Geometry problem, solve for X

Answer:

a =4 and b= 3

Step-by-step explanation:

Stare at it for a bit. You have the squre of x, then(ignoring the minus sign) 2 times x times 4. What's left is the square of 4, which is 16; you have 13, you are 3 short. Let's add them to both sides:

[tex]x^2-8x+13+3=3 \rightarrow x^2-8x+16 = 3\\(x-4)^2 = 3[/tex]

so a =4 and b= 3

the answer is t<-48

i hope this helped you if you need the explanation lmk

13. 12008.

14. 59286.

15. 21459.

16. 80478.

17. 130567.

18. 11100.

19. Seventy-two thousand, one hundred eighty.

20. Eighty thousand, seven hundred eighty-six.

Hope This Helps...:)

Answer:

Hi! I hope this answer helps you.

In mathematics, the vertical line test is a visual way to determine if a curve is a graph of a function or not. A function can only have one output, y, for each unique input, x.

any vertical line in the plane can intersect the graph of a function at most once.

HOW TO DO THIS

take your pencil and place it on your paper vertically (up and down direction)

move the pencil across the paper to the right

if the pencil crosses more than two points on the line it is not a function

the first problem would be a function

the second problem would be a function

the third problem would not be a function

hope this helps !!!!

Answer:

-2, -0.5, -.025, 0.05, 5

Answer:

110 degrees I think

Step-by-step explanation:

Answer:

For the one on the far left its 104 m2

Step-by-step explanation:

u split the shape in a square and rectangle

them u fin the area of the square by multiplying both sides. (8*8)

then u find the area of the rectangle by using the formula

2*(16+4)

when u find both areas u count them up and it'll become 104 m squared

Answer: 12 students

Step-by-step explanation:

Let X and Y stand for the number of students in each respective class.

We know:

X/Y = 2/5, and

Y = X+24

We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:

(Y-x)/(X+x) = 1

---

We can rearrange X/Y = 2/5 to:

X = 2Y/5

The use this value of X in the second equation:

Y = X+24

Y =2Y/5+24

5Y = 2Y + 120

3Y = 120

Y = 40

Since Y = X+24

40 = X + 24

X = 16

--

Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:

(Y-x)=(X+x)

(40-x)=(16+x)

24 = 2x

x = 12

12 students must transfer to the more difficult, very early morning, class.

Answer:

A

Step-by-step explanation:

Answer:

no graph how am i supposed to answer

Step-by-step explanation:

DUDE PUT THE GRAPH WHERE IS iT

Answer:

8 and 2

Step-by-step explanation:

Answer:

1/4 and 1/2

Step-by-step explanation:

One number is twice another number.

x and 2x

The sum of their reciprocals is 6

[tex]\frac{1}{x}[/tex] + [tex]\frac{1}{2x}[/tex] = 6

Use common denominator of 2x

[tex]\frac{2}{2x}[/tex] +  [tex]\frac{1}{2x}[/tex] = 6

[tex]\frac{3}{2x}[/tex] = 6

multiply botn sides by 2x

3 = 12x

Divide both sides by 12

1/4 = x

x = 1/4

2x = 1/2

The numbers are

1/4 and 1/2

Answer:

9

Step-by-step explanation:

2+4 over 2

x 3

= 9

Answer:

12

Step-by-step explanation:

House A is 24. So divide it by two to get 12. Which is house B

Step-by-step explanation:

Write properties of function:

x intercept/zero: ; T1= -1 and T2=10

vertex form: g(t)=  (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

Explanation Write properties of function: Write properties of function:

x intercept/zero: ; t1=-1, and t2=10

vertex form: (t-9/2)^2, (-121/4)

vertex: 9/2, 121/4

hope this helped

The height of the bottom of the hole after the second day is -35 11/12 feet

Given:

Day 1 height = -45 1/4 feet

Day 2 height = -45 1/4 + 9 1/3

= - 181/4 + 28/3

= (-543 + 112) / 12

= -431/12

= -35 11/12 feet

Therefore, the height of the bottom of the hole after the second day is -35 11/12 feet

Read more:

https://brainly.com/question/11871698

Answer: a = 2.5 (an-1)

Step-by-step explanation: trust me;)

The function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

sequence where each succeeding term is produced by multiplying each preceding term by a fixed number, which is called a common ratio. This progression is as a geometric sequence of  numbers.

[tex]a_{n} =ar^{n-1}[/tex]

Where,

[tex]a_{n}[/tex] is the nth term of the sequence or geometric progression

n is the total number of terms

r is the common ratio

and a is the first term

According to the given question

We have

A geometric progression

8, 20, 50, 125, 312.5

Now the common ratio for the above progression is given by

[tex]r = \frac{20}{8} = 2.5[/tex]

And the first term is

a = 8

Therefore, the function which is used to represent the above sequence is given by

[tex]a_{n} = 8(2.5)^{n-1}[/tex]

Hence, the function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

Learn more about geometric progression here:

https://brainly.com/question/4853032

#SPJ2

Answer:

8 batches

Step-by-step explanation:

You would have to divide 3 1/5 by 2/5, which gets you 8 batches of brownies.

if the value of x is 1 then the y value is 6

Answer:

There is a area of triangle and there is two trapezium so 8×17=136

Using the normal distribution, it is found that:

a) The 65th percentile is of 37.31.

b) The 90th percentile is of 42.68.

c) There is a 0.5705 = 57.05% probability of getting a raw score between 28 and 38.

d) There is a 0.0919 = 9.19% probability of getting a raw score between 41 and 44.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

Question a:

The 65th percentile is X when Z has a p-value of 0.65, so X when Z = 0.385.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.385 = \frac{X - 35}{6}[/tex]

[tex]X - 35 = 0.385(6)[/tex]

[tex]X = 37.31[/tex]

The 65th percentile is of 37.31.

Question b:

The 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.28 = \frac{X - 35}{6}[/tex]

[tex]X - 35 = 1.28(6)[/tex]

[tex]X = 42.68[/tex]

The 90th percentile is of 42.68.

Question c:

The probability is the p-value of Z when X = 38 subtracted by the p-value of Z when X = 28, hence:

X = 38:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{38 - 35}{6}[/tex]

[tex]Z = 0.5[/tex]

[tex]Z = 0.5[/tex] has a p-value of 0.6915.

X = 28:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{28 - 35}{6}[/tex]

[tex]Z = -1.17[/tex]

[tex]Z = -1.17[/tex] has a p-value of 0.121.

0.6915 - 0.121 = 0.5705.

There is a 0.5705 = 57.05% probability of getting a raw score between 28 and 38.

Question d:

The probability is the p-value of Z when X = 44 subtracted by the p-value of Z when X = 41, hence:

X = 44:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{44 - 35}{6}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a p-value of 0.9332.

X = 41:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{41 - 35}{6}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.8413.

0.9332 - 0.8413 = 0.0919

There is a 0.0919 = 9.19% probability of getting a raw score between 41 and 44.

A similar problem is given at https://brainly.com/question/24663213

Answer:

1/5

Step-by-step explanation:

rise = 2 ft

run = 10 ft

slope = rise/run = 2/10 = 1/5

Answer: 1/5

Answer:

1/5

Step-by-step explanation:

The slope is the rise over the run

Y / x

2/10

1/5

Answer:

0, 1/18, and 1/36

Step-by-step explanation:

For i = 2, the probability it lands on 6 is 0, because you cannot sum to 2 with a 6. The same applies to i = 3 thru i = 6.

For the probability that at least one of a pair of fair dice lands on 6 for i = 7, there are only two possible ways, the first roll is a 6 and the second roll is a 7, and the first roll is a 1 and the second roll is a 6. The total amount of ways is 6 * 6 = 36, so the total probability is 1/18. This also applies to i = 8 thru i = 11.

For i = 12, there is only one way to get 12, the first dice lands on 6 and the second dice lands on 6. Assuming the dice are indistinguishable, the probability is 1/36.

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

We have,

The complementary probability of "at least one die lands on 6" is "neither of the dice lands on 6."

Therefore, you need to find the probability that neither of the dice lands on 6 for each possible sum i, and then subtract that probability from 1 to get the desired probability.

Let's go through the cases:

i = 2 (only possible sum with two dice):

In this case, both dice must show a 1.

The probability of this happening on a fair 6-sided die is

(1/6) * (1/6) = 1/36.

i = 3: The combinations are (1, 2) and (2, 1).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 4:

The combinations are (1, 3), (2, 2), and (3, 1).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 5:

The combinations are (1, 4), (2, 3), (3, 2), and (4, 1).

The probability of any of these happening is 4 * (1/6) * (1/6) = 1/9.

i = 6:

The combinations are (1, 5), (2, 4), (3, 3), (4, 2), and (5, 1).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 7:

The combinations are (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

The probability of any of these happening is 6 * (1/6) * (1/6) = 1/6.

i = 8:

The combinations are (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2).

The probability of any of these happening is 5 * (1/6) * (1/6) = 5/36.

i = 9:

The combinations are (3, 6), (4, 5), and (5, 4).

The probability of any of these happening is 3 * (1/6) * (1/6) = 1/12.

i = 10:

The combinations are (4, 6) and (6, 4).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 11:

The combinations are (5, 6) and (6, 5).

The probability of either happening is 2 * (1/6) * (1/6) = 1/18.

i = 12:

The combination is (6, 6).

The probability of this happening is (1/6) * (1/6) = 1/36.

Now, sum up the probabilities for each case:

(1/36) + (1/18) + (1/12) + (1/9) + (5/36) + (1/6) + (5/36) + (1/12) + (1/18) + (1/18) + (1/36)

This simplifies to:

69/36 = 23/12

Thus,

The probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is i, where i ranges from 2 to 12, is 23/12.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ3

Answer:

Step-by-step explanation:

Let the number is x.

2/3 of a number is 10:

0.15 times of the number is:

Correct choice is d

Answer:

h(4) = -1 ;   h(-5) = 1        h(0) = -9

Step-by-step explanation:

a)    h(x) = |-2x| - 9       Substitute x = 4

       h(4) = | -2 · 4| - 9

       h(x) = | -8| - 9

       h(4) = 8 - 9

       h(4) = -1

b)  h(x) = |-2x| - 9            Substitute x = -5

    h(-5) = |-2 · -5| - 9

    h(-5) = |-10| - 9

     h(-5) = 10 - 9

      h(-5) = 1

c)   h(x) = |-2x| - 9             Substitute x = 0

     h(0) = |-2 · 0| - 9

     h(0) = |0| - 9

     h(0) = 0 - 9

      h(0) = -9

Answer:

y = -12.35

Step-by-step explanation:

Plug in 2.65 for x giving you y = 2.65 - 15

Answer:

[tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]

Step-by-step explanation:

Given the algebraic equation, [tex]{\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}[/tex], and that we must solve for z :

The first step is to multiply both sides by 4 to eliminate the fraction on the right-hand side of the equation:

[tex]{\huge{\green{\mathsf{x\:=\frac{3yz^2}{4}}}}[/tex]

[tex]{\huge{\green{\mathsf{(4)\:x\:=\frac{3yz^2}{4}(4)}}}[/tex]

4x = 3yz²

Next, divide both sides by 3y:

[tex]{\huge{\green{\mathsf{\frac{4x}{3y}\:=\frac{3yz^2}{3y}}}}[/tex]

[tex]{\huge{\green{\mathsf{\frac{4x}{3y}\:=z^2}}}[/tex]

Lastly, take the square root of both sides to isolate the variable, z :

[tex]{\huge{\green{\mathsf{\sqrt{\frac{4x}{3y}}\:=\sqrt{z^2}}}}[/tex]

[tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]

Therefore, the equation for z is:   [tex]{\huge{\green{\mathsf{z\:=\sqrt{\frac{4x}{3y}}}}}[/tex]

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Un significant figured Volume=1099.56

3 sf = 1100.00