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How is the product of 2 and 5 shown on a number line?
2-1 0 1 2 3 4 5.7.1
-10
101235
7.
-13-
3-L 1 2 3
5
-1012
4 5

The answer is : -4/15

Answer:

-4/15

Step-by-step explanation:

slope is simply the rise over the run which is the change in y over the change in x.

( (y_2) - (y_1) ) / ( (x_2) - (x_1) )

if you plug in your variables that gives you

(14-10) / (-7-8)

which equals

4/-15

- (4/15)

[tex]3 \times 25\% \times 40 = 3 \times \dfrac{25}{100} \times 40 = 3 \times 10 =30[/tex]

The value of the numerical expression 3 × 25% × 40 will be 30.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expression is given below.

⇒ 3 × 25% × 40

Simplify the expression, then the value of the expression will be given as,

⇒ 3 × 25% × 40

⇒ 3 × 0.25 × 40

⇒ 30

The value of the numerical expression 3 × 25% × 40 will be 30.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

Answer:

50 in²

Step-by-step explanation:

The area of the rectangle = 8 × 4 = 32 in²

area of Δ NPO = [tex]\frac{1}{2}[/tex] × PO × PN = [tex]\frac{1}{2}[/tex] × 3 × 4 = 6 in² ( PN = RM )

area of Δ PQR = [tex]\frac{1}{2}[/tex] × RP × 3 = [tex]\frac{1}{2}[/tex] × 8 × 3 = 12 in² ( RP = MN )

area of MNOPQR = 32 + 6 + 12 = 50 in²

Answer:

Answer# 1: A. 26

Answer# 2: A. 25

1. What is m + 5n where m = 1 and n = 5?

Substitute 1 for "m" and 5 for "n":

[tex]\sf (1)+5(5)[/tex]

Multiply 5*5 =25

[tex](1)+25[/tex]

Add :

[tex]\sf 26[/tex]

____________________

2. What is 5m + 5n where m = 10 and n = -5?

Substitute 10 for "m" and -5 for "n".

[tex]\sf 5\left(10\right)\:+\:5\left(-5\right)[/tex]

Multiply 5 * 10= 50

[tex]\sf 50+5\left(-5\right)[/tex]

Multiply 5 * -5 = -25

[tex]\sf 50-25[/tex]

Subtract:

[tex]\sf 25[/tex]

___________________________________

Answer:

Step-by-step explanation:

5 / 6 = 0.83333333...

0.833333...•100 = 83.333333...

83.3%

Answer:

You can do this type of questions with inverse proportion.

_

%83,3

Answer:

B: (-2,-3)

Step-by-step explanation:

The problem basically wants you to find the vertex because that is the turning point of an absolute value graph where the slope goes from negative to positive immediately. B is the best choice because the vertex is translated 2 to the left and 3 down.

Answer:

about 20 cents

Step-by-step explanation:

#Shop A

Pack of 70pens:-

[tex]\\ \sf\longmapsto 7(2.30)=16.10[/tex]

#2

Pack of 70

[tex]\\ \sf\longmapsto 14(1.60)=20.80[/tex]

But you get half price

Difference:-

[tex]\\ \sf\longmapsto 16.10-10.40=5.70\£[/tex]

Answer:

It is b

Step-by-step explanation: Because only one that makes sense

Answer: the answer is in the attachment.

Answer:

Hope this helps :)

Step-by-step explanation:

Using the z-distribution, it is found that the p-value for this test is of 0.0375.

At the null hypothesis, it is tested if the expenses are the same as the national average, that is, of $5,423. Hence:

[tex]H_0: \mu = 5423[/tex]

At the alternative hypothesis, it is tested if it is higher, hence:

[tex]H_1: \mu > 5423[/tex]

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

The parameters are:

For this problem, the values of the parameters are: [tex]\overline{x} = 5516, \mu = 5423, \sigma = 979, n = 352[/tex]

The value of the test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{5516 - 5423}{\frac{979}{\sqrt{352}}}[/tex]

[tex]z = 1.78[/tex]

The p-value is the probability of finding a sample mean above $5,516, which is 1 subtracted by the p-value of z = 1.78.

1 - 0.9625 = 0.0375

Hence, the p-value for this test is of 0.0375.

A similar problem is given at https://brainly.com/question/25549474

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Answer:

Step-by-step explanation:

I am sorry but please give detailed question

Answer:

1386

Step-by-step explanation:

V=πr²*h

V=22/7*7²*9

V=1386

1. 3/7 = 72/x

By cross multiplication we get :

➟ 3x = 72 × 7

➟ x = 72 × 7/3

➟ x = 24 × 7

➟ x = 168

2. m/8 = 8/20

By cross multiplication we get :

➟ 20m = 8 × 8

➟ 20m = 64

➟ m = 64/20

➟ m = 16/5

Answer:

3x8m= 14 is the equation that matches the description.

Step-by-step explanation:

It is simply the number three, multiplied by eight with the variable m, and is equal to the number 14.

Answer:

what answer

Step-by-step explanation:

?????????????

Answer:

Angle 145 degrees

Step-by-step explanation:

Hope it can help you lovelots

Answer:

6^3

Step-by-step explanation:

3 × 3 × 3 × 3 × 3 × 3=729

6^3=216

3 × 3 × 3 × 3 × 3 × 3=729

3^6=729

Hope this helps :)

3 × 3 × 3 × 3 × 3 × 3

63

9 × 9 × 9

36

Answer:

6 cm for both sides

Step-by-step explanation:

Answer:

Step-by-step explanation:

Zero's of the function are the points of intersection of the graph with the x-axis.

From the picture we see zeros:

Zeros are

[tex]\\ \sf\longmapsto (-4,0)U(0,0)U(2,0)[/tex]

Answer:

four times a number less 10 is equall to 16 ia not

Answer:

The only way she was able to use it if she knew your email and linked you to the account or she had some sort of permissions to get brainly on her device.

Answer/Step-by-step explanation:

[tex]\frac{1-\cos \left(x\right)}{\sin \left(x\right)}=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}[/tex]

When you have an equation like this, you can start from either side. So, let us start from the left side.

[tex]\underline{\mathrm{Left\:side:}} \quad\frac{1-\cos \left(x\right)}{\sin \left(x\right)}[/tex]

[tex]\sf{Rewrite\: using \:Trig \:identities=\frac{\sin \left(x\right)}{1+\cos \left(x\right)}}\\\\\mathrm{Therefore,\: it \:is \:true}[/tex]

Answer:

20 three-point scores

61/3=20 R1

Answer:

7

Step-by-step explanation:

61 divided by 8 = 7 remainder 5

you can do 7 3's and 7 5's which would make 7x3 = 21  +  7 x 5 = 35  21 + 35 = 56

61 - 56  = 5 (add 1 to the amount of 5's)

7 3's and 8 5's

Answer:

proportion of ratio will be used

Answer:

C. 1 4/10 + 9/10 + 6/10

got it right

Answer:

0.00706666666

Step-by-step explanation: