HELP ME PLZ !!! IT'S ALGEBRA

Answer:

x = - 8/23

y = 40/23

Step-by-step explanation:

-5x- y = 0

and

-8x+3y = 8

The first step to solve this would be to get what one of the two variables equal. The easiest in this case is y from the first equation.

-5x-y = 0

-y = 5x

y = - 5x

Now you can take this y value and plug it into the section equation.

-8x + 3(-5x) = 8

-8x - 15x = 8

-23x = 8

x = - (8/23)

Once you get the x value you can plug it back into equation one to get y's value

-5*-(8/23)  - y = 0

40/23 - y = 0

y = 40/23

Using two numbers 40 and 32 what is the ratio

look yall i got 10 math questions if you get all ten right brainlliest so if yall could help a man out here it would be great
here they are

1.)Which of the following best describes the squaring property of equality?
A.
if a=b,then [tex]a^{2} =b^{2}[/tex]
B
if [tex]a\leq b then a^{2} \leq b^{2}[/tex]
C
[tex]if a\geq b then a^{2} \geq b^{2}[/tex]
D
[tex]if a \neq b then a^{2} \neq b^{2}[/tex]

2.)Solve for x.
[tex]\sqrt{x-2} =9[/tex]
A.
11
B.
20
C.
83
D
no solution

3.)The length of a side of a square is [tex]\sqrt{x^{2}-4 }[/tex] If the area of the square is 12, find x.
A.
16
B.
4
C.
12
D.
[tex]\sqrt{148}[/tex]

4).Solve for x.
[tex]5x^{2} +3=-122[/tex]

A.
no solution
B.
–5
C.
±5
D.
±25

5.)solve for x[tex]x^{2} +5=30[/tex]

A.
±25
B.
[tex]\sqrt{35}[/tex]
C.
±5
D.
no real solutions
6.)The acceleration of an object can be described by the equation[tex]a=\frac{2d}{t²} where a is acceleration, d is the distance, and t is time. Suppose an object accelerates for a distance of 15 meters. Which of the following equations relates the time to the acceleration?
A.
[tex]t=\sqrt{\frac{a}{30} }[/tex]
B.
[tex]t=\sqrt{\frac{a}{15} }[/tex]
C.
[tex]t=\sqrt{\frac{30}{a} }[/tex]
D.
[tex]t=2\sqrt{\frac{30}{a} }[/tex]

7.)The acceleration of an object can be described by the equation [tex]a=\sqrt{\frac{2d}{t²} }[/tex] , where a is acceleration, d is the distance, and t is time. Suppose an object accelerates at a rate of 5 meters per second squared. Which of the following equations relates the time of the acceleration to the distance?
A.
[tex]t=\sqrt{10d}[/tex]
B.
[tex]t=\sqrt{2d}[/tex]
C.
[tex]t=\sqrt{\frac{5d}{2} }[/tex]
D.
[tex]t=\sqrt{\frac{2d}{5} }[/tex]

8.)Solve for x [tex]\sqrt{2x+8}=2[/tex]

A.
2
B.
–3
C.
–2
D.
no solution

9.)Solve for x:[tex]\sqrt{3x-2}=2[/tex]

A.
2
B.
[tex]-\frac{2}{3}[/tex]
C.
–2
D.
no solution

10.)What is the first step to solve the equation [tex]x^{2} -3=15[/tex]
A.
Take the square root of [tex]x^{2}[/tex], 3, and 15.
B.
Square 15.
C.
Add 3 to both sides of the equation.
D.
Add 1 to both sides of the equation.

can yall help a brother out im in deep sh|t if i dont pass so if your gunna do it do it right thank yall for helpen me out oh and i already tried to look em up so that dont work

help please! im really confused and stuck

HELP (ENGLISH)
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Please help me with this

True or false : The function shown has an absolute Minimum

Pick the answer that best fits the description

Harley solved the following equation and knows she made a mistake. Explain to her where her error was and then solve the equation correctly.

The sinusoidal function f(x)=33sin(7x−π12)+33 models the height, in centimeters, that a valve stem of the a tire is above ground x seconds after the tire begins to rotate.

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WORTH 67 PTS!! I WILL GIVE BRAIBLIEST!
Write an expression that is equivalent to
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3/4a + 2/3 - 1/2a - 1/3 + 1/2a
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ILL GIVE BRAINLIEST PLEAS EHELP

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Please help!! I will make you brainlest.

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