HELP PLS! :/

A ball thrown straight up takes 1.89s to reach a height of 41.6m.
Taking g =9.81 m/s2 the balls initial speed was:

Help plsss

HELP PLS! :/A Ball Thrown Straight Up Takes 1.89s To Reach A Height Of 41.6m.Taking G =9.81 M/s2 The

Answers

Answer 1

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck


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Answer:

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A girl of mass m1=60.0 kilograms springs from a trampoline with an initial upward velocity of vi=8.00 meters per second. At height h=2.00 meters above the trampoline, the girl grabs a box of mass m2=15.0 kilograms. (Figure 1)

For this problem, use g=9.80 meters per second per second for the magnitude of the acceleration due to gravity.

What is the speed vbefore of the girl immediately before she grabs the box?
Express your answer numerically in meters per second.

What is the speed vafter of the girl immediately after she grabs the box?
Express your answer numerically in meters per second.

What is the maximum height hmax that the girl (with box) reaches? Measure hmax with respect to the top of the trampoline.

Answers

The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

 

Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.

The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.

The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.

Let's solve this exercise in parts:

a) Let's use kinematics to find the speed of the girl before she grabs the box

              v² = v₀² - 2 g y₁

              v² = 8² - 2 9.8 2.00

              v = R 24.8 = 4.98 m / s

b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.

Initial instant. Just before you grab the box.

              p₀ = M v + 0

Final moment. Right after taking the box

             [tex]p_f[/tex]  = (m + M) [tex]v_f[/tex]

         

In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.

           [tex]p_o = p_f[/tex]  

           mv = (m + M) [tex]v_f[/tex]  

           [tex]v_f = \frac{m}{m+M} \ v[/tex]

Let's calculate

           [tex]v_f = \frac{15}{15+ 60} \ 4.98[/tex]  

           [tex]v_f[/tex]  = 0.996 m / s

c) Now we use conservation of energy after the girl has the box.

Starting point. When the girl has the box

           Em₀ = K + U

           Em₀ = ½ (m + M) v² + (m + M) g y₁

Final point. At the highest point of the trajectory

          [tex]Em_f[/tex]  = U

         [tex]Em_f[/tex] = (m + M) g y₁

As there is no friction, the energy is conserved.

           [tex]Em_o = Em_f[/tex]  

          ½ (m + M) v² + (m + M) g y₁ = (m + M) g y

          y = [tex]\frac{v^2}{2g} + y_1[/tex]  

Let's calculate

           y = [tex]\frac{0.996^2}{2 \ 9.8} + 2.0[/tex]

           y = 2.05 m

In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

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Answer:

Vbefore = 4.98 m/s

Vafter = 3.98 m/s

Hmax = 2.81 m

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Answer:

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Explanation:

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Answers

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l = 0.302 m

Therefore T = 2 × 3.14159 × √[tex]\frac{0.302}{10}[/tex]

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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Which of the following scenarios would have the MOST friction force between the object and the surface?
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A hot air balloon rising vertically is tracked by an observer located 2 miles from the lift-off point. At a certain moment, the angle between the observer's line-of-sight and the horizontal is , and it is changing at a rate of 0.1 rad/min. How fast is the balloon rising at this moment

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We have that for the Question, it can be said that

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From the question we are told

An observer located 2 miles from the lift-off point. At a certain moment, the angle between the observer's line-of-sight and the horizontal is , and it is changing at a rate of 0.1 rad/min.

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Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

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Answer:

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Answer:

In animal cells, they help sequester waste. In plants, they help maintain water balance.

the height of the upper falls at Yellowstone falls is 33.2m. when the water reaches the botton of the falls, its speed is 25.8 m/s. neglecting air resistance, what is the speed of the water at the to of te falls.

Answers

Answer:

Hi there

The water acquires a vertical velocity component during the fall equal to

Vy = sqrt(2gH) = 25.5 m/s. Its velocity at the bottom is 25.8 m/s, so the horizontal component at the bottom must be sqrt[(25.8)^2 - (25.5)^2] = 3.9 m/s

That must be the horizontal component at the top also, since it does not change during the fall. It is the velocity magnitude there.

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Acceleration of a car that speeds from 4.3 m/s to 12.9 m/s in 2 seconds

Answers

Explanation:

let v1 = 4.3 m/s

v2 = 12.9 m/s

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Answers

Answer:

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Câu 9. Một dây dẫn đồng chất, tiết diện đều 20mm2 có dòng điện không đổi 12A đi qua. Tính trị trung bình mật độ dòng điện j ?

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Answer:

Sorry I can't understand you

If you do 72 J of work in 1.2 seconds, how much power is produced

Answers

Answer:

Explanation:

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Alex is x years old . June is 7years older than Alex . their total combined ages is 29 years . find June,s age . show all work algebraically

Answers

Answer:

18 years

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

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Answers

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