Geometry help pls and thank you :)


What is the area of this triangle?



Enter your answer in the box.

(answer) units²

Answer:

-1

Step-by-step explanation:

(-2 , 5) = (x1 , y1)

(6 , -3) = (x2 , y2)

slope of a line = y2 - y1/x2 - x1

=-3 - 5/6 - (-2)

=-8/6+2

=-8/8

=-1

therefore slope of a line is -1.

Answer:

The maximum volume of the box is:

[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]

Step-by-step explanation:

Given

[tex]Surface\ Area = 10m^2[/tex]

Required

The maximum volume of the box

Let

[tex]a \to base\ dimension[/tex]

[tex]b \to height[/tex]

The surface area of the box is:

[tex]Surface\ Area = 2(a*a + a*b + a*b)[/tex]

[tex]Surface\ Area = 2(a^2 + ab + ab)[/tex]

[tex]Surface\ Area = 2(a^2 + 2ab)[/tex]

So, we have:

[tex]2(a^2 + 2ab) = 10[/tex]

Divide both sides by 2

[tex]a^2 + 2ab = 5[/tex]

Make b the subject

[tex]2ab = 5 -a^2[/tex]

[tex]b = \frac{5 -a^2}{2a}[/tex]

The volume of the box is:

[tex]V = a*a*b[/tex]

[tex]V = a^2b[/tex]

Substitute: [tex]b = \frac{5 -a^2}{2a}[/tex]

[tex]V = a^2*\frac{5 - a^2}{2a}[/tex]

[tex]V = a*\frac{5 - a^2}{2}[/tex]

[tex]V = \frac{5a - a^3}{2}[/tex]

Spit

[tex]V = \frac{5a}{2} - \frac{a^3}{2}[/tex]

Differentiate V with respect to a

[tex]V' = \frac{5}{2} -3 * \frac{a^2}{2}[/tex]

[tex]V' = \frac{5}{2} -\frac{3a^2}{2}[/tex]

Set [tex]V' =0[/tex] to calculate a

[tex]0 = \frac{5}{2} -\frac{3a^2}{2}[/tex]

Collect like terms

[tex]\frac{3a^2}{2} = \frac{5}{2}[/tex]

Multiply both sides by 2

[tex]3a^2= 5[/tex]

Solve for a

[tex]a^2= \frac{5}{3}[/tex]

[tex]a= \sqrt{\frac{5}{3}}[/tex]

Recall that:

[tex]b = \frac{5 -a^2}{2a}[/tex]

[tex]b = \frac{5 -(\sqrt{\frac{5}{3}})^2}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{5 -\frac{5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{15 - 5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{10}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{5}{3}}{\sqrt{\frac{5}{3}}}[/tex]

Apply law of indices

[tex]b = (\frac{5}{3})^{1 - \frac{1}{2}}[/tex]

[tex]b = (\frac{5}{3})^{\frac{1}{2}}[/tex]

[tex]b = \sqrt{\frac{5}{3}}[/tex]

So:

[tex]V = a^2b[/tex]

[tex]V =\sqrt{(\frac{5}{3})^2} * \sqrt{\frac{5}{3}}[/tex]

[tex]V =\frac{5}{3} * \sqrt{\frac{5}{3}}[/tex]

[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]

The maximum volume of the box which has a 10 m² surface area is given below.

[tex]\rm V_{max} = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

We want to construct a box with a square base and we currently only have 10 m² of material to use in the construction of the box.

The surface area = 10 m²

Let a be the base length and b be the height of the box.

Surface area = 2(a² + 2ab)

  2(a² + 2ab) = 10

      a² + 2ab = 5

Then the value of b will be

[tex]\rm b = \dfrac{5-a^2}{2a}[/tex]

The volume of the box is given as

V = a²b

Then we have

[tex]\rm V = \dfrac{5-a^2 }{2a}* a^2\\\\V = \dfrac{5a - a^3}{2}\\\\V = \dfrac{5a}{2} - \dfrac{a^3}{2}[/tex]

Differentiate the equation with respect to a, and put it equal to zero for the volume to be maximum.

[tex]\begin{aligned} \dfrac{dV}{da} &= \dfrac{d}{da} ( \dfrac{5a}{2} - \dfrac{a^3}{2} ) \\\\\dfrac{dV}{da} &= 0 \\\\\dfrac{5}{2} - \dfrac{3a^2 }{2} &= 0\\\\a &= \sqrt{\dfrac{5}{2}} \end{aligned}[/tex]

Then the value of b will be

[tex]b = \dfrac{5-\sqrt{\dfrac{5}{2}} }{2*\sqrt{\dfrac{5}{2}} }\\\\\\b = \sqrt{\dfrac{5}{2}}[/tex]

Then the volume will be

[tex]\rm V = (\sqrt{\dfrac{5}{2}} )^2*\sqrt{\dfrac{5}{2}} \\\\V = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]

More about the differentiation link is given below.

https://brainly.com/question/24062595

using sin∆ = 5/13

= 0.3846

therefore ∆ = 22.62

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the image of the polygon is not given.

I will answer this question with the attached image (similar to your question)

The attached polygon is a trapezoid of the following dimensions.

[tex]Height = 4ft[/tex]

Parallel sides

[tex]Side\ 1 = 4ft[/tex]

[tex]Side\ 2 = 4ft+1ft = 5ft[/tex]

So, the area is:

[tex]Area = \frac{1}{2} * (Side\ 1 + Side\ 2) * Height[/tex]

[tex]Area = \frac{1}{2} * (4ft + 5ft) * 4ft[/tex]

[tex]Area = \frac{1}{2} * 9ft * 4ft[/tex]

[tex]Area = 18ft^2[/tex]

Answer:

84 sq meters

Step-by-step explanation:

First, divide the shape in 2 or more parts so that you can find it step by step

Divide this shape in three parts:

One part (blue): 2 m and 3 m rectangle

Second part (orange): 5 m and 12 m rectangle

Third part (red): 6 m and 3 m rectangle

(you can also see this below: in the pic there are three parts so you figure out that which is the correct value for the sides)

Now, find area of each shape by multiplying its values:

1st shape: 3 x 2 = 6

2nd shape: 5 x 12 = 60

3rd shape: 6 x 3 = 18

As you have the area of all the different shapes,

add all of them:

6 + 60 + 18 = 84 sq meters

I hope this helps :)

Answer:

B

Step-by-step explanation:

Have a nice day :)

The circumcenter is the center of the circle that contains the vertices of a triangle

When a triangle is inscribed in a circle, the vertices of the triangle touch the circumference of the circle

A line drawn through the center of the circle and passes through each of the triangle vertex is its circumcenter.

Hence, the name of the required point is the circumcenter

Read more about circumcenter at:

https://brainly.com/question/14368399

#SPJ2

Answer:

B. The point of intersection of the perpendicular bisectors of the side

Step-by-step explanation:

definition of circumcenter as the previos question answered

9514 1404 393

Answer:

  10

Step-by-step explanation:

Possible tower heights using 3 blocks are ...

  {9, 10, 11, 12, 14, 15, 16, 19, 20, 24}

There are 10 different heights possible.

_____

Each block can be used 1, 2, or 3 times.

Using a 3 in block as the smallest, we have ...

  3+3+3 = 9

  3+3+4 = 10

  3+3+8 = 14

  3+4+4 = 11

  3+4+8 = 15

  3+8+8 = 19

Using a 4-in block as the smallest, we have ...

  4+4+4 =12

  4+4+8 = 16

  4+8+8 = 20

And ...

  8+8+8 = 24

The number of patients chose chicken on Monday is 90.

In Mathematics, fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

Given that, there were 240 patients in total.

1/3 of these patients chose pasta.

Number of patients chose pasta

= 1/3 ×240

= 60

3/8 of these patients chose beef stew.

Number of patients chose beef stew

= 3/8 ×240

= 90

Number of patients chose chicken

= 240-(60+90)

= 240-150

= 90

Therefore, the number of patients chose chicken on Monday is 90.

To learn more about the fraction visit:

brainly.com/question/1301963.

#SPJ2

Answer:

3/10

Step-by-step explanation:

1/10 + 1/5 =          need to get common denominators to add.

1/10 + 2/10 = 3/10

Answer:

285 mi

Step-by-step explanation:

We can see that for every gallon, Josh drives 30 more miles. This means that he will drive 30*9.5 mi.

30*9.5 = 285

Answer:

3/4 and -3/4

or

0.75 and -0.75

but there is no solution for

10 times the smaller number added to 6 times the larger number to get 3 as result.

the absolute values of x and y must be equal and with opposite signs (due to their sum being 0).

therefore, 10 times the negative value can never be compensated by 6 times the same but positive value. the sum will always be negative and not positive (and therefore not +3).

it only works with 10 times the larger (positive) number plus 6 times the smaller (negative) value.

Step-by-step explanation:

x + y = 0

10×x + 6×y = 3

=>

x = -y

10×(-y) + 6×y = 3

-10y + 6y = 3

-4y = 3

y = -3/4

=>

x = -y = -(-3/4) = 3/4

control :

10×(3/4) + 6×(-3/4) = 30/4 - 18/4 = 3

12/4 = 3

3 = 3

correct

Answer:

hey. pls complete your question.

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

[tex]\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right][/tex]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Answer:

√53

Step-by-step explanation:

Distance between two points =  

√(4−6)^2+(−2−5)^2

√(−2)^2+(−7)^2  

= √4+49

=√53

= 7.2801

Hope this helps uwu

9514 1404 393

Answer:

  option 2: √53

Step-by-step explanation:

The distance formula is useful for this:

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)

  d = √53

The distance between the given points is √53.

Step-by-step explanation:

by order pair we obtain:

[tex] \displaystyle \begin{cases} \displaystyle 3p = 2p - 1 \dots \dots i\\2q - p = 1 \dots \dots ii\end{cases}[/tex]

cancel 2p from the i equation to get a certain value of p:

[tex] \displaystyle \begin{cases} \displaystyle p = - 1 \\2q - p = 1 \end{cases}[/tex]

now substitute the value of p to the second equation:

[tex] \displaystyle \begin{cases} \displaystyle p = - 1 \\2q - ( - 1) = 1 \end{cases}[/tex]

simplify parentheses:

[tex] \displaystyle \begin{cases} \displaystyle p = - 1 \\2q + 1= 1 \end{cases}[/tex]

cancel 1 from both sides:

[tex] \displaystyle \begin{cases} \displaystyle p = - 1 \\2q = 0\end{cases}[/tex]

divide both sides by 2:

[tex] \displaystyle \begin{cases} \displaystyle p = - 1 \\q = 0\end{cases}[/tex]

by order pair we obtain:

[tex] \displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\3y= x + y \dots \dots ii\end{cases}[/tex]

cancel out y from the second equation:

[tex] \displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\ x = 2y \dots \dots ii\end{cases}[/tex]

substitute the value of x to the first equation:

[tex] \displaystyle \begin{cases} \displaystyle 2.2y-y= 3 \\ x = 2y \end{cases}[/tex]

simplify:

[tex] \displaystyle \begin{cases} \displaystyle 3y= 3 \\ x = 2y \end{cases}[/tex]

divide both sides by 3:

[tex] \displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2y \end{cases}[/tex]

substitute the value of y to the second equation which yields:

[tex] \displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2 \end{cases}[/tex]

by order pair we obtain;

[tex] \displaystyle \begin{cases} \displaystyle 2p + q = 2 \dots \dots i\\3q + 2p = 3 \dots \dots ii\end{cases}[/tex]

rearrange:

[tex] \displaystyle \begin{cases} \displaystyle 2p + q = 2 \\2p + 3q= 3 \end{cases}[/tex]

subtract and simplify

[tex] \displaystyle \begin{array}{ccc} \displaystyle 2p + q = 2 \\2p + 3q= 3 \\ \hline - 2q = - 1 \\ q = \dfrac{1}{2} \end{array}[/tex]

substitute the value of q to the first equation:

[tex] \displaystyle 2.p+ \frac{1}{2} = 2[/tex]

make q the subject of the equation:

[tex] \displaystyle p = \frac{3}{4} [/tex]

hence,

[tex] \displaystyle q = \frac{1}{2} \\ p = \frac{3}{4} [/tex]

Answer:

see above

............

Answer:

The plumber worked 50 hours, and his assistant worked 25 hours.

Step-by-step explanation:

Since a plumber and his assistant work together to replace the pipes in an old house, and the plumber charges $ 30 an hour for his own labor and $ 20 an hour for his assistant's labor, and the plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $ 2000, to determine how long did the plumber and his assistant work on this job the following calculation must be performed:

40 x 30 + 20 x 20 = 1200 + 400 = 1600

50 x 30 + 25 x 20 = 1500 + 500 = 2000

Therefore, the plumber worked 50 hours, and his assistant worked 25 hours.

Answer:

1 1/6

Step-by-step explanation:

5/6 + 3/9

Simplify 3/9 by dividing the top and bottom by 3

5/6 + 1/3

Get a common denominator of 6

5/6 + 1/3 *2/2

5/6 + 2/6

7/6

Rewriting

6/6 +1/6

1 1/6

Given:

1. 60 is the sum of 15 and Mabel's age.

2. Given equation is

[tex]-8(x+1)=-40[/tex]

To find:

1. The equation for the given situation.

2. Complete the two column proof.

Solution:

1.

60 is the sum of 15 and Mabel's age.

Let m be the Mabel's age. Then,

[tex]15+m=60[/tex]

Therefore, the required equation for the given situation is [tex]15+m=60[/tex].

2.

The complete two column proof is:

        Steps                                            Reasons

[tex]-8(x+1)=-40[/tex]                                   Given equation

[tex]\dfrac{-8(x+1)}{-8}=\dfrac{-40}{-8}[/tex]                                  Division Property of Equality

[tex]x+1=5[/tex]                                               Simplifying

[tex]x+1-1=5-1[/tex]                                   Subtraction Property of Equality

[tex]x=4[/tex]                                                     Simplifying

Answer:

arc cosine (4/5)

(the third answer)

Step-by-step explanation:

a) [tex]\log \left(\dfrac{A^3B}{C} \right) = 3\log A + \log B - \log C[/tex]

b) [tex]\log \left(\dfrac{\sqrt{A}}{B^2} \right) = \frac{1}{2}\log A - 2\log B[/tex]

Answer:

A; 120 cubic inches

Step-by-step explanation:

Let us start with the formula of the volume of a rectangular prism,[tex]V=l*w*h[/tex], where l represents the length of the prism, w represents the width of the prism, and h represents the height of the prism. It is given to us that h =5 inches, w =3 inches, and l =8 inches. Let's plug the values in:

[tex]V= 8*3*5\\V=120[/tex]

A. The volume of the rectangular prism is 120 cubic inches.

I hope this helps! Let me know if you have any questions :)

D: 2/7

The probability of an event x is how likely the event will occur. It is given as;

P(x) = number of expected outcomes / number of possible outcomes

Given:

Event A = The place is a city.

Therefore,

P(A) is the probability that the event A happens. i.e the probability that a place is a city.

P([tex]A^c[/tex]) is the probability that the event A does not happen. i.e the probability that a place is not a city

Also,

The sum of the probability that an event happens and the probability that the event does not happen is equal to 1. i.e

P(A) + P([tex]A^c[/tex]) = 1

From the table,

P([tex]A^c[/tex]) is found by counting the number of places that does not have a tick on the "is a city" column, then divide the result by the total number of places. i.e

P([tex]A^c[/tex]) = 2 ÷ 7

P([tex]A^c[/tex]) = 2/7

Therefore P([tex]A^c[/tex]) which is the probability that the place is not a city is 2/7

Answer:

10

Step-by-step explanation:

We know there are 5 quarts.

There are 2 pints for each quart.

This can be though of as a ratio of:

2 : 1

There are 5 quarts, which is 5 times bigger than the ratio of 1.

So this means we need to mutliply both sides of the ratio by 5, to make the quarts equivelent to 5:

2*5 : 1*5

=

10 : 5

So for every 5 quarts there are 10 pints.

Hope this helps!

Answer:

Ŷ = 76.4064+5.4254X

0.786

Strong positive relationship

Score = 98

Step-by-step explanation:

Using technology, the linear model obtained by fitting the data is :

Ŷ = 76.4064+5.4254X

Where, slope = 5.4254

y = test score ; x = study time

The Correlation Coefficient obtained is 0.786 ; which depicts that there exist a strong positive relationship between the two variables.

Using the model; test score, if x = 4

Ŷ = 76.4064+5.4254(4)

Y = 98.108

Test score = 98