HELP PLEASEEEEEEE ASAP

Answer:

10x-20

Step-by-step explanation:

(5×2x)-(5×4)

10x-20

Answer:

System of equations

[tex]x + y = 5[/tex]

[tex]y - 2x = -4[/tex]

[tex](x,y) = (3,2)[/tex] --- solution

See attachment for graph

Step-by-step explanation:

Solving (a): Linear equations with 1 solution

The only condition to this is that, the system must have 1 solution.

Other than that, there is no other condition.

A linear equation is represented as:

[tex]ax + by= c[/tex]

For the equation to have 1 solution;

[tex]a_1 * b_2 \ne a_2 * b_1[/tex]

And example of such equation is:

[tex]x + y = 5[/tex]

[tex]y - 2x = -4[/tex]

Solving (b): The graph

See attachment for graph

The solution is the point of intersection of both lines of the graph. So, we have:

[tex](x,y) = (3,2)[/tex]

Answer:

D.

Step-by-step explanation:

f(x) = [tex]\sqrt[3]{4x}[/tex]

g(x) = 2x + 3

[tex]\frac{f}{g}[/tex] (x)  = 'f' divided by 'g'

[tex]\frac{\sqrt[3]{4x} }{2x+3}[/tex]    Substitute.

x cannot be -[tex]\frac{3}{2}[/tex] because that would create a zero in the denominator.

That's a no-no.

It makes it 'undefined'

Answer:

180

Step-by-step explanation:

Consider the equation x + y + z = 15

From algebraic identities, we know that (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

So,

(x + y + z)^2 = x^2 + y^2 + z^2 + 2(xy + yz + xz)

From the question, x^2 + y^2 + z^2 = 83 and x + y + z = 15

So,

152 = 83 + 2(xy + yz + xz)

=> 225 – 83 = 2(xy + yz + xz)

Or, xy + yz + xz = 142/2 = 71

Using algebraic identity a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca),

x3 + y3 + z3 – 3xyz = (x + y + z)(x² + y² + z² – (xy + yz + xz))

Now,

x + y + z = 15, x² + y² + z² = 83 and xy + yz + xz = 71

So, x^3 + y^3 + z^3 – 3xyz = 15(83 – 71)

=> x^3 + y^3 + z^3 – 3xyz = 15 × 12

Or, x^3 + y^3 + z^3 – 3xyz = 180

Answered by GAUTHMATH

Part A: The amount of ergs of radiant energy, Q produced in time t = 1.55 × 10⁷ s  is 6.045 × 10⁴⁰ ergs.

Since the sun produces 3.9 × 10³³ ergs of radiant energy per second, which is  a rate, r = 3.9 × 10³³ ergs/s.

We require the amount of ergs of radiant energy, Q produced in time t = 1.55 × 10⁷ s.

So, this heat Q = rate × time

Q = rt

Substituting the values of r and t into the equation, we have

Q = 3.9 × 10³³ ergs/s × 1.55 × 10⁷ s

Q = 6.045 × 10³³ × 10⁷ ergs

Q = 6.045 × 10⁴⁰ ergs

So, the amount of ergs of radiant energy, Q produced in time t = 1.55 × 10⁷ s  is 6.045 × 10⁴⁰ ergs.

Part B: The measurement of the diameter of human hair 1.8 × 10⁻² mm is more reasonable.

Since 1.8 × 10⁻² mm = 1.8  × 10⁻² mm  ×  1cm/10 mm = 1.8  × 10⁻³ cm (since 10 mm = 1 cm) and

1.8 × 10² mm = 1.8 × 10² mm × 1 cm/10 mm = 1.8 × 10 cm = 18 cm (since 10 mm = 1 cm)

Since the human hair is small and its diameter of human hair cannot be 18 cm since 18 cm is a large diameter, then the diameter of the human hair has to be 1.8  × 10⁻³ cm = 1.8  × 10⁻² mm which is a small value.

So, measurement of the diameter of human hair 1.8 × 10⁻² mm  is more reasonable.

Learn more about radiant energy here:

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Answer:

WAS THE OTHER ANSWER CORRECT????

Step-by-step explanation:

Answer:

Step-by-step explanation:

55 +80 + ∠C = 180   {Angle  sum property}

135 + ∠C = 180

∠C = 180 - 135

∠C = 45

The side opposite to the biggest angle is the longest side

Biggest angle is ∠B. So the longest side is AC

Smallest angle is ∠C. So, the shortest side is BA

Answer: -21/2 or -10.5

Step-by-step explanation:

Let x be the number that is going to be subtracted from the rational number

3 × (-8/3) - x = 5/2 ⇒ Write the equation

-8 - x = 5/2 ⇒ Do multiplication

-8 - x + x = 5/2 +x ⇒ Add x on both sides

-8 = 5/2 + x ⇒ Simplify

-8 - 5/2 = 5/2 + x - 5/2 ⇒ Subtract 5/2 on both sides

x = -21/2 = -10.5 ⇒ Simplify

Hope this helps!! :)

Please let me know if you have any questions

Answer:

18

Step-by-step explanation:

The height of the cone is 8, and the diameter is 3. This means that the radius is 3/2, or 1.5. We can plug everything into the formula (using 3 for pi):

[tex]\frac{3(1.5)^2(8)}{3}[/tex]

We can cancel out the 3 from the numerator and the denominator, so we are left with 1.5^2 times 8. 1.5 squared is equal to 2.25, and 2.25 times 8 is equal to 18.

Answer:

The answer would be C.

Compared to the original graph (red), the new graph (blue) is shifted 7 units to the left.

Step-by-step explanation:

Answer:

shift 7 units to the LEFT

Step-by-step explanation:

Answer:

90 units

Step-by-step explanation:

circumference C = 2 [tex]\pi[/tex]r

taking [tex]\pi[/tex] as 3.

C = 2 × 3 × 15

(15 is the radius of the circle)

C = 90 units

Answer:

90

Step-by-step explanation:

The Answer will be 90 because Pie is being replaced with 3, so it would be like 2(3)(15) which equals to 90.

But If Pie remains pie the equation would look like (2)(3.14)(15) which would turn out to be 94.2

These triangles are congruent by SAS, therefore HI and IJ will be the same length.

3v = v + 60

2v = 60

v = 30

Hope this helps!

Answer:

the first one

Step-by-step explanation:

check which graph passes through the point (2,4)

Answer:

First graph

Step-by-step explanation:

Edge

Answer:

Hello,

Step-by-step explanation:

Since 4u²+8u=4u(u+2)

Zeroes ={0,-2}

Coefficients={4,8}

But i don't know the relationship.

Answer:

There are three laws of indices.

Answer:

Open the image. (Hope you don't mind about bad writing)

Answer:

130 độ

Step-by-step explanation:

góc BOC= góc AOC-góc AOB

=180°-100°=80°

góc MOB = góc AOB/2=100°/2=50°( vì OM là tia phân giác của góc AOB)

góc COM= góc MOB + góc BOC

= 50° + 80°

= 130°

Answer:

Step-by-step explanation:

First of all, something is wrong with either the wording in the problem or the equation that you wrote; if the upward velocity is 18, we should see 18t in the equation, not 10t. I solved using 10t.

To find the max height of the ball and the time it took to get there, we need to complete the square on this quadratic and solve for the vertex. That will give us both of those answers in one!

To complete the square, set the quadratic equal to 0 and then move over the constant, like this:

[tex]-5t^2+10t=-35[/tex]  The rule is that we have to have a 1 as the leading coefficient, and right now it's a -5, so we factor that out, leaving us with:

[tex]-5(t^2-2t)=-35[/tex] and now we are ready to begin the process to complete the square.

The rule is: take half the linear term, square it, and add it to both sides. Our linear term is a -2 (from the -2t); half of -2 is -1, and -1 squared is 1. We add in a one to both sides. BUT when we put the 1 into the set of parenthesis on the left, we didn't just add in a 1, we have that -5 out front that is a multiplier. That means that we actually added in a -5 after it's all said and done.

[tex]-5(t^2-2t+1)=-35-5[/tex] and we'll clean that up a bit. The right side is easy, that's a -40. The left side...not so much.

The reason we complete the square is to put this quadratic into vertex form. Completing the square creates a perfect square binomial on the left, which for us is, along with the simplification on the right:

[tex]-5(t-1)^2=-40[/tex]

Lastly, we move the -40 back over by adding and setting the quadratic back to equal y:

[tex]-5(t-1)^2+40=y[/tex] and we see that the vertex is (1, 40). That translates to a height of 40 meters at 1 second after launch. That's the vertex which, by definition, is the max or min of the parabola. Because our parabola is negative, the vertex for us is a max.

To find out how long it takes the ball to hit the ground, set the quadratic equal to 0 and factor however it is you are currently doing this in class. You can continue to factor from the vertex form we have the equation in if you'd like. Let's do that, since we are already most of the way there. Begin here:

[tex]-5(t-1)^2=-40[/tex] and divide both sides by -5 to get

[tex](t-1)^2=8[/tex] and take the square root of both sides to "undo" that squaring on the left:

t - 1 = ±√8. Now add 1 to both sides to isolate the t:

t = 1 ± √8. In decimal form:

t = 1 + √8 is 3.828 seconds and

t = 1 - √8 is -1.828 seconds.

Since we all know that time will NEVER be a negative value, the time it takes the ball to hit the ground is 3.828 seconds.

Answer:

i have also no idea but plz mark me as brainlist

Answer:

yes it is a function         A

Step-by-step explanation:

Answer:

[tex]\left(6x^2-4x-5\right)\left(2x^2+3x\right)[/tex]

[tex]=6x^2\cdot \:2x^2+6x^2\cdot \:3x+\left(-4x\right)\cdot \:2x^2+\left(-4x\right)\cdot \:3x+\left(-5\right)\cdot \:2x^2+\left(-5\right)\cdot \:3x[/tex]

[tex]=6\cdot \:2x^2x^2+6\cdot \:3x^2x-4\cdot \:2x^2x-4\cdot \:3xx-5\cdot \:2x^2-5\cdot \:3x[/tex]

[tex]=12x^4+10x^3-22x^2-15x[/tex]

OAmalOHopeO

point slope form:y-2=4(x+1)

then distribute 4 and simplify y-2=4x+4 , y=4x+6 is the slope -y intercept form

then, move 4x on the left side, you get -4x+y=6 , multiply every term by -1, you get 4x-y=-6 which is standard form.

Answer:

1. - 8

2. 3

3. - 2

Step-by-step explanation:

1.

80 = - 10b

- 10b = 80

b = 80 / - 10

b = - 8

2.

6 = 2n

2n = 6

n = 6 / 2

n = 3

3.

- 16r = 32

r = 32 / - 16

r = - 2

If 0 < θ < π/2, then 0 < θ/2 < π/4, and for such angles we expect sin(θ/2) to be positive. Also, we know both sin(θ) and cos(θ) will be positive.

Given that tan(θ) = 2, we can find sec(θ) from the Pythagorean identity:

tan²(θ) + 1 = sec²(θ)   ==>   sec(θ) = √(tan²(θ) + 1)

…   ==>   cos(θ) = 1/√(tan²(θ) + 1)

…   ==>   cos(θ) = 1/√5

Now, recall the half-angle identity for sine:

sin²(θ/2) = (1 - cos(θ))/2

==>   sin(θ/2) = √[(1 - cos(θ))/2]

==>   sin(θ/2) = √[(1 - 1/√5)/2]

==>   sin(θ/2) = √[(√5 - 1)/(2√5)]

==>   sin(θ/2) = √[(5 - √5)/10]

Answer:

A

Step-by-step explanation:

The correct inequality that represents the given situation is: A.) n - 87 < 320.

The situation states that Samuel played a video game and gained some points. Let's represent the points he gained as 'n'.

Next, it is mentioned that he lost 87 points. To represent this in the inequality, we subtract 87 from the initial points gained, which gives us 'n - 87'.

Finally, the situation specifies that Samuel finished with less than 320 points. This means that the final score, represented by 'n - 87', is less than 320.

This inequality represents that the initial points gained by Samuel (n) minus 87 points is less than 320 points, indicating that his final score is less than 320 points after losing 87 points.

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Answer:

a)[tex]X=3300[/tex]

b)[tex]Y=7770[/tex]

Step-by-step explanation:

From the question we are told that:

Number Teachers [tex]T=6[/tex]

Number Student [tex]S=12[/tex]

Number in committee [tex]n=5[/tex]

a) Generally the equation for exactly 3 students on the committee is mathematically given by

[tex]X=^{S}C_3*^{T}C_3[/tex]

[tex]X=^{12}C_3*^{6}C_3[/tex]

[tex]X=3300[/tex]

b) Generally the equation for at least one teacher and at least one student on the committee is mathematically given by

Total Ways-(no of ways of selection no teacher or student)

Where total Ways

[tex]T=^{(6+12)}C_5[/tex]

[tex]T=8568[/tex]

Therefore

[tex]Y=8568-^{6}C_0*^{12}C_5+^{12}C_0*^{6}C_5[/tex]

[tex]Y=8568-798[/tex]

[tex]Y=7770[/tex]

Answer:

Step-by-step explanation:

abscissa = x coordinate

ordinate = y coordinate

table:

A( 2,-3)   / (2, -3) / 2/  -3

B(-1,-7)    / (-1, -7) / -1/  -7

C(2,0)    / (2,0)   / 2 / 0

D(-9, 6)  / (-9,6) / -9 / 6

E(2,4) .  / (2,4) .  / 2 / 4

F(0,-5)  /  (0,-5) / 0 / -5

Answer:

540$

Step-by-step explanation:

9x9 = 81

9 + 9 + 9 + 9 = 36

36 x 15 =540

Answer:

-cos α

is the answer-------

Answer:

Step-by-step explanation:

If we have 5 terms to the right of the -1 outside the box thing, that means that our original polynomial is a 4th degree (the degree is one lower than the number of terms in order to allow for the constant which has no variable). Set up the synthetic division as shown in the problem. The rule is to bring down the first term, the 1 to the right of the box, multiply it by the number outside, -1, and put that product up under the next number in line inside the box. Like this:

-1 |   1    7     15     9     7

          -1                        

      1  

Now add straight down, multiply the sum by -1 and put that product up under the next term in line, the 15:

-1 |   1     7     15     9     7

            -1     -6              

      1     6  

Then add straight down again, multiply the sum by -1 and put that product up under the next term in line, the 9:

-1 |     1     7     15     9     7

              -1     -6    -9      

        1     6     9

Then do the same thing. Add straight down, multiply the sum by -1 and put the product up under the next term in line, the 7:

-1 |     1     7     15     9     7

              -1     -6    -9     0

        1     6      9     0     7

This is the final result. The last number, the 7 is the remainder, but the rest of it makes up what we call the depressed polynomial and is a polynomial that is one degree less than the degree we started with. So this depressed polynomial is a 3rd degree. The numbers are the coefficients on the x terms:

[tex]1x^3+6x^2+9x+0R7[/tex] or more simply stated:

[tex]x^3+6x^2+9xR7[/tex]