Given that line a is parallel to line b and that line c isparallel to line d, if m<13 = (12x – 22)° and m<14 = (9x – 29)°, find m<2

7n-16

Step-by-step explanation:

Sry can u give me the picture

Answer:

2(2)+7=11

2(3)+7=13

2(4)+7=15

2(5)+7=17

2(9)+7=25

Step-by-step explanation:

2(2)+7

4+7=11

2(3)+7

6+7=13

2(4)+7

8+7=15

2(5)+7

10+7=17

2(9)+7

18+7=25

Step-by-step explanation:

Eueydhhdgdgdbdbddbdbhd

Answer:

Hello,

[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]

Step-by-step explanation:

[tex]Formula: \ L=\theta*R\\[/tex]

[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]

Answer:

In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]

The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3

Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).

The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.

Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.

The sum area of shaded region​ is [tex]\frac{1}{3}[/tex].

The formula to find the sum of infinite geometric progression is

[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]

Given

S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]

Using geometric progression

S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]

Using summation formula for geometric progression

[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]

= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]

= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]

= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]

[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0

S  = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]

The sum area of shaded region​ is [tex]\frac{1}{3}[/tex].

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Answer:

y-intercept is 0, x-intercept is 0 and 1

Step-by-step explanation:

For y-intercept, x=0 :

[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]

For x-intercept, y=0 :

[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]

Answer:

-3/2 >x

Step-by-step explanation:

-5-15>10+20x

Combine like terms

-20 > 10 +20x

Subtract 20 from each side

-20 -10 > 10+20x-10

-30> 20x

Divide by 20

-30/20 >20x/20

-3/2 >x

Answer:

-3/2 > x

Step-by-step explanation:

-5 - 15 > 10 + 20x

 ^    ^

  -20

-20 > 10 + 20x

-10    -10

---------------------

-30 > 20x

-----   -------

20     20

-3/2 > x

Hope this helped.

Answer:

Step-by-step explanation:

Slope intercept form is y = mx + b where m is the slope and b is the y intercept SO

y = mx + b

3y - 9 = 12x

3y = 12x + 9 (divide by common denominator 3)

y = 4x + 3

Answer:

{1/√3+1/2} ÷{1/√3× 1/2}

msin²x+cos²x=m-1

since the interval are 0 and π/4

Therefore

msin²(0)+cos²(0)=m-1

m(0)+1=m-1

1=m-1

m=2

use π/4 now

msin²(π/4)+cos²(π/4)=m-1

m(1/2)+(1/2)=m-1

m+1=2(m-1)

m+1=2m-2

-m=-3

m=3

Therefore

m=2 or 3

Answer: x ≥ 87

Step-by-step explanation:

Set the minimum score on the next test as x & calculate it:

[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]

So they need at least a score of 87 for the average to be 80+.

Answer:

x ≥ 87

Step-by-step explanation:

Answer:x²-3 x+4/ 2x-3 units

Step-by-step explanation:

Area = Length * Width sq. units

x^2 - 3x + 4 = Length * 2x - 3

=>Length = x^2- 3 x + 4/ 2 x − 3 units

Answer:

Yes it can be right angle triangle

Answer:

16

Step-by-step explanation:

First use the Pythagorean theorem a^2+b^2=c^2.

12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.

Step-by-step explanation:

using pythogoras theory

hyp^2=opp^2+adj^2

you have been given the hyp and the opp so lets make the unknown x

20^2=12^2+x^2

400 =144+x^2

make x the subject of the formula

400-144=x^2

266=x^2

x=the square root of 266

Answer:

x = y² - 7

Step-by-step explanation:

the inverse function is simply an exchange of x and y (and then the simplification happens to transform the whole expression back into a form y = ....)

Answer:

92

Step-by-step explanation:

180-88

Answer:

3 hours 26 minutes

Step-by-step explanation:

26 minutes(9.34am to 10am)+3 hours(10am to 1pm)=3 hours 26 minutes

The total time that she spend fixing her bicycle is 3 hr 26 minutes

Given the following parameters

Time that Olivia starts fixing bicycle= 9:34 am

Time she finishes = 1pm

The total number of hours spent from 9:34am and 12:34pm is 3 hrs. The remaining minutes to 1 pm is 26 minutes.

Hence the total time that she spend fixing her bicycle is 3 hr 26 minutes

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To obtain an estimate of a parameter of a population, we use confidence intervals.

Confidence intervals:

The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.

Thus, you should select the highest sample size in the options.

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Answer:

Option A is correct

Step-by-step explanation:

Hope it is helpful....

Answer:

a/b

Step-by-step explanation:

The rational form of a:b or simply a/b is in the simplest form.

Answer:

Step-by-step explanation:

the answer is option 2 from the above sheet

Answer:

40 kg

Step-by-step explanation:

[tex]\frac{5}{83.75} :\frac{y}{670}[/tex]

y · 83.75 = 5 · 670

83.75y = 3350

83.75y ÷ 83.75 = 3350 ÷ 83.75

y = 40

The amount of rice you can buy for ₹670 is given by the equation

A = 40 kilograms

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of rice for ₹670 be A

Now , the equation will be

The amount for 5 kg of rice = ₹ 83.75

So , the amount for 1 kg of rice = amount for 5 kg of rice / 5

The amount for 1 kg of rice = 83.75 / 5

The amount for 1 kg of rice = ₹ 16.75

So , the amount of rice for ₹ 670 = 670 / amount for 1 kg of rice

The amount of rice for ₹ 670 = 670 / 16.75

The amount of rice for ₹ 670 = 40 kilograms

Therefore , the value of A is 40 kilograms

Hence , the amount of rice is 40 kg

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Answer:

50 km

Step-by-step explanation:

c = √a^2+b^2

=√30^2+40^2

= √900 + 1600

=√2500

= 50 km

Answer:

50km

Step-by-step explanation:

Answer:

84

Step-by-step explanation:

[tex]4^3+4^2+2^2= 64+16+4=84[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{4^3 + 4^2 + 2^2}}[/tex]

[tex]\huge\boxed{\mathsf{4^3}}[/tex]

[tex]\huge\boxed{\mathsf{= 4 \times 4 \times 4}}[/tex]

[tex]\huge\boxed{\mathsf{= 16\times 4}}[/tex]

[tex]\huge\boxed{\mathsf{= \bf 64}}[/tex]

[tex]\huge\boxed{\mathsf{4^2}}[/tex]

[tex]\huge\boxed{\mathsf{= 4 \times 4}}[/tex]

[tex]\huge\boxed{\mathsf{= \bf 16}}[/tex]

[tex]\huge\boxed{\mathsf{2^2}}[/tex]

[tex]\huge\boxed{\mathsf{= 2 \times 2}}}[/tex]

[tex]\huge\boxed{\mathsf{= \bf 4}}[/tex]

[tex]\huge\boxed{\mathsf{= 64 + 16 + 4}}[/tex]

[tex]\huge\boxed{\mathsf{= 80 + 4}}[/tex]

[tex]\huge\boxed{\mathsf{= \bf 84}}[/tex]

[tex]\huge\boxed{\mathsf{Answer: 84}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

1) The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.

2) The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.

Step-by-step explanation: I just did the tutorial right now i hope this helps

Answer:

part a = The number of hours since Vicky took the phone off the charger is the independent quantity, so the variable x should represent it.

part b = The percentage of battery life left in hours is the dependent quantity, so the variable y should represent it.

part c = The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.

part d = The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.

part e = The rate of change of the function, m, is -5, and the initial value of the function, b, is 100. Substitute the values of m and b in the equation y = mx + b. The equation of the function that models the phone’s remaining battery life in terms of the number of hours from the time Vicky took it off the charger is y = -5x + 100.

Step-by-step explanation:

All edmentum answers :)

Step-by-step explanation:

i Will help wit Shape A and Next Try to figure out Shape B

shape A Looks the Shape XY coordinate, which Horizontal & Vertical Line

Shape A Coordinate

X = 7, 8.5, 7,5, 7.5,

Y = 7, 7, 6.5 , 5

if you wanna to understand this coordinate between X & Y try plotting with Horizontal or Vertical Line at your Shape And you Would be Understanding about these coordinate meaning

0Answer:

A

Step-by-step explanation:

Find the zeros by letting y = 0 , that is

x² - x - 6 = 0 ← in standard form

(x - 3)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x + 2 = 0 ⇒ x = - 2

Since the coefficient of the x² term (a) > 0

Then the graph opens upwards and will be positive to the left of x = - 2 and to the right of x = 3 , that is in the intervals

(-∞, - 2) and (3, ∞ ) → option A

Answer:

multiply 4 by 12 okay bro

Answer:

y = [tex]\frac{1}{3}[/tex] x

Step-by-step explanation:

Given that y and x are proportional then the equation relating them is

y = kx ← k is the constant of proportion

To find k use the condition y = 4 when x = 12 , then

4 = 12k ( divide both sides by 12 )

k = [tex]\frac{4}{12}[/tex] = [tex]\frac{1}{3}[/tex]

y = [tex]\frac{1}{3}[/tex] x ← equation of proportion

Answer:

[tex] \frac{5}{18} = 0.27[/tex]

Step-by-step explanation:

[tex] \frac{(4 - 5)^{2} + {(2 + 1)}^{2} }{ {(4 + 2)}^{2} } [/tex]

[tex] = \frac{ {( - 1)}^{2} + {3}^{2} }{ {6}^{2} } [/tex]

[tex] = \frac{1 + 9}{36} [/tex]

[tex] = \frac{10}{36} [/tex]

[tex] = \frac{5}{18} [/tex]

= 0,27

Answer:

[tex]{ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}[/tex]