For some integer m, every odd integer is of the form a) m b) m + 1 c) 2m d) 2m + 1
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Answer:

Step-by-step explanation:

V = B * h

B = pi r^2

r = 12 km

B = 12^2 * pi

B = 144 * pi

h = 7 km

Volume = 144 *7 * pi

Volume = 1008 * pi

Volume = 3165.1

The gometric means G1, G2, G3, 1/4

Answer:

13.5

Step-by-step explanation:

Given

tan34° = [tex]\frac{x}{20}[/tex] ( multiply both sides by 20 )

20 × tan34° = x , then

x ≈ 13.5 ( to the nearest tenth )

Answer:

Step-by-step explanation:

The perimeter formula is P = 2L + 2W. If the perimeter is given as 68 feet, then our P will be filled in with 68. If the length is "5 inches shorter than twice the width" is an expression that looks like this, keeping in mind that "shorter" means subtraction, "twice" means doubled, and the word "is" means equals:

L = "length is"

2W is "twice the width"

5 inches shorter is " - 5". Putting it all together:

L = 2W - 5. Now we can fill in the perimeter formula:

68 = 2W + 2(2W - 5) and

68 = 2W + 4W - 10 and

68 = 6W - 10 and

78 = 6W so

W = 13. The width is 13 inches and the length is

L = 2(13) - 5 so the length is

L = 21 inches.

Answer:

answer is 533 because we add all the no.

the work that you're required to do has to contain all three requirements in order to earn the maximum number of points, and it also has to be creative (meaning no copying other people's work)

Answer:

7.2

Step-by-step explanation:

Apply Law of Cosines, given that b is 13.5, c is 8.9, and Angle a is 29.

[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \cos(a) [/tex]

[tex] {a}^{2} = {13.5}^{2} + {8.9}^{2} - 2(13.5)(8.9) \times \cos(29) [/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 240.3 \times 0.8746[/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 210.1711[/tex]

[tex]a = 7.2[/tex]

Answer:

[tex]a\approx7.2[/tex]

Step-by-step explanation:

The given problem presents one with the following information:

To solve this problem, one can use the law of cosines. The law of cosines is a property that can apply to any triangle. This property comes in the form of a formula, which is as follows:

[tex]a^2=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

Where (a), (b), and (c) are sides of the triangle, and (<A) is the angle opposite the side (a).

Substitute the given information into the formula and solve for the unknown side (a):

[tex]a=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

Simplify,

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

[tex]a=\sqrt{182.25+79.21-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-210.1711}[/tex]

[tex]a=\sqrt{51.2889}[/tex]

[tex]a\approx7.2[/tex]

Answer:

60

Step-by-step explanation:

A significant figure means the most important (biggest) number.

As it just wants 1 significant figure, you count 1 to the right and round the 6 up.

Hope this helps :)

Answer:

<1 = 64

Step-by-step explanation:

The exterior angle is equal to the sum of  the opposite interior angles for triangles

40  +<1 = 104

Subtract 40 from each side

<1 = 104 -40

<1 = 64

Answer:

3√3

Step-by-step explanation:

to get x, we divide 6 by 2 and get 3

therefore, we multiply the short leg by √3

the answer finally equals to 3√3

Answer:

[tex]\boxed {\boxed {\sf y=3}}[/tex]

Step-by-step explanation:

We are asked to find y, a missing side in a triangle.

This triangle is special. There is a 30-degree angle and a right angle or 90 degree angle, the unlabeled angle is 60 degrees. This is a 30-60-90 triangle so the sides are always in a specific relationship.

The side across from the 30-degree angle is a, the hypotenuse is 2a, and the side across from the 60-degree angle is √3 a.

y is across from the 30 degree angle, so it is equal to a. However, we have to find a. We are given one side that measures 6. It is the hypotenuse because it is across from the right angle. Therefore, it is equal to 2a.

a is being multiplied by 2. Divide both sides by 2 to solve for a.

y is across from the 30-degree angle, so it is equal to a or 3.

We can also solve using the 3 main trigonometric functions.

y is opposite the 30-degree angle and 6 is the hypotenuse, and we will use sine.

[tex]sin \theta= \frac{opposite}{hypotenuse}[/tex]

[tex]sin (30)= \frac{y}{6}[/tex]

y is being divided by 6. The inverse operation of division is multiplication. Multiply both sides by 6 to solve for y.

[tex]6 * sin(30)= \frac{y}{6} *6[/tex]

[tex]6 * 0.5 = y[/tex]

[tex]3= y[/tex]

The missing side, y , is equal to 3.

Answer:

Hello,

None !!!

Step-by-step explanation:

[tex]f(x)=x(x+5)(x+2)\\=x(x^2+5x+2x+10)\\\\=x^3+7x^2+10x\\[/tex]

Step-by-step explanation:

People also ask

What is Heron's formula of area of triangle?

Then the semi-perimeter is, s = (a + b + c)/2 = (3 + 6 + 7)/2 = 8. We will find the area of the triangle using the Heron's formula. This formula was derived by a mathematician known as the Hero of Alexandria.

...

Area of Triangle With 3 Sides.

1. Area of Triangle with 3 Sides Formula

3. FAQs on Area of Triangle with 3 Sides

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Answer:

[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

Step-by-step explanation:

Heron's formula allows us to find the area of any triangle when given the length of the three sides of the triangle. Let [tex]s[/tex] represent the semi-perimeter of the triangle and let the three sides be [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex].

The semi-perimeter is equal to half the perimeter and is calculated by:

[tex]s=\frac{a+b+c}{2}[/tex]

After you've found [tex]s[/tex], multiply it by the difference between it and each of the sides of the triangle. Then take the square root of that value to find the area of the triangle. Therefore, Heron's Formula is:

[tex]\boxed{A=\sqrt{s(s-a)(s-b)(s-c)}}[/tex]

Answer:                                                      __

Yes I think so because 1.55555... is just 1.55. And that is rational so I would assume this is rational

Answer:

C

Step-by-step explanation:

The domain is the left side of the table

360 squared centimeter.

Answer:

Step-by-step explanation:

(-6 , 1) & (8 , 1)

d1 = 8 + I - 6I = 8 + 6 = 14

(1,6) & (1 , -4)

d2 = 6 + I -4 I = 6 + 4 = 10

Area of rhombus = [tex]\frac{d_{1}*d_{2}}{2}[/tex] where  d1 & d2 are the diagonals

                            [tex]\frac{14*10}{2} = 7 * 10 = 70 \ square \ units[/tex]

Answer:

C. x + 5

Brainliest, please!

Step-by-step explanation:

RS = 4x + 1 - (3x - 4)

RS = 4x + 1 - 3x + 4

RS = x + 5

Step-by-step explanation:

9.

it is a rectangle. 18m × 4m = 72 m²

the paving costs $35 per m², and we have 72 m², so it does not take a genius to figure out what to do next ...

right : we multiply 35 by 72

35×72 = $2520

10.

how much volume is a liter ?

a liter fits into a cube of 10cm side length.

and 1 meter = 100 cm = 10×10cm.

so, 1 m³ = 10×10×10 = 1000 such cubes of 10cm side length = 1000 liters.

the pool is 5 m × 15 m × 1.5 m = 112.5 m³ = 112500 liters

we need 2 kg salt for every 10000 liters water, so we have how many units of 10000 liters in the pool ?

112500 / 10000 = 11.25

so, we need

11.25 × 2 = 22.5 kg salt

11.

12 seconds = 1/5 of a minute.

so, batman runs at 3 km / min (= 60×3 km/hour = 180 km/h - not possible in real life for any human being, but let's play ...) for 12 seconds = 1/5th of a minute, and so he runs 3km/5 = 600 meters in that time.

that means he has 2km - 600m = 1400m left to run in the 2 km race.

it takes him 1400/3000th of a minute (3000 m would take him the full minute)

1400 m × minute / 3000 m = 14/30 = 7/15 minutes

1/15th minute = 60 seconds / 15 = 4 seconds.

so, 7/15th of a minute = 7×4 seconds = 28 seconds.

the bionic woman runs the full 2000 m with 5 km / minute.

it takes her 2000/5000th of a minute

2000 m × minute / 5000 = 2/5th of a minute.

1/5th of a minute is 60 seconds / 5 = 12 seconds.

so, 2/5th of a minute is 12×2 = 24 seconds.

therefore, the bionic woman wins by 4 seconds (24 seconds vs. 28 seconds).

12.

there is enough food for 150 students for 5 days = 150×5 =750 "food units".

therefore, if there were only 100 students, the food would last 750/100 = 7.5 days.

and if the food runs out after 4 days it means there are

750/4 = 187.5 students (how much sense that makes to have half a student ...).

13.

x = the workload to be done

Michelle's work speed is x/6 days

Danielle's work speed is x/4 days

on each day working together they achieve

1× x/6 + 1× x/4 of the total work load.

that is

2x/12 + 3x/12 = 5x/12

so, they need 5x/12 × a days to finish the whole x.

5x/12 × a = x

5/12 × a = 1

5a = 12

a = 12/5 = 2.4 days to finish the whole work when working together.

Answer:

rgre5ydytye453efdfe45fgs4terwt

Step-by-step explanation:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbvbcn

Answer:1. 0.889, 2. −0.4, 3. 0.636 (i rounded the answers to the nearest thousandths)

Step-by-step explanation: the thing is when you are changing them from fraction to decimal you use long division for example

let us say the fraction is a half.

we put the numerator inside and the denominator outside.

so in this case 2 is outside and 1 is inside.

(forgive my drawing)

So after the zero we put a point if it is any number we still put a point after the first division answer.

We also put a zero next to 1 even though it is any other number a the answer on top we still put a zero if the number is over like in this case.

so 10 divide by 2 is 5 we put it on top.

Since we got an answer with no reminder our answer is 0.5.

The sides of the image and pre-image are congruent

Each point has moved the same number of units

Answer:

Given expression:

The first root is valid when:

The second root is valid when:

So the variable x can get values within interval:

Answer:

y=-11

Step-by-step explanation:

A line can be represented by a linear equation of

[tex]y = mx + b[/tex]

where m is the slope and y is the y intercept.

The slope is 0 so this function will be

[tex]y = b[/tex]

Which is also called a constant function. The y intercept is -11. So the answer is

[tex]y = - 11[/tex]

2 | 550,750,900

2 | 275,375,450

3 | 275,375,225

3 | 275,125,75

5 | 275,125,25

5 | 55,25,5

5 | 11,5,5

11 | 11,1,1

LCM:-2×2×3×3×5×5×5×11=49500

Lets solve

[tex]\\ \sf\longmapsto 7w<-56[/tex]

[tex]\\ \sf\longmapsto w<dfrac{-56}{7}[/tex]

[tex]\\ \sf\longmapsto w<-8[/tex]

Answer:

[tex]\boxed {\boxed {\sf w < -8}}[/tex]

Step-by-step explanation:

We are given an inequality and asked to solve for the variable w.

[tex]7w < -56[/tex]

In order to solve for w, we must isolate the variable. It is being multiplied by 7. The inverse of multiplication is division, so we divide both sides of the inequality by 7.

[tex]\frac {7w}{7} < \frac {-56}{7}[/tex]

[tex]w < \frac{-56}{7}[/tex]

[tex]w < -8[/tex]

w is less than -8 or w < -8.

Answer:

please help me to solve these qustions

Answer:

If the son’s age is x, the father’s age is 2x.

If the son’s age is x, the father’s age is 2x.Ten years ago:

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 52

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 52

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 24

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.

.

.

Answer:

Step-by-step explanation:

Answer:

Total earning last week = 225

Step-by-step explanation:

Given:

Earning per hour = 12 pesos

Deduct per late delivery = 15 pesos

Total number of hour = 25 hour

Total number of late delivery = 5

Find:

Total earning last week

Computation:

Total earning last week = (Total number of hour)(Earning per hour) - (Deduct per late delivery)(Total number of late delivery)

Total earning last week = (12)(25) - (15)(5)

Total earning last week = 300 - 75

Total earning last week = 225