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Answer:

-12, 0

Step-by-step explanation:

Answer:

45 degrees

Step-by-step explanation:

Since we have a right triangle, we use the appropriate trigonometric ratio

The angle marked P faces QR and that makes it the opposite side

PR faces the right angle and that makes it the hypotenuse

The trigonometric ratio that links the opposite and the hypotenuse is the sine

It is the ratio of the opposite to the hypotenuse

Thus;

sin P = √26/2 √13

Sin P = √2/2

P = arc sin √2/2

P = 45 degrees

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2 + b^2 = c^2

B^2 + 8^2 = 15^2

B^2 + 64 + 225

B^2 = 225 - 64

B^2 = 161

B = [tex]\sqrt{161}[/tex]    OR  12.7

Answer:

d 180 miles

Step-by-step explanation:

4.5×40= 180 miles

The actual distance to college Lisa and Susan going together is 180 miles.

The scale factor defines a variable in a ratio of two different measurements.

Sometimes drawings of large models are represented in a scale factor of a smaller unit.

Given, The map scale is 1 in. = 40 mi.

Lisa and Susan are driving to college together, On the map, Lisa measures the distance to be 4.5 inches.

Therefore,

The actual distance to college is,

= (4.5×40) miles.

= 180 miles.

learn more about scale factors here :

https://brainly.com/question/30215119

#SPJ2

Answer:

Step-by-step explanation:

Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:

                #lbs     x       $/lb       =         Total

T

K

Mix

Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:

                 #lbs        x        $/lb       =        Total

T                                           9

K                                         13.50

Mix

Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound

                  #lbs      x       $/lb        =        Total

T                                         9

K                                       13.50

Mix              50                 9.54

Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:

                 #lbs       x       $/lb      =      Total

T                   x        x          9         =        9x

K             50 - x      x       13.50     =    675 - 13.50x

Mix            50        x         9.54     =     477

The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:

9x + 675 - 13.5x = 477 and

-4.5x = -198 so

x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.

Step-by-step explanation:

y = 5^x -9

5^x = y + 9

x = ^5 log (y+9)

f~'(x) = ^5 log (x+9)

Step-by-step explanation:

The last two answers is correct

Answer:

4

Step-by-step explanation:

The answer to T - H is negative

Answer:

27

Step-by-step explanation:

3v+6=5v-8

3v+14=5v

14=2v

v=7

3*7+6

21+6

27

u were right on 7 u just need to plug it into the equation

Answer:

f(x)= 1/4

(4)

x

for x=1→f(1)=

4

1

⋅4

1

=1→(1; 1)

for x=2→f(2)=

4

1

⋅4

2

=

4

1

⋅16=4→(2; 4)

Answer: The graph nr 4.

Other method:

f(x)=\dfrac{1}{4}\cdot4^x=4^{-1}\cdot4^x=4^{x-1}f(x)=

4

1

⋅4

x

=4

−1

⋅4

x

=4

x−1

Used:

\begin{gathered}a^{-1}=\dfrac{1}{a}\\\\a^n\cdot a^m=a^{n\cdot m}\end{gathered}

a

−1

=

a

1

a

n

⋅a

m

=a

n⋅m

Draw the graph of y = 4^x and next shift it 1 unit right.

Answer:

area of the larger figure=32 yd×37 yd

=1184 yd²

area of the smaller figure=21 yd ×26 yd

=546 yd²

area of the shaded region=1184 yd² -546 yd²

=638 yd²

Answer:

[tex]\sqrt{53}[/tex]

Step-by-step explanation:

Answer:

a. (3.83952, 5.16049)

b. (7.32, 8.88)

c. The difference in the range of the confidence intervals suggest that taking the zinc loz-enges reduces the overall duration of cold symptoms

d. The assumptions required for the validity validity of a t-test include that the data is sampled from a source that have data that are normally distributed

Step-by-step explanation:

The given parameters are;

The number of participants that took zinc lozenges, n₁ = 25

The number of participants that took a placebo, n₂ = 23

The mean duration of the symptoms for the zinc lozenge group, [tex]\overline x_1[/tex] = 4.5 days

The standard deviation of overall duration, s₁ = 1.6 days

The mean duration of the symptoms for the placebo group, [tex]\overline x_2[/tex] = 8.1 days

The standard deviation, s₂ = 1.8 days

a. The 95% confidence interval if everyone in the population were to take zinc lozenges is given as follows;

[tex]CI=\bar{x}_1\pm t_{\alpha/2} \times \dfrac{s_1}{\sqrt{n_1}}[/tex]

n₁ = 25, the degrees of freedom (df) = n₁ - 1 = 24

The t-value for 95% confidence interval, with df = 24, with t = 2.064

Therefore, we have;

[tex]CI_{zl}=4.5 \pm 2.064 \times \dfrac{1.6}{\sqrt{25}}[/tex]

[tex]CI_{zl}[/tex] = 4.5 ± 0.66048

[tex]CI_{zl}[/tex] = (3.83952, 5.16049)

b. The 95% confidence interval if everyone in the population were to take the placebo is given as follows;

[tex]CI_p=\bar{x_2}\pm t_{\alpha/2} \times \dfrac{s_2}{\sqrt{n_2}}[/tex]

n₂ = 23, the degrees of freedom (df) = n₂ - 1 = 22

The t-value for 95% confidence interval, with df = 22, with t = 2.074

Therefore, we have;

[tex]CI_p =8.1 \pm 2.074 \times \dfrac{1.8}{\sqrt{23}}[/tex]

[tex]CI_p[/tex] = 8.1 ± 0.7784

[tex]CI_p[/tex] = (7.32, 8.88)

c. Based on the difference in the range of the 95% confidence interval for the mean duration of cold symptoms of the group that take zinc lozenges, (3.83952, 5.16049), and the mean of the group that are on a placebo, (7.32, 8.88), there is sufficient statistical evidence to suggest that there is a difference between the mean and taking zinc lozenges reduces the overall duration of cold symptoms more than if taking placebo

d. The assumptions required for validity when carrying out a t-test include;

i) The measurement scale is ordinal or continuous

ii) The sample is a simple random sample

iii) The data gives a normal distribution curve

iv) The sample size is reasonably large

v) The variance are homogeneous

Among these assumptions, the data must be randomly sampled from the population of interest and that the data variables follow a normal distribution

The common assumptions made when doing a t-test include those regarding the scale of measurement, random sampling, normality of data distribution, adequacy of sample size and equality of variance in standard deviation

=============================================================

Explanation:

Ignore the sides that are 'a' units long.

We'll compare the sides that are 26 units and 27 units long. We see the 27 unit side is larger, which makes the 93 degree angle larger than the 3x-9 degree angle.

Symbolically, we would say

3x-9 < 93

At the same time, the 3x-9 is also larger than 0

So

3x-9 > 0 or 0 < 3x-9

Put together, we can form this compound inequality

0 < 3x-9 < 93

-------------------

Let's isolate x like so

0 < 3x-9 < 93

0+9 < 3x-9+9 < 93+9 .... add 9 to all sides

9 < 3x < 102

9/3 < 3x/3 < 102/3 .... divide all sides by 3

3 < x < 34

x is any number between 3 and 34, but cannot equal either endpoint

For example, x = 10 is valid since 3 < 10 < 34 is true. But x = 50 is not a solution since 3 < 50 < 34 is false. We can't have x = 3 and we also can't have x = 34 either, but we can have anything in between those endpoints.

Answer:

7.36

Step-by-step explanation:

Area=92

Height=23

Base=?

Area=1/2*base*height

92=1/2*23*height

92=12.5*height

920/125=height

7.36=height

Pleae mention unit in answer

Mark me as brainliest

Answer:

Step-by-step explanation:

suface area of base=1/2×9×7.8=9×3.9=35.1 yd²

lateral surface area=3×1/2×9×10=135 yd²

total surface area=135+35.1=170.1 yd²

i assumed it is an equilateral triangular base.

as √(7.8²+4.5²)=9.0049≈9

Answer:

Step-by-step explanation:

Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.

Your

Answer:

For 5 the yellow square stays the same, while the blue adds 2 each time.

5. 1(2x) something like that.

6. 3 is 6 4 is 7 5 is 8

I have gotten too old for this, my bad somethings just dont make sense anymore.

Answer:

5.

a. 2 blue blocks added

b. 2 blue blocks are added on the top blue blocks

c.y = 2x +3

6.

a.

1,4

2,5

3,6

4,7

5,8

b. starting off with 4 triangles and ending with a bottom triangle a triangle is added first from the top, then the bottom for each increase (increment)

c. y = x+4

Step-by-step explanation:

all the answers are up

Answer:

760

Step-by-step explanation:

Answer:

Answer:

(6/5) π in^2 or 1.2 π in^2

Step-by-step explanation:

the area of a circle and the area of one circle sector are proportional.

Area of the circle = radius^2 * π = 3^2 π = 9π in^2

the hidden date is that the centre angle of a circumference is 360 degrees

we have now to use a proportion that has this meaning:

if the area is 9π in^2 when the angle is 360 degrees, what is the area when the angle is 48 degrees?

9π : 360 = x : 48

x = (48 *9π)/360 = (6/5) π in^2

Answer:

V = 400 m^3

Step-by-step explanation:

The volume of a square pyramid is

V = 1/3 Bh where B is the area of the base and h is the height

B = 10 *10 = 50

V = 1/3 (100)* 12

V = 400 m^3

Consider IJ and GL are the parallel sides of the trapezoid.

Given:

In a trapezoid GIJL, HK is the mid segment, IJ =7 cm and GL=15 cm.

To find:

The length of the mid segment HK.

Solution:

The length of the mid segment of a trapezoid is:

[tex]\text{Midsegment}=\dfrac{b_1+b_2}{2}[/tex]

where, [tex]b_1,b_2[/tex] are two parallel side or bases of the trapezoid.

HK is the mid segment, and the parallel sides are IJ =7 cm and GL=15 cm. So, the length of the mid segment is:

[tex]HK=\dfrac{IJ+GL}{2}[/tex]

[tex]HK=\dfrac{7+15}{2}[/tex]

[tex]HK=\dfrac{22}{2}[/tex]

[tex]HK=11[/tex]

Therefore, the length of HK is 11 units.

Answer:

7, 17, 37, 47, 73, 79, 97

Step-by-step explanation:

they have 7's as one of their digits

Answer:

1 pair of parallel sides: B

2 pairs of parallel sides: A, D

3 pairs of parallel sides: C

Step-by-step explanation:

When two lines are parallel, they will never intersect.

Answer:

Angle HFG = 24 degrees

Step-by-step explanation:

From the diagram, we have the following;

Angle EFH and angle HFG are complementary (they add up to be 90 degrees)

angle EFH + angle HFG = 90

Angle HFG = 90-66

Angle HFG = 24 degrees

Answer:

At least two of the lateral faces are congruent.

Step-by-step explanation:

Because the words "at least" are used this means that at a minimum 2 of the faces are congruent. Because the base is in the shape of a triangle, this will definitely be true.

hope this helps:)

Answer:

At least two of the lateral faces are congruent.

Step-by-step explanation:

Because the words "at least" are used this means that at a minimum 2 of the faces are congruent. Because the base is in the shape of a triangle, this will definitely be true.

hope this helps:)

Answer: pretty sure it is 201 tiles

please mark me brainlies. That would be helpful

Answer:

a23, a31, a21, a11, a12, a33

Step-by-step explanation: I got it right on Edumentum.

Answer:

a23, a31, a21, a11, a12, a33

Step-by-step explanation:

Answer:

[tex]P = (3,0)[/tex]

Step-by-step explanation:

Given

[tex]A = (-3,-2)[/tex] ---- [tex](x_1,y_1)[/tex]

[tex]B = (6,1)[/tex] --- [tex](x_2,y_2)[/tex]

[tex]m:n =2:1[/tex]

Required

The coordinates of P

This is calculated as:

[tex]P = (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}][/tex]

So:

[tex]P = (\frac{2*6+1*-3}{2+1},\frac{2*1+1*-2}{2+1})[/tex]

[tex]P = (\frac{9}{3},\frac{0}{3})[/tex]

[tex]P = (3,0)[/tex]