number.

[tex]x[/tex] - the number of the games he played

[tex]\dfrac{x}{2}[/tex] - the number of the games he won

[tex]\dfrac{x}{3}[/tex] - the number of the games he lost

[tex]x=\dfrac{x}{2}+\dfrac{x}{3}+2\Big|\cdot6\\6x=3x+2x+12\\x=12[/tex]

[tex]15-12=3[/tex]

so, he has still 3 games to play

Answer:

Step-by-step explanation:

[tex] \sf{ - 7y = - 91}[/tex]

Divide both sides of the equation by -7

⇒[tex] \sf{ \frac{ - 7y}{ - 7} = \frac{ - 91}{ - 7} }[/tex]

Calculate

⇒[tex] \sf{y = 13}[/tex]

Hope I helped!

Best regards!!

Answer:

[tex] \boxed{\sf y = 13} [/tex]

Step-by-step explanation:

Solve for y:

[tex] \sf \implies - 7y = - 91[/tex]

Divide both sides of -7y = -91 by -7:

[tex] \sf \implies \frac{ - 7y}{ - 7} = \frac{ - 91}{ - 7} [/tex]

[tex] \sf \frac{ - 7}{ - 7} = 1 : [/tex]

[tex] \sf \implies y = \frac{ - 91}{ - 7} [/tex]

[tex] \sf \implies y = \frac{ \cancel{ - 7} \times 13}{ \cancel{ - 7}} [/tex]

[tex] \sf \implies y = 13[/tex]

Answer:

a. 2

b. x²+10x+26

c. x²+2x+2

Step-by-step explanation:

To find each value, you plug in the x value into the function and solve.

a. 2

f(2)=(2)²-2(2)+2                              [combine like terms]

f(2)=4-4+2

f(2)=2

---------------------------------------------------------------------------------------------------------

b. x²+10x+26

f(x+6)=(x+6)²-2(x+6)+2                  [use FOIL method and distributive property]

f(x+6)=x²+12x+36-2x-12+2            [combine like terms]

f(x+6)=x²+10x+26

---------------------------------------------------------------------------------------------------------

c. x²+2x+2

f(-x)=(-x)²-2(-x)+2                            [combine like terms]

f(-x)=x²+2x+2

x=2.86

Step-by-step explanation:

[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]

[tex] {24}^{2} + {32}^{2} = 40[/tex]

[tex]c = 40[/tex]

[tex]6x + 6 + 9x - 9 = 40[/tex]

[tex](6x + 9x) + (6 - 9) = 40[/tex]

[tex]15x - 3 = 40[/tex]

[tex]15x = 43[/tex]

[tex]x = 2.866[/tex]

[tex]23.16 + 16.74 = 39.9[/tex]

the

[tex]6(2.86) + 6 = 23.16[/tex]

[tex]9(2.86) - 9 = 16.74[/tex]

Answer:

Inokkohgy8uokokj76899

Answer:

The range of the function f(x)= (x-4)(x-2) is all real numbers greater than or equal to -1

Step-by-step explanation:

Answer:

the value of the test statistic is calculated as "T - distribution" with the formula;

t = (x-bar - μ)/(s/√n)

Step-by-step explanation:

We are told that the standard deviation is unknown. But normally, we use a z-distribution if the standard deviation is known.

However, in a hypothesis test for a population mean where the population standard deviation is unknown is still conducted in the same way like we do when we know the population standard deviation. The only difference in this case is that we will use the t-distribution rather than the standard normal z-distribution.

The t-distribution formula used is;

t = (x-bar - μ)/(s/√n)

Full question attached:

Answer and explanation:

A) B2*B10: cell B2 and B10 have the values regular swear costs and number of swears respectively and we need to multiply these two values to get our answer

B) =IF(B10>10,(B10-10)*B3,0): Sam is supposed to pay an extra $2 for swear words over 10 and so we check if his swear words are above 10 and if they are we find out how many they are by subtracting 10 from them and then we multiply the value gotten by the cost for extra swear words($2)

C) =IF(B10<5,B10*B4,0): here we check if swear words are less than 5 and if they are we multiply number of swears words less than by 5 by the cost ($0.50)

D) F10=C10+D10+E10: to calculate total money in jar(F10), we simply add up regular cost(C10), extra cost(D10) and refund(E10)

Answer:

work is pictured and shown

Answer:

Step-by-step explanation:

1. 4/4+4-4=1

2. 4/4+4/4=2

3. 4+4/4-4=3

4. 4 × (4 − 4) + 4=4

5. (4 × 4 + 4) / 4=5

6. 44 / 4 − 4=6

7. 4+4-4/4=7

8. 4+4+4-4=8

9. 4+4+4/9=9

10. 44 / 4.4=10

Answer:

1 = (4 x 4)/(4 x 4) or  (4 + 4)/(4 + 4) or  (4 / 4) x (4 / 4) or  (4 / 4)/(4 / 4)  

2= (4 x 4)/(4 + 4) or 4 / ((4+4)/4)

3= (4 + 4 + 4)/4 or (4 x 4 - 4)/4

4 = 4 - (4 - 4)/4

5 = (4 x 4 + 4)/4

6 = 4 + (4 + 4)/4

7 = 4 - (4/4) + 4

8 = 4 + (4 x 4)/4

9 = 4 + 4 + (4/4)

10 - I tried the best. You might need ! or sqrt operator to get 4.

Updated:

I forgot we could use 4, 44, 444, or 4444, so that 10 could be expressed as:

10 = (44 - 4)/4

Answer:

The  test statistic is  [tex]t = 3.744[/tex]

Step-by-step explanation:

From the question we are told that

  The population mean is  [tex]\mu = 140[/tex]

  The  The  level of significance is  [tex]\alpha = 0.05[/tex]

  The  sample size is  n =  18

   The  null hypothesis is  [tex]H_o : \mu = 140[/tex]

    The  alternative hypothesis is  [tex]H_a : \mu > 140[/tex]

    The sample mean is  [tex]\= x = 155[/tex]

     The  standard deviation is  [tex]\sigma = 17[/tex]

Generally the test statistics is mathematically represented as

       [tex]t = \frac{\= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }[/tex]

substituting values

      [tex]t = \frac{ 155 - 140 }{ \frac{ 17 }{ \sqrt{18} } }[/tex]

      [tex]t = 3.744[/tex]

The answer is $12792

Explanation:

It is known Tessa pays $108.00 to contribute to family coverage every two weeks and this represents 18% of the total payment. This implies the employer pays the 82% missing (100% - 18% = 82%). Additionally, with this information, it is possible to know the amount the employer has to pay every two weeks that represents 82%. The process is shown below:

1. Write the values you know and use x to represent the value you need to find

108 = 18        

  x =   82      

3. Cross multiply

x 18 = 8856

4. Find  the value of x by solving this simple equation

x = 8856 ÷ 18

x = 492 - Amount the employer pays every two weeks for Tessa's family coverage

Now that we know the money the employer pays every two weeks, it is possible to calculate the annual amount of money. Follow the process below.

1. Consider one year has a total of 52 weeks and divide this number of weeks by 2 because the payment for the family coverage occurs every 2 weeks

52 ÷ 2 = 26

2. Finally, multiply the money paid by the employer every two weeks by 26

26 weeks x $492 = $12792- This is the total the employer pays annually

Answer:

(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.

Step-by-step explanation:

The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.

If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.

So the initial weight would occur at (0, 79.5) which is the positive y-intercept.

And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.

Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.

Cheers.

Answer:

The equation is y= -4x -8

Step-by-step explanation:

The -4 is the slope and the -8 is the y intercept

Answer:

Slope: -4

Line type: Straight and diagonal from left to right going down.

Rate of change: a decrease by 4 for every x vaule

y-intercept is: (0,-8)

x-intercept is: (-2,0)

Step-by-step explanation:

Slope calculations:

y2 - y1 over x2 - x1

0 - 4

-2 - ( -3) or -2 + 3

=

-4/1 =

-4

More slope info on my answer here: https://brainly.com/question/17148844

Hope this helps, and have a good day.

Answer:

Step-by-step explanation:

notice

The temperature starts off below zero in the early morning and stays cold until the sun comes up. Then it warms rapidly to an above zero temperature that peaks in early afternoon. Once the sun gets lower, the temperature starts cooling off again. (The daily temperature range of 25-27 degrees is pretty typical for partly-cloudy sky conditions and stable weather.)

wonder

We wonder if this isn't a location that is on the east- or north-side of a mountain, or in a mountain valley, where the sun hits it early and is shaded later in the day. (The topo map attached seems to show it is in such a location.)

Answer:

Mr. Anderson can run like Naruto iff he is a ninja.

Step-by-step explanation:

This is because, in the statement "If Mr. Anderson is a ninja, then  he can run like Naruto.", the sub-statement, "he can run like Naruto.", depends on the sub-statement 'If Mr Anderson is a Ninja'. This means that although Mr. Anderson is a Ninja, he can only run like Naruto if and only if he is a Ninja implying that if Mr Anderson is not a Ninja, he cannot run like Naruto.

So, Mr Anderson can run like Naruto iff he is a Ninja is the correct answer

Answer:

1

Step-by-step explanation:

Answer: $27,279

Step-by-step explanation:

The data is:

Clarissa earned $2,247 per month, in the first 7 months.

After that, she earned $2,310 per month.

What total gross pay did Clarissa  earned in one year?

Ok, a year has 12 months, in the first 7 months she earned $2,247 per month, so 7 times $2,247, this is:

7*$2,247 = $15,729

And in the other 12 - 7 = 5 months, she earned $2,310 per month, so 5 times $2,310.

5*$2,310 = $11,550

Adding those togheter:

Total gross = $15,729 + $11,550  = $27,279

Answer:

I know the answer

Step-by-step explanation:

If we use 150 the answer would be 6(150) - 200 = 700. The answer is 200.

Brooklyn Burn sold 150 bottles of hot sauce every month, 700 is the profit they make eachmonth.

Answer:

192 [tex]ft^2[/tex]

Step-by-step explanation:

Given that

Volume of spherical sculpture = 256 ft³

[tex]\pi[/tex] is used as 3.

To find:

Surface area of sculpture = ?

Solution:

First of all, let us learn about the formula for Volume and Surface Area of Sphere:

1. [tex]Volume =\frac{4}{3}\pi r^3[/tex]

2. [tex]Surface\ Area = 4\pi r^2[/tex]

Given volume is 256 ft³.

[tex]256 = \dfrac{4}{3}\pi r^3\\\Rightarrow 256 = \dfrac{4}{3}\times 3 r^3\\\Rightarrow 256 = 4 r^3\\\Rightarrow r^3=64\\\Rightarrow \bold{r = 4\ ft}[/tex]

Now, let us put r = 4 in the formula of Surface Area to find the value of Surface Area:

[tex]Surface\ Area = 4\pi 4^2 = 4 \times 3 \times 16 = \bold{192\ ft^2}[/tex]

So, approximate surface area of sculpture is 192 [tex]ft^2[/tex].

Answer:

192

Step-by-step explanation:

Answer:

A) Q(t) = 4e^-(0.0079t)

B) t = 115.99 ≈ 116

Therefore scientist will be able to receive data after 116 years

Step-by-step explanation:

a)

to write a function of the form Q(t)= Q₀e⁻^kt to model the quantity Q(t) of ²³⁸Pu left after t-years.

so given that; half-life of ²³⁸Pu is 87.7 years,

∴ t =  87.7 years , Q(t) = 0.5Q₀

Now we substitute these value in the form  Q(t)= Q₀e⁻^kt

Q(t)= Q₀e⁻^kt

0.5Q₀ = Q₀e^ -(87.7k)

0.5 = e^ -(87.7k)

now we take the natural logarithm of both sides

In(0.5) = Ine^ -(87.7k)

Now using the property logₙnᵃ = a

-87.7k = In(0.5)

k = - In(0.5) / 87.7

k = 0.0079

ALSO it was given that Q₀ = 4.0 kg

Therefore , model quality Q(t) of ²³⁸pu left after t years is:

Q(t) = 4e^-(0.0079t)

b)

to find the time left after 1.6kg of ²³⁸pu

we simple substitute  Q(t) = 1.6 into Q(t) = 4e^-(0.0079t)

so we have

1.6 = 4e^-(0.0079t)

e^-(0.0079t) = 1.6/4

e^-(0.0079t) = 0.4

again we take the natural logarithm of both sides,

Ine^-(0.0079t) = In(0.4)

again using the property logₙnᵃ = a

-0.0079t = In(0.4)

t = - in(0.4) / 0.0079

t = 115.99 ≈ 116

Therefore scientist will be able to receive data after 116 years

━━━━━━━☆☆━━━━━━━

▹ Answer

1 - 9/7n

▹ Step-by-Step Explanation

1/7 - 3(3/7n - 2/7)

Remove the parentheses (Distribute -3 among the parentheses):

1/7 - 9/7n + 6/7

Calculate:

1 - 9/7n

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

1-9/7n

Step-by-step explanation:

[tex]\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7} ) \\=\frac{1}{7}-\frac{9}{7}n +\frac{6}{7} \\=\frac{1-9n+6}{7} \\=\frac{7-9n}{7}\\=1-\frac{9}{7}n[/tex]

Answer:

X+9=24

Or,x=24-9

:.x=15

Step-by-step explanation:

Answer:

B. x=15

Step-by-step explanation:

To find the solution to the equation, we must get x by itself on one side of the equation.

[tex]x+9=24[/tex]

9 is being added to x. The inverse of addition is subtraction. Subtract 9 from both sides of the equation.

[tex]x+9-9=24-9[/tex]

[tex]x=24-9[/tex]

[tex]x=15[/tex]

Let's check our solution. Plug 15 in for x.

[tex]x+9=24 (x=15)[/tex]

[tex]15+9=24[/tex]

[tex]24=24[/tex]

This checks out, so we know our solution is correct. The answer is B. x=15

Answer: stratified

Step-by-step explanation:

In stratified sampling, you divide the population into subgroups, or strata, with similar characteristics, like here we have divided the population into subgroups that depend on their political alignment. This is used when you can expect that the results have a noticeable variation between the different subgroups. Usually, you want to have the same number of population for eac subgroup, but sometimes it is hard for different reasons (not enough people in one subgroup, for example)

In cluster sampling we also use subgroups, but the subgroup itself is the unit of the sampling, while in this case, we are randomly selecting individuals of the given subgroups.

So this would be a "stratified sampling".

Answer:

x - 8y - z = 1

Step-by-step explanation:

Data provided according to the question is as follows

f(x,y) = z = ln(x - 8y)

Now the equation for the tangent plane to the surface

For z = f (x,y) at the point P [tex](x_0,y_0,z_0)[/tex] is

[tex]z - z_0 = f_x(x_0,y_0)(x-x_0) + f_y(x_0,y_0)(y-y_0)\\[/tex]

Now the partial derivatives of f are

[tex]f_x(x,y) = \frac{1}{x-8y} \\\\f_y(x,y) = \frac{8}{x-8y} \\\\P(x_0,y_0,z_0) = (9,1,0)\\\\f_z(9,1,0) = (\frac{1}{x-8y})_^{(9,1,0)}[/tex]

[tex]\\\\=\frac{1}{9-8}[/tex]

= 1

Now

[tex]f_y(9,1,0)=(\frac{8}{x-8y})_{(9,1,0)}\\\\ = -\frac{8}{9 - 8}[/tex]

= -8

So, the tangent equation is

[tex]z - 0 = 1\times (x - 9) -8\times (y - 1)[/tex]

Now after solving this, the following equation arise

z = x - 9 - 8y + 8

z = x - 8y - 1

Therefore

x - 8y - z = 1

The equation of the tangent plane is [tex]x-8y-z=1[/tex]

An equation of the tangent plane to the given surface at the point [tex]P(x_0,y_0,z_0)[/tex] is,

[tex]z-z_0=f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)[/tex]

The function is,

[tex]z = ln(x-8y)[/tex]

And the point is (9,1,0)

Now, calculating [tex]f_x,f_y[/tex]

[tex]f_x(x,y)=\frac{1}{x-8y}\\ f_y(x,y)=\frac{x-8}{x-8y}[/tex]

Now, substituting the given points into the above functions we get,

[tex]f_x(9,1)=\frac{1}{9-8(1)}=1\\ f_y(x,y)=\frac{-8}{9-8(1)}=-8[/tex]

So, the equation of the tangent plane is,

[tex]z-0=1(x-9)-8(y-1)\\z=x-8y-1\\x-8y-z=1[/tex]

Learn more about the topic tangent plane:

https://brainly.com/question/14850585