Answers
Answer:
XY = 24
Step-by-step explanation:
In similar triangles, the corresponding sides are in same ratio.
[tex]\frac{AC}{XZ}=\frac{AB}{XY}\\\\\frac{x+6}{30}=\frac{16}{2x-4}[/tex]
Cross multiply,
(x + 6 )(2x-4) = 16*30
Use FOIL method
x*2x + x*(-4) + 6*2x + 6*(-4) = 480
2x² - 4x + 12x - 24 = 480 {Combine like terms}
2x² + 8x - 24 = 480
2x² + 8x - 24 - 480 = 0
2x² + 8x - 504 = 0
Divide the entire equation by 2
x² + 4x - 252 = 0
Sum = 4
Product = -252
Factors = 18 , -14 {18 +(-14) = 4 & 18*(-14) = -254 }
x² + 4x - 252 = 0
x² + 18x - 14x - 252 = 0 {Rewrite middle term}
x(x + 18) - 14(x + 18) = 0
(x + 18)(x - 14) = 0
x - 14 = 0 {Ignore x + 18 = 0 as measurement will not come in negative}
x = 14
XY = 2x - 4
= 2*14 -4
= 28 - 4
= 24
Related Questions
Am I suppose to substitute the variables with random numbers in order to answer these questions???
Translation A maps (x, y) to (x + n, y + 1). Translation B maps (x, y) to (x +s, y + m).
1. Translate a point using Translation A, followed by Translation B. Write an algebraic rule for the final image of the point after this composition.
2. Translate a point using Translation B, followed by Translation A. Write an algebraic rule for the final image of the point after this composition.
3. Compare the rules you wrote for parts (a) and (b). Does it matter which translation you do first? Explain your reasoning.
Answers
9514 1404 393
Answer:
(x, y) ⇒ (x +n +s, y +1 +m)(x, y) ⇒ (x +s +n, y +m +1)they are identical in effect; order does not matterStep-by-step explanation:
Substitute the expressions.
A then BAfter the first translation, the value of x is (x+n). Put that as the value of x in the second translation.
x ⇒ x +s . . . . . . . . . the definition of the second translation
(x+n) ⇒ (x+n) +s . . . the result after both translations
The same thing goes for y. After the first translation, its new value is (y+1).
y ⇒ y +m . . . . . . . . the definition of the second translation
(y+1) ⇒ (y+1) +m . . . the result of both translations
Then the composition of A followed by B is (x, y) ⇒ (x +n +s, y +1 +m).
__
B then AThe same reasoning applies. After the B translation, the x-coordinate is (x+s) and the y-coordinate is (y+m). Then the A translation changes these to ...
x ⇒ x +n . . . . . . . . . . definition of translation A
(x+s) ⇒ (x+s) +n . . . . translation A operating on point translated by B
y ⇒ y +1 . . . . . . . . . . . definition of translation A
(y+m) ⇒ (y+m) +1 . . . . translation A operating on point translated by B
The composition of B followed by A is (x, y) ⇒ (x + s + n, y + m + 1).
__
You should recognize that the sums (x+n+s) and (x+s+n) are identical. The commutative and associative properties of addition let us rearrange the order of the terms with no effect on the outcome.
The two translations give the same result in either order.
u4gent help needed
help me with the question of o.math
Answers
Answer:
1≤f(x)≤5
Step-by-step explanation:
-1≤x≤1
-2≤2x≤2 (Multiplied by 2 both side)
-2+3≤2x+3≤2+3 (Adding three both sides)
1≤f(x)≤5
0.25(4f-3)=0.005(10f-9)
Simplify the following
Answers
Answer:
apoco la propiedad asociativa en los siguiente ejercicio 25x11x18=
find the mean value of the following. 5, 11, 4, 10, 8, 6
Answers
44/6 = 7.33….
answer: 7.33…..
Help what is x
When x^5 is 225
Answers
Answer:
Solution given:
x^5=225
we have
x=[tex] \sqrt[5]{225} [/tex]
x=2.9541
Hello!
[tex] \bf {x}^{5} = 225[/tex]
Extract the radical on both sides of the equation.[tex] \bf x = \sqrt[5]{225} [/tex]
[tex] \bf x ≈2.95418[/tex]
Answer: x ≈ 2,95418
Good luck! :)
Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...
A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34
Answers
the answer is
A. 28, 25, 22
[tex]x + 0.25 = -0.25[/tex]
Answers
Answer:
x = -0.5
Step-by-step explanation:
x + 0.25 = -0.25
x = -0.25 - 0.25
x = -0.5
If you have to invest in an account that pays 5.3 compound annually, after 10 years how much interest is earned
Answers
[tex]\\ \sf\longmapsto Interest=Rate\times Time[/tex]
[tex]\\ \sf\longmapsto Interest=5.3(10)[/tex]
[tex]\\ \sf\longmapsto Interest =53[/tex]
It means that if your principal is $100 after 10years you will receive $53 as interest
Step-by-step explanation:
[tex]thank \: you[/tex]
In the number 9663 which places contain digits where one dogit is 10 times as great as the other?
Answers
Answer: Hundreds and tens place values (the two copies of '6')
Explanation:
We're looking for where the digits are the same, which would be those two copies of '6'
The first 6 on the left is in the hundreds place. It represents 600
The other 6 is in the tens place, and it represents 60
The jump from 60 to 600 is "times 10".
Point Q is located at (-4, 6). Point R is located at (8, 6).
What is the distance from point Q to point R?
Answers
Step-by-step explanation:
Hi there!
Given;
Point Q is located at (-4, 6). Point R is located at (8, 6).
Note: Use distance formula.
Now;
[tex](d) = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]
Keep all values;
[tex](d) = \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2} } [/tex]
Simplify;
[tex](d) = \sqrt{( {12)}^{2} } [/tex]
Therefore, the distance is 12 units.
Hope it helps!
HELP ITS DUE IN THE MORNING AND ITS 3:57
Answers
Answer:
A " (1,-2)
B " (4,0)
C " (6,-3)
Step-by-step explanation:
Hope it helped.
° ° °
2^12÷2^(k/2 )= 32 find k
Answers
Answer:
k = 14
Step-by-step explanation:
Prime factorize 32
32 = 2 * 2 * 2 * 2 * 2 = 2⁵
[tex]\frac{2^{12}}{2^{\frac{k}{2}}}= 32\\\\\frac{2^{12}}{2^{\frac{k}{2}}}=2^{5}\\\\2^{12-\frac{k}{2}}=2^{5}[/tex]
Both sides base are same.So, compare exponents
[tex]12-\frac{k}{2}=5\\[/tex]
Subtract 12 from both side
[tex]-\frac{k}{2}=5-12\\\\-\frac{k}{2}=-7\\[/tex]
Multiply both sides by (-2),
[tex](-2)*(-\frac{k}{2})=-7*(-2)\\\\k = 14[/tex]
Describe the pattern in the following sequence and list the next three terms:
4, 8, 16, 32, ...
I’ll mark brainliest! Please help me
Answers
Multiples of 4 after continuing 2 digits skip one multiple and continue;-;
a sum of money Doubles itself in 5 years what is rate of simple interest
Answers
Step-by-step explanationIf you are reading this say
thank u
Find the surface area of the triangular prism
Answers
1/2 x 6 x 4 = 12
Back: 12 square centimeters
1/2 x 6 x 4 = 12
Right: 15 square centimeters
3 x 5 = 15
Left: 15 square centimeters
3 x 5 = 15
TOTAL: 54 square centimeters
The surface area is the added areas of each face of a 3D figure.
Formulas I’ve used:
Area of a parallelogram:
A = bh
Area of a triangle:
A = 1/2bh
If n equals 5 and b equals 4 what is n + b * 5
Answers
Answer:
25Step-by-step explanation:
Given,
n = 5
and, b = 4
Equation:
n + b × 5
= 5 + 4 × 5
= 5 + 20
= 25 (Ans)
Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3
Answers
Answer:
O D. 3x2 + 2x-3
Answer:
A.7x2-5x questions 2of 20
help please ITS OF TRIGONOMETRY
PROVE
Answers
Answer:
The equation is true.
Step-by-step explanation:
In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation. Please note that each side is named with respect to the angle is it across from.
Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}[/tex]
One is given the following equation,
[tex]\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0[/tex]
As per the attached reference image, one can state the following, using the right angle trigonometric ratios,
[tex]sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}[/tex]
Substitute these values into the given equation. Then simplify the equation to prove the idenity,
[tex]\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0[/tex]
[tex]\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0[/tex]
[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}[/tex]
Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).
[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}[/tex]
[tex]\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}[/tex]
[tex]1+(-1)=0[/tex]
[tex]1-1=0[/tex]
[tex]0=0[/tex]
Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=
Answers
Answer:
33/14
Step-by-step explanation:
[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]
[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]
[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]
[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]
[tex] = \frac{33}{14} [/tex]
stan dreamcatcher
2x²+3x²+3.(-1) =5x.x+5x .1
Answers
[tex]\\ \sf\longmapsto 2x^2+3x^2+3(-1)=5x.x+5x.1[/tex]
[tex]\\ \sf\longmapsto 5x^2-3=5x^2+5x[/tex]
[tex]\\ \sf\longmapsto 5x^2-5x^2-3=5x[/tex]
[tex]\\ \sf\longmapsto 5x=-3[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-3}{5}[/tex]
The circumference of a circle is 20π. What is the area of the circle?
Answers
Answer:
The area of the circle is 100 square units.
Step-by-step explanation:
We are given that the circumference of a circle is 20π, and we want to determine its area.
Recall that the circumference of a circle is given by the formula:
[tex]\displaystyle C = 2\pi r[/tex]
Substitute:
[tex]20 \pi = 2 \pi r[/tex]
Solve for the radius:
[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]
The area of a circle is given by:
[tex]\displaystyle A = \pi r^2[/tex]
Since the radius is 10 units:
[tex]\displaystyle A = \pi (10)^2[/tex]
Evaluate:
[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]
In conclusion, the area of the circle is 100 square units.
Trigonometric ratios
class 9
please answer my questions
Answers
Step-by-step explanation:
Hi there!
Please see the answer in the picture.
Hope it helps!
1. Approach
One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]
Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.
2. Problem (9)
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
As per the attached image, the following statements regarding the value of each ratio can be made:
[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]
Substitute,
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
Simplify,
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]
Thus, this equation is true.
2. Problem (10)
Use a similar strategy to evaluate this equation,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
Use the attached image to evaluate the ratios.
[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]
Substitute,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
Simplify,
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
Rationalize the denominator,
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]
[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]
[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]
[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]
[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]
Therefore, this equation is also true.
I don't understand need help?
Answers
9514 1404 393
Answer:
2. (only)
Step-by-step explanation:
The Pythagorean theorem tells you the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. To determine if these are right triangles, determine if that condition is met.
1. 3^2 +5^2 = 9 + 25 = 34 ≠ (√35)^2 . . . . not a right triangle
2. 5^2 +4^2 = 25 +16 = 41 = (√41)^2 . . . a right triangle
3. 6^2 +8^2 = 36 +64 = 100 ≠ (√10)^2 . . . . not a right triangle
4. 3^2 +3^2 = 9 +9 = 18 ≠ (3√3)^2 = 27 . . . . not a right triangle
Atlantic Hurricanes
Number
1925
1930
1935
1940
1945
1950
1955
1960
1965
1970
1975
Year
Between which years was
the biggest change in the
number of hurricanes?
Answers
Answer:
1950
Step-by-step explanation:
because 1950 column has the most highest number which is 11
Answer:
Between 1945 and 1950 ( from 5 to 11 ),
Step-by-step explanation:
Which is the graph of y = [x]-2?
PLEASE HELP TIMED PLEASE
Answers
Answer:
3rd graph
Step-by-step explanation:
solve for w.
-9/7=-2/3w-1/2
Answers
Answer: [tex]w=\frac{33}{28}[/tex]
Step-by-step explanation:
To solve for w, we want to isolate w.
[tex]-\frac{9}{7}=-\frac{2}{3}w-\frac{1}{2}[/tex] [add both sides by 1/2]
[tex]-\frac{11}{14}=-\frac{2}{3}w[/tex] [multiply both sides by -3/2]
[tex]w=\frac{33}{28}[/tex]
Now we know that [tex]w=\frac{33}{28}[/tex].
Answer:
[tex]\sf w=\dfrac{33}{28} \\[/tex]
Step-by-step explanation:
[tex]\sf -\dfrac{9}{7} =-\dfrac{2w}{3} -\dfrac{1}{2}[/tex]
First, take -2w/3 to the left side.
[tex]\sf -\dfrac{9}{7}+\dfrac{2w}{3} = -\dfrac{1}{2}[/tex]
Then, add 9/7 to both sides.
[tex]\sf \dfrac{2w}{3} = -\dfrac{1}{2}+\dfrac{9}{7}[/tex]
Make the denominators the same and add the fractions.
[tex]\sf \dfrac{2w}{3} = -\dfrac{1*7}{2*7}+\dfrac{9*2}{7*2}\\\\\sf \dfrac{2w}{3} = -\dfrac{7}{14}+\dfrac{18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{-7+18}{14}\\\\\sf \dfrac{2w}{3} = \dfrac{11}{14}[/tex]
Use cross multiplication.
[tex]\sf 2w*14=11*3\\\\28w=33[/tex]
Divide both sides by 28.
[tex]\sf w=\dfrac{33}{28} \\[/tex]
Si Juana tiene dos perros y lo simbolizamos y 2p y le regalan un hato y lo simbolizamos por g como se representa en el leguaje algebraico.
A) 3P
B) 3G
C) 2PTG
D) 2P-G
Answers
How many gallons equal 26 liters
Answers
Answer:
6.8 gallions i believe. im not quite sure
Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational
Answers
Answer:
-117 is irrational number
Answer:
Irrational
Step-by-step explanation:
Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.
find the missing length indicated
Answers
Answer:
240
Step-by-step explanation:
We are given a right triangle. Based on the leg rule, the following equation shows how the length of a leg in a right triangle relates with the segments connected to the hypotenuse:
Hypotenuse/leg = leg/part
Where,
Hypo = 400
Leg = x
Part = 144
Substitute
400/x = x/144
Cross multiply
400*144 = x*x
57,600 = x²
√57,600 = x
240 = x
x = 240
