Answer:
Amount of plastic need to cover paper role = 565.2 inches
Step-by-step explanation:
Given:
Diameter of paper role = 10 inch
Height of paper role = 13 inch
Find:
Amount of plastic need to cover paper role
Computation:
Radius of paper role = Diameter of paper role / 2
Radius of paper role = 10 / 2
Radius of paper role = 5 inch
Amount of plastic need to cover paper role = Total surface area of cylinder
Amount of plastic need to cover paper role = 2πr(h+r)
Amount of plastic need to cover paper role = 2(3.14)(5)(13+5)
Amount of plastic need to cover paper role = (3.14)(10)(18)
Amount of plastic need to cover paper role = 565.2 inches
Is the discriminant of g positive, zero, or negative?
HURRY NEED ASAP TRYNA FINISH SUMMER SCHOOL LOL, I WILL MARK BRAINLIEST :)) PICTURE IS THERE FOR U
Answer:
B.
Step-by-step explanation:
Since the numbers in the root is all the same, lets say [tex]\sqrt{2}[/tex] is a variable.
7x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex]
Group with like terms:
7x[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]
Combine like terms:
8x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]
There you have it! Since all the square roots are the same thing, we can treat them like variables.
the answer is B..................
A student draws two parabolas on graph paper. Both parabolas cross the x-axis at (-4, 0) and (6.0). The y-intercept of
the first parabola is (0,–12). The y-intercept of the second parabola is (0, -24). What is the positive difference between
the a values for the two functions that describe the parabolas ? Write your answer as a decimal rounded to the nearest
tenth.
Answer:
∆a = 1/2
Step-by-step explanation:
parabolas cross the x-axis at (-4, 0) and (6, 0)
y = a(x + 4)(x - 6)
At the y-intercept x = 0
y = a(0 + 4)(0 - 6)
y = -24a
-----------------------
y-intercept of the first parabola is (0,–12)
-12 = -24a
a = 1/2
-----------------------
y-intercept of the second parabola is (0, -24)
-24 = -24a
a = 1
----------------------
What is the positive difference between the a values
∆a = 1 - 1/2
∆a = 1/2
What is the value of x?
Enter your answer, as a decimal, in the box.
Answer:
x = 50.6
Step-by-step explanation:
Please help me with this one
Answer:
240
Step-by-step explanation:
well do *
so 8x6x5 = 240 there's your answer
Answer:
[tex]S.A=1/2(8+8)(9^{2})+8\times 6+8\times 5[/tex]
[tex]=26\times2+48+40[/tex]
[tex]=140 ~cm^{2}[/tex]
-------------------------
HOPE IT HELPS
HAVE A GREAT DAY!!
what single transformation maps triangle ABC onto A’B’C?
Answer:
the answer is rotation hope it helps ahhaha
When Zero added to any integer, what is the result?
Answer:
answer will be the integer only which was added to zero
What conversion ratio was skipped in this multiple-step conversion?
Answer:
B
Step-by-step explanation:
B was missed. You have to convert this from hours into minutes before you can deal with seconds.
CAN SOMEONE HELP ME ASAP!!!
Answer:
5÷35 = 1/7× 100
Step-by-step explanation:
P(E)= n(E)÷ n(s)
Answer:
17%
Step-by-step explanation:
Add all of the students up and then form a ratio:
30 students in total; 5 seniors/30 students
5/30 = 1/6 = 16.67%
(I think that's the answer, hope it helps)
Which equation can be used to determine the reference angle
Answer:
2nd option
Step-by-step explanation:
[tex]\frac{7\pi }{12}[/tex] is an angle in the second quadrant
Thus to find the reference angle, subtract from π , that is
r = π - θ
find missing side of triangle, help!
Answer:
2√10 km
Step-by-step explanation:
By Pythagoras theorem,
x^2 + 9^2 = 11^2
x^2 + 81 = 121
x^2 = 121 - 81
x^2 = 40
= 4 x 10
x^2 = 2^2 x 10
x = 2√10 km
can anyone help me here asapp,, I am in this question for nearly an hour
Answer:
See below
Step-by-step explanation:
Let side AB equal x. Since triangle ABC is equilateral, sides AB, BC, and Ac are all the same length, x. In any isosceles triangle(equilateral is a type of isosceles triangle) the median is the same as the altitude and angle bisector. This means we can say that AD is also a median. A median splits a side into two equal sections, so we can say BD = DC = x / 2. We are given that DC = CE, so we can also say CE = DC = x / 2. Now, we can use the pythagorean theorem to find the length of AD. So we get the equation:
AB^2 - BD^2 = AD^2
We have the values of AB and BD, so we can substitute them and solve for AD:
x^2 - (x/2)^2 = AD^2
x^2 - x^2 / 4 = AD^2
AD^2 = 3x^2 / 4
AD = x√3 / 2
DE is equal to the sum of DC and CE because of segment addition postulate, so we can say DE = DC + CE = x / 2 + x/ 2 = x. We can again use the pythagorean theorem to find the length of AE:
AD^2 + DE^2 = AE^2
(x√3 / 2)^2 + x^2 = AE^2
3x^2 / 4 + x^2 = AE^2
AE^2 = 7x^2 / 4
AE = x√7 / 2
Now, we know(from before) that AE squared is 7x^2 / 4. We can say EC squared is x^2 / 4 because EC is x / 2 and x / 2 squared is x^2 / 4. We can also notice that AE squared is 7 times EC squared because 7x^2 / 4 = 7 * x^2 / 4
Therefore, we can come to the conclusion AE^2 = 7 EC^2
Use a half angle identity to find the exact value of tan 5pi/12
a. 2+squared3/2
b. 2-squared3/2
C.2+squared 3
D.2-squared3. Please select the best answer from the choices provided
Observe that
5/12 = 1/4 + 1/6
so that
tan(5π/12) = tan(π/4 + π/6)
Then
tan(5π/12) = sin(π/4 + π/6) / cos(π/4 + π/6)
… = (sin(π/4) cos(π/6) + cos(π/4) sin(π/6)) / (cos(π/4) cos(π/6) - sin(π/4) sin(π/6))
… = (cos(π/6) + sin(π/6)) / (cos(π/6) - sin(π/6))
(since sin(π/4) = cos(π/4) = 1/√2)
… = (√3/2 + 1/2) / (√3/2 - 1/2)
… = (√3 + 1) / (√3 - 1)
… = (√3 + 1) / (√3 - 1) × (√3 + 1) / (√3 + 1)
… = (√3 + 1)² / ((√3)² - 1²)
… = ((√3)² + 2√3 + 1²) / (3 - 1)
… = (3 + 2√3 + 1) / 2
… = (4 + 2√3) / 2
… = 2 + √3 … … … (C)
If you insist on using the half-angle identity, recall that
sin²(x) = (1 - cos(2x))/2
cos²(x) = (1 + cos(2x))/2
==> tan²(x) = (1 - cos(2x)) / (1 + cos(2x))
Let x = 5π/12. The angle x lies in the first quadrant, so we know tan(x) is positive.
==> tan(x) = +√[(1 - cos(2x)) / (1 + cos(2x))]
We also know
cos(2x) = cos(5π/6) = -√3/2
which means
tan(x) = tan(5π/12) = √[(1 - (-√3/2)) / (1 + (-√3/2))]
… = √[(1 + √3/2) / (1 - √3/2)]
… = √[(2 + √3) / (2 - √3)]
… = √[(2 + √3) / (2 - √3) × (2 + √3) / (2 + √3)]
… = √[(2 + √3)² / (2² - (√3)²)]
… = √[(2 + √3)² / (4 - 3)]
… = √[(2 + √3)²]
… = 2 + √3
5 + 3bc =
9a + b =
cd + bc =
Answer:
You can't answer these questons
sorry
Hope This Helps!!!
There is money to send four of nine city council members to a conference in Honolulu. All want to go, so they decide to choose the members to go to the conference by a random process. How many different combinations of four council members can be selected from the nine who want to go to the conference
Answer:
126
Step-by-step explanation:
There are 9 city council members.
We have to choose 4 of them.
We have to use the combination as :
[tex]$^9C_4$[/tex]
where, 9 is the population size
4 is the sample size.
Therefore, the total number of possible samples without replacement is given as :
[tex]$^9C_4=\frac{9!}{4!(9-4)!}$[/tex]
[tex]$=\frac{9!}{5! \ 4!}$[/tex]
[tex]$=\frac{9 \times 8 \times 7 \times 6}{4 \times 3 \times 2 \times 1}$[/tex]
= 126
What number line model represents the expression 5 1/2 + (-3)
Answer:
(A)
Step-by-step explanation:
The bottom arrow goes to 5 1/2, and then because adding -3 is the same as subtracting 3, the top arrow correctly goes back 3, resulting in an answer of 2 1/2.
Hope it helps (●'◡'●)
You are given the exponential function g(x)=3^x. Which ootion below gives the formula for the new function h created by stretching g by a factor of 3 along the y-axis?
Answer:
h(x) = 3^(x + 1)
Step-by-step explanation:
The exponential function is;
g(x) = 3^(x)
Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;
g(x) = c•b^(x)
In this question, we are told it is stretched by a factor of 3 along the y-axis.
Thus, new function h is;
h(x) = 3 × 3^(x)
Using law of indices, we have;
h(x) = 3^(x + 1)
Find all possible values of α+
β+γ when tanα+tanβ+tanγ = tanαtanβtanγ (-π/2<α<π/2 , -π/2<β<π/2 , -π/2<γ<π/2)
Show your work too. Thank you!
Answer:
[tex]\rm\displaystyle 0,\pm\pi [/tex]
Step-by-step explanation:
please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation
===========================
we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first
cancel tanγ from both sides which yields:
[tex] \rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma ) [/tex]
factor out tanγ:
[tex]\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)[/tex]
divide both sides by tanαtanβ-1 and that yields:
[tex]\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}[/tex]
multiply both numerator and denominator by-1 which yields:
[tex]\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)[/tex]
recall angle sum indentity of tan:
[tex]\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta ) [/tex]
let α+β be t and transform:
[tex]\rm\displaystyle \tan( \gamma ) = - \tan( t) [/tex]
remember that tan(t)=tan(t±kπ) so
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi ) [/tex]
therefore when k is 1 we obtain:
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi ) [/tex]
remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus
[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi ) [/tex]
recall that if we have common trigonometric function in both sides then the angle must equal which yields:
[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm \pi [/tex]
isolate -α-β to left hand side and change its sign:
[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }[/tex]
when is 0:
[tex]\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 ) [/tex]
likewise by Opposite Angle Identity we obtain:
[tex]\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 ) [/tex]
recall that if we have common trigonometric function in both sides then the angle must equal therefore:
[tex]\rm\displaystyle \gamma = - \alpha - \beta \pm 0 [/tex]
isolate -α-β to left hand side and change its sign:
[tex]\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }[/tex]
and we're done!
Answer:
-π, 0, and π
Step-by-step explanation:
You can solve for tan y :
tan y (tan a + tan B - 1) = tan a + tan y
Assuming tan a + tan B ≠ 1, we obtain
[tex]tan/y/=-\frac{tan/a/+tan/B/}{1-tan/a/tan/B/} =-tan(a+B)[/tex]
which implies that
y = -a - B + kπ
for some integer k. Thus
a + B + y = kπ
With the stated limitations, we can only have k = 0, k = 1 or k = -1. All cases are possible: we get k = 0 for a = B = y = 0; we get k = 1 when a, B, y are the angles of an acute triangle; and k = - 1 by taking the negatives of the previous cases.
It remains to analyze the case when "tan "a" tan B = 1, which is the same as saying that tan B = cot a = tan(π/2 - a), so
[tex]B=\frac{\pi }{2} - a + k\pi[/tex]
but with the given limitation we must have k = 0, because 0 < π/2 - a < π.
On the other hand we also need "tan "a" + tan B = 0, so B = - a + kπ, but again
k = 0, so we obtain
[tex]\frac{\pi }{2} - a=-a[/tex]
a contradiction.
Find the measure of the missing angle using the exterior angle sum theorm
Answer:
160=130+x
x=160-130
x=30
Work out the area of this circle.
Give your answer in terms ofand state its units.
units:
Submit ANSWEI
6 mm
Plss help due in very soon
Answer:
36π mm²
Step-by-step explanation:
Formula: πr²
r=radius
r=6
π6²=36π
Find the values of x and y from the following equal ordered pairs. a) (x,-2) = (4,y) b) (3x, 4) = (6, 2y) c) (2x-1, y + 2) = (-1,2) d) (2x + 4, y + 5) = (3x + 3,6) e) (x + y,y + 3) = (6, 2y) f) (x + y, x - y) - (8,0)
Answer:
a)
x=4, y=-2
b)
x=2, y=2
c)
x=0, y=0
d)
x=1, y=1
e)
x=3, y=3
f)
x=4, y=4
Step-by-step explanation:
a) (x,-2) = (4,y)
x=4
y=-2
b) (3x, 4) = (6, 2y)
3x=6 => x=2
2y=4 => y=2
c) (2x-1, y + 2) = (-1,2)
2x-1 =-1 => x=0
y+2 = 2 => y=0
d) (2x + 4, y + 5) = (3x + 3,6)
2x+4 = 3x+3 => x=1
y+5 = 6 => y=1
e) (x + y,y + 3) = (6, 2y)
x+y = 6 => x+3 = 6 => x=3
y+3 = 2y => y=3
f) (x + y, x - y) - (8,0)
x+y = 8 => 2x=8 => x=4
x-y = 0 => x=y => y=4
If z varies jointly as x and y and inversely as w^2?, and
z = 72 when x = 80, y = 30 and
w=5, then find z when x = 20, y = 60 and w=9.
Answer:
Step-by-step explanation:
z = (k*x*y) / w²
Where,
k = constant of proportionality
z = 72 when x = 80, y = 30 and w = 5
z = (k*x*y) / w²
72 = (k * 80 * 30) / 5²
72 = 2400k / 25
Cross product
72 * 25 = 2400k
1800 = 2,400k
k = 2,400/1800
k = 24/18
= 4/3
k = 1 1/3
k = 1.33
find z when x = 20, y = 60 and w=9
z = (k*x*y) / w²
z = (1.33 * 20 * 60) / 9²
z = (1596) / 81
Cross product
81z = 1596
z = 1596/81
z = 19.703703703703
Approximately,
z = 19.7
Solve the equation to find a positive value of c: 3^2 + 4^2 = c^2
Answer:
The answer is c=5,-5
someone help me please with this algebra problem
Answer:
D.
Step-by-step explanation:
She cannot buy a negative number of notebooks. She can buy 0 notebooks, or 1 notebook, or 2, or 3, etc. The number of notebooks she buys must be a non-negative integer.
Answer: D.
Answer qn in attachment
Answer:
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Step-by-step explanation:
The given expression to us is ,
[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]
Now take the LCM as ( x - 1 ) and Simplify , we have ,
[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]
Simplifying further , we get ,
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Hence the second option is correct .
Step-by-step explanation:
[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1) - 2}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2 - 2} \\ = \frac{7 - 4x}{2x - 4} = \frac{ - 4x - 7}{2(x - 2)} \\ thank \: you[/tex]
[tex]option \: b \\ thank \: you[/tex]
using quadratic equation:
help me solve it
[tex]10x - \frac{1}{x } = 3[/tex]
Answer:
[tex]10x - \frac{1}{x} = 3 \\ 10x = 3 + \frac{1}{x} \\ 10x = \frac{3x + 1}{x} \\ 10x \times x = 3x + 1 \\ 10 {x}^{2} = 3x + 1 \\ 10 {x}^{2} - 3x - 1 = 0 \\ 10 {x}^{2} - 5x + 2x - 1 = 0 \\ 5x(2x - 1) + 1(2x - 1) = 0 \\ (5x + 1)(2x - 1) = 0 \\ \\ 5x + 1 = 0 \\ 5x = - 1 \\ x = \frac{ - 1}{5} \\ \\ 2x - 1 = 0 \\ 2x = 1 \\ x = \frac{1}{2} [/tex]
hope this helps you.
Have a nice day!
Six liters of paint will cover 50 square meters. How many square meters will nine liters cover?
Answer:
75 m²Step-by-step explanation:
Six liters of paint will cover 50 square meters.
6L ⇒ 50m²
then,
1L ⇒ 50/6 m²
9L ⇒ 50 × [tex]\frac{9}{6}[/tex] m²
⇒ 75 m²
A recipe for a soup calls for 2/4 cup of chopped onion and 1/5 cup of chopped
celery. What is the total amount of celery and onion needed for the soup?
Answer:
The total amount of celery and onion needed for the soup is 7/10 cup.
Step-by-step explanation:
2/4 + 1/5 = 7/10 cup.
hope it helped :)
mark me brainliest!
A man invests $ 16800 in savings plan that pays simple interest at a rate of 5% per annum. Find the Tim’s taken for his investment to grow to $18900
Answer:
2.5 years
Step-by-step explanation:
The given amount invested, which is the principal, P = $16,800
The simple interest rate, R = 5% per annum
The intended total value of the investment, A = $18,900
The simple interest on the principal, I = A - P
∴ I = $18,900 - $16,800 = $2,100
The formula for the simple interest, I, is given as follows;
[tex]I = \dfrac{P \times R \times T}{100}[/tex]
Therefore, we have;
[tex]T = \dfrac{I \times 100}{P \times R}[/tex]
Plugging in the values, gives;
[tex]T = \dfrac{2,100 \times 100}{16,800 \times 5} =2.5[/tex]
The time it will take the investment to grow to $18,900 is T = 2.5 years
The daily listening audience of an AM radio station is five times as large as that of its FM sister station. If 144,000 people listen to these two radio stations, how many listeners does the FM station have?
Answer:
The number of FM listereners are 24000.
Step-by-step explanation:
Let the listeners of FM are p and thus the istereners of AM are 5p.
According to the question,
p + 5 p = 144000
6 p = 144000
p = 24000
The number of FM listereners are 24000.