5x+4-2x là biểu thức đại số
The difference between 15 and 9 is subtracted from 5 times the sum of 7 and 3
Answer:
44
Step-by-step explanation:
The difference between 15 and 9 is 6. 5 times the sum of 7 and 3 is 50 because 7+3=10 and 10 times 5 is 50. So if you subtract the difference between 15 and 9 from 50 you get 44.
pls help thank u so very much
Answer:
D
Step-by-step explanation:
The parent function is
[tex]f(x) = \sqrt[3]{x} [/tex]
g(x) translates to the right 2 units so we can represent this as
[tex] \sqrt[3]{x - 2} [/tex]
G(x) is shifted up 1 so our function is now
[tex] \sqrt[3]{x - 2} + 1[/tex]
how many numbers are there from x through 7x-8
What is sciences technoligy ?
Answer:
See both definitions below
Step-by-step explanation:
Let us define science
Science is a body of knowledge, it is a systematic application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence.
Let us define Technology
Simply put, technology is the application of scientific knowledge
Answer:
Simply put, technology is the application of scientific knowledge Step-by-step explanation:
What is the length of the line? Answer choices:
8
12
Square root of 60
Square root of 136
Distance between two points
Answer:
I think the answer. is 10
Answer:
square root of 136
Step-by-step explanation:
Khan Academy Answer
prove that √2 + √3 is irrational
Step-by-step explanation:
Let √2 + √3 be a / b.
a and b are co - primes.
a and b have 1 as a common factor.
√2 + √3 = a / b
( √2 + √3 )^2 = ( a / b )^2
(√2)^2 + (√3)^2 + 2.√2.√3 = a^2 / b^2
2 + 3 + 2.√2.√3 = a^2 / b^2
5 + 2.√2.√3 = a^2 / b^2
2.√2.√3 = ( a^2 / b^2 ) - 5
2.√2.√3 = ( a^2 - 5b^2 ) / b^2
√2.√3 = ( a^2 - 5b^2 ) / 2b^2
a and b are not co - primes, as they more than 1 as a common factor.
So,
√2 + √3 is irrational.
Hence, proved.
gcf of 46gh and 6g^3h^6?
Answer: 2gh
polynomial factoring [tex]\displaystyle\ 46gh=\boldsymbol{2 \cdot gh}\cdot 23 \\\\6g^3\cdot h^6= \boldsymbol{2 \cdot gh}\cdot 3 \cdot g^2\cdot h^5[/tex] accordingly, the highlighted part is the GFC of both numbers then [tex]\displaystyle\boldsymbol{ GFC(46gh \ ; \ 6g^3h^6)=2gh}[/tex]once again i’m in a pickle please help
Answer:
19
Step-by-step explanation:
You will need expand so you can plug in the givens
Quotient rule: log(b^7)-[log(a^5c^6)]
Product rule: log(b^7)-[log(a^5)+log(c^6)]
Distribute: log(b^7)-log(a^5)-log(c^6)
Power rule: 7log(b)-5log(a)-6log(c)
Plug in: 7(4)-5(3)-6(-1)
Simplify: 28-15+6
Simplify: 13+6
Simplify: 19
Scott bought a pen and received change of $4.75 in 25 coins, all dimes and quarters. How many of each kind did he receive?
Answer:
He received 10 dimes and 15 quarters.
Step-by-step explanation:
Dimes = $0.10
Quarters = $0.25
Variable x = dimes
Variable y = quarters
Create a pair of linear equations:
0.10x + 0.25y = 4.75
x + y = 25
Isolate any variable, using an equation of your choice:
x + y = 25
x = 25 - y
Plug in this new value of x into the other equation:
0.10(25 - y) + 0.25y = 4.75
Use the distributive property:
2.5 - 0.10y + 0.25y = 4.75
Combine like terms:
2.5 + 0.15y = 4.75
Isolate variable y:
0.15y = 2.25
y = 15
Plug in the value of y into any equation:
x + y = 25
x + 15 = 25
Isolate variable x:
x = 10
6. Solve the triangle by finding the length of DF and the measures of all the angles. For side lengths, round to the
nearest tenth. For angles, round to the nearest degree. (2 points)
D
5 ft
E
DF =
D
LE=
5.83 ft
ZF =
F
Answer:
∠F = 59°
∠E = 31°
DF = ≅ 3 (2.98)
Step-by-step explanation:
Identifying Types Of Angles: Check all relationships between angle 1 and angle 2.
Am I doing this right?
#1. Vertical
#2. Adjacent, Complementary
#3. Adjacent, Linear Pair, Supplementary
---A linear pair forms a line, which is equal to 180 degrees
#4. Adjacent
#5. Vertical, Complementary
#6. Vertical, Supplementary
---There is a 90 degree angle within this problem. If one angle is 90 degrees, then they are all 90 degrees, which makes the sum of angle 1 and 2 = 180. So, they are supplementary.
Hope this helps!
The relationship between angle 1 and 2 are as follows:
1. ∠1 ≅ ∠2 (vertical angles)
2. ∠1 and ∠2 are adjacent and complementary angles.
3. ∠1 and ∠2 are linear pairs and supplementary angles
4. ∠1 and ∠2 are adjacent angles
5. ∠1 and ∠2 are vertical angles
6. ∠1 and ∠2 are vertical angles and supplementary angles.
1.
Vertical angles:Vertical angles that are pair of opposite angles formed by intersecting lines. Vertical angles share the same vertex.Therefore,
∠1 ≅ 2 (vertical angles)
2.
Adjacent angles:Adjacent angles have common sides and common vertexComplementary angle :This angles sum up to 90 degrees.Therefore,
∠1 and ∠2 are adjacent and complementary angles.
3.
Linear pair angles:This is a pair of adjacent angles form when two lines intersect. It sum up to 180 degrees. Supplementary angles:Supplementary angles are angles that sum up to 180 degrees.∠1 and ∠2 are linear pairs and supplementary angles.
4.
∠1 and ∠2 are adjacent angles
5.
∠1 and ∠2 are vertical angles
6.
∠1 and ∠2 are vertical angles and supplementary angles
learn more on angles here: https://brainly.com/question/18166236?referrer=searchResults
find the missing length indicated
Answer:
25+144+X=180°
169+X=180°
X= 180-169
Therefore, x= 11°
checking process: (25+144+11= 180°)
Answer:
x = 11 i beileve!
Step-by-step explanation:
Can someone help please please
Answer:
c!
Step-by-step explanation:
Easton is deciding between two landscaping companies for his place of business. Company A charges $25 per hour and a $150 equipment fee. Company B charges $35 per hour and a $100 equipment fee. Let AA represent the amount Company A would charge for tt hours of landscaping, and let BB represent the amount Company B would charge for tt hours of landscaping. Write an equation for each situation, in terms of t,t, and determine the number hours, t,t, that would make the cost of each company the same.
Answer:
5 hours
Step-by-step explanation:
Company A:
Charge for an hour =$ 25
Charge for 't' hours = 25 *t = 25t
Total cost = Equipment fee + charge for t hours
AA = 150 + 25t
Company B:
Charge for an hour =$ 35
Charge for 't' hours = 35 *t = 35t
Total cost = Equipment fee + charge for t hours
BB = 100 + 35t
BB = AA
100 + 35t = 150 + 25t
Subtract 25t from both sides
100 + 35t - 25t = 150
100 + 10t = 150
Subtract 100 from both sides
10t = 150 - 100
10t = 50
Divide both sides by 10
t = 50/10
t = 5
Can someone help me with this math homework please!
Answer:
it is the second statement x⇒∞ Y⇒ ∞
Step-by-step explanation:
Answer:
As the x -values go to positive infinity, the functions values go to positive infinity.
Step-by-step explanation:
Correct and fastest answer gets brainest! 12 divided 2/5
30
Answer:
12÷2/5=12*5/2=30 is a required answer
Answer:
30
Step-by-step explanation:
What is the midpoint of the line segment graphed below?
(-1,2)
(9,5)
Answer:
1,3
Step-by-step explanation:
Answer:
(4, 2.5 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex], [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (9, 5) , then
midpoint = ( [tex]\frac{-1+9}{2}[/tex], [tex]\frac{2+5}{2}[/tex] ) = ( [tex]\frac{8}{2}[/tex], [tex]\frac{7}{2}[/tex] ) = (4, 3.5 )
Tre and Hector want to calculate the maximum possible throw at this field.
They calculate that the farthest point on the field would be the center fielder standing back at the dead center wall at point (322, 322). Suppose the center fielder threw the ball from here to home base.
How far is the throw?
Answer:
[tex]d=455.38~units[/tex]
Step-by-step explanation:
The coordinates of the dead center of the field, [tex]D\equiv (322,322)[/tex]
Home base in a coordinate system is always the origin, [tex]O\equiv(0,0)[/tex]
The center fielder threw the ball form the dead center to the home base, hence the distance of throw:
[tex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]
[tex]d=\sqrt{(322-0)^2+(322-0)^2}[/tex]
[tex]d=455.38~units[/tex]
Answer:Hector threw the ball 65 feet while Tre threw the ball 63 feet far
Step-by-step explanation:
The farthest throw would probably be around 450 feet
Paisley has 8\tfrac{1}{4}8 4 1 cups of yogurt to make smoothies. Each smoothie uses \tfrac{11}{16} 16 11 cup of yogurt. How many smoothies can Paisley make with the yogurt?
Given:
Total Yogurt = [tex]8\dfrac{1}{4}[/tex] cups
Yogurt required for each smoothie = [tex]\dfrac{11}{16}[/tex] cup
To find:
The number of smoothies that Paisley can make with the yogurt.
Solution:
We know that,
[tex]\text{Number of smoothies}=\dfrac{\text{Total yogurt}}{\text{Yogurt required for each smoothie}}[/tex]
Substituting the given values, we get
[tex]\text{Number of smoothies}=\dfrac{8\dfrac{1}{4}}{\dfrac{11}{16}}[/tex]
[tex]\text{Number of smoothies}=8\dfrac{1}{4}\times \dfrac{16}{11}[/tex]
[tex]\text{Number of smoothies}=\dfrac{32+1}{4}\times \dfrac{16}{11}[/tex]
[tex]\text{Number of smoothies}=\dfrac{33}{4}\times \dfrac{16}{11}[/tex]
[tex]\text{Number of smoothies}=3\times 4[/tex]
[tex]\text{Number of smoothies}=12[/tex]
Therefore, the number of smoothies is 12.
HELP ASAP PLZ I NEED IT
Answer:
4. 38 more schools offer basketball than golf.
5. Tennis is offered in the least amount of schools.
Step-by-step explanation:
4. take the number of schools that offer basketball (321) and subtract the number of schools that offer golf (283) to get how many more offer basketball than golf.
5. look at the numbers to the side of the chart and find the lowest number (276). then follow over to the left, and you will find that the least offered sport in schools is tennis.
A set of data that shows temperature highs for 10 days and satisfies all conditions below mean:72 median:74 mode:68 range:21
Answer:
[tex]58, 68, 68, 68, 74, 74, 76, 77, 78, 79[/tex]
Step-by-step explanation:
Given
[tex]n=10[/tex]
[tex]Mean = 72[/tex]
[tex]Median = 74[/tex]
[tex]Mode = 68[/tex]
[tex]Range = 21[/tex]
Required
The complete dataset
The question has missing options (available online)
From the mean, we have:
[tex]Mean = \frac{\sum x}{n}[/tex]
This gives:
[tex]72 = \frac{\sum x}{10}[/tex]
Cross multiply
[tex]\sum x = 72 * 10[/tex]
[tex]\sum x = 720[/tex]
This means that the sum of all elements of the dataset is 720
Next, we test the median
Since n = 10, then:
[tex]Median = \frac{n + 1}{2}[/tex]
[tex]Median = \frac{10 + 1}{2}[/tex]
[tex]Median = \frac{11}{2}[/tex]
[tex]Median = 5.5th[/tex]
This implies that the median is the average of the 5th and 6th item.
So, we have:
[tex]Median = \frac{5th + 6th}{2}[/tex]
Cross multiply
[tex]5th + 6th = 2 * Median[/tex]
[tex]5th + 6th = 2 * 74[/tex]
[tex]5th + 6th = 148[/tex]
This means that the 5th and 6th element add up to 148
Also, we have:
[tex]Mode = 68[/tex]
This means that 68 has to appear at least twice in the dataset
[tex]Range = 21[/tex]
This implies that the difference between the highest and the least is 21.
The dataset that satisfies the above condition is:
[tex]58, 68, 68, 68, 74, 74, 76, 77, 78, 79[/tex]
the tens digit of a two digit number is 5 greater the units digit. If you subtract double the reversed number from it, the result is a fourth of the original number. Find the original number.
Given:
The tens digit of a two digit number is 5 greater the units digit.
If you subtract double the reversed number from it, the result is a fourth of the original number.
To find:
The original number.
Solution:
Let n be the two digit number and x be the unit digit. Then tens digit is (x+5) and the original number is:
[tex]n=(x+5)\times 10+x\times 1[/tex]
[tex]n=10x+50+x[/tex]
[tex]n=11x+50[/tex]
Reversed number is:
[tex]x\times 10+(x+5)\times 1=10x+x+5[/tex]
[tex]x\times 10+(x+5)\times 1=11x+5[/tex]
If you subtract double the reversed number from it, the result is a fourth of the original number.
[tex]11x+50-2(11x+5)=\dfrac{1}{4}(11x+50)[/tex]
[tex]11x+50-22x-10=\dfrac{1}{4}(11x+50)[/tex]
[tex]40-11x=\dfrac{1}{4}(11x+50)[/tex]
Multiply both sides by 4.
[tex]160-44x=11x+50[/tex]
[tex]160-50=11x+44x[/tex]
[tex]110=55x[/tex]
Divide both sides by 55.
[tex]\dfrac{110}{55}=x[/tex]
[tex]2=x[/tex]
The unit digit is 2. So, the tens digit is [tex]2+5=7[/tex].
Therefore, the original number is 72.
SOMEONEEEE HELPPP MEEEE OUTTTTTTT!!!!!
Answer:
4/3
Step-by-step explanation:
Since this is a right triangle,
tan C = opp side / adjacent side
tan C = 36/ 27
tan C = 4/3
Given: x - 7 > -2.
Choose the solution set.
A. {x | x R, x > 14}
B. {x | x R, x > -5}
C. {x | x R, x > 5}
D. {x | x R, x > -9}
Given set:- x - 7 > - 2
Solving It:-
x - 7 > - 2
x > -2 + 7 [Here '7' is greater than '-2' So Sign Changes To Positive]
x > 5
So Correct Solution Set Will Be
Option C= {x | x R, x > 5}
Hope This Helps Youayuda el tema en concreto es "Métodos de solución de ecuaciones simultáneas"
Answer:
x = 3 y y = 2
Step-by-step explanation:
a) Metodo de reduccion:
Para aplicar este metodo debemos multiplcar por 3 la ecuacion 2 y sumarlas.
[tex]4x-3y=6[/tex]
[tex]5x+y=17[/tex] *3
[tex]4x-3y=6[/tex]
[tex]15x+3y=51[/tex]
-------sumamos las ecuacioens--------
[tex]19x=57[/tex]
[tex]x=3[/tex]
Ahora, remplazamos x en la ecuacion 2.
[tex]5(3)+y=17[/tex]
[tex]y=2[/tex]
b) Igualacion
Debemos despejar x en ambas y luego igualarlas
[tex]x=\frac{6+3y}{4}[/tex]
[tex]x=\frac{17-y}{5}[/tex]
Igualando:
[tex]\frac{6+3y}{4}=\frac{17-y}{5}[/tex]
[tex]5(6+3y)=4(17-y)[/tex]
[tex]19y=8[/tex]
[tex]y=2[/tex]
Ahora, remplazamos y en la ecuacion 2.
[tex]5x+2=17[/tex]
[tex]5x=15[/tex]
[tex]x=3[/tex]
c) Sustitucion
Despejamos x de la primero ecuacion y lo remplazamos en dos.
[tex]x=\frac{6+3y}{4}[/tex]
[tex]5\frac{(6+3y)}{4}+y=17[/tex]
Multiplicamos por 4
[tex]5(6+3y)+4y=68[/tex]
[tex]30+15y+4y=68[/tex]
[tex]30+19y=68[/tex]
[tex]19y=38[/tex]
[tex]y=2[/tex]
Remplazando en 1.
[tex]4x-3(2)=6[/tex]
[tex]4x-6=6[/tex]
[tex]4x=12[/tex]
[tex]x=3[/tex]
What traumatic stressors have you faced in your life? What chronic stressors have you faced or do you currently face? What coping strategies and lifestyle choices do you employ to respond to such stressors?
Step-by-step explanation:
What traumatic stressors have you faced in your life? What chronic stressors have you faced or do you currently face? What coping strategies and lifestyle choices do you employ to respond to such stressors?
When AG = 16 ft, find the area of the region that is NOT shaded. Round to the nearest tenth.
Answer:
730.88
Step-by-step explanation:
Area of the entire circle = pi * r^2
r = 16
Area = 3.14 * 16^2
Area = 803.84
1/4 of the circle contains the shaded area. It's area = 1/4 * 803.84
Area of 1/4 circle =
200.96
the area of the triangle
Area = 1/2 AG * G?
AG and G? are equal
Area = 1/2 * 16^2
Area = 128
Area of 1/4 circle - area of the triangle = area of the shaded portion
shaded portion = 200.95 - 128
Shaded Portion = 72.96
So the area of the unshaded part
unshaded = 803.84 - 72.96
Unshaded = 730.88
pls answer quick it's gr 9 academic math lol
Answer:
1. (3^3 + 3^2)^2 actually equals (27 + 9)^2
which is the first mistake
2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7
3. 3^7 DOES NOT EQUAL 21
Step-by-step explanation:
when you add powered numbers together, it does not multiply it, as your example:
1. (3^3 + 3^2)^2 actually equals (27 + 9)^2
which is the first mistake
2. (27 + 9)^2 does not equal (3^5)2, so (36)^2 does not equal 3^7
3. 3^7 DOES NOT EQUAL 21
Hi there!
Error 1
[tex](3^3+3^2)^2\\= (3^5)^2[/tex]
The student added the exponents of 3³ and 3² and wrote 3⁵. This rule can only be applied to exponents with the same base that are being multiplied. 3³ and 3² were being added, not multiplied, so this rule can't be applied.
Error 2
[tex](3^5)^2\\= 3^7[/tex]
When a power has a power, we multiply them, not add. Here is the correct way of doing it:
[tex](3^5)^2\\= 3^5^*^2\\= 3^1^0[/tex]
Error 3
[tex]3^7\\= 21[/tex]
The student multiplied 3 and 7 to get 21, but 3⁷ actually means 3 multiplied by itself 7 times. The correct answer for this part would be 2187.
I hope this helps!
A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7
years. The hospital has 228 g of cobalt-60. Calculate the amount of colbalt-60 remaining after 18 months.
Round to two decimal places.
Answer:
We have 197 g of Co-60 after 18 months.
Step-by-step explanation:
We can use the decay equation.
[tex]M_{f}=M_{i}e^{-\lambda t}[/tex]
Where:
M(f) and M(i) are the final and initial mass respectivelyλ is the decay constant (ln(2)/t(1/2))t(1/2) is the half-life of Cot is the time at the final amount of m[tex]M_{f}=228e^{-\frac{ln(2)}{7} 1.5}[/tex]
[tex]M_{f}=197\: g[/tex]
Therefore, we have 197 g of Co-60 after 18 months.
I hope it helps you!
The function f(t) = 3 - t shows the cost of an ice cream sundae ($) with a different number of toppings (t). What is the slope of the function?
Answer:
-1
Step-by-step explanation:
are you sure this is the right equation ? it would mean that the more toppings the cheaper the ice cream.
but as it is written, the slope is -1.
the slope of a line is always the factor of the variable in the equation.
it is the ratio of y/x indicating how many units y is changing for a given change of x.
in our example here, if x changes 1 unit to the right (+1), then y changes 1 unit down (-1).
so, -1/+1 = -1
The slope of the function f(t) = 3 - t is -1
What is function?"It defines a relation between input and output values."
What is the slope of the function?"It is the rate of change of the dependent variable of the function with respect to that of the independent variable."
For given question,
We have been given a function f(t) = 3 - t
We need to find the slope of the function.
[tex]m=\frac{d}{dt}f(t)\\\\ m=\frac{d}{dt}( 3 - t)\\\\m=-1[/tex]
Therefore, the slope of the function f(t) = 3 - t is -1
Learn more about the slope of the function here:
https://brainly.com/question/9554035
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