Given the following cross TtYyRr x TtyyRr (T = tall; t = short Y = yellow; y = green R = round; r = wrinkled), what proportion of offspring would be expected to be short plants with round, green seeds. Write your answer as a reduced fraction - e.g. 1/2 proportion is

Answers

Answer 1

Answer:

3/32 ttyyR-  

Explanation:

Cross: Tall, Yellow, Rounded individuals with a tall, green, rounded individual

Parentals) TtYyRr      x      TtyyRr      

Gametes) TYR, TyR, TYr, Tyr, tYR, tyR, tYr, tyr (Parent one)

                 TyR, TyR, Tyr, Tyr, tyR, tyR, tyr, tyr (Parent two)

We need to know what proportion of offspring is expected to be short plants with round, green seeds. So we need to identify the gametes for these traits. The genotypes are:

Shot → ttRound → RR or RrGreen → yy

⇒ Parent one can provide gametes tyR and tyr

⇒ Parent two can provide gametes tyR and tyr

(1/8 tyR x 2/8 tyR) + (1/8 tyR x 2/8 tyr) + (1/8 tyr x 2/8 tyR) =

2/64 ttyyRR + 2/64 ttyyRr + 2/64 ttyyRr =

1/32 ttyyRR + 2/32 ttyyRr =

3/32 ttyyR-          

Answer 2

The branch of science which deals with the gene and inheritance is called biology.

The correct answer is 3/32.

When a parent has 3 characters and crosses with other parents which have a 3 character is called a trihybrid cross.

In this question, the genotype of the parent is given as follows:-

Mother - TtYyRrFather - TtyyRr

The gametes formed by the parents is as follows:-

TYR, TYr, TyR, Tyr,  tYR, tYr, tyR, tyr is gamete of motherTYR, TYr, TyR, Tyr,  tYR, tYr, tyR, tyr is gamete of father.

According to the law of inheritance it stated that the each gamete can fused with any gamete to increase the chances of variation.

Hence, after the crossing the number of offspring will form is 32.

Therefore the offspring which has a short plant with a round green seed is 3/32.

Hence, the correct answer is 3/32.

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