Hannah invested $820 in an account paying an interest rate of 1.8% compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 16 years?

Answer:

This is a rational decimal and is not a repeating decimal.

Step-by-step explanation:

the answer would be in the y=m(m=slope of the line)x + b( the y intercept) so it works be

y=3x+-3

Answer:

82.20

Step-by-step explanation:

Answer:

alguien habla español

Step-by-step explanation:

Answer:

no i dont think so

Step-by-step explanation:

Answer:

0.25km

Step-by-step explanation:

Answer:

12.6

Step-by-step explanation:

Use long multiplication to evaluate.

Answer:

12.6

Step-by-step explanation:

0.12*105=12.6

Answer:

600 whiskers

Step-by-step explanation:

25*25=600

It's 61/21. That's the answer.

Answer:

1,3

Step-by-step explanation:

Parallel lines are defined to be two lines that will never intersect even when they go on infinitely. Think of it like railroad tracks. The rails must always be parallel, or the train will gets stuck. By observing lines L and M, you'll notice both lines make perfect railroad tracks, and they will never intersect. These lines are parallel.

Answer:3/4

Step-by-step explanation:

First get the common denominator that is 12 then divide 12 by the first denominator which is 2 then add the numerator which is 1 then you will get 7 then repeat to second denominator just divide 12 by 12 then add 1 then add the numerator and copy the denominator. To simplify your answer just divide both by 3 and you will get the final answer of 3/4.

Answer:

13 : 4

Step-by-step explanation:

13 : 4

he has 13 cows and he has 4 bales of hay so 13:4

you can't simplfy it so its still 13 : 4

Answer:

261.48

Step-by-step explanation:

Answer:

x=3.2

Step-by-step explanation:

4(6 – x) + 4 = 2 (3x + 1) – 6

24 - 4x + 4 = 6x + 2 - 6

28 - 4x = 6x -4

-4x - 6x = - 4 - 28

-10x = - 32

divide both sides

x = 16/5 or x = 3.2

hope this helps :)

Answer:

15

Step-by-step explanation:

15x4 times the string=60

60+15 is the length of the smaller string=75 inches of the total string.

Hope this helps pls give brainliest

Answer:

Many situations will call for you to round decimals to the nearest tenth to make the number easier to work with. Once you understand how to find the tenths and hundredths place, the process is very similar to rounding whole numbers.

Step-by-step explanation:

Many situations will call for you to round decimals to the nearest tenth to make the number easier to work with. Once you understand how to find the tenths and hundredths place, the process is very similar to rounding whole numbers.

Answer:

6

Step-by-step explanation:

The way you wrote it, it is already rounded.....

The value I remember for pi is 3.14159. This is rounded to the nearest 10-thousandth. Another way of saying the same thing is that it is "rounded to 5 decimal places".

pi--rounded off in decreasing precision:

3.14159

3.1416

3.142

3.14

3.1

3

Watch out for a trap in rounding:

Suppose I start with 5.49. To the nearest 10th, it would be 5.5. To the nearest whole digit, it is 5, not 6. If the original number were 5.51, then rounded to the nearest whole digit would be 6.

Answer:

=2.64

Step-by-step explanation:

Answer:

4.474 it is simple you just add them

Answer:

6.474

Step-by-step explanation:

i calculated it

Answer:

252=252 so

Step-by-step explanation:

Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

[tex] PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] P (1, 1) = (x_1, y_1) [/tex]

[tex] R(-3, 5) = (x_2, y_2) [/tex]

Plug in the values into the formula.

[tex] PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2} [/tex]

[tex] PR = \sqrt{(-4)^2 + (4)^2} [/tex]

[tex] PR = \sqrt{16 + 16} [/tex]

[tex] PR = \sqrt{32} [/tex]

[tex] PR = 5.7 units [/tex] (to nearest tenth)

Answer:

[tex]\frac{1}{2}[/tex] blocks

Step-by-step explanation:

If it takes 15 minutes to walk 7 1/2 blocks, it should be 15:17[tex]\frac{1}{2}[/tex]

The left side is minutes and the right side is the number of blocks

15:17[tex]\frac{1}{2}[/tex]

 1: ?  Since we are figuring out how many blocks he can walk in a minute, the left side is 1 and the right side is a question mark because we have not figured it out yet.

15: 17 [tex]\frac{1}{2}[/tex]    Divide by 15 on both sides because that is the "distance" from 15 to1

 1 : ?

1: [tex]\frac{1}{2}[/tex]

So the answer is [tex]\frac{1}{2}[/tex]

Answer:

-10 :)

Hey champ! Here's the 'splination!

equation: 50-5x=100

50=-5x. (subtract 50 from both sides)

-10=x (divide both sides by -5)

Answer:

n/4 + 1 =5

n/4 = 5-1

n/4 = 4

n = 4*4

n = 16

Answer:

So do this,

Step-by-step explanation:

stand up and go ask your mom!

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

[tex]\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}[/tex]

2.

Using partial fraction decomposition to find the definite integral of:

[tex]\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx[/tex]

By using the long division method; we have:

[tex]x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }[/tex]

                  [tex]- 2x^3 -16x^2-40x[/tex]

                                            [tex]x+ 20[/tex]

So;

[tex]\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}[/tex]

By using partial fraction decomposition:

[tex]\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}[/tex]

                         [tex]= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}[/tex]

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

[tex]A = \dfrac{5}{2}[/tex]     [tex]B = \dfrac{3}{2}[/tex]

Now;

[tex]\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}[/tex]

Thus;

[tex]\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}[/tex]

Now; the integral is:

[tex]\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx[/tex]

[tex]\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}[/tex]

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

Answer:

39.75

Step-by-step explanation:

First, subtract 50 from both sides

200z + 50 - 50 = 8000 - 50

200z = 7950

Then isolate the variable by dividing both sides by 200

200z/200 = 7950/200

z=39.75