Answer:
[tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyAlgebra I
Terms/CoefficientsExpand by FOILFunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = (x^3 + 7x - 1)(5x + 2)[/tex]
Step 2: Differentiate
Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)][/tex]Basic Power Rule [Derivative Property - Addition/Subtraction]: [tex]\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)[/tex]Simplify: [tex]\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)[/tex]Expand: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)[/tex][Distributive Property] Distribute 5: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5[/tex]Combine like terms: [tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
find the slope of the line graphed above
Answer:
The slope of the line is -6.
ASAP!!!!!!!!! Please show process!!! Using law of sines!!!!!!!! Thank you so much
Answer:
the answers are on the picture but the numbers may be rounded
How many boxes could you stack safely on a pallet if the pallet is 5 feet deep, five feet across, every box is 1 x 1 and the maximum safe stacking height is 5 boxes? *
Answer:
125 boxes
Step-by-step explanation:
5*5*5
y + x + z =762500
z : x = 15/9 : 2
y : x = 1 : 3/4
Step-by-step explanation:
true
Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.5 feet and a standard deviation of 0.4 feet. A sample of 45 men’s step lengths is taken. Step 1 of 2 : Find the probability that an individual man’s step length is less than 1.9 feet. Round your answer to 4 decimal places, if necessary.
Answer:
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 2.5 feet and a standard deviation of 0.4 feet.
This means that [tex]\mu = 2.5, \sigma = 0.4[/tex]
Find the probability that an individual man’s step length is less than 1.9 feet.
This is the p-value of Z when X = 1.9. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1.9 - 2.5}{0.4}[/tex]
[tex]Z = -1.5[/tex]
[tex]Z = -1.5[/tex] has a p-value of 0.0668
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.
Which is a stretch of an exponential decay function?
f(x) =4/5(5/4)
f(x) = 4/5(4/5)
f(x) =5/4(4/5)
fx) = 5/4(5/4)
Answer:
f(x) = 4/5(5/4)Step-by-step explanation:
correct me if I am wrong
what was the original price of the car? MUST SHOW ALL STEPS OF THE PROCESS.
Answer:
19219.48
Step-by-step explanation:
16540x0.162+16540
The original price would be 100%
It was marked down 16.2%
100 % - 16.2% = 83.8%
The price you paid was 83.8% of the original price.
To find the original price divide the amount you paid by the percentage of the original price:
16,540 / 0.838 = 19.737.47
Original price: $19,737.47
Compute the total cost per year of the following pair of expenses. Then complete the sentence: On an annual basis, the first set of expenses is _______% of the second set of expenses.
Vern buys seven lottery tickets each week at a cost of $3 each and spends $900 per year on his textbooks.
Answer:
So 912$ is 58% of 1584 $
Step-by-step explanation:
Which of the following functions shows the reciprocal parent function, F(x) = 1, shifted left?
Answer:
G(x)=1/x+15
Step-by-step explanation:
.
f(x) = 4x3 + 7x2 – 2x – 1
g(x) = 4x – 2
Find (f - g)(x).
please help
9514 1404 393
Answer:
(f-g)(x) = 4x^3 +7x^2 -6x +1
Step-by-step explanation:
(f -g)(x) = f(x) -g(x)
= (4x^3 +7x^2 -2x -1) -(4x -2)
= 4x^3 +7x^2 +(-2-4)x +(-1+2)
(f -g)(x) = 4x^3 +7x^2 -6x +1
Emily drove to town with an average speed of 32 miles per hour, and then back home with an average speed of 38 miles per hour. If her total traveling time was 42 minutes, how far is it from home to town?
Answer:
12.16 milesStep-by-step explanation:
Speed - s, Distance - d, Time - t
Equation of time is:
t = d/sGiven,
s1 = 32 m/h, s2 = 38 m/h, t1 + t2 = 42 min = 42/60 h = 7/10 hTotal time is the sum of time values to and from the town:
d/32 + d/38 = 7/10d/16 + d/19 = 7/5d(1/16 + 1/19) = 7/5d(16 + 19) = 7(16*19)/535d = 425.6d = 425.6/35d = 12.16It is given that,
→ s1= 32 miles/h
→ s2 = 38 miles/h
Now t1 + t2 is,
→ 42 min
→ 42/60 hours
→ 7/10 hours
The formula we use,
→ Time = Distance/Speed
→ t = d/s
Then the total time is the,
Sum of time values to and from the town.
→ d/32 + d/38 = 7/10
→ d/16 + d/19 = 7/5
→ d{(1/16) + (1/19)} = 7/5
→ d(16 + 19) = (7/5) × (16 × 19)
→ 35d = 425.6
→ d = 425.6/35
→ d = 12.16
Hence, the distance is 12.16 miles.
When 4(9y − 5) = 10(3y + 17) − 40 is solved, the result is:
A=20.
B=25.
C=-10.
D=10.
Answer:
B = 25
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
4(9y - 5) = 10(3y + 17) - 40
Step 2: Solve for y
[Distributive Property] Distribute 4: 36y - 20 = 10(3y + 17) - 40[Distributive Property] Distribute 10: 36y - 20 = 30y + 170 - 40Combine like terms: 36y - 20 = 30y + 130[Subtraction Property of Equality] Subtract 30y on both sides: 6y - 20 = 130[Addition Property of Equality] Add 20 on both sides: 6y = 150[Division Property of Equality] Divide 6 on both sides: y = 25[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{4(9y - 5) = 10(3y + 17) - 40}\\\\\large\textsf{4(9y) + 4(-5) = 10(3y) + 10(17) - 10(40)}\\\\\large\textsf{36y - 20 = 30y + 170 - 40}\\\\\large\textsf{COMBINE the LIKE TERMS}\\\\\large\textsf{36y - 20 = (30 y)+ (170 - 40)}\\\\\large\textsf{36y - 20 = 30y + 130}\\\\\large\textsf{SUBTRACT 30y to BOTH SIDES}\\\\\large\textsf{36y - 20 - 30y = 30y + 130 - 30}}\\\\\large\textsf{Cancel out: 30y - 30y because that gives you 0}\\\\\large\textsf{Keep: 20 - 30y because helps solve for the y-value}[/tex]
[tex]\large\textsf{NEW EQUATION: 6y - 20 = 130}\\\\\large\textsf{ADD 20 to BOTH SIDES}\\\\\large\textsf{6y - 20 + 20 = 130 + 20}\\\\\large\textsf{Cancel out: -20 + 20 because that gives you 0}\\\\\large\textsf{Keep: 130 + 20 because that helps solve for the y-value}\\\\\large\textsf{130 + 20 = \bf 150}\\\\\large\textsf{NEW EQUATION: 6y = 150}\\\\\large\textsf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6y}{6}= \dfrac{150}{6}}\\\\\large\textsf{Cancel: }\mathsf{\dfrac{6}{6}\large\textsf{ because that gives you 1}}[/tex]
[tex]\large\textsf{Keep: }\mathsf{\dfrac{150}{6}}\large\textsf{ because it helps solve for the y-value}\\\\\large\textsf{\bf y = }\mathsf{\dfrac{150}{6}}\\\\\large\textsf{OR }\\\\\mathsf{\dfrac{150}{6} }\large\textsf{ = \bf y}\\\\\\\large\textsf{SIMPLIFY ABOVE AND TOU YOU HAVE YOUR Y-VALUE}\uparrow\\\\\\\\\boxed{\boxed{\large\textsf{\huge\textsf{Answer: \bf y = 25} (Option B.)}}}\huge\checkmark\\\\\\\\\large\text{Good luck on your assignment and enjoy your day!}\\\\\\\\\\\frak{Amphitrite1040:)}[/tex]
Find the distance from the vertices of AABC to the corresponding vertices of the other three triangles, and enter them in the table. For AJKL-
you'll need to use the distance formula da (01 – 12) + (y1 - y2) . Verify your calculations using the tools available in GeoGebra.
Answer:
See explanation
Step-by-step explanation:
The question is incomplete, as the vertices of the triangle are not given.
A general explanation is as follows;
To calculate distance between two points, we use:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]
Take for instance;
[tex]A = (1,4)[/tex]
[tex]B = (3,-2)[/tex]
Distance AB is:
[tex]AB = \sqrt{(1 - 3)^2 + (4 - -2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (4 +2)^2}[/tex]
[tex]AB = \sqrt{(- 2)^2 + (6)^2}[/tex]
Evaluate the exponents
[tex]AB = \sqrt{4 + 36}[/tex]
[tex]AB = \sqrt{40}[/tex]
[tex]AB = 6.32[/tex]
Answer:
for edmentum
Step-by-step explanation:
Feedback:Correct answer
Question 2 of 10
10.0 Points
3
Find the interquartile range for a data set having the five-number
summary: 4.6, 14.3, 19.7, 26.1, 31.2
A. 26.6
B. 11.8
C. 11.5
D. 15.1
Dora drove 80 km in 40 minutes then 120 km in 1 hour and then the final 200km took him 1 hour 20 minutes. what is his average speed for the whole journey
9514 1404 393
Answer:
133 1/3 km/hour
Step-by-step explanation:
Average speed is computed as ...
average speed = (total distance)/(total time)
= (80 km +120 km +200 km)/(2/3 + 1 + 1 1/3 hour) = 400 km/(3 hour)
= 133 1/3 km/hour
Suppose triangle ABC is reflected over the x-axis. If the distance between point A and A’ is 14, what is the distance between the x-axis and A’.
1. 7
2. -7
3. 3.5
4. There is not enough information given.
Given:
The triangle ABC is reflected over the x-axis.
The distance between point A and A’ is 14.
To find:
The distance between the x-axis and A’.
Solution:
If a figure is reflected across the x-axis then the corresponding parts are mirror image of each other about the x-axis.
It means the distance between A and x-axis is same as the distance between x-axis and A'.
The distance between point A and A’ is 14.
Let d be the distance between the x-axis and A’. Then,
[tex]d+d=14[/tex]
[tex]2d=14[/tex]
[tex]d=\dfrac{14}{2}[/tex]
[tex]d=7[/tex]
Therefore, the correct option is 1.
Which system of equations shows a solution of (0.5, -1)?
Need answers asap plzzz
Answer:
The first graph
Step-by-step explanation:
If the cutoff Z score on the comparison distribution is 2.33 and the sample value has a score of 2.35 on the comparison distribution, the correct decision is to:____.
A) fail to reject the null hypothesis.
B) reject the null hypothesis.
C) accept the researc hypothesis.
D) reject the research hypothesis.
Answer:
B) reject the null hypothesis.
Step-by-step explanation:
If a number is added to the numerator of 5/6 and twice as much is added to the denominator the result is 3/5 find the number
Answer:
"(5+x)/(6+2x) = 3/5" is the answer
What is the absolute value of -20?
there was a number line so
——————————————
-20 -10 0 10 20
and the options were
A.) -20
B.) 0
C.) 20
D.) 40
Answer:
C) 20
Step-by-step explanation:
The absolute value of a number represents the positive distance between the number and zero. Absolute value is therefore always positive.
The distance between -20 and 0 is 20 and therefore the answer is C) 20.
Answer:
20
Step-by-step explanation:
Absolute value = | -20 |
= 20
Option C is correct .
the admission fee for a charity event is $7 for children and 10$ for adults. The event was attended by 700 people, and the total amount collected in admissions was $6,400.
Answer:
200 kids and 500 adults
Step-by-step explanation:
x+y=700
7x+10y=6,400
(200,500)
kids=200
adults=500
Construct a frequency distribution and a relative frequency histogram for the accompanying data set using five classes. Which class has the greatest relative frequency and which has the least relative frequency?Complete the table below. Use the minimum data entry as the lower limit of the first class.Class Frequency, f Relative frequencyx-x x xx-x x xx-x x xx-x x xx-x x x sumf= X?(Type integers or decimals. Round to the nearest thousandth as needed.)DATA:Triglyceride levels of 26 patients (in milligrams per deciliter of blood)138 199 240 143 294 175 240 216 223180 138 266 161 175 402 172 459 147391 152 199 294 188 320 421 161
Answer:
[tex]\begin{array}{cc}{Class}& {Frequency} & 138 - 202 & 14 & 203 - 267 & 5 & 268 - 332 & 3 & 333 - 397 & 1 & 398 - 462 & 3 \ \end{array}[/tex]
The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397
Step-by-step explanation:
Solving (a): The frequency distribution
Given that:
[tex]Lowest = 138[/tex] --- i.e. the lowest class value
[tex]Class = 5[/tex] --- Number of classes
From the given dataset is:
[tex]Highest = 459[/tex]
So, the range is:
[tex]Range = Highest - Lowest[/tex]
[tex]Range = 459 - 138[/tex]
[tex]Range = 321[/tex]
Divide by the number of class (5) to get the class width
[tex]Width = 321 \div 5[/tex]
[tex]Width = 64.2[/tex]
Approximate
[tex]Width = 64[/tex]
So, we have a class width of 64 in each class;
The frequency table is as follows:
[tex]\begin{array}{cc}{Class}& {Frequency} & 138 - 202 & 14 & 203 - 267 & 5 & 268 - 332 & 3 & 333 - 397 & 1 & 398 - 462 & 3 \ \end{array}[/tex]
Solving (b) The relative frequency histogram
First, we calculate the relative frequency by dividing the frequency of each class by the total frequency
So, we have:
[tex]\begin{array}{ccc}{Class}& {Frequency} & {Relative\ Frequency} & 138 - 202 & 14 & 0.53 & 203 - 267 & 5 & 0.19 & 268 - 332 & 3 & 0.12 & 333 - 397 & 1 & 0.04 & 398 - 462 & 3 & 0.12 \ \end{array}[/tex]
See attachment for histogram
The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397
Given the points (-7, -1) and (8, 5) find the slope.
Answer:
(-7, -1) =(x1,y1)
(8, 5)=(x2,y2)
now
[tex]slope (m) = \frac{y2 - y1}{x2 - x1} [/tex]
[tex]or = \frac{5 - ( - 1)}{8 - ( - 7)} [/tex]
[tex]or = \frac{5 + 1} {8 + 7} [/tex]
[tex]or = \frac{6}{15} [/tex]
[tex]or = \frac{2}{5} [/tex]
Step-by-step explanation:
Explanation is in the attachmenthope it is helpful to you ☺️
The table shows the relationship between the number of faculty members and the number of students at a local school. What is the missing value?
Faculty
Students
1
17
2
34
3
51
4
?
17
68
85
102
Answer:
68
Step-by-step explanation:
I did it on my test
The missing value in the table is 68. The correct answer would be option (B).
What is the linear relationship?A linear relationship is a connection that takes the shape of a straight line on a graph between two distinct variables - x and y. When displaying a linear connection using an equation, the value of y is derived from the value of x, indicating their relationship.
The table shows the relationship between the number of faculty members and the number of students at a local school.
Faculty Students
1 17
2 34
3 51
4 ?
The relationship between the number of faculty members and the number of students at the local school is that for every faculty member, there are 17 students.
Therefore, if there are 4 faculty members, we can find the number of students by multiplying 4 by 17, which gives us 68.
Thus, the missing value in the table is B. 68.
Learn about the linear relationship here :
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Simplify the following expression.
3x4 + 2x3 - 5x2 + 4x2 + 6x-2x-3x4 +7XS - 3X3
Answer:
39+4x
Step-by-step explanation:
Since two opposites add up to zero, remove them from the expression
2x3-5x+2+4x2+6x-2x+7x5
Calculate the sum or difference
39+6x-2x
A chemical company makes two brands of antifreeze the first brand contains 65% pure antifreeze and the second brand contains 80% pure antifreeze in order to obtain 60 gallons of a mixture that contains 70% pure antifreeze how many gallons of each brand of antifreeze must be used
Answer:
30 gallons of each brand
Step-by-step explanation:
1 gallon of 60% + 1 gallon of 80% = 2 gallons 70% (60/2 = 30)
Practice Question
1) VAT (value-added tax) is paid on things that you buy.
The table on the right shows the 2019 VAT rates.
This is how much VAT is charged on certain items
as a percentage of the item's cost.
VẬT (%)
20
5
0.
Items
Chocolate and crisps
Gas and electric
Fruit and vegetables
Currena
Before VAT is added, Simon pays 12p per unit of
electricity plus a fixed charge of £87 per year.
How much does Simon pay in VAT if he uses 3000 units of electricity in one year?
er hour
Shane and Space
Simon will pay £18 in VAT for using 3000 units of electricity in one year.
The VAT rate for gas and electric is 5%.
Therefore, Simon will pay VAT on his electricity usage.
Let's calculate Simon's annual electricity cost without VAT:
Cost per unit of electricity = 12p
= £0.12
Number of units used in one year = 3000
Electricity cost without VAT = Cost per unit × Number of units
= £0.12 × 3000
= £360
Now, let's calculate the VAT amount:
VAT rate = 5% = 0.05
VAT amount = Electricity cost without VAT × VAT rate
= £360 × 0.05
= £18
Therefore, Simon will pay £18 in VAT for using 3000 units of electricity in one year.
To learn more on VAT amount click:
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Please help me out here.
Answer:
19.634954085
Step-by-step explanation:
Pipe Diameter = Height of the trench
Pipe Height = Width of the trench
V = Pi*r^2*L/ Pi*r^2*h
= 22/7 x (2.5/2)^2 x 4
= 19.634954085
Please help me in this question
Answer:
3/8
Step-by-step explanation:
the total number of possible results is 4×4=16.
out of these 16 only the results
1 2
1 3
1 4
2 2
2 3
3 2
are desired results. these are 6.
so the probability of a desired result is 6/16 = 3/8
Find the slope of every line that is parallel to the line on the graph ob Enter the correct answer. 6 4 OOO DONE Clear al N ? (-8,0) 10-12 pop -6 ko 8 ४ 2 2 8 do
Step-by-step explanation:
x=-6 y= 0
x0 y= -1
y=mx+b
b= -1
0= -6m -1
-6m= 1
m= -1/6
parallel lines have the same slope
slope = -1/6