Guys i need help please

Answer:

The upthrust or buoyant force helps the duck doesn't sink.

For example, there is a duck which weighs 3 pounds and tree pints of water also weigh three pounds. In this case the volume of the duck is more than the volume of three pints of water, so the duck floats.

Hope it helps!<3

Answer:

a= g = - 9.81 m/s2.

The following equations will be helpful:

a = (vf - vo)/t d = vot + 1/2 at2 vf2 = vo2 + 2ad

When you substitute the specific acceleration due to gravity (g), the equations are as follows:

g = (vf - vo)/t d = vot + 1/2 gt2 vf2 = vo2 + 2gd

If the object is dropped from rest, the initial velocity ("vi") is zero. This further simplifies the equations to these:

g = vf /t d = 1/2 gt2 vf2 = 2gd

The sign convention that we will use for direction is this: "down" is the negative direction. If you are given a velocity such as -5.0 m/s, we will assume that the direction of the velocity vector is down. Also if you are told that an object falls with a velocity of 5.0 m/s, you would substitute -5.0 m/s in your equations. The sign convention would also apply to the acceleration due to gravity as shown above. The direction of the acceleration vector is down (-9.81 m/s2) because the gravitational force causing the acceleration is directed downward.

hope this info helps you out!

Answer:

143

Explanation:

Using one of the 3 fundamental equations in physics, y=vo*t+1/2gt^2, we can use this equation to find the total distance that was traveled.

Acceleration due to gravity is always 9.8m/s^2 and time is 5.4s, we also have no initial velocity.

Given this, we can plug in the known variables.

y=0t+1/2*9.8*5^2

simplify,

y=4.9*5.4^2

y=4.9*29.16

y=142.884m which we can round up to 143 meters

Final Answer: 143 meters

Answer:

5 years worth of work (aka all of the homework i currently have)

Answer:

Explanation:

Given parameters:

Weight of object  = 49N

Force applied = 12N

Unknown:

Acceleration of object  = ?

Solution:

The acceleration of the object is found by dividing the force by the weight;

 Acceleration  = [tex]\frac{12}{49}[/tex]   = 0.25m/s²

Answer:

a. 3.68 m b. 0.61 m c. 3.07 m

Explanation:

a. What is the maximum height the ball reaches on the moon?

Using v² = u² - 2g'h where u = initial velocity of baseball = 12 m/s, v =  final velocity of baseball = 0 m/s (since it stops at maximum height), g' = acceleration due to gravity on moon = g/6 where g = acceleration due to gravity on earth = 9.8 m/s², so g' = 9.8 m/s²/6 = 1.63 m/s² and h = maximum height of ball on moon.

So, making h subject of the formula, we have

h = -(v² - u²)/2g'

substituting the values of the variables, we have

h = -((0 m/s)² - (12 m/s)²)/2(1.63 m/s²)

=  -(- 12 m²/s²)/2(1.63 m/s²)

= 6 m²/s²)/(1.63 m/s²)

= 3.68 m

b. What is the maximum height the ball reaches on the earth?

Using the same equation for the maximum height the baseball travels on the moon for that on the earth, the maximum height h' the baseball travels on the earth is given by  

h' = -(v² - u²)/2g where u = initial velocity of baseball = 12 m/s, v =  final velocity of baseball = 0 m/s (since it stops at maximum height),  g = acceleration due to gravity on earth = 9.8 m/s²and h' = maximum height of ball on moon.

substituting the values of the variables, we have

h = -((0 m/s)² - (12 m/s)²)/2(9.8 m/s²)

=  -(- 12 m²/s²)/2(9.8 m/s²)

= 6 m²/s²)/(9.8 m/s²)

= 0.61 m

c. What is the difference in the maximum height the ball reaches on the Moon compared to on Earth?

The difference in the maximum height the ball reaches on the Moon compared to on Earth is d = h - h' = 3.68 m - 0.61 m = 3.07 m

Answer:

idgaf

Explanation:

lol

Answer:

The resistance of an ammeter should be low. This is because an ammeter is connected in series with the circuit for the measurement of electric current. In case, its resistance is high, then some amount of current may lost in heating it leading to the inaccurate reading. An ideal ammeter is one which has zero resistance.

Answer:

Bread contains energy in form of

Carbohydrates

Explanation:

Answer:

CHEMICAL ENERGY

Answer:

Average speed 62.5 miles an hour.  If the train was traveling at a constant speed in a straight line it would be much faster on getting to its destination

Explanation:

Answer:

i believe it's 7

Explanation:

Answer:

a change in velocity can be a change in magnitude (or speed), but it can also be a change in direction.

Answer:

A. im not for sure hope it helps

Explanation:

Answer:

forever

Explanation:

Answer:

d

Explanation:

Answer:

Earth absorbs heat from the sun.

Explanation:

This radiation is absorbed by greenhouse gases which then radiate energy into all directions including downwards and thereby trapping heat in the atmosphere.

Hope you have a good day :)

Answer:

68.2 Quadrillion meters

Explanation:

A lightyear is the distance that light travels in one year.

Speed of light is [tex]3*10^8\ m/s[/tex]

So light covers 300,000,000 meters in one second.

One year has 31536000 seconds so , light covers

[tex]9.461*10^{15}\ meters\ in\ one\ year[/tex]

so 7.2 light years is

[tex]7.2*(9.461*10^{15})\\6.82*10^{16}[/tex]

so 7.2 light years is

6.82 x 10^(16) meters or

68.2 Quadrillion meters

Answer:it would make it thicker

Explanation:

Answer:

"The equation shows that the current in a circuit is inversely proportional to the resistance of the circuit. An increase in resistance would result in a decrease in current. And the factor by which the resistance increases is the same factor by which the current decreases."

Explanation:

Because it's just like wearing a glove/mitten when getting something out of the oven, because of the insulation from the glove/mitten, it reduces the heat that gets through into your hand, and it protects it. Just like what the "answer" says, it said that the resistance would decrease current.

Answer:

B.

pole position

Answer:

The answer is actually a. Cathode

Explanation:

Just took the quiz

In an electrolytic cell, the reduction occurs at the cathode. So, the correct option is a.

Reduction is defined as the process through which a reactant gain electrons during a chemical reaction.

Here,

An electrolytic cell is an equipment that uses electric current to drive a redox reaction.

Redox reactions are the type of reaction that involves the transfer of electrons between the reactants. That means, in redox reactions, both oxidation and reduction occurs. The reactant that gains the electrons is said to be reduced and the one that losses the electrons is said to be oxidized.

In an electrolytic cell, cathode is the positively charged electrode. So, electrons are attracted towards it, and as a result, the cathode gets reduced.

Hence,

In an electrolytic cell, the reduction occurs at the cathode.

To learn more about reduction, click:

https://brainly.com/question/1222373

#SPJ2

Answer:

[tex]\huge\boxed{10\:watts}[/tex]

Explanation:

Power = Current × Voltage

P = I × V

P = 2 × 5

P = 10 watts

Answer:

[tex]\eta_{turbine} = 0.777 = 77.7\%[/tex]

[tex]\eta_{combined} = 0.728 = 72.8\%[/tex]

Explanation:

First we calculate the power input to the turbine. The input power will be equal to the potential energy of water per unit time:

Input Power = [tex]P_{in} = \frac{Work}{Time} = \frac{Potential\ Energy\ of\ Water}{t} \\P_{in} = \frac{(mass)(g)(height)}{Time} = (mass flow rate)(g)(height)\\\\P_{in} = (1500\ kg/s)(9.81\ m/s^2)(70\ m)\\P_{in} = 1.03\ x\ 10^6\ W = 1030\ KW[/tex]

Now, for turbine efficiency:

[tex]\eta_{turbine} = \frac{Mechanical\ Power\ Out}{P_{in}}\\\\\eta_{turbine} = \frac{800\ KW}{1030\ KW}\\\\\eta_{turbine} = 0.777 = 77.7\%[/tex]

for generator efficiency:

[tex]\eta_{generator} = \frac{Power\ Generation}{Mechanical\ Power\ Out}\\\\ \eta_{generator} = \frac{750\ KW}{800\ KW}\\\\\eta_{turbine} = 0.9375 = 93.75\%[/tex]

Now, for combined efficiency:

[tex]\eta_{combined} = \eta_{turbine}\ \eta_{generator}\\\\\eta_{combined} = (0.777)(0.937)\\\eta_{combined} = 0.728 = 72.8\%[/tex]

Answer:Control S, Command S on MAC=Save

Answer:

The value is [tex]T_t = 2.5659 \ s[/tex]    

Explanation:

From the we are told that  

         The initial speed of the object is  [tex]u = 8 \ m/s[/tex]

         The greatest height it reached is  [tex]h = 15 \ m[/tex]

Generally from kinematic equation we have that

      [tex]v^2 = u^2 + 2gH[/tex]

At maximum height v  =  0 m/s

So

      [tex]0^2 = 8^2 + 2 * - 9.8 * H[/tex]

=>    [tex]H = 3.27 \ m[/tex]

Here H is the height from the initial height to the maximum height

So the initial height is mathematically represented as  

      [tex]s = h - H[/tex]

=>    [tex]s = 15 - 3.27[/tex]

=>    [tex]s = 11.73 \ m[/tex]

Generally the time taken for the object to reach maximum height is mathematically evaluated using kinematic equation as follows

            [tex]v = u + (-g) t[/tex]

At maximum height v  =  0 m/s

           [tex]0 = 8 - 9.8t[/tex]

=>         [tex]t = 0.8163 \ s[/tex]

Generally the time taken for the object to move from the maximum height to the ground is mathematically using kinematic equation as follows

       [tex]h = ut_1 + \frac{1}{2} gt_1^2[/tex]

Here the initial velocity is  0 m/s given that its the velocity at maximum height

Also  g is positive because we are moving in the direction of gravity  

So

       [tex]15 = 0* t + 4.9 t^2[/tex]

=>      [tex]t_1 = 1.7496[/tex]

Generally the total time taken is mathematically represented as

          [tex]T_t = t + t_1[/tex]

=>        [tex]T_t = 0.8163 + 1.7496[/tex]

=>        [tex]T_t = 2.5659 \ s[/tex]