Help pls , will give brainliest!

Answer:

choose B is the greatest variablity

Answer:

35square meters

Step-by-step explanation:

5×7=35

Answer:

Red: 13/41

Yellow: 19/41

Blue: 9/41

Step-by-step explanation:

[tex]8 log_{5}( {x}^{5} ) = 8 \times 5 log_{5}(x) \\ = 40 log_{5}(x) [/tex]

Answer:

c

Step-by-step explanation:

to much working out but just as a summary section of working out

3*15=45

300+45=$345(1st year)

345+300=645

6.45*15=96.75

645+96.75=$741.75(2nd year)

keep on doing that until you beat 2 in list and use common sense to realise that (d) is too big, and (b, a) is too small so (c) is the correct amount. (this is quicker than actually doing all 20 years)

The total money with Lin after 20 years will be $4910.   

The formula for compound interest -

[tex]$A = P(1 + \frac{r}{n}) ^{nt}[/tex]

Given is that Lin is saving $300 per year in an account that pays 15% interest per year, compounded annually.

We can write the total money with Lin after 20 years as -

[tex]$A = P(1 + \frac{r}{n}) ^{nt}[/tex]

A = 300(1 + 0.15/1)²⁰

A = 300(1 + 0.15)²⁰

A = 300 x (1.15)²⁰

A = 300 x 16.37

A = 4910

Therefore, the total money with Lin after 20 years will be $4910.   

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Answer:

B. [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

Step-by-step explanation:

No. of students from first grade = 15

No. of students from second grade = 5

There are 5 rows of seats

Each row contains 5 seats

Total seats = 25

No. of ways for second-grade students to occupy the first row (i.e first 5 seats) = [tex]^{5} P_{5}[/tex]

Remaining seats = 20

So, now we are left with 15 first grade students  

So, No. of ways for first-grade students occupy remaining seats = [tex]^{20} P_{15}[/tex]

Using the counting rule principle,

No. of ways for the students can be seated if all of the second-grade students occupy the first row = [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

So, Option B is the correct answer

Hence, no. of ways for the students can be seated if all of the second-grade students occupy the first row is ×

There are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

A permutation in math is the number of ways in which a set of data or objects can be ordered or arranged, where the order matters.

Given that, a school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second-grade travel in the bus.

Since you have to place all first-grade students in the first three rows,

Therefore,

For the 15 first-graders of the first three rows (15 seats), we have ¹⁵P₁₅ since all 15 places have to be occupied by all 15 first-graders.

Then we have 10 remaining seats left to be assigned to the 5 second-graders = ¹⁰P₅

We then multiply the permutation numbers of those two arrangements to get the total ways:

¹⁵P₁₅ x ¹⁰P₅

Hence there are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

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Answer:

Hi, there the answer is -1

Step-by-step explanation:

Answer:

I think 180

Step-by-step explanation:

I think 180 because it looks like M+n are supplimetary angles.

Sorry if this is wrong.

Answer:

y-8x+7=0

Step-by-step explanation:

slope(m)=8

using slope intercept form of equation of staright line we get

y=mx+b

y=8*x+b

y-8x=b ................  eq(i)

since the line include the point (2,9) it satisfies the euation,

here x=2 and y=9

equation: y-8x=b

9-8*2=b

9-16=-b

-7=b

substituting the value of b in eq(i) we get

y-8x=-7

y-8x+7=0   is a required equation of the line.

Answer: 4'6 2'4

Step-by-step explanation:

Answer: 4) The center is located at (1, 3), and the radius is 6

Step-by-step explanation:

Solve the general equation of the circle.

x^2 -2x +1+ y^2-6y+9= 26+1+9 (x-1)^2+(y-3)^2=36=6^2

Hence, the coordinates of the center (1,3) And the radius will be 6

The center is located at (1,3) and the radius is 6.

"The center is the point from which all of the points on the circle are the same distance."

"The radius is the exact distance from the center to any point on the circle."

We have

[tex]x^{2} -2x+y^{2}-6y = 26\\[/tex]

Add 1 and 9 on both sides of equation

⇒[tex]x^{2} -2x+1+y^{2}-6y+9 = 26+1+9[/tex]

⇒[tex](x-1)^{2} +(y-3)^{2}= 36[/tex]

⇒[tex](x-1)^{2}+(y-3)^{2}=6^{2}[/tex].......(1)

We know the Standard form of equation of the circle

[tex](x-h)^{2}+(y-k)^{2} =r^{2}[/tex]

By comparing the standard form and equation (1)

Center (h, k) = (1, 3) and radius is 6

Hence, The center is located at (1,3) and the radius is 6.

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Answer:

The maximum angle is 84.3 degree.

Step-by-step explanation:

Sides of a triangle is

a = 6 , b = 11, c = 12

The maximum angle is opposite to c.

So,

[tex]a =6, b =11, c = 12 \\\\cos C =\frac{a^2+b^2-c^2}{2 ab}\\\\cos C =\frac{36+121-144}{2\times 6\times 11}\\\\cos C = \frac{13}{132}\\\\cos C = 0.0985\\\\C =84.3^o[/tex]

Answer:

The person above got it wrong its 84

Step-by-step explanation:

got it wrong on edge

Answer:

A two-column proof uses a table to present a logical argument and assigns each column to do one job, and then the two columns work in lock-step to take a reader from premise to conclusion.

Step-by-step explanation:

Basically in simple terms, one side is the statements, and the otherside is the reasoning

Answer:

48

Hope this helps!

Step-by-step explanation:

yes friend and your answe is wring

Answer:

a =9  b=0 c=6

Step-by-step explanation:

6+9x^2

Rewrite

9x^2 +0x+6

This is in the form

ax^2+bx+c

a =9  b=0 c=6

Answer:

the third option

Step-by-step explanation:

Answer:

C    The mean or median

Step-by-step explanation:

Answer:

No solution is possible from the information provided

Step-by-step explanation:

you didn't include the function.

Answer:

2&3

Step-by-step explanation:

Answer:

Mean= 44.2

Median=45

Mode=6

Range=50

Step-by-step explanation:

Mean= (10x1 +30x2 + 40x3 +50x2 +60x4)/12

= 530/12

=44.17

=44.2

Median= 40+50 /2

=45

Mode= 6

Range= 60-10

=50

Answer:

[tex]AB = 21.3[/tex]

Step-by-step explanation:

Given

[tex]\sin(25) = \frac{9}{c}[/tex]

See attachment

Required

Find AB

We have:

[tex]\sin(25) = \frac{9}{c}[/tex]

Make c the subject

[tex]c = \frac{9}{\sin(25)}[/tex]

[tex]c = 21.3[/tex]

From the attached triangle;

[tex]AB = c = 21.3[/tex]

Hence:

[tex]AB = 21.3[/tex]

Answer:

[tex] \displaystyle d)\frac{d ^{2} y}{d{x}^{2} } = 2 + \frac{ 42}{ {x}^{4} }[/tex]

Step-by-step explanation:

we would like to figure out the second derivative of the following:

[tex] \displaystyle y = \frac{ {x}^{4} + 7}{ {x}^{2} } [/tex]

we can rewrite it thus rewrite:

[tex] \displaystyle y = {x}^{2} + 7 {x}^{ - 2} [/tex]

take derivative in both sides:

[tex] \displaystyle \frac{dy}{dx} = \frac{d}{dx}( {x}^{2} + 7 {x}^{ - 2} )[/tex]

by sum derivation we obtain:

[tex] \displaystyle \frac{dy}{dx} = \frac{d}{dx}{x}^{2} + \frac{d}{dx} 7 {x}^{ - 2}[/tex]

by exponent derivation we acquire:

[tex] \displaystyle \frac{dy}{dx} = 2{x}^{} - 14 {x}^{ - 3}[/tex]

take derivative In both sides once again:

[tex] \displaystyle \frac{d ^{2} y}{d{x}^{2} } = \frac{d}{d x } (2{x}^{} - 14 {x}^{ - 3})[/tex]

use difference rule which yields:

[tex] \displaystyle \frac{d ^{2} y}{d{x}^{2} } = \frac{d}{d x } 2{x}^{} - \frac{d}{dx} 14{x}^{ - 3}[/tex]

use exponent derivation which yields:

[tex] \displaystyle \frac{d ^{2} y}{d{x}^{2} } = 2 + 42{x}^{ - 4}[/tex]

by law of exponent we get:

[tex] \displaystyle \frac{d ^{2} y}{d{x}^{2} } = 2 + \frac{ 42}{ {x}^{4} }[/tex]

hence, our answer is d)

The Answer is:

C.) (x+2)(x+3)

Answer:

(x-2)(x+3)

Step-by-step explanation:

1. Start by setting up the synthetic division. The numbers 1, -4, -11, and 30 go on the inside on the division. To get the number on the outside, set x-5 equal to 0. solve and get 5.

2. bring the one down. multiply the one and the five and place the number you get underneath the -4 in the next column. From there, add the two numbers in the column.

3. After adding those two numbers, put the number you get (which should be 1) directly below the 5. Now multiply that number and the 5 again.

4. Repeat these steps until you fill the spaces under the next two columns. If you do it correctly, the number at the bottom of the very last column should be 0. This zero is known as the remainder. The remainder is not needed to complete this problem.

 Now that you have finished synthetic division, it is time to set up the new equation you got.

5. The 1 on the bottom left will be your [tex]x^{2}[/tex] value, the next 1 will be your x value, and the -6 will be your c. You should get the equation [tex]x^{2} + x -6[/tex]

6. From here, factor the polynomial. The factors must add up to the middle value (1) and multiple to c (-6). The factors -2 and 3 add up to 1 and multiply to -6

Therefore, your answer will be (x-2)(x+3)

Answer:

-3

Step-by-step explanation:

This is a quadratic equation. Therefore, one way we can solve this is by using the quadratic formula, [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex].

a, b, and c represent the coefficients in our equation [tex]x^2-5x-24=0[/tex]. a represents the coefficient of the term with degree of 2, which is 1. b represents the coefficient of the term with degree of 1, which is -5. c represents the coefficient of the term with degree of 0, which is -24.

Let us plug them in the equation! Let us start with this one: [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5+\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5+\sqrt{25+96} }{2} =\\\frac{5+\sqrt{121} }{2} =\\\frac{5+11}{2} =\\\frac{16}{2} =\\8[/tex]

Oops! We are looking for the other solution. Let us plug in the values in this equation instead: [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5-\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5-\sqrt{25+96} }{2} =\\\frac{5-\sqrt{121} }{2} =\\\frac{5-11}{2} =\\\frac{-6}{2} =\\-3[/tex]

I hope this helps! Let me know if you have any questions :)

Answer: the 23rd term of the arithmetic sequence=91

Step-by-step explanation:

The nth term of an arithmetic sequence is given as

an=a+  (n-1) d

Given common difference , d=4 and

first term is a^1 = 3.

We have that

a₂₃=3+  (23-1) 4

a₂₃=3+  (22) 4

a₂₃=3+  88

a₂₃=91

the 23rd term of the arithmetic sequence=91

Answer:

ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm   and i Oop

Step-by-step explanation: