Help me or ill fail plz

Help Me Or Ill Fail Plz

Answers

Answer 1

Answer:

1,108 in²

Step-by-step explanation:

SA = (12×20) + (2×20×5 + 2×12×5) + (2×½×12×9)

+ (2×20×11)

= 240+320+108+440

= 1,108 in²


Related Questions

There are 200 blue balls and 10 red balls in an urn. Suppose that 10 balls are taken random;ly from the urn and let X denote the number of red balls selected.
a) The distribution of the random variable X is___.
i) Binomial.
ii) Hypergeometric.
iii) Poisson.
iv) Normal.
v) Exponential.
vi) Uniform
b) Find P(all 10 balls are red).
c) Which distribution from those listed in part (a) can be used as an approximation to the distribution of X? With this approximation find P(X = 10).

Answers

Answer:

Hypergeometric

Kindly check explanation

Step-by-step explanation:

For a hypergeometric distribution, the following conditions must be met :

1.) The total number of samples must be fixed.

2.) Sample size will be a portion of the population

3.) The probability of success changes per trial. This is because sampling is done without replacement

The above scenario meets the condition described:

Total number of samples = 210

Sample size, n = 10

Blue balls = 200 ; red balls = 10

P(10 red balls)

Using the hypergeometric distribution function and the calculator :

X ~ H(n, N, M)

X ~ (10, 200, 210) = 0.6072

Question 1 of 10
One advantage of a long-term loan compared to a short-term loan is that a
long-term loan:
A. does not require the borrower to have a good credit score.
O
B. can be paid off in full without the borrower paying any interest.
C. does not force the borrower to make payments every month.
D. allows a person to borrow more money at a lower interest rate.

Answers

Answer:

D. allows a person to borrow more money at a lower interest rate

Math algebra two plz show your work

Answers

Answer:

The answer is [tex]b=3, a=-2[/tex], and [tex]c=3[/tex].

Step-by-step explanation:

To solve this system of equations, start by solving for (a) in the third equation.

To solve for (a) in the third equation, add [tex]3b[/tex] to both sides of the equation, which will look like [tex]2a=-13+3b\\-a+b-c=2\\2a+3b-4c=-7[/tex]. Next, divide each term in [tex]2a=-13+3b[/tex] by 2 and simplify, which will look like [tex]\frac{2a}{2}=\frac{-13}{2} +\frac{3b}{2} \\-a+b-c=2\\2a+3b-4c=-7[/tex]   =  [tex]a=\frac{-13}{2} +\frac{3b}{2} \\-a+b-c=2\\2a+3b-4c=-7[/tex].

Then, replace all variables of (a) with [tex]-\frac{13}{2} +\frac{3b}{2}[/tex] in each equation and simplify, which will look like [tex]-13+6b-4c=-7\\-\frac{2c-13+b}{2}=2\\a=-\frac{13}{2}+\frac{3b}{2}[/tex].

The next step is to reorder [tex]-\frac{13}{2}[/tex] and [tex]\frac{3b}{2}[/tex], which will look like [tex]\frac{3b}{2}-\frac{13}{2}\\-13+6b-4c=-7\\-\frac{2c-13+b}{2} =2[/tex].

Then, solve for (b) in the second equation. To solve for (b) in the second equation start by moving all terms not containing (b) to the right side of the equation, which will look like [tex]6b=6+4c\\a=\frac{3b}{2}-\frac{13}{2} \\-\frac{2c-13+b}{2} =2[/tex]. Next, divide each term in                ([tex]6b=6+4c[/tex]) and simplify, which will look like [tex]b=1+\frac{2c}{3} \\a=\frac{3b}{2} -\frac{13}{2\\}\\-\frac{2c-13+b}{2} =2[/tex].

Then, replace all variables of (b) with [tex]1+\frac{2c}{3}[/tex] in each equation and simplify, which will look like [tex]-\frac{2(2c-9)}{3}=2\\a=c-5\\b=1+\frac{2c}{3}[/tex].

The next step is to solve for (c) in the first equation. To solve for (c) in the first equation start by multiplying both sides of the equation by [tex]-\frac{3}{2}[/tex] and simplify, which will look like [tex]2c-9=-3\\a=c-5\\b=1+\frac{2c}{3}[/tex]. Then, move all terms not containing (c) to the right side of the equation, which will look like [tex]2c=6\\a=c-5\\b=1+\frac{2c}{3}[/tex]. Next, divide each term in [tex]2c=6[/tex] by 2 and simplify, which will look like [tex]c=3\\a=c-5\\b=1+\frac{2c}{3}[/tex].

Then, replace all variables of (c) with 3 in each equation and simplify, which will look like [tex]b=3\\a=-2\\c=3[/tex]. Finally, the list of all the solutions are [tex]b=3,a=-2[/tex], and [tex]c=3[/tex].

Candice is preparing for her final exam in Statistics. She knows she needs an 74 out of 100 to earn an A overall in the course. Her instructor provided the following information to the students. On the final, 200 students have taken it with a mean score of 68 and a standard deviation of 4. Assume the distribution of scores is bell-shaped. Calculate to see if a score of 74 is within one standard deviation of the mean.
a) Yes, 74 is the upper limit of one standard deviation from the mean.
b) Yes, the upper level of one standard deviation is 72.
c) Yes, 74 is greater than the 64, one standard deviation below the mean.
d) No, 74 is greater than the mean of 68.

Answers

Answer:

Hence the correct option is option b) Yes, the upper level of one standard deviation is 72.

A score of 74 is not within one standard deviation of the mean.

Step-by-step explanation:

Here the given details are,

Mean = 68  

SD = 4  

Distribution is normal.  

Z-score for x = 74 is given as below:  

[tex]Z = (X - mean)/SD\\Z = (74 - 68)/4\\Z = 1.5[/tex]  

So, the score of 74 is 1.5 standard deviations from the mean.  

[tex]Mean + 1\timesSD = 68 + 1\times4 = 72Mean - 1\timesSD = 68 - 1\times4 = 64[/tex]  

Therefore the score is not lies between 64 and 72.  

Yes, the upper level of one standard deviation is 72.  

Help please. I'm stuck

Answers

Answer:

The numbers are 65, 67, and 69

Step-by-step explanation:

Hi there!

We need to find 3 consecutive odd integers.

Consecutive numbers are numbers that follow each other (ex. 1, 2, 3, 4)

We're given that 5 times the first number + 4 times the second + 3 times the third = 800

Let's make the first number x

Since the second number is consecutive to the first and odd, it will be x+2 (Why? Well, let's say x is 5. In that case, x+1=6, which is even. However, x+2=7)

Therefore, the third number is x+4 (once again, if x is 5, x+3=8, but x+4=9)

5 times the first number is 5x

4 times the second is 4(x+2)

3 times the third is 3(x+4)

And of course, that equals 800

As an equation, it'll be:

5x+4(x+2)+3(x+4)=800

open the parenthesis

5x+4x+8+3x+12=800

combine like terms

12x+20=800

Subtract 20 from both sides

12x=780

Divide by 12 on both sides

x=65

The first number is x, so the first number is 65

The second number is x+2, or 65+2=67

The third number is x+4, or 65+4=69

Hope this helps!

Find the solution set.

The solution set for 5v2 – 125 = 0

Answers

V=25/2
You multiply the number first (5•2=10)
10v-125=0
Then add 125 to both sides
10v-125+125=0+125
Simply it then divide
10v=125, 10v/10= 125/10
Lastly simply it
V=25/2
Answer will be V=25/2

Given the data points below, compute the sum of squared errors for the regression equation
Y
=
2
+
3
X
.


X

0

3

7

10

Y

5

5

27

31

Answers

Answer:

The sum of squared errors for the regression equation is 62.

Step-by-step explanation:

The sum of squared errors can be computed as follows:

X            Y           Y* = 2 + 3X         Y - Y*           (Y - Y*)^2

0            5                  2                      3                    9

3            5                  11                     -6                  36

7            27               23                     4                    16

10          31                32                    -1                     1  

20         68               68                     0                   62

From the above, we have:

Error = Y -  Y*

Error^2 = (Y - Y*)^2

Sum of squared errors = Sum of Error^2 = Total of (Y - Y*)^2 = 62

Therefore, the sum of squared errors for the regression equation is 62.

Order the following decimals. State your method of choice and your reasons for choosing it. Explain how you know this order is accurate.

Answers

Answer:

.40 is the greatest .350 is the second greatest and last but not least .3456 is the lowest

Step-by-step explanation:

Compute ????×????, where ????=????−2????+5????, ????=2????+????+3????. (Write your solution using the standard basis vectors ????, ????, and ????. Use symbolic notation and fractions where needed.)

Answers

Given: ????=????−2????+5????

and ????=2????+????+3????

To find: We need to find the value of ????×????

Solution: Here given,

????=????−2????+5????

and ????=2????+????+3????

Therefore, solving these two we have, ????=0

So,????×????=0

what graph shows the solution to the equation below log3(x+2)=1

Answers

Answer:

The solution to the equation  log3(x+2)=1 is given by x=1

Step-by-step explanation:

We are given that

[tex]log_3(x+2)=1[/tex]

We have to find the graph which shows the  solution to the equation log3(x+2)=1.

[tex]log_3(x+2)=1[/tex]

[tex]x+2=3^1[/tex]

Using the formula

[tex]lnx=y\implies x=e^y[/tex]

[tex]x+2=3[/tex]

[tex]x=3-2[/tex]

[tex]x=1[/tex]

When f(x) = 4 , what is the value of ?
A. 0
B. 2
C. 3
D. 4

Answers

The answer is 4 hope this helps

Yuki bought a drop–leaf kitchen table. The rectangular part of the table is a 2–by–3–foot rectangle with a semicircle at each end, as shown.

Answers

Answer:

[tex](a)\ Area = 13.0695[/tex]

[tex](b)\ Area = 26.139[/tex]

Step-by-step explanation:

Given

The attached image

Solving (a): The area (one side up)

This is calculated as:

Area= Area of semicircle + Area of rectangle

So, we have:

[tex]Area = \pi r^2 + l *w[/tex]

Where:

[tex]l,w =2,3[/tex] --- the rectangle dimension

[tex]d = 3[/tex] --- the diameter of the semicircle

So, we have:

[tex]Area = \pi * (3/2)^2 + 2 * 3[/tex]

[tex]Area = \pi * 2.25 + 6[/tex]

[tex]Area = 2.25\pi + 6[/tex]

[tex]Area = 2.25*3.142 + 6[/tex]

[tex]Area = 13.0695[/tex]

Solving (b): Area when both leaves are up.

Simply multiply the area in (a) by 2

[tex]Area = 2 * 13.0695[/tex]

[tex]Area = 26.139[/tex]

I can’t remember how to solve this?

Answers

Answer:

Step-by-step explanation:

[tex]\frac{(5.27+x)}{2} =-4.51[/tex],[tex]\frac{8.21+y}{2} = 1.37[/tex]

(3.75,-5.47)

We have the number of emergency room admissions to SWTRHA hospital on 6 different Friday the 13ths along with the number of admissions to the same hospital on the previous Friday the 6th. Is there any difference between admissions on the 6th and the 13th. Conduct a depedent samples t-test to find out. What is the value of your t Stat

Answers

Answer:

Test statistic = - 2.71

Step-by-step explanation:

Table of the sample data is attached below :

Using a dependent sample t test :

H0 : μd = 0

H0 : μd ≠ 0

The difference in the 6th and 13th date data is :

Difference, d = -4, -6, -3, -1, 1, -7

The sample size, n = 6

The mean of d ; μd = Σd/ n = - 3.667

Standard deviation of difference, Sd = 3.011

The test statistic : μd/(Sd/√n)

Test statistic = - 3.33 / (3.011/√6)

Test statistic = - 3.33 / 1.2292356

Test statistic = - 2.709

Test statistic = - 2.71

Which of the following are rational numbers?

Answers

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

{7, -5, (2/3), 5.79}

»»————- ★ ————-««  

Here’s why:  

Rational numbers are numbers that could be written as a fraction with two integers.

⸻⸻⸻⸻

[tex]\boxed{\text{\underline{\textbf{Some Examples of Rational Numbers Are...}}}}\\\\\rightarrow \text{Integers}\\\\\rightarrow \text{Perfect Squares}\\\\\rightarrow \text{Terminating Decimals}\\\\\rightarrow \text{Recurring Decimals}[/tex]

⸻⸻⸻⸻

7 and -5 are integers, so they are rational. [tex]\frac{2}{3}[/tex] is already a fraction with integers. It is rational.5.79 is a terminating decimal. It is rational.The number π is a famous irrational number. It does not terminate nor repeat. [tex]\sqrt{13}[/tex] is not a perfect square. It is irrational.[tex]\sqrt{-4}[/tex] is a perfect square, but it is simplified to a complex number. Complex numbers are not rational.

⸻⸻⸻⸻

The rational numbers are {7, -5, (2/3), 5.79}.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

hello guys i need help

Answers

Step-by-step explanation:

90*8.25=742 rounds to 675 because its the closest. 85-95=10 divided by 2=5+85=90. 9-7.5=1.5 divided by 2=0.75+7.5=8.25. thats how i got those numbers. THE ANSWER IS C

B. 600 hours is the answer just took the test

If the rectangle were translated three units down, then reflected across the y-axis, what would be the coordinates of point D ?

Answers

Answer

all y values change sign that is reflection over x axis SKETCH IT !!!!

More

Simplify this math problem plz show your work

Answers

9514 1404 393

Answer:

  (8a -a²)/(a +2)

Step-by-step explanation:

Cancel common factors from numerator and denominator.

  [tex]\dfrac{-56+15a-a^2}{a^2+2a}\div\dfrac{a-7}{a^2}=-\dfrac{(a-7)(a-8)(a^2)}{a(a+2)(a-7)}\\\\=-\dfrac{a(a-8)}{a+2}=\boxed{\dfrac{8a-a^2}{a+2}}[/tex]

√(9+ √32)

Please simplify

Answers

Answer:

3.82

Step-by-step explanation:

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Do not confirm the answer unless your equation looks like that?

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Start by the [tex]\sqrt{32}[/tex]

[tex]\sqrt{(9+5.65) }[/tex] Now add (9 + 5.65)

[tex]\sqrt{14.65}[/tex]         Finally Simplify

[tex]3.82[/tex]              Final answer



√9


√32


3


5.6569
≈ 0.5303

What is the probability a person admitted to the hospital is paid a malpractice claim (to decimals)

Answers

Full question:

Astudy of 31,000 hospital admissions in New York State found that 4% of the admissions

led to treatment-caused injuries. One-seventh of these treatment-caused injuries resulted in

death, and one-fourth were caused by negligence. Malpractice claims were filed in one out

of 7.5 cases involving negligence, and payments were made in one out of every two claims

What is the probability a person admitted to the hospital is paid a malpractice claim (to decimals)

Answer:

Explanation:

Since 4% of admissions lead to treatment-caused injuries, we have 4/100×31000= 1240 treatment caused injuries for every 31000 people admitted

1/7 resulted in death = 1/7×1240= 177 people die for every 1240 treatment caused injuries

1/4 from negligence= 1/4×1240= 310 people get treatment caused injuries from negligence for every 1240 people

Malpractice claims in one of out of 7.5 cases of negligence= 13.3% of negligence cases= 0.1333×310= 41 claims for every 1240 people with treatment caused injuries

Payments were made in one out of every two claims, therefore payments for claims =50% of 41 cases of negligence= 21 payments(approximately) for every 1240 people with treatment caused injuries

Probability= number of favorable outcomes /total number of outcomes

Probability that a person admitted into the hospital will be paid a claim= 21/31000= 0.000677

1. 650 - 700 - 800 = ?
2. 25 - 45 + 23 =?​

Answers

1. −8502. 3

carry on learning

Answer:

- 850

3

Step-by-step explanation:

650 - 700 - 800

650 - 1500

- 850

25 - 45 + 23

- 20 + 23

3

Change 9/3 to percentage

Answers

Answer:

300%

Step-by-step explanation:

because 9/3×100=900/3=300 so it is 300%

Answer:

300%

Step-by-step explanation:

9/3 * 100%

900%/3 = 300%

This one is tricky! Imagine that you meet a new friend who is also a beginner, and she can run the 5k in 23.5 minutes. You wonder what percentage of the beginner running population could run the 5k faster than your new friend (that is, what percentage of the population has a time that is less than your new friend

Answers

Answer:

38.74%

Step-by-step explanation:

Given the data:

21 21 22 22 23 23 23 24 24 24 24 24 25 25 25 26 26 27 27

We obtain the beginner running population and standard deviation

Population mean, μ = Σx/n = 456/19 = 24

Standard deviation, σ = 1.747 (using calculator)

Friend's Runtime, x = 23.5 minutes

Obtaining the friend's Zscore :

Z = (x - μ) / σ

Z = (23.5 - 24) / 1.747

Z = - 0.286

Obtaining the Pvalue :

Using a standard normal distribution table :

P(Z < - 0.286) = 0.38744

Hence. Percentage of population that has lesser time :

0.38744 * 100% = 38.74%

Solve by using matrices. 2x – y +2 + w = -3 x + 2y – 3z + w = 12 3x - y - + 2w = 3 -2x + 3y + 2 – 3w = -3​

Answers

Some symbols and numbers are missing. I assume the system is supposed to read

2x - y + 2z + w = -3

x + 2y - 3z + w = 12

3x - y - z + 2w = 3

-2x + 3y + 2z - 3w = -3

In matrix form, this is

[tex]\begin{bmatrix}2&-1&2&1\\1&2&-3&1\\3&-1&-1&2\\-2&3&2&-3\end{bmatrix}\begin{bmatrix}x\\y\\z\\w\end{bmatrix}=\begin{bmatrix}-3\\12\\3\-3\end{bmatrix}[/tex]

which we can strip down to the augmented matrix,

[tex]\left[\begin{array}{cccc|c}2&-1&2&1&-3\\1&2&-3&1&12\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]

Now for the row operations:

• swap rows 1 and 2

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\2&-1&2&1&-3\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]

• add -2 (row 1) to row 2, -3 (row 1) to row 3, and 2 (row 1) to row 4

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&-7&8&-1&-33\\0&7&-4&-1&21\end{array}\right][/tex]

• add 7 (row 2) to -5 (row 3), and row 3 to row 4

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&16&-2&-24\\0&0&4&-2&-12\end{array}\right][/tex]

• multiply through rows 3 and 4 by 1/2

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&8&-1&-12\\0&0&2&-1&-6\end{array}\right][/tex]

• add -4 (row 4) to row 3

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&0&3&12\\0&0&2&-1&-6\end{array}\right][/tex]

• swap rows 3 and 4

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&3&12\end{array}\right][/tex]

• multiply through row 4 by 1/3

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&1&4\end{array}\right][/tex]

• add row 4 to row 3

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&0&-2\\0&0&0&1&4\end{array}\right][/tex]

• multiply through row 3 by 1/2

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]

• add -8 (row 3) and row 4 to row 2

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&0&0&-15\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]

• multiply through row 2 by -1/5

[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]

• add -2 (row 2) and 3 (row 3) and -1 (row 4) to row 1

[tex]\left[\begin{array}{cccc|c}1&0&0&0&-1\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]

Then the solution to the system is (x, y, z, w) = (-1, 3, -1, 4).


Find the mean or average of these savings accounts $215, $156,$318, $75, and $25​

Answers

Answer:

157.8

Step-by-step explanation:

Add them all up to get 789 and divide them by 5 as there are five numbers to get the answer:)

Find the maximum and the minimum value of the following objective​ function, and the value of x and y at which they occur. The function F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___

Answers

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7):  E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!

Answers

Answer:

9

[tex]3^{\frac{4}{2} }[/tex] = [tex]3^{2} =9[/tex]

Step-by-step explanation:

NO LINKS OR ANSWERING WHAT YOU DON'T KNOW?

1. Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5?

a. 15
b. 5
c. 25
d. 1

2. Suppose y varies inversely with x, and y = a when x = a^2. What inverse variation equation related x and y?

a. y = a^2/x
b. y = a^3/x
c. y= a^3x
d. y = ax

3. Suppose y varies inversely with x, and y = 3 when x = 1/3. What is the inverse variation equation that relates x and y?

a. y = 1/x
b. y =x
c. y = 3x
d. y = 3/x

Answers

Answer:

1. D. 1

2. B. y=a³/x

3. A. y=1/x

Step-by-step explanation:

too long to give te explanations but they're there in the attachments

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a standard deviation of 118. Determine the 26th percentile for the number of chocolate chips in a bag. ​(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags. ​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Answers

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that [tex]\mu = 1262, \sigma = 118[/tex]

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.643 = \frac{X - 1262}{118}[/tex]

[tex]X - 1262 = -0.643*118[/tex]

[tex]X = 1186[/tex]

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.96 = \frac{X - 1262}{118}[/tex]

[tex]X - 1262 = -1.96*118[/tex]

[tex]X = 1031[/tex]

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.96 = \frac{X - 1262}{118}[/tex]

[tex]X - 1262 = 1.96*118[/tex]

[tex]X = 1493[/tex]

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.675 = \frac{X - 1262}{118}[/tex]

[tex]X - 1262 = -0.675*118[/tex]

[tex]X = 1182[/tex]

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.675 = \frac{X - 1262}{118}[/tex]

[tex]X - 1262 = 0.675*118[/tex]

[tex]X = 1342[/tex]

IQR:

1342 - 1182 = 160

Find the volume (in cubic inches) of an exercise ball with a radius of 14 inches. (Round your answer to one decimal place.)

Answers

Answer:

11,494.0³

Step-by-step explanation:

Volume of a sphere= (4/3) × pi × radius³

4÷3 × 3.14 ×14³

= 11,494.0³

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