Mathematics High School

HELP PLEASE HURRY


THANKS

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Answer 1

Answer:

Step-by-step explanation:

Related Questions

Can someone help me with this please !!

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Step-by-step explanation:

I need help to...

I keep putting it in and no one has ever answered it and I'm struggling and getting stressed.

Solve inequality problem (urgent help please)

Answers

Answer:

B

Step-by-step explanation:

|3m-2|=>1

1 <= 3m-2 or 3m-2 <= -1

3 <= 3m or 3m <= 1

1 <= m or m <= (1/3)

Y'ALL PLEASE HELP ME I WOULD GREATLY APPRECIATE IT!!!!!:)!!!!!!

Find the measure of angle TOS in the figure below. SHOW YOUR WORK SO I CAN SEE HOW YoU GOT IT!!!!

Answers

Step-by-step explanation:

<TOS=122° [being vertically opposite angle]

Answer:

angleTOS =122°

EXPLANATION:

[ If two straight lines intersect at point O, vertically opposite angles are equal]As vertically opposite angles are equal; Hence AngleTOS=QOR=122°

The number of bags of Brand Y dog food sold on these five days was 175. Which bar represents the data for Day 5 for Brand Y?

Answers

Answer:

30

Step-by-step explanation:

solve for x.
solve for x.
solve for x.

Answers

Answer:

[tex]x=10[/tex]

Step-by-step explanation:

A secant is a line segment that intersects a circle in two places. One property of a secant is the product of the lengths ratio. This ratio can be described as the following, let ([tex]inside[/tex]) refer to the part of the secant that is inside the circle, and ([tex]outside[/tex]) refer to the part that is outside of it. ([tex]total[/tex]) will refer to the entirety of the secant or ([tex]inside+outside[/tex]). The numbers (1) and (2) will be used as subscripts to indicate that there are two different secants.

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

Substitute,

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

[tex](outside_1)(inside_1+outisde_1)=(outside_2)(inside_2+outside_2)[/tex]

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

Simplify,

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

[tex]6(x+11)=7(x+8)[/tex]

[tex]6x+66=7x+56[/tex]

Inverse operations,

[tex]6x+66=7x+56[/tex]

[tex]66=x+56[/tex]

[tex]10=x[/tex]

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