geometry peculiar pool
please help!!!

after the sketch answer
1. Let x represent the length of BC. Write expressions for the lengths of AB, CD, and DE.

Answer:

rgre5ydytye453efdfe45fgs4terwt

Step-by-step explanation:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbvbcn

Answer:1. 0.889, 2. −0.4, 3. 0.636 (i rounded the answers to the nearest thousandths)

Step-by-step explanation: the thing is when you are changing them from fraction to decimal you use long division for example

let us say the fraction is a half.

we put the numerator inside and the denominator outside.

so in this case 2 is outside and 1 is inside.

(forgive my drawing)

So after the zero we put a point if it is any number we still put a point after the first division answer.

We also put a zero next to 1 even though it is any other number a the answer on top we still put a zero if the number is over like in this case.

so 10 divide by 2 is 5 we put it on top.

Since we got an answer with no reminder our answer is 0.5.

Answer:

Step-by-step explanation:

The lateral surface area is:

[tex]\\ \tt\longmapsto SA=2\pi rh[[/te]

[tex]\\ \tt\longmapsto SA=2\times 22}{7}\times (2.5)(9.25)[/tex]

[tex]\\ \tt\longmapsto SA=145.23in^2[/tex]

Answer:

<1 = 64

Step-by-step explanation:

The exterior angle is equal to the sum of  the opposite interior angles for triangles

40  +<1 = 104

Subtract 40 from each side

<1 = 104 -40

<1 = 64

Answer:

y=-11

Step-by-step explanation:

A line can be represented by a linear equation of

[tex]y = mx + b[/tex]

where m is the slope and y is the y intercept.

The slope is 0 so this function will be

[tex]y = b[/tex]

Which is also called a constant function. The y intercept is -11. So the answer is

[tex]y = - 11[/tex]

Answer: 1/3

Step-by-step explanation:

On side of the smaller quadrilateral is 8, the same side on the larger one is 24. 8 times 3 is 24. So the scale factor from the smaller to the larger is 1/3.

Answer:

1/3

Step-by-step explanation:

similar means all sides are proportinal, in this case one side is 3x bigger in the 2nd figure, so the same must be true of the other fig.

Answer:

7.2

Step-by-step explanation:

Apply Law of Cosines, given that b is 13.5, c is 8.9, and Angle a is 29.

[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \cos(a) [/tex]

[tex] {a}^{2} = {13.5}^{2} + {8.9}^{2} - 2(13.5)(8.9) \times \cos(29) [/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 240.3 \times 0.8746[/tex]

[tex] {a}^{2} = 182.25 + 79.21 - 210.1711[/tex]

[tex]a = 7.2[/tex]

Answer:

[tex]a\approx7.2[/tex]

Step-by-step explanation:

The given problem presents one with the following information:

To solve this problem, one can use the law of cosines. The law of cosines is a property that can apply to any triangle. This property comes in the form of a formula, which is as follows:

[tex]a^2=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

Where (a), (b), and (c) are sides of the triangle, and (<A) is the angle opposite the side (a).

Substitute the given information into the formula and solve for the unknown side (a):

[tex]a=\sqrt{b^2+c^2-2bc(cos(A))}[/tex]

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

Simplify,

[tex]a=\sqrt{(13.5)^2+(8.9)^2-2(13.5)(8.9)(cos(29))}[/tex]

[tex]a=\sqrt{182.25+79.21-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-240.3(cos(29))}[/tex]

[tex]a=\sqrt{261.46-210.1711}[/tex]

[tex]a=\sqrt{51.2889}[/tex]

[tex]a\approx7.2[/tex]

Answer:

The answer is x=3. YOU add the 6 to the zero and then divide the 2x by 6 and you get 3

Hi there!

check the pic

#YoghurtCup!

Answer: F

Step-by-step explanation:

Put all numbers with 1 exponent.

[tex](\sqrt{8^4} *\sqrt{6^4} )^{\frac{3}{2} }\\\\=(2^{\frac{3*4}{2} }*(2^{\frac{4}{2} }*3^{\frac{4}{2}} )\ )^{\dfrac{3}{2} }\\\\\\=(2^6*2^2*3^2)^{\dfrac{3}{2} }\\\\=2^{8*\frac{3}{2} }*3^{2*\frac{3}{2}} \\\\\\\boxed{=2^{12}*3^3}\\\\\\Answer\ F[/tex]

Answer:

90

Step-by-step explanation:

Use angle-arc relation,

For a and 45, Inscribed angle's relation can be utilized

Inscribed angle=Half the arc

45=1/2a

Therefore, a=90

Lets solve

[tex]\\ \sf\longmapsto 7w<-56[/tex]

[tex]\\ \sf\longmapsto w<dfrac{-56}{7}[/tex]

[tex]\\ \sf\longmapsto w<-8[/tex]

Answer:

[tex]\boxed {\boxed {\sf w < -8}}[/tex]

Step-by-step explanation:

We are given an inequality and asked to solve for the variable w.

[tex]7w < -56[/tex]

In order to solve for w, we must isolate the variable. It is being multiplied by 7. The inverse of multiplication is division, so we divide both sides of the inequality by 7.

[tex]\frac {7w}{7} < \frac {-56}{7}[/tex]

[tex]w < \frac{-56}{7}[/tex]

[tex]w < -8[/tex]

w is less than -8 or w < -8.

Answer:

C

Step-by-step explanation:

The domain is the left side of the table

Answer:                                                      __

Yes I think so because 1.55555... is just 1.55. And that is rational so I would assume this is rational

Answer:

hope this helps

Step-by-step explanation:

hope this helps

2 | 550,750,900

2 | 275,375,450

3 | 275,375,225

3 | 275,125,75

5 | 275,125,25

5 | 55,25,5

5 | 11,5,5

11 | 11,1,1

LCM:-2×2×3×3×5×5×5×11=49500

if you convert it all into one hour, Team B clearly worked at a faster pace.

Answer:

[tex]team \: a \: \\ 8in \: number \: with \: in \: 2 \: hours \\ so \: in \: 1 \: hour \: \frac{8}{2} = 4 \: in \: number \\ \\ team \: b \\ 5 \: in \: 1hour \\ so \: \: team \: b \: work \: in \: fast \\ thank \: you[/tex]

Answer:

The answer is  x = 2y

Step-by-step explanation:

(3x + 2y) (3y + 2 y)

3x = 3y + 2y + 2y

3x = 7y

x = 7 ÷ 3

x = 2y

The gometric means G1, G2, G3, 1/4

Answer:

13.5

Step-by-step explanation:

Given

tan34° = [tex]\frac{x}{20}[/tex] ( multiply both sides by 20 )

20 × tan34° = x , then

x ≈ 13.5 ( to the nearest tenth )

Answer:

Step-by-step explanation:

V = B * h

B = pi r^2

r = 12 km

B = 12^2 * pi

B = 144 * pi

h = 7 km

Volume = 144 *7 * pi

Volume = 1008 * pi

Volume = 3165.1

Answer:

If the son’s age is x, the father’s age is 2x.

If the son’s age is x, the father’s age is 2x.Ten years ago:

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 52

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 52

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 24

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48

If the son’s age is x, the father’s age is 2x.Ten years ago:(x - 10) + (2x - 10) = 523x + 20 = 523x = 72x = 242x = 48So the son’s age is 24 and the father’s is 48. Ten years ago, they were 14 and 38, which adds up to 52.

.

.

Answer:

false it would be something like x root 2

Step-by-step explanation:

Step-by-step explanation:

Step-by-step explanation:

People also ask

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Then the semi-perimeter is, s = (a + b + c)/2 = (3 + 6 + 7)/2 = 8. We will find the area of the triangle using the Heron's formula. This formula was derived by a mathematician known as the Hero of Alexandria.

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Answer:

[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

Step-by-step explanation:

Heron's formula allows us to find the area of any triangle when given the length of the three sides of the triangle. Let [tex]s[/tex] represent the semi-perimeter of the triangle and let the three sides be [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex].

The semi-perimeter is equal to half the perimeter and is calculated by:

[tex]s=\frac{a+b+c}{2}[/tex]

After you've found [tex]s[/tex], multiply it by the difference between it and each of the sides of the triangle. Then take the square root of that value to find the area of the triangle. Therefore, Heron's Formula is:

[tex]\boxed{A=\sqrt{s(s-a)(s-b)(s-c)}}[/tex]

Answer:

Hello,

None !!!

Step-by-step explanation:

[tex]f(x)=x(x+5)(x+2)\\=x(x^2+5x+2x+10)\\\\=x^3+7x^2+10x\\[/tex]

[tex]\boxed{\sf sin\Theta=\dfrac{P}{H}}[/tex]

[tex]\\ \sf\longmapsto sin\theta=\dfrac{4}{16}[/tex]

[tex]\\ \sf\longmapsto sin\theta=\dfrac{1}{4}[/tex]

[tex]\\ \sf\longmapsto sin\theta=\dfrac{sin30}{2}[/tex]

[tex]\\ \sf\longmapsto sin\theta=sin15[/tex]

[tex]\\ \sf\longmapsto \theta=15°[/tex]