HELP ME ASAP I DONT UNDERSTAND

Answer:

Total distance = 6,540,000 km

Step-by-step explanation:

Given

Number of bicycles = 9,000,000

Average Distance = 6.5 km (to 1 d.p)

Required

Calculate the upper bound of all bicycle distance

First, we need to determine the range of the distance traveled by each bicycle;

Since, the average distance is approximated, then the Range is:

[tex]Range = (6.45km\ to\ 6.54km)[/tex]

All number in this range approximate to 6.5km

Note that the upper bound of the range is 6.54km;

Hence, total distance is calculated as thus;

[tex]Total\ distance = Number\ of\ bicycle * upper\ bound[/tex]

[tex]Total\ distance = 1,000,000 * 6.54km[/tex]

[tex]Total distance = 6,540,000km[/tex]

Answer:

EF = 2 units

Step-by-step explanation:

Given:

Line segment DF and point E on it.

DF = 11 unit

DE = 9 Unit

Find:

EF

Computation:

We know that,

DF = DE + EF

11 = 9 + EF

EF = 11-9

EF = 2 units

Answer:

2/3

Step-by-step explanation:

dy/dx equals derivative of y by x

dy/dx=20t/30t=2/3

Answer:

0.35, 0.359, 1

Step-by-step explanation:

0.359 = 359 thousandths

0.35 = 0.350 = 350 thousandths

1 = 1.000 = 1000 thousandths

Since 350 < 359 < 1000, then from least to greatest you get

0.35, 0.359, 1

Step-by-step explanation:

Hi, there!!!

Here, the question is about the volume of cone,

given that,

diameter = 12m

radius of a circle= 12m/2= 6m

height (h)=9 m

now, we have,

volume of a cone= 1/3×pi× r^2×h

or, v= 1/3×3.14×(6)^2×9

After simplifying it we get,

v= 339.12 m^3

Hope it helps....

Answer:

Step-by-step explanation:

Given that :

the  perpendicular distance of the point from x axis = 2 units

the perpendicular distance from y axis is 3 units

The objective is to the write the coordinates of the points if it lies in

(i) | Quadrant  (ii) || Quadrant (iii) ||| Quadrant (iv) |v Quadrant

The position of a point in a plane is conveniently specified by the distances fro two perpendicular lines.The lines are called the x-axis and y-axis and their [point of intersection is called the origin.

The perpendicular distance from the y-axis is called the x- coordinate or abscissa and the perpendicular distance from x-axis is called the y-coordinate or ordinate,The  coordinate form an ordered pair with the abscissa written as first.

With that be said, So In the given question,

the  perpendicular distance of the point from x axis = 2 units

y coordinate = ±2

the perpendicular distance from y axis is 3 units

x coordinate = ±3

The ordered pair of the coordinates = ( ±3, ±2)

Therefore;

in | quadrant ; we have (3,2)   where  x and y are both on the positive axis

in || quadrant ; we have (-3,2)   x is on the negative axis and y is on the positive axis

In ||| quadrant ; we have (-3. -2) both x and y are on the negative axis

In |v quadrant ; we have ( 3, -2)  x is on the positive axis and y is on the negative axis.

Answer:

D

Step-by-step explanation:

-1/2x > 6 (you have to flip the sign when you multiply or divide by negative

x < -12

Answer:

False

Step-by-step explanation:

Because the question says you pick a different shirt on Tuesday than on Monday, that means you have one less shirt you can select, so the event is dependent.

Answer:

grade point average​ (GPA) as a weighted mean = 3.14

Yes, student makes the Dean's list.

Step-by-step explanation:

Since the data is not given I will explain the question with a relevant example:

For example

Data:

Students grades are:  A, C, B, A, D

The corresponding number of credit hours: 3, 3, 3, 4, 1

The grading system assigns quality points to letter grades as​:

A = 4

B = 3

C = 2

D = 1

F = 0

To find:

grade point average​ (GPA) as a weighted mean

If the​ Dean's list requires a GPA of 3.00 or​ greater, did this student make the​ Dean's list?

Solution:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

Here

Using the earned grades of A, C, B, A, D and corresponding quality points to these letter grades we get:

A = 4

C = 2

B = 3

A = 4

D = 1

So the values in x[tex]_{i}[/tex] are:

x

4

2

3

4

1

Now the number of credit hours are represented as weights w[tex]_{i}[/tex] :

w

3

3

3

4

1

In order to calculate weighted mean first multiply x[tex]_{i}[/tex] with w[tex]_{i}[/tex]

x[tex]_{i}[/tex] w[tex]_{i}[/tex]

4 * 3 = 12

2 * 3 = 6

3 * 3 = 9

4 * 4 = 16

1 * 1 = 1

The sum of x[tex]_{i}[/tex] w[tex]_{i}[/tex] is :

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 12 + 6 + 9 + 16 + 1 = 44

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex]  =  44

Now compute the sum of w[tex]_{i}[/tex]

Σw[tex]_{i}[/tex] = 3 + 3 + 3 + 4 + 1 = 14

Σw[tex]_{i}[/tex] = 14

Putting the values in the weighted mean formula:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

                           =  44 / 14

                           = 3.1429

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex] = 3.14

Since the​ Dean's list requires a GPA of 3.00 or​ greater and the grade point average​ (GPA) as a weighted mean of the student is 3.14 so the student makes the​ Dean's list because his/her GPA is higher than 3.00

Answer:

6000

Step-by-step explanation:

Divide top and bottom by the common factor.  

[tex]\dfrac{3 }{4} \times 8000 = 3 \times 2000[/tex]

Simplify

3 × 2000 = 6000

Answer:

16%

Step-by-step explanation:

rental charge per year = $80

rental charge at the rate $8 per year = 8 * 12 = 96

the increased amount = 96 - 80 = 16

% = 16 / 100 = 16%

Answer:

[tex]\huge \boxed{14}[/tex]

Step-by-step explanation:

Q is a point on the line segment PR.

PQ = 3

QR = 11

PR = PQ + QR

PR = 3 + 11 = 14

Answer:

[tex]\huge\boxed{PR = 14}[/tex]

Step-by-step explanation:

QR = 11

PQ = 3

Given that Q is on line segmant PR

So,

PR = PQ + QR

PR = 3 + 11

PR = 14

Answer:

  PQRS is a parallelogram with right-angle corners

Step-by-step explanation:

We know that the midsegment of a triangle is parallel to the base.

  QR is the midsegment of triangle BCD, so is parallel to BD.

  SP is the midsegment of triangle DAB, so is parallel to BD.

QR and SP are both parallel to BD, so are parallel to each other.

  RS is the midsegment of triangle CAD, so is parallel to AC.

  PQ is the midsegment of triangle ABC, so is parallel to AC.

RS and PQ are both parallel to AC, so are parallel to each other.

__

We have shown that opposite sides of PQRS are parallel to each other, so the figure is at least a parallelogram.

__

By virtue of the congruence of corresponding angles where a transversal crosses parallel lines, each of the so-far named lines can be shown to be perpendicular to any of the lines it meets.* Hence the figure PQRS must be a parallelogram with right angles, a rectangle.

_____

* Transversal BD crosses PQ, AC, and RS at right angles. Hence, transversals RS and PQ cross QR, BD, and SP at right angles. That is, the angles at corners P, Q, R, and S of the parallelogram are right angles.

==================================================

Work Shown

We'll be using these vector properties

To get the following

-2u + v = -2*(-1, 5) + (2,7)

-2u + v = (-2*(-1), -2*5) + (2,7) .... apply rule 2

-2u + v = (2, -10) + (2, 7)

-2u + v = (2+2, -10+7) .... use rule 1

-2u + v = (4, -3)

Answer:

x = 3

Step-by-step explanation:

Given

5 - (4 - 3x) = 10 ← distribute the terms in the parenthesis by - 1

5 - 4 + 3x = 10, that is

1 + 3x = 10 ( subtract 1 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Step 1:

62cm - (25*2)=12cm

62-25=37cm

Length for both sides 25

Width=37cm=x

Answer: plot a point at (-8, -5)

The y coordinate flips from positive to negative, or vice versa, when we reflect over the horizontal x axis. The x coordinate stays the same.

The rule can be written as [tex](x,y) \to (x,-y)[/tex]

Answer: [tex]y-1=\dfrac32(x+3)[/tex]

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = [tex]\dfrac{d-b}{c-a}[/tex]

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =[tex]\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}[/tex]

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

[tex](y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)[/tex]

Required equation: [tex]y-1=\dfrac32(x+3)[/tex]

Answer:

Area= 452.23 ft²

Step-by-step explanation:

Angle at U = 180-48-20

Angle at U = 112°

UT/sin 112=46/sin 48

UT= 0.9272*46/0.7431

UT=57.4 ft

UV= sin 20*46/sin48

UV= 0.3420*46/0.7431

UV= 21.2 ft

S=( 21.2+57.4+46)/2

S=124.6/2

S= 62.3

Area= √((62.3)(62.3-21.2)(62.3-57.4)(62.3-46))

Area= √((62.3)(41.1)(4.9)(16.3))

Area= √204509.5311

Area= 452.23 ft²

Answer:

Step-by-step explanation:

for the first equation x= -2 and y=-7

the second equation x=3 and y is 3 now just plot x and y from the same equation on the same line

Answer:

[tex]\huge\boxed{x = -4; y = 7}[/tex]

Step-by-step explanation:

By plotting the points, we see that both of the lines intersect at (-4, 7)

Which means (X,y) = (-4,7)

So,

x = -4

y = 7

See the attached file so that you can know how would it be graphed.

Answer:

49 square meters represent area of the square garden

Step-by-step explanation:

Each side length=7 meters

He multiplied 7 × 7 times to find the amount of space

=49 square meters

Jack is trying to measure the area of his square garden

Area of the square garden = length^2

=Length × length

Recall,

Length=7 meters

Area of the square garden= 7 meters × 7 meters

=49 square meters

Answer:

Step-by-step explanation:

Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.

On expanding the left hand side of the expression we have;

= (8x² −15x)−(x² −27x)

Open the paranthesis

= 8x² −15x−x²+27x

collect the like terms

= 8x²−x²+27x −15x

=  7x²+12x

Comparing the resulting expression with ax²+bx

7x²+12x =  ax²+bx

7x² = ax²

a = 7

Also;

12x = bx

b =12

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a is equivalent to 5

The value of b minus a is 5

Since the expression is

[tex](8x^2 -15x)-(x^2 -27x) = ax^2 +bx[/tex]

Here we have to expand the left-hand side of the expression so it should be like

[tex]= (8x^2 -15x)-(x^2 -27x)\\\\= 8x^2 -15x-x^2+27x\\\\= 8x^2-x^2+27x -15x\\\\= 7x^2+12x[/tex]

Now

[tex]7x^2+12x = ax^2+bx\\\\7x^2 = ax^2[/tex]

a = 7

Also;

12x = bx

b =12

So,

The value of b - a = 12 - 7

b -a = 5

Hence the value of b-a should be 5

Learn more about equation here: https://brainly.com/question/24540444

Answer:

1. tan A = 1/(tan B)

Step-by-step explanation:

By definition,

tangent A = opposite / adjacent = a / b

and

tangent B = opposite / adjacent = b / a

Therefore tangent A = a/b = 1/tan(B)

Answer: Tan a=tan b

I belive

Step-by-step explanation:

Answer:

15 flamingos and 12 alligators

Step-by-step explanation:

Because there are 27 heads, that means there is a total of 27 flamingos and alligators. Flamingos have 2 feet and alligators have 4 feet.

1. Set up a system of equations

(x = number of flamingos, y = number of alligators)

1x + 1y = 27 heads

2x + 4y = 78 feet

2. Multiply to get the same coefficient

2(1x + 1y = 27) → 2x + 2y = 54

3. Subtract

 2x + 2y = 54

- 2x + 4y = 78

 0x + -2y = -24

4. Solve for y

-2y = -24

y = 12

5. Plug in y to solve for x

1x + 1(12) = 27

x + 12 = 27

x = 15

Answer:

3 24/25 MPH

Step-by-step explanation:

We know Rami runs 6 3/5 miles in 1 2/3 hrs --> Convert into an improper fraction

--> 6 3/5 = 33/5

--> 1 2/3 = 5/3

Speed = Distance divided by Time

Distance = 33/5

Time = 5/3

33/5 / 5/3 = 33/5 x 3/5

33/5 x 3/5 = 99/25

1/25 less than 4 = 3 24/25

Thus, our answer is 3 24/25 MPH

Hope this helps!

Answer:

[tex]\frac{64}{27}[/tex] cm³

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = lbh ( l is length, b is breadth and h is height ), thus

V = [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] = [tex]\frac{4^3}{3^3}[/tex] = [tex]\frac{64}{27}[/tex] cm³

Answer:

Step-by-step explanation:

I am more than happy to answer anymore questions. If needed an explanation I can put one in the comments.

Answer:

3

= 15/5

= [tex]\sqrt[3]{27}[/tex]

= 1.5*2

= 3/1

= 3*1

= 3¹

= 1/3⁻¹

= 3⁴ / 3³

= 3⁵ * 3⁻⁴

Answer:

C.) 7.14 in²

Step-by-step explanation:

The figure is made up of a square and a circle. The circle is divided in half and each piece is set on one side of the square. This means that the diameter of the circle is equal to the length of the sides of the square, 2 inches.

The area of the square can be found by multiplying length times the width:

[tex]2*2=4[/tex]

The area of the square is 4 inches, and since we multiplied two lengths, we square the value:

A=4in²

Now find the area of the circle using the formula:

[tex]A=\pi r^2[/tex]

The radius is half of the diameter, so the radius is 1. Insert values and solve:

[tex]A=\pi *1^2\\\\A=\pi *1\\\\A=\pi[/tex]

The area of the circle is equal to π. Add the values together:

[tex]4+\pi =7.14[/tex]

The area of the figure is 7.14 in²

:Done

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Answer:.

Step-by-step explanation:.

Answer:

The value of the derivative at x = 9 is -25

Step-by-step explanation:

Here in this question, we are told to find the derivative of the given equation at the point where x = 9

What we need to do here is simply, differentiate f(x), then substitute that value x = 9 into the differentiated equation

In notation form, what we are to find is f’(9)

So;

f(x) = -2x^2 + 11x

f’(x) = -4x + 11

So therefore;

f’(9) = -4(9) + 11

f’(9) = -36 + 11

f’(9) = 11-36

f’(9) = -25