h (t) = -10t + 6

h ( ? ) = -44

I'm looking for the T that goes in the parenthesis

This is from Algebra 1 - Khan Academy, Unit Functions

Answer:

x = 70     y = 140

Step-by-step explanation:

Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.

The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.

The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.

Answer:

Step-by-step explanation:

See the picture

It should be self-explanatory

The top part of the angle a is:

The bottom part of the angle a is:

The measure of angle a is:

Firstly, draw a line parallel to UT

Something like in the picture

Now,

a = BNU

Also,

BNU + BNM = 165°

Answer:

h(x) = -4 x –7

h(3) = -4(3) —7

h(3) = –12 –7

h(3) = – 19

Answer:

y + 5 = 2(x - 4)

Step-by-step explanation:

y + 5 = 2(x - 4)

Answer:

9a. GCF: 16. LCM: 960

9b. GCF: 55. LCM: 275

9c. GCF: 24. LCM: 114

9d. GCF: 40. LCM: 600

10a. GCF: 120. LCM: 1440

10b. 10, 2, 5, 20

10c. 2880, 4320, 5760, 7200

Which value is 10,000 times larger than 1,300?

answer= 1300×10000

= 13,000,000

Hello,

let's assume a=the length and b the width.

[tex]\left\{\begin{array}{ccc}a&=&2*b\\2(a+b)&=&60\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\a+b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\3b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b&=&10\\a&=&20\\\end{array}\right.\\\\\\Area=10*20=200\ (ft^2)\\[/tex]

Answer:

last option

Step-by-step explanation:

3.9x3 -4.1x2+7.3

Answer:

Pythagoras theorem states that c²=a²+b²

14²=12²+x²

14²-12²=x²

196-144=x²

52=x²

√52=√x²

7.2111025509279785=x

rounded up to the nearest hundredth=7.21

Answer:

a) 71

b) an = a1 + (n-1)×7

c) the 37th term

Step-by-step explanation:

clearly, an+1 = an + 7

so, any new term is the previous term plus 7.

a1 = 8

and then the sequence goes on. starting with a2 we add 7 every time.

so, for an we added 7 n-1 times to a1. n-1 because for a1 we did not have to add 7.

therefore, the building function of this sequence to calculate the nth term is

an = a1 + (n-1)×7

a10 = a1 + 9×7 = 8 + 63 = 71

and

ax = 260 = a1 + (x-1)×7 = 8 + 7x - 7 = 1 + 7x

259 = 7x

x = 37

=> the 37th term of the sequence is 260

Answer:

1. Population mean

2. Sample mean

3. Population standard deviation

4. Sample standard deviation

Step-by-step explanation:

Required

Complete the gaps

The answer is self-explanatory.

All you need to do in this question is to look for the keywords (mean/standard deviation) and (population/sample).

In addition, the symbol of the parameters are:

1. Population mean [tex]\mu[/tex]

2. Sample mean [tex]\bar x[/tex]

3. Population standard deviation [tex]\sigma[/tex]

4. Sample standard deviation [tex]\sigma_x[/tex]

Answer: ∠p and ∠s, ∠q and ∠r

Step-by-step explanation:

From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.

The sets of angles are corresponding angles are; ∠p and ∠s, ∠q and ∠r

It can be defined as, corresponding means pair wise angles. Like the right corner angles of two triangles etc. But usually we take them as:

For two similar figures, the pair by pair similar angles of those two similar figures are called corresponding angles. They are of same measurement.

From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.

We can conclude the sets of angles that are corresponding angles;

∠p and ∠s, ∠q and ∠r

Learn more about  angles here:

https://brainly.com/question/2882938

#SPJ1

Answer:

5/12

Step-by-step explanation:

1/2 x 5/6 = 5/12

Answer:

6²

Ste㏒㏒㏑p-by-step explanation:

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]3^{x}+3^{x+2}=\frac{10}{3} \\=> 3^{x} + 3^{x}*3^{2}= \frac{10}{3} \\\\=> 3^{x} (1+9)=\frac{10}{3} \\=> 3^{x}=\frac{10}{3}:10\\=> 3^{x}=\frac{1}{3} \\ \\=> x=-1[/tex]

Answer:

300 seconds

Step-by-step explanation:

The first dog run at v₁ = 15 m/sec     the second one run at  v₂ = 12 m/sec

we know that  d = v*t  then  t  =  d/v

Then the first dog will take  300/ 12  =  25 seconds to make a turn

The second will take   300 / 15   =   20 seconds to make a turn

Then the first dog in 12 turns 12*25 will be at the start point, and so will the second one at the turn 15.

To check  first dog    12 *  25 = 300

And the second dog 15 * 20 = 300

That means that time required for the two dogs to be at the start point together is

300 seconds, in that time the first dog finished the 12 turns, and the second had ended the 15.

Another procedure to solve this problem is as follows:

between  12  m/sec and  15 m/sec   the minimum common multiple  is 300 ( 300 is the smaller number that accept 12 and 15 as factors         12*15 = 300) Then when time arrives at 300 seconds the two dogs will be again in the starting point

Answer:

x = 12

Step-by-step explanation:

First we need to add x & 1/4x.

Pretend there's a 1 infront of x, so that the equation looks like:

1x + 1/4x = 15

To combine the two terms, we need to get the 1 to have the same denominator as 1/4, so let's multiply 1 (which is the same as 1/1) by 4/4.

You get 4/4! Substitute that into the equation:

4/4x + 1/4x = 15

Now combine the terms:

(4/4x + 1/4x = 5/4x)

5/4x = 15

Finally, multiply both sides by 4/5 to cancel out the 5/4:

x = 15*4/5

x = 60/5

x = 12

Hope it helps (●'◡'●)

dåså, man på rådets ordförande

Answer:

Step-by-step explanation:

2x + 3y = 2750

x + y = 1250

where x is student tickets and y is adult tickets

x = 1250 – y

2x = 2500 – 2y

→

(2500 – 2y) + 3y = 2750

2500 + y = 2750

y = 250 →

x + y = 1250

x = 1000

Answer:

960$

Step-by-step explanation:

First you want to find out how much money she makes per hour by doing 840/35. That equals 24, so now you multiply it by the amount of hours for this week. 24*40= 960$.

Hope this helps :D

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that [tex]a[/tex] raised to the power [tex]b[/tex] can be written as [tex]a^b[/tex].

Any non zero number raised to the power 0 is always 1. It means,

[tex]a^0=1[/tex], where [tex]a\neq 0[/tex].

-3 raised to the power 0 [tex]=(-3)^0[/tex]

                                         [tex]=1[/tex]

Therefore, the value of the given statement is 1.

Answer:

(a) is 8 x 7 x 3 = 168

(b) is 8 x 7 = 56

(b2) is weird I don't know what it's asking

Answer:

FOR LETTER A

Volume of prism (expression) = Length x Width/Breadth x Height

Volume of prism (expression) = 8 units x 7 units x 3 units = 168 cubic units

FOR LETTER B

Area of the shaded base = 8 x 7 = 56 square units

Volume of prism = Area of the shaded base x Height

Volume of prism = 56 square units x 3 units = 168 cubic units

Step-by-step explanation:

To find the volume of rectangular prism, we multiply the length of the prism by the width of the prism by the height of the prism.

Volume of rectangular prism = length × width × height

To get the area of the shaded base, when the base is in rectangular shape:

Definition: Area of rectangle is the region occupied by a rectangle within it's four sides or boundaries.

The area of a rectangle depends on its sides. Basically, the formula for area is equal to the product of length and breadth of the rectangle. Whereas when we speak about the perimeter of a rectangle, it is equal to the sum of all its four sides. Hence, we can say, the region enclosed by the perimeter of the rectangle is its area. But in the case of a square, since all the sides are equal, therefore, the area of the square will be equal to the square of side-length.

Area of rectangle = Length × Breadth

A = l × b

Answer:

0.5miles

Step-by-step explanation:

800meters is 0.497097miles

Round 0.497097miles to the nearest hundredth which would be 0.5 miles.

Hello,

Let's x² the square number

and 3*y the multiple of 3.

[tex]x^2+3y=90\\\\\boxed{y=-\dfrac{1}{3} x^2+30}\\\\[/tex]

2 solutions : for (x,y) as integers : (-6,18) and (6,18)

but one solution for (x²,3y) as integers : (36,54)

Answer:

4. D.

5. C.

6. A.

Step-by-step explanation:

It's just simple ratios... It's been a while since I learned it so I don't really remember how to explain the answers.

Answer:

Step-by-step explanation:

Set the equation and solve for x:

Correct choice is B

Answer:

Step-by-step explanation:

Slope = m = 3

(x₁ , y₁) = (-1 , 2)

Point slope form: y - y₁ = m(x - x₁)

y - 2 = 3(x - [-1] )

y - 2 = 3(x + 1)

y - 2 = 3*x + 3*1

y - 2 = 3x + 3

    y = 3x + 3 + 2

    y = 3x + 5

Answer:

I hope the pic i gave is helpful!!!

Answer:

It is the last one: (4x-9)(x+8)

Step-by-step explanation:

You have to split the "b", or split the 23x so that you can perform grouping, and then combine.

Answer:

(4x-9)(x+8)is the correct answer

Answer:

I’m sorry but you need to edit this question, it is incomplete.

Step-by-step explanation:

I see nothing, if there is supposed to be an image attached, please i attach it again, tnx!

I could help you though

Given:

The matrix is:

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

To show:

[tex](A^{-1})^{-1}=A[/tex]

Solution:

If a matrix is:

[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]

Then,

[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]

We have,

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

Using the above formula, we get

[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

Now, the inverse of [tex]A^{-1}[/tex] is:

[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]

[tex](A^{-1})^{-1}=A[/tex]

Hence proved.