Given points A(2,1,3) and B(0,5,0), find a point C in the xy-plane that creates an isosceles right triangle such that:_______

a. AB and BC are the legs of the right triangle
b. AB is the hypotenuse of the right triangle (for part ii, just doing all the set-up work is sufficient; you do not need to solve and find the points)

Answers

Answer 1

Answer:

a.)Point C will be either (4.82, 7.41) or ( -4.82, 2.59)

b.) -x² + 2x + 6y - y² - 5= 0  , 8y - 4x = 11

Step-by-step explanation:

As given A(2,1,3) and B(0,5,0)

a.)

We have to find C  in the xy-plane

⇒ C is of the form (x, y, 0)    ( Because in xy plane , z coordinate is zero)

Now, given AB and BC are the legs of the right triangle .

AB = (0, 5, 0) - (2, 1, 3) = ( -2, 4, -3)

BC = (x, y, 0) - (0, 5, 0) = ( x, y-5, 0)

As AB and BC are legs of triangle

⇒AB is perpendicular to BC

⇒(AB).(BC) = 0

⇒( -2, 4, -3).( x, y-5, 0) = 0

⇒ -2x + 4(y-5) -0 = 0

⇒ -2x + 4y- 20 = 0

⇒ -x + 2y- 10 = 0

⇒ 2y = 10 + x

⇒ y = 5 + [tex]\frac{x}{2}[/tex]         ......(1)

As ABC is making an isosceles right triangle

It means two sides of the triangle are equal

Now,

|AB| = √(-2)² + (4)² + (-3)² = √4+16+9 = √29

|BC| = √(x)² + (y-5)² + 0² = √(x)² + (y-5)²

Now,

AS AB = BC

⇒|AB| = |BC|

⇒|AB|² = |BC|²

⇒29 = (x)² + (y-5)²

⇒29 = (x)² + (5 + [tex]\frac{x}{2}[/tex] -5)²

⇒29 = (x)² + ( [tex]\frac{x}{2}[/tex] )²

⇒29 = x²( 1 + [tex]\frac{1}{4}[/tex] ) = x²(  [tex]\frac{5}{4}[/tex] )

⇒ x² = [tex]\frac{116}{5}[/tex] = 23.2

⇒ x = 4.82 , -4.82

⇒y = 7.41 , 2.59

so, Point C will be either (4.82, 7.41) or ( -4.82, 2.59)

b.)

As given AB is the hypotenuse of the right triangle

S, AC and CB will perpendicular to each other

Now,

AC = (x, y, 0) - ( 2, 1, 3) = ( x-2, y-1, -3)

CB = (0, 5, 0) - (x, y, 0) = (-x, 5-y, 0)

As, AC and CB is perpendicular

⇒(AC).(CB) = 0

⇒( x-2, y-1, -3).(-x, 5-y, 0) = 0

⇒(x-2)(-x) + (y-1)(5-y) - 0 = 0

⇒-x² + 2x + 5y - y² - 5 + y = 0

⇒-x² + 2x + 6y - y² - 5= 0    ..........(2)

As ABC is making an isosceles right triangle

It means two sides of the triangle are equal

Now,

|AC| = √(x-2)² + (y-1)² + (0-3)² = √(x-2)² + (y-1)² + 9

|BC| = √(x)² + (y-5)² + 0² = √(x)² + (y-5)²

Now,

AS AC = BC

⇒|AC| = |BC|

⇒|AC|² = |BC|²

⇒(x-2)² + (y-1)² + 9  = (x)² + (y-5)²

⇒x² + 4 - 4x + y² + 1 - 2y + 9 = x² + y² + 25 - 10y

⇒ 4 - 4x + 1 - 2y + 9 = 25 - 10y

⇒14 - 4x - 2y  = 25 - 10y

⇒10y - 2y - 4x = 25 - 14

⇒8y - 4x = 11            ........(3)

Now, we have 2 equations

-x² + 2x + 6y - y² - 5= 0  , 8y - 4x = 11

Solve these equations to find x, y


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Answers

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What is the area of the composite figure?

Answers

Hello! :)

[tex]\large\boxed{A = 32.5cm^{2}}[/tex]

We can use the following area to solve for the area of the trapezoid pictured:

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Where:

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Answers

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Answers

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Answers

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Step-by-step explanation:

☆Remember: [tex]m =  \frac{y_2 - y_1}{x_2 - x_1} [/tex]

☆Slope-intercept: [tex]y = mx + b[/tex]

---

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---

☆Now we need to find the y-intercept. We are going to plug in the slope and a set of coordinates to find the y-intercept.

[tex]y = mx + b \\ 3 = 6( -1 ) + b \\ 3 = - 6 + b \\ \frac{ + 6 = + 6 \: \: \: \: \: \: \: \: \: \: }{9 = b \: \: \: \: \: \: \: \: \: \: \: } [/tex]

---

☆Now all we need to do is plug in and we are done!

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Answers

Answer:

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Consider the expressions (3m+2n−6) and (−4−6m+7n).

Part A


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The sum is

Answers

Answer:

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Step-by-step explanation:

Given the equation (3m+2n−6) and (−4−6m+7n).

Also, given that we're told that

n = -2 and

m = 5, if we take a rather direct approach by substituting like for like, we have

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Answers

Answer:

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Michael spent $700 in April and May and $800 in June and July. His average monthly expenses are:____

Answers

$420+$350+$432=kelsey's monthly expenses  

$700+$800=Micheal's Monthly expenses

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What is the average?

The average value in a set of numbers is the middle value, calculated by dividing the total of all the values by the number of values. When we need to find the average of a set of data, we add up all the values and then divide this total by the number of values.

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Answers

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There's no problem for now but it still needs to be monitored in case something might happen.


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Answer:

19

Step-by-step explanation:

Answer:

19

Step by step explanation:

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Answers

The probability of an incorrect conclusion is,

In 84 % of inspection,  [tex]7.56\%[/tex]  of them labeled as not defective but they are actually defective

Probability :

It is given that,

A quality assurance check is 91% accurate for non-defective devices and 97% accurate for defective devices.

Of the devices checked, 84% are not defective.

Actual not defective is,

            [tex]\frac{91*84}{100} = 76.44\%[/tex]

In  [tex]84\%[/tex] of inspection,[tex]76.44\%[/tex] are actually not defective

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Answer:

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