Given m n, find the value of X.

Answer:

1-90

2-80

3-033

Step-by-step explanation:

Answer:

cant see it

Step-by-step explanation:

just type it out

Answer:

27 xy^2

Step-by-step explanation:

(3xy) (9y)

Multiply

3*9 =27

xy*y = xy^2

Combine

27 xy^2

Answer:

The committee of 8 members can be selected in 990,675 different ways.

Step-by-step explanation:

The order in which the teachers and the students are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

4 teachers from a set of 6.

4 students from a set of 37.

Then

[tex]T = C_{6,4}C_{37,4} = \frac{6!}{4!2!} \times \frac{37!}{4!33!} = 990675[/tex]

The committee of 8 members can be selected in 990,675 different ways.

Answer:

1/8

Step-by-step explanation:

Hope this helps you! <33

Answer:

1/8

Step-by-step explanation:

We all know 1/2 is 0.5, right?

If you split that in half again, you get 0.25 as 1/4.

If you divide that again by two, you get 1/8 as 0.125

Answer:

The limit is 0, and the answer is given by option E.

Step-by-step explanation:

Limit to the right:

The limit of a function approacing a value of x to the right is given by the value of the function quite close to the point, looking to the right.

In this question:

Approacing by the right(x quite close, but more than -1, that is, -0.9999...), y tends to 0, so the limit is 0, and the answer is given by option E.

A quadratic function's graph being wide or narrow is determined or depended on a-term:

[tex] \large{y = a {x}^{2} + bx + c}[/tex]

If |a| has a lot of value, for example a = 2 or a = 100. The graph will get narrower if increasing the value of |a|. On the other hand, If |a| has small value, for example a = 1/2 or a = 1/10000. The graph would be wide.

Also it does not matter if a-term is negative or not since a-term being positive or negative determines if a parabola is upward or downward. Only |a| determines how narrow/wide the graph is.

From the question, it is clear that the parabola y = 2x^2 is the narrowest graph since it has the highest |a| value out of all choices.

Answer

Answer:

I am pretty sure that it's the second one

Answer:

To find the estimated value we add all of them together then divide it by the amount of them

45.8+43.9+46.2+48.5+47.2+45.8+49.1+43.9+47.6+42.8+46.5+44.9+46.8+45.8 +44.6=689.4

now we divide it by 15 since there is 15 blocks so

689.4 divided by 15=45.96

so the average weight is 45.96

Answer:

A = 41.4°

Step-by-step explanation:

Reference angle = A

Length of Adjacent side = 6

Length of Hypotenuse = 8

Apply the trigonometric function, CAH.

Cos A = Adj/Hyp

Substitute

[tex] Cos(A) = \frac{6}{8} [/tex]

[tex] A = Cos^{-1}(\frac{6}{8}) [/tex]

A = 41.4° (approximated to the nearest tenth)

Answer:

A

Step-by-step explanation:

Step-by-step explanation:

sum of 5 times a number and -2, + 8n

becomes:

5n + (-2) + 8n, or

5n -2 +8n, or. 13n - 2

Answer:

The non-negative zero of the function f(x) is x = 2.

Step-by-step explanation:

For a given function f(x), the "zeros" of the function are the values of x such that:

f(x) = 0

In this case, we have the function:

f(x) = 6*x^2 - 9*x - 6

If we want to find the zeros of this function, we need to solve:

f(x) = 0 =  6*x^2 - 9*x - 6

To solve this, we can use the Bhaskara's formula, which says that for a general quadratic equation:

0 = a*x^2 + b*x + c

The zeros are:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]

In this case our equation is:

0 =  6*x^2 - 9*x - 6

then, in the above notation, we have:

a = 6

b = -9

c = -6

Replacing these in our general formula, we get:

[tex]x = \frac{-(-9) \pm \sqrt{(-9)^2 - 4*6*(-6)} }{2*6} = \frac{9 \pm 15 }{12}[/tex]

Then we have two zeros:

x = (9 + 15)/12 = 24/12 = 2

x = (9 - 15)/12 = -6/12 = -1/2

But we want only the non-negative, so we can discard the second one.

Concluding, the non-negative zero of the function f(x) is x = 2.

Part (a)

1 meter = 100 cm

25 meters = 2500 cm .... multiply both sides by 25

Divide the 2500 cm over the 53 cm to get 2500/53 = 47.1698

Ignore the stuff after the decimal point. This means we can cut exactly 47 smaller bits of string, each 53 cm long

====================================================

Part (b)

We found that we can cut exactly 47 smaller bits of string, each 53 cm long. That takes up 47*53 = 2491 cm overall

The leftovers would be 2500 - 2491 = 9 cm which isn't longer than 53 cm

Convert 9 cm to mm by multiplying by 10 (because 1 cm = 10 mm).

9 cm = 90 mm

Answer:

B. Quincy's claim is correct.

Step-by-step explanation:

Margin of error of a confidence interval:

The margin of error of a confidence interval has the following format:

[tex]M = z\frac{s}{\sqrt{n}}[/tex]

In which z is related to the confidence level, s is the standard error and n is the size of the sample.

From this interval, we have that the margin of error and the sample size are inversely proportional, that is, if we increase the sample size, the margin of error decreases, and so does the width of the confidence interval.

Peggy claims that the width of the confidence interval will increase if a sample size of 30 is used, all other things remaining the same.

Peggy is wrong, as the increase of the sample size results on the decrease of the margin of error, and a decrease of the width.

Quincy claims that the width of the confidence interval will decrease if a sample size of 30 is used.

Margin of error decreases, and so does the width of the interval, thus, Quincy's claim is correct, and the correct answer is given by option b.

Answer:

30.00×.06=1.8+30.00=31.8

Answer:

show the graphs?

Step-by-step explanation:

Answer:

1.d. None of these measures  (do not exist interpreted as all of these exist)

2.The mean is increased from 346.8 to 361.32

Step-by-step explanation:

After calculations we find that all the measures of central tendency exist for this data. The mean , median and mode can be easily calculated .

The mean is 346.8

The mode is 281

The median is 316

Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169.  The mean would be affected by the change.

The mean is 361.32

The mode is 281

The median is 316

The mean is increased from 346.8 to 361.32

Answer:

Apr 16, 2018 — p>Which exponential function is represented by the graph?</p><span>f(x) = 2(1/​2)^x </span><span>f(x) = 1/2(2)^x </span><span>f(x) = 1/2

Step-by-step explanation:

I dont think I can be answered with just the given info... is some of the q missing still?

Closest we can do with above is dress cost = 120+ c

Step-by-step explanation:

Tập nghiệm của [tex]2^x=-1[/tex] là tập rỗng nha bạn. Vì 2 là số dương nên mũ mấy cũng dương hết.

9514 1404 393

Answer:

  (a) The decrease in the value of the truck, which is 12%

Step-by-step explanation:

The only reasonable choice among the offered answers is the one shown above.

__

We would describe the value 0.88 as the annual multiplier of the truck's value, which decreases 12% each year.

Answer:

[tex]{ \tt{graph \: y \:and \:graph\: z}}[/tex]

Your Answer is in the above image.

Answer:

No solution is possible from the information provided

Step-by-step explanation:

Answer:

V = 64 in^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 4^3

V = 64 in^3

Answer:

64

Step-by-step explanation:

volume of a cube formula: V = a^3

a is just one of the edges

[tex]4^{3}[/tex] = 64 = V

:)

Answer:

The campsites can be chosen in 5,765,760 different ways.

Step-by-step explanation:

Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:

16 x 15 x 14 x 13 x 12 x 11 = X

240 x 182 x 132 = X

240 x 24,024 = X

5,765,760 = X

Therefore, the campsites can be chosen in 5,765,760 different ways.