Answer:
H-Br bond is polar, hydrogen is partly positive and bromine is partly negative
H-Cl bond is polar, hydrogen is partly positive and bromine is partly negative
O-H bond in water is polar, hydrogen is partly positive and oxygen is partly negative
C-O bond in CH40 is polar, carbon is partly positive and oxygen is partly negative
Explanation:
A molecule possess a dipole moment when there is a large difference in electro negativity between two bonding atoms in the molecule.
The presence of dipole moments introduces polarity to the molecule. In all the molecules listed in the answer, the shared electron pair of the bond is closer to the more electronegative atom causing it to be partially negative while the less electronegative atom in the bond is partially positive.
LAB: Warm up: Drawing a right triangle This program will output a right triangle based on user specified height triangle_height and symbol triangle_char. (1) The given program outputs a fixed-height triangle using a character. Modify the given program to output a right triangle that instead uses the user-specified triangle_char character. (1 pt) (2) Modify the program to use a loop to output a right triangle of height triangle_height. The first line will have one user-specified character, such as % or* Each subsequent line will have one additional user-specified character until the number in the triangle's base reaches triangle_height. Output a space after each user-specified character, including a line's last user-specified character. (2 pts) Example output for triangle_char = % and triangle_height = 5: Enter a character: Enter triangle height: 5 273334.1408726 LAB ACTIVITY 16.6.1: LAB: Warm up: Drawing a right triangle 0/3 main.py Load default template... 1 triangle_char - input('Enter a character:\n') 2 triangle_height = int(input('Enter triangle height:\n')) 3 print('') 4 5 print ('*') 6 print ("**') 7 print ("***') 8
Answer:
The modified program in Python is as follows:
triangle_char = input('Enter a character:\n')
triangle_height = int(input('Enter triangle height:\n'))
for i in range(triangle_height):
print(triangle_char * (i+1))
Explanation:
This gets the character from the user
triangle_char = input('Enter a character:\n')
This gets the height of the triangle from the user
triangle_height = int(input('Enter triangle height:\n'))
This iterates through the height
for i in range(triangle_height):
This prints extra characters up to the height of the triangle
print(triangle_char * (i+1))
Here's the modified program that incorporates the requested changes:
python
Copy code
triangle_char = input('Enter a character:\n')
triangle_height = int(input('Enter triangle height:\n'))
print('')
for i in range(1, triangle_height + 1):
line = triangle_char * i + ' ' * (triangle_height - i)
print(line)
This program uses a loop to iterate from 1 to triangle_height. In each iteration, it creates a line by concatenating triangle_char repeated i times with spaces (' ') repeated (triangle_height - i) times. The resulting line is then printed.
For example, if the user enters % as the character and 5 as the height, the output will be to make sure to maintain the indentation properly in your code for it to work correctly.
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01 Describe all the possible component of a chart
Answer:
Explanation:
1) Chart area: This is the area where the chart is inserted. 2) Data series: This comprises of the various series which are present in a chart i.e., the row and column of numbers present. 3) Axes: There are two axes present in a chart. ... 4)Plot area: The main area of the chart is the plot area
what are the different steps while solving a problem using computer? explain
Explanation:
The following six steps must be followed to solve a problem using computer.
Problem Analysis.
Program Design - Algorithm, Flowchart and Pseudocode.
Coding.
Compilation and Execution.
Debugging and Testing.
Program Documentation.
Consider a file system using the indexed allocation. The block size is 512 bytes and the pointer to a block takes 2 bytes. The largest file size that a one level indexed allocation method could handle is ___________ KB. Recall that 1KB is equal to 210 bytes. Answer -1 if there is no limit based on the provided information.
Answer:
128 KB
Explanation:
Given data :
The block size = 512 bytes
Block pointer size = 2 bytes
In an indexed allocation, a special block named Index Block contains all the pointers to the blocks that the file had occupied.
Therefore, the maximum number of block pointer in 1 block :
[tex]$=\frac{\text{block size}}{\text{pointer size}}$[/tex]
[tex]$=\frac{512}{2}$[/tex]
= 256
Thus, a block can hold maximum 256 pointers.
It is given the level of indexing is one. So,
Maximum size of the file = maximum number of block pointers in 1 file x block size
= 256 x 512
[tex]$=2^8 \times 2^9$[/tex]
[tex]$=2^{8+9}$[/tex]
[tex]$=2^{17}$[/tex]
[tex]$=2^7 \times 2^{10}$[/tex]
[tex]$=128 \times 2^{10}$[/tex]
= 128 KB (∵ 1 KB = [tex]2^{10} \ B[/tex] )
Therefore, the largest file that 1 level if indexed allocation method can handle is 128 KB.
Which XXX declares a student's name. public class Student { XXX private double myGPA; private int myID; public int getID() { return myID; } } Group of answer choices String myName; public String myName; private myName; private String myName;
Which XXX declares a student's name.
public class Student {
XXX
private double myGPA;
private int myID;
public int getID() {
return myID;
}
}
Group of answer choices
a. String myName;
b. public String myName;
c. private myName;
d. private String myName;
Answer:private String myName;
Explanation:To declare a student's name, the following should be noted.
i. The name of the student is of type String
ii. Since all of the instance variables (myGPA and myID) have a private access modifier, then myName (which is the variable name used to declare the student's name) should be no exception. In other words, the student's name should also have a private access.
Therefore, XXX which declares a student's name should be written as
private String myName;
Option (a) would have been a correct option if it had the private keyword
Option (b) is not the correct option because it has a public access rather than a private access.
Option (c) is not a valid syntax since, although it has a private access, the data type of the variable myName is not specified.
Option (d) is the correct option.
2. 5s is a Chinese principle adapted for use in the workplace.
True or False
Answer:
A. true
Explanation:
because 5s is the.................
what is a microscope
Answer:
an optical instrument used for viewing very small objects, such as mineral samples or animal or plant cells, typically magnified several hundred times
Answer:
A microscope is a laboratory instrument used to examine objects that are too small to be seen by the naked eyes.
