Given the equation:
H2O (l)
KNO3(s) ————> KNO3(aq)

As H20(l) is added to KNO3(s) to form KNO3(aq), the entropy of the system…

1. decreases
2. increases
3. remains the same

Answer:

NASA stands for National Aeronautics and Space Administration

Answer:

National Aeronautics and Space Administration

hope this will help you more

Answer:

There is no unit for Kc

Explanation:

Answer:

please correct it, the question is incomplete

Answer:

I think u willl get the answer fast in......

Answer:

this is because when a salt dissolves, its dissociated ions can move freely in solution, allowing a charge to flow. The resulting solution will conduct electricity because it contains ions.

Explanation:

Answer:

pH = 5.76

Explanation:

We can solve this problem by using Henderson-Hasselbach's equation:

pH = pKa + log[tex]\frac{[SodiumAcetate]}{[AceticAcid]}[/tex]

We are already know all the required information, thus we input the data given by the problem:

pH = 4.76 + log(20/2)

And finally calculate the pH:

pH = 5.76

The pH of that acetic acid solution is 5.76.

Answer:

11.

O4 means 4 atoms of oxygen. H2O

has one atom of oxygen, so seven "units" of

H2O has 7.

Answer:

C - N Bond formation.

Explanation:

Imide synthesis is a chemical reaction in organic chemistry which consists of two acyl groups which bond to nitrogen atom. The compound structure is related to acid anhydrides. Imides are monoacyl which are used as valuable intermediates in organic synthesis.

Answer:

b. HCOOH/ NaHCOO.

Explanation:

A buffer system may be formed in one of two forms:

Chose the pairs below that you could use to make a buffered solution.

a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.

b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.

c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.

d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.

Answer:

79.7

Explanation:

Answer:79.7

Explanation:just got it right on the quiz!

Answer:

D. Van der Waals forces are the strongest force between H2

molecules and between NH3 molecules.  

Explanation:

Van der Waal’s forces are the forces which arises due to disturbance in the electron density of the molecule.  

These are usually found in non polar molecules. Hence N2 is said to exhibit this force.

Out of these Van der Waals is the weakest force.

(a) shows both acidic and basic properties

(b) creates a neutral pH in solution

(c) is an ionic compound formed from an acid-base reaction

(d) can react with acid but not with a base

Answer:

neither of them plays cricket,does anyone?

Explanation:

I know you will think I its weird but it is the rule of grammar and 100% correct!

Answer:

neither of them plays cricket, do you?​

Explanation:

Answer:

tanong mo sa teacher mo ok

Answer:

E = (50.0 kg)(3.00 x 108 m/s)2

Explanation:

Answer:

c.

brain and spinal cord.

Explanation:

Answer:

because.......

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Answer:

[tex]\left(\frac{V_m}{V}\right)^N[/tex]

Explanation:

Given :

Number of identical volumes = N

The molecular volume = [tex]V_m[/tex]

The total volume = V

Temperature = T

Therefore, the number of the ways for locating one molecule within the volume V is :  [tex]\frac{V_m}{V}[/tex]

There are N molecules.

So, the total umber of ways of locating N molecules is [tex]\left(\frac{V_m}{V}\right)^N[/tex]

Explanation:<3 sorry.

Answer: The empirical formula of the compound is [tex]KMnO_4[/tex]

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Let the mass of the compound be 100 g

Given values:

% of K = 24.7%

% of Mn = 34.76%

% of O = 40.50%

Mass of K = 24.7 g

Mass of Mn = 34.76 g

Mass of O = 40.50 g

To calculate the empirical formula of a compound, few steps need to be followed:

We know:

Molar mass of K = 39.10 g/mol

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol[/tex]

[tex]\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol[/tex]

[tex]\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol[/tex]

[tex]\text{Mole fraction of K}=\frac{0.632}{0.632}=1[/tex]

[tex]\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1[/tex]

[tex]\text{Mole fraction of O}=\frac{2.53}{0.632}=4[/tex]

The empirical formula of the compound becomes [tex]K_1Mn_1O_4=KMnO_4[/tex]

Hence, the empirical formula of the compound is [tex]KMnO_4[/tex]

The empirical formula of the compound is KMnO₄

Divide by their molar mass

K = 24.74 / 39 = 0.634

Mn = 34.76 / 55 = 0.632

O = 40.50 / 16 = 2.531

Divide by the smallest

K = 0.634 / 0.632 = 1

Mn = 0.632 / 0.632 = 1

O = 2.531 / 0.632 = 4

Therefore, the empirical formula of the compound is KMnO₄

Learn more about empirical formula:

https://brainly.com/question/24297883

Answer:

1.7 × 10⁴ J

Explanation:

Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C

We will use the following expression.

Q₁ = c(ice) × m × ΔT

Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J

Step 2: Calculate the heat required to melt 25 g of ice

We will use the following expression.

Q₂ = C(fusion) × m

Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J

Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C

We will use the following expression.

Q₃ = c(water) × m × ΔT

Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J

Step 4: Calculate the total heat required

Q = Q₁ + Q₂ + Q₃

Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J

Answer:

waves, energy is transferred through vibrations of electric and magnetic fields.

Explanation:

In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles

Answer: The mass of NaOH is 40 g

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(1)

Given values:

Molarity of NaOH = 1 M

Molar mass of NaOH = 40 g/mol

Volume of the solution = [tex]1000cm^3=1000 mL[/tex]            (Conversion factor: [tex]1cm^3=1mL[/tex])

Putting values in equation 1, we get:

[tex]1=\frac{\text{Mass of NaOH}\times 1000}{40\times 1000}\\\\\text{Mass of NaOH}=\frac{1\times 40\times 1000}{1000}=40g[/tex]

Hence, the mass of NaOH is 40 g

The image is not given in the question, it is attached below:

Answer: The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

Explanation:

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide [tex](CO_2)[/tex] compound

The combination of 2 blue spheres will represent nitrogen molecule [tex](N_2)[/tex]

The combination of 1 blue and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound

The combination of 1 black and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

We are given:

Given moles of NO = 6 moles

Given moles of CO = 4 moles

For the given chemical equation:

[tex]2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)[/tex]

By stoichiometry of the reaction:

If 2 moles of CO reacts with 2 moles of NO

So, 4 moles of CO will react with = [tex]\frac{2}{2}\times 4=4mol[/tex] of NO

As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

Answer:

0.30

Explanation:

Step 1: Calculate the known initial and equilibrium molar concentrations

[N₂]i = 5 mol/2 L = 2.5 M

[Cl₂]i = 10 mol/2 L = 5 M

[NCl]e = 3 mol/2 L = 1.5 M

Step 2: Make an ICE chart

        N₂(g) + Cl₂(g) ⇄ 2 NCl(g)

I         2.5       5                0

C        -x        -x              +2x

E      2.5-x    5-x               2x

Step 3: Find the value of x

We know that [NCl]e = 2x = 1.5 ⇒ x = 0.75 M

Step 4: Calculate the concentrations at equilibrium

[N₂]e = 2.5-x = 2.5-0.75 = 1.75 M

[Cl₂]e = 5-x = 5-0.75 = 4.25 M

[NCl]e = 1.5 M

Step 5: Calculate the equilibrium constant (Kc)

Kc = [NCl]² / [N₂] × [Cl₂]

Kc = 1.5² / 1.75 × 4.25 = 0.30

Answer:

2

Explanation:

there are 2 electrons close to the nucleus

Answer:

2

Explanation:

2*n^2, where n is the electron shell.

If we plug 1 in, we will get 2*1, which is 2.

Answer:

The sideways movement occurs because the maximum velocity of the stream shifts toward the outside of the bend, causing erosion of the outer bank. At the same time the reduced current at the inside of the meander results in the deposition of coarse sediment, especially sand

Answer:

Fe2O3 is the formula this is your correct answer

Answer:

1.47 atm

Explanation:

Step 1: Calculate the moles corresponding to 41.6 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

41.6 g × 1 mol/32.00 g = 1.30 mol

Step 2: Convert 30.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30.0 + 273.15 = 303.2 K

Step 3: Calculate the pressure exerted by the oxygen

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm

The question is incomplete, the complete question is;

A certain liquid X has a normal freezing point of 5.40 °C and a freezing point depression constant K=3.05 ?kg mol solution made of 46.1g of alanine (C3H,NO2) dissolved in 750. g of i. Round your answer to 3 significant digits.

Answer:

3.3 °C

Explanation:

If ∆T= K m I

Where;

∆T = freezing point depression

K = freezing point constant

m= morality of solution

i= Van't Hoff factor

Number of moles of solute = 46.1 g/89.09 g/mol = 0.52 moles

Molality of solution = 0.52 moles /750 ×10-3Kg

= 0.69 m

∆T= 3.05 × 0.69 × 1

∆T= 2.10 °C

Freezing point of solution the solution = freezing point of pure solvent - freezing point depression

= 5.40°C - 2.10 °C

= 3.3 °C