HELP NEEDED PLEASE :(
Identify the center and the radius of a circle that has a diameter with endpoints at (5, 8)
and (7,6).

Answers

Answer 1

Answer:

Centre is,

((5+7)/2,(8+6)/2)

or, (12/2,14/2)

or, (6,7)

radius is,

[√{(5-7)²+(8-6)²}]/2

= [√(2²+2²)]/2

= [√(4+4)]/2

= [√8 ]= [2√2]/2 = √2

Answer 2

The center of a circle = (6, 7)

the radius of a circle = [tex]\sqrt{2}[/tex] units

What is the distance formula?

"The distance between two points [tex](x_1,y_1),(x_2,y_2)[/tex] is given by  [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2}[/tex]"

What is midpoint formula?

"The coordinates of the midpoint of the line segment having endpoints [tex](x_1,y_1),(x_2,y_2)[/tex] is given by [tex]m=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex] "

What is diameter of circle?

"It is the line segment through the center and touching two points on its edge. "

For given question,

The diameter of circle has endpoints at (5, 8) and (7,6).

Let [tex](x_1,y_1)=(5,8),(x_2,y_2)=(7,6)[/tex]

First we find the length of the diameter of the circle.

Using the distance formula,

[tex]\Rightarrow d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2} \\\\\Rightarrow d=\sqrt{(7-5)^2+(6-8)^2} \\\\\Rightarrow d=\sqrt{2^2+(-2)^2}\\\\\Rightarrow d=\sqrt{4+4}\\\\\Rightarrow d=2\sqrt{2}~units[/tex]

We know that the diameter = 2 × radius

⇒ radius (r) = [tex]\frac{2\sqrt{2} }{2}[/tex]

⇒ r = [tex]\sqrt{2}[/tex] units

We know that the midpoint of the diameter is the center of the circle.

Using midpoint formula the center of the circle would be,

[tex]\Rightarrow O=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\\\\Rightarrow O=(\frac{5+7}{2} ,\frac{8+6}{2} )\\\\\Rightarrow O=(\frac{12}{2} ,\frac{14}{2} )\\\\\Rightarrow O=(6,7)[/tex]

Therefore, the center of the circle is (6,7)

Hence, the center of a circle = (6, 7)

the radius of a circle = [tex]\sqrt{2}[/tex]

Learn more about the distance formula and mid-point formula here:

https://brainly.com/question/11231122

#SPJ3


Related Questions

If b < 0 and a/b > c/b, then what is the relationship between a and c?

Answers

Answer:

a < c

Step-by-step explanation:

Given inequality:

a/b > c/b

Since b is negative, when multiplied by b, the inequality changes to opposite direction:

b(a/b) < b(c/b)a < c

what percent of 70 is 35

Answers

Answer:

50%

Step-by-step explanation:

35 is halve of 70 therefore it is 50%

hope it helps u...........

Solve each equation for the given variable?

Answers

Answer:

1. x = 20     2. n = 50

Step-by-step explanation:

1/4x - 2 = 3

1/4x = 5

x = 20

2. 8 = 1/5n - 2

10 = 1/5n

n = 50

Answer:

Question 1

Original equation:

1/4x-2=3

Add 2 to both sides:

1/4x=5

Multiply both sides by 4/1:

x=20

Question 2

Original equation:

8=1/5n x 2

Divide both sides by 2

4 = 1/5n

Multiply both sides by 5/1

n=20

Let me know if this helps!

Find m a 24.7
b 79.2
c 68.3
d 57.4
e 46.5
f 80.1
g 35.6

Answers

Answer:

68.3 degrees

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan I = opp side / adj side

tan I = sqrt(82) / sqrt(13)

tan I = sqrt(82/13)

Taking the inverse tan of each side

tan ^-1 ( tan I) = tan ^-1( sqrt(82/13))

I = 68.2892

Rounding to the nearest tenth

I = 68.3 degrees

Factor the following expressions completely. Show and check all work on your own paper.
x^2+169

Factor the following expressions completely. Show and check all work on your own paper.
5x^2-50x+125

Factor the following expressions completely. Show and check all work on your own paper.
100x^2-25y2

Answers

Answer:

See the expressions and the answers below

Step-by-step explanation:

Given data

The first expression is given as

x^2+169 .-> we can not factorize the expression anymore

The second expression

5x^2-50x+125

5(x^2-10x+25)

The third expression

100x^2-25y2

25(4x^2-y^2)

A.) Evaluate f(1)

B.) given: f(x) =1, find x

Answers

Answer:

f(1) = -2

f(x) =1 when x=0 or x=-2

Step-by-step explanation:

f(1) is the y value when x=1

f(1) = -2

f(x) = 1 means find the x value when y=1

when y =1, x =0 and -2

help asap plzzz I NEED HELP !!!!!!!!

Answers

Answer:

1520.5 in^2

Step-by-step explanation:

Surface area=2*pi*r^2+2*pi*r*h=2*pi*r*(r+h)=2*pi*11*22=1520.5 in^2

What is the unit rate for $7.30 for 5 pounds.

Answers

Answer:

1.46 dollars per pound

Step-by-step explanation:

Take the total cost and divide by the number of pounds

7.30 dollars / 5 pounds

1.46 dollars per pound

Answer:

1.46

Step-by-step explanation:

Unit rate is the amount for only one pound. To do this, divide 7.30 and 5.

Divide:

7.3 / 5 = 1.46

Each pound is $1.46

Hope this helped.

An expression is shown below:

6x2y − 3xy − 24xy2 + 12y2

Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)

Part B: Factor the entire expression completely. Show the steps of your work. (6 points)

Answers

Given:

The given expression is:

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

Taking out the highest common factor 3y, we get

[tex]=3y(2x^2-x-8xy+4y)[/tex]

Therefore, the required expression is [tex]3y(2x^2-x-8xy+4y)[/tex].

Part B:

From part A, we have,

[tex]3y(2x^2-x-8xy+4y)[/tex]

By grouping method, we get

[tex]=3y(x(2x-1)-4y(2x-1))[/tex]

[tex]=3y(x-4y)(2x-1)[/tex]

Therefore, the required factored form of the given expression is [tex]3y(x-4y)(2x-1)[/tex].

Can someone do #4 #5 #6?

Answers

4. Percent increase

Because Original Value < New Value

5. Percent

6. Whole

Because it's asking what number that means total.

Thanks :)

Love from India :)

Martina got a prepaid debit card with $20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 19 cents per yard. If after that purchase there was $15.63 left on the card, how many yards of ribbon did Martina buy?

Answers

Phone card = $20  

You need to minus 17.92 from 20 = $2.08  

$2.08 / 0.13 = how many minutes  

= 16

What type of line is PQ?
A. angle bisector
B. median
C. altitude
D. side bisector

Answers

Answer:

D

Step-by-step explanation:

RS is a side.

RQ = QS  They are both equal to seven.

That means that the answer is A or D

Since the word side is in D, it must be the answer.

It’s time so please ASAP
Which expression is equivalent to the following complex fraction
3
-4
X-1
2-
2
X-1

O
2(x-2)
-4x+7
-4x+7
O 2(x-2)
-4x+7
2(x2-2)
21x²-2)
-4x+7

Answers

Answer:

B

Step-by-step explanation:

The answer can be obtained by simplifying the whole fraction

Customers receive rewards pints based on the purchase type:

Answers

Grocery, travel, dinning, and other.

Verify the identity algebraically:
Csc(-x)tanx =-secx

Answers

Step-by-step explanation:

Recall that

[tex]\sin(-x) = -\sin x[/tex]

Therefore,

[tex]\csc(-x) = \dfrac{1}{\sin(-x)} = -\dfrac{1}{\sin x}[/tex]

so

[tex]\csc(-x)\tan x = \left(-\dfrac{1}{\sin x}\right)\left(\dfrac{\sin x}{\cos x}\right)[/tex]

[tex]\:\:\:\:\:\:\:\:\:= -\dfrac{1}{\cos x} = -\sec x[/tex]

. A swimming pool was filling with water at a constant rate of 200 gallons per hour. The pool had
50 gallons before the timer started. Write an equation in standard form to model the situation, then
find the amount of water in the pool after 2 hours and 15 minutes.

Answers

300 amount of the water in the pool after 2 hours and 15 minutes

Use the given information to determine which of the following relationships
can be proved and why.
L= 20
ME ZP
ML = PO
A. ALMN - A OPQ, because of AAS.
B. ALMNE A OPQ, because of ASA.
C. We cannot prove any relationship based on these data.
D. ALMN=A OPQ, because of SAS,

Answers

Answer:

B. ∆LMN ≅ ∆OPQ because of ASA

Step-by-step explanation:

Two triangles are congruent if two angles and an included side of one triangle are congruent to two corresponding angles and a corresponding included side of the other.

From the information given, we have:

Two angles (<L and <M) in ∆LMN that are congruent to two corresponding angles (<O and <P) in ∆OPQ.

Also, included side in both triangles are congruent (ML ≅ PO).

Therefore, ∆LMN ≅ ∆OPQ by the ASA Theorem.

Select the statement that best justifies the conclusion based on the given information.

If a(b + c) = d, then ab + ac = d.

associative
commutative
distributive
closure

Answers

Answer:

distributive

Step-by-step explanation:

a(b + c)=ab + ac

it's distributive one

Charity is planting trees along her driveway, and she has 6 pine trees and 6 willows to plant in one row. What is the probability that she randomly plants the trees so that all 6 pine trees are next to each other and all 6 willows are next to each other

Answers

Answer:

0.0022 = 0.22% probability that she randomly plants the trees so that all 6 pine trees are next to each other and all 6 willows are next to each other.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, the elements are arranged, so we have to use the arrangements formula.

Arrangements formula:

The number of possible arrangements of n elements is:

[tex]A_{n} = n![/tex]

Desired outcomes:

Pine trees(6!) then the willows(6!) or

Willows(6!) then the pine trees(6!). So

[tex]D = 2*6!*6! = 1036800 [/tex]

Total outcomes:

12 trees, so:

[tex]T = 12! = 479001600 [/tex]

What is the probability that she randomly plants the trees so that all 6 pine trees are next to each other and all 6 willows are next to each other?

[tex]p = \frac{D}{T} = \frac{1036800 }{479001600 } = 0.0022[/tex]

0.0022 = 0.22% probability that she randomly plants the trees so that all 6 pine trees are next to each other and all 6 willows are next to each other.

Find y' for the following.​

Answers

Answer:

[tex]\displaystyle y' = \frac{5x - 2xy^2}{2y(x^2 - 3y)}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Implicit Differentiation

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 5x^2 - 2x^2y^2 + 4y^3 - 7 = 0[/tex]

Step 2: Differentiate

Implicit Differentiation:                                                                                 [tex]\displaystyle \frac{dy}{dx}[5x^2 - 2x^2y^2 + 4y^3 - 7] = \frac{dy}{dx}[0][/tex]Rewrite [Derivative Property - Addition/Subtraction]:                                 [tex]\displaystyle \frac{dy}{dx}[5x^2] - \frac{dy}{dx}[2x^2y^2] + \frac{dy}{dx}[4y^3] - \frac{dy}{dx}[7] = \frac{dy}{dx}[0][/tex]Rewrite [Derivative Property - Multiplied Constant]:                                   [tex]\displaystyle 5\frac{dy}{dx}[x^2] - 2\frac{dy}{dx}[x^2y^2] + 4\frac{dy}{dx}[y^3] - \frac{dy}{dx}[7] = \frac{dy}{dx}[0][/tex]Basic Power Rule [Product Rule, Chain Rule]:                                             [tex]\displaystyle 10x - 2 \Big( \frac{d}{dx}[x^2]y^2 + x^2\frac{d}{dx}[y^2] \Big) + 12y^2y' - 0 = 0[/tex]Basic Power Rule [Chain Rule]:                                                                     [tex]\displaystyle 10x - 2 \Big( 2xy^2 + x^22yy' \Big) + 12y^2y' - 0 = 0[/tex]Simplify:                                                                                                         [tex]\displaystyle 10x - 4xy^2 - 4x^2yy' + 12y^2y' = 0[/tex]Isolate y' terms:                                                                                             [tex]\displaystyle -4x^2yy' + 12y^2y' = 4xy^2 - 10x[/tex]Factor:                                                                                                           [tex]\displaystyle y'(-4x^2y + 12y^2) = 4xy^2 - 10x[/tex]Isolate y':                                                                                                       [tex]\displaystyle y' = \frac{4xy^2 - 10x}{-4x^2y + 12y^2}[/tex]Simplify:                                                                                                         [tex]\displaystyle y' = \frac{5x - 2xy^2}{2y(x^2 - 3y)}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

What is the common ratio for this geometric sequence?
27, 9, 3, 1, ...

Answers

Answer:

27:9 3:1.................

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! Given this frequency chart of 1490 passengers from the Titanic who died, choose the class(es) whose relative frequency would comprise just under, 1/2 of a pie chart​

Answers

Answer:

b and e

Step-by-step explanation:

Second and Third which gives in total:

0.112 + 0.354 = 0.466

This is under 1/2 and greater than Crew.

Hellp PLZZzzzzzzzxxxmxxxxxxxxxx

Answers

Answer:

12. We use Rational numbers when the number is in P/q form

we don't use integers because they are not in p/q form

13.  Aron is wrong . he is not correct

an opposite of rational number can out be  negative it should be irrational number

opposite of integers are negative  that's why

*so opposite of rational numbers will ne irrational numbers not negative

14. Greatest to least

   -3.02 , -4 , -4.09 , -4.32, -4,35 , -5.11

plzzzzz helllllllppppppp worth 25 points

Answers

Answer:

Step-by-step explanation:

Let's fill that in with what the variables are "worth":

(3)(-3)+2(-2) and simplify to

-9 + (-4) which, when you add those 2 negatives, gives you

-13, choice B.

Answer:

[tex]x = 3 \\ y = - 3 \\ z = - 2 \\ xy + 2z = 3 \times - 3 + 2 \times - 2 \\ = - 9 - 4 \\ = - 13 \\ thank \: you[/tex]

Help me with this question please...


Each of the following statements is true or false. Which statements are true?

A. A triangle where at least two angles are acute is called an acute triangle.
B. Some polygons are neither convex nor concave.
C. The sum of the interior angles of a concave pentagon is $540^{\circ}.$
D. The interior angles of a regular $1000$-gon are greater than the interior angles of a regular $100$-gon.
E. The exterior angles of a regular $1000$-gon are greater than the exterior angles of a regular $100$-gon.

Answers

9514 1404 393

Answer:

  A. False

  B. False

  C. True

  D. True

  E. False

Step-by-step explanation:

A. False -- any triangle has at least two acute angles, whether it is acute, right, or obtuse.

B. False -- by definition, any polygon that is not convex is concave.

C. True -- the angle sum is the same regardless of whether the pentagon is convex or concave. (Provided it is a "simple" polygon, with no crossing sides.)

D. True -- the measure of the interior angle of a regular polygon increases as the number of sides increases. (see E)

E. False -- the exterior angles of a regular polygon are 360° divided by the number of sides. As the number of sides increases, the measure of each exterior angle decreases. (Interior angles are the supplement of exterior angles, so they increase as the number of sides increases.)

11
Select the correct answer.
Which expression is equivalent to the given expression?
In(2e/x)
O A. In 2 – In x
OB. 1 + In 2 - In x
Oc. In 2 + In x
OD. In 1 + In 2 - In
Reset
Next

Answers

Answer:

B. 1 + ln 2 - ln x

General Formulas and Concepts:

Algebra II

Natural logarithms ln and Euler's number eLogarithmic Property [Multiplying]:                                                                     [tex]\displaystyle log(ab) = log(a) + log(b)[/tex] Logarithmic Property [Dividing]:                                                                         [tex]\displaystyle log(\frac{a}{b}) = log(a) - log(b)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle ln(\frac{2e}{x})[/tex]

Step 2: Simplify

Expand [Logarithmic Property - Dividing]:                                                      [tex]\displaystyle ln(\frac{2e}{x}) = ln(2e) - ln(x)[/tex]Expand [Logarithmic Property - Multiplying]:                                                  [tex]\displaystyle ln(\frac{2e}{x}) = ln(2) + ln(e) - ln(x)[/tex]Simplify:                                                                                                             [tex]\displaystyle ln(\frac{2e}{x}) = ln(2) + 1 - ln(x)[/tex]Rewrite:                                                                                                             [tex]\displaystyle ln(\frac{2e}{x}) = 1 + ln(2) - ln(x)[/tex]

A box contains two blue cards numbered 1 and 2, and three green numbered 1 through 3. A blue card ins picked, followed by a green card. Select sample space for such experiment
a) {1, 1), (1, 2, (1, 3)(2, 1), (2, 2), (2, 3)}
b) {(1, 1)(1, 2), (2, 1), (2, 2), (3, 1), (3, 2)}
c) {5}
d) {6}

Answers

Answer:

The answer is a.

The second term in a geometric sequence is 50. The forth term in the same sequence is 112.5. what is the common ratio in this sequence?

Answers

Answer:

1.5

Step-by-step explanation:

Let the first term be a and the common ratio be r

ATQ, ar=50 and ar^3=112.5, divide these two. r^2=2.25, r=1.5

What is the answer for 75% of test takers whovscored below average withou an unknown mean and standard deviation

Answers

Answer:

sir she hey Jen Jen Jenn receive surge

Answer:

Hello,

Step-by-step explanation:

z=0.7734

p(z<?)=0.75 ==> ?=0.7734

Write the piecewise defined function for the total cost of parking in the garage. That is, state the function C(x), where x is the number of hours a car is parked in the garage.

Answers

Answer:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

Step-by-step explanation:

Given

See attachment for question

Required

The piece-wise function

From the attachment, we have:

(1) $4/hr for first 2 hours

This is represented as:

[tex]C(x) = 4x[/tex]

The domain is: [tex]0 \le x \le 2[/tex]

(2) $2/hr for next 4 hours

Here, we have:

[tex]Rate = 2[/tex]

The total cost in the first 2 hours is:

[tex]C(x) = 4x[/tex]

[tex]C(2) = 4*2 = 8[/tex]

So, this function is represented as:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex] ----- 2 represents the first 2 hours

So, we have:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex]

[tex]C(x) =8 + 2(x - 2)[/tex]

Open brackets

[tex]C(x) =8 + 2x - 4[/tex]

Collect like terms

[tex]C(x) =8 - 4+ 2x[/tex]

[tex]C(x) =4+ 2x[/tex]

The domain is:

[tex]2 < x \le 2 + 4[/tex]

[tex]2 <x \le 6[/tex]

(3) 0 charges for the last 2 hours

The maximum charge from (2) is:

[tex]C(x) =4+ 2x[/tex]

[tex]C(6) = 4 + 2*6[/tex]

[tex]C(6) = 4 + 12[/tex]

[tex]C(6) = 16[/tex]

Since there will be no additional charges, then:

[tex]C(x) = 16[/tex]

And the domain is:

[tex]6 < x \le 8[/tex] --- 8 represents the limit

So, we have:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

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